Quantitative Aptitude

Trigonometry Guide & Practice

Master trigonometric ratios, identities, height and distance problems with solved examples and free SSC CGL/Defence exam mock tests. Explore dynamic solver blueprints, master fundamental equations, examine step-by-step solved examples, and practice with real exam-grade mock test sets.

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1. Fundamentals & Definitions

Angles and Measurements

  • Angle: The measure of rotation of a given ray about its initial point.
    • Vertex: The point of rotation.
    • Initial Side: The original position of the ray before rotation.
    • Terminal Side: The final position of the ray after rotation.
    • Positive Angle: Angle generated when the rotation is anticlockwise.
    • Negative Angle: Angle generated when the rotation is clockwise.
  • Systems of Angle Measurement:
    • Sexagesimal System (Degree Measure):
      • If a rotation from the initial side to the terminal side is 1360th\frac{1}{360}^{\text{th}} of a complete revolution, the angle is defined as one degree (11^\circ).
      • A degree is divided into 6060 minutes (1=601^\circ = 60').
      • A minute is divided into 6060 seconds (1=601' = 60'').
    • Circular System (Radian Measure):
      • An angle subtended at the center of a unit circle (radius r=1r = 1) by an arc of length 11 unit is defined as 11 radian (1 rad1\text{ rad}).
      • In a circle of radius rr, an arc of length ll subtends an angle θ\theta (in radians) at the center: θ=lr    l=rθ\theta = \frac{l}{r} \implies l = r\theta
    • Relation between Degrees and Radians:
      • π radians=180\pi \text{ radians} = 180^\circ
      • 1 radian=180π5716221 \text{ radian} = \frac{180^\circ}{\pi} \approx 57^\circ 16' 22''
      • 1=π180 radians0.01745 radians1^\circ = \frac{\pi}{180} \text{ radians} \approx 0.01745 \text{ radians}
      • Conversion Formulas: Radian measure=π180×Degree measure\text{Radian measure} = \frac{\pi}{180} \times \text{Degree measure} Degree measure=180π×Radian measure\text{Degree measure} = \frac{180}{\pi} \times \text{Radian measure}

Trigonometric Ratios (Right-Angled Triangle)

For a right-angled triangle ABCABC, right-angled at BB (B=90\angle B = 90^\circ) with acute angle A=θ\angle A = \theta:

  • Base (Adjacent Side, bb): The side adjacent to angle θ\theta (ABAB).
  • Perpendicular (Opposite Side, pp): The side opposite to angle θ\theta (BCBC).
  • Hypotenuse (hh): The side opposite to the right angle (ACAC).
  • Definitions:
    • sinθ=PerpendicularHypotenuse=ph\sin\theta = \frac{\text{Perpendicular}}{\text{Hypotenuse}} = \frac{p}{h}
    • cosθ=BaseHypotenuse=bh\cos\theta = \frac{\text{Base}}{\text{Hypotenuse}} = \frac{b}{h}
    • tanθ=PerpendicularBase=pb=sinθcosθ\tan\theta = \frac{\text{Perpendicular}}{\text{Base}} = \frac{p}{b} = \frac{\sin\theta}{\cos\theta}
    • cscθ=HypotenusePerpendicular=hp=1sinθ\csc\theta = \frac{\text{Hypotenuse}}{\text{Perpendicular}} = \frac{h}{p} = \frac{1}{\sin\theta}
    • secθ=HypotenuseBase=hb=1cosθ\sec\theta = \frac{\text{Hypotenuse}}{\text{Base}} = \frac{h}{b} = \frac{1}{\cos\theta}
    • cotθ=BasePerpendicular=bp=1tanθ\cot\theta = \frac{\text{Base}}{\text{Perpendicular}} = \frac{b}{p} = \frac{1}{\tan\theta}

Unit Circle Trigonometry

Let P(x,y)P(x, y) be any point on a unit circle centered at the origin O(0,0)O(0, 0) such that the ray OPOP makes an angle θ\theta with the positive x-axis.

  • cosθ=x\cos\theta = x
  • sinθ=y\sin\theta = y
  • tanθ=yx(x0)\tan\theta = \frac{y}{x} \quad (x \neq 0)
  • Quadrantal Angles: Angles that are integral multiples of π2\frac{\pi}{2} (0,π2,π,3π2,2π0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi, etc.). For these, the terminal side coincides with a coordinate axis.

Height & Distance Terminology

  • Line of Sight: The straight line path from the observer's eye to the object being viewed.
  • Angle of Elevation: The angle between the line of sight and the horizontal plane when the object is above the horizontal plane.
  • Angle of Depression: The angle between the line of sight and the horizontal plane when the object is below the horizontal plane.

2. Core Concepts & Formulas

Trigonometric Values of Standard Angles

Angle (Degrees)Angle (Radians)sinθ\sin\thetacosθ\cos\thetatanθ\tan\thetacscθ\csc\thetasecθ\sec\thetacotθ\cot\theta
00^\circ00001100Undefined11Undefined
3030^\circπ6\frac{\pi}{6}12\frac{1}{2}32\frac{\sqrt{3}}{2}13\frac{1}{\sqrt{3}}2223\frac{2}{\sqrt{3}}3\sqrt{3}
4545^\circπ4\frac{\pi}{4}12\frac{1}{\sqrt{2}}12\frac{1}{\sqrt{2}}112\sqrt{2}2\sqrt{2}11
6060^\circπ3\frac{\pi}{3}32\frac{\sqrt{3}}{2}12\frac{1}{2}3\sqrt{3}23\frac{2}{\sqrt{3}}2213\frac{1}{\sqrt{3}}
9090^\circπ2\frac{\pi}{2}1100Undefined11Undefined00
180180^\circπ\pi001-100Undefined1-1Undefined
270270^\circ3π2\frac{3\pi}{2}1-100Undefined1-1Undefined00
360360^\circ2π2\pi001100Undefined11Undefined

Special Competitive Exam Angles

Angle (Degrees)sinθ\sin\thetacosθ\cos\thetatanθ\tan\thetacotθ\cot\theta
1515^\circ (π12\frac{\pi}{12})3122\frac{\sqrt{3}-1}{2\sqrt{2}}3+122\frac{\sqrt{3}+1}{2\sqrt{2}}232-\sqrt{3}2+32+\sqrt{3}
7575^\circ (5π12\frac{5\pi}{12})3+122\frac{\sqrt{3}+1}{2\sqrt{2}}3122\frac{\sqrt{3}-1}{2\sqrt{2}}2+32+\sqrt{3}232-\sqrt{3}
1818^\circ (π10\frac{\pi}{10})514\frac{\sqrt{5}-1}{4}10+254\frac{\sqrt{10+2\sqrt{5}}}{4}125\sqrt{1 - \frac{2}{\sqrt{5}}}5+25\sqrt{5+2\sqrt{5}}
3636^\circ (π5\frac{\pi}{5})10254\frac{\sqrt{10-2\sqrt{5}}}{4}5+14\frac{\sqrt{5}+1}{4}525\sqrt{5-2\sqrt{5}}1+25\sqrt{1 + \frac{2}{\sqrt{5}}}
22.522.5^\circ (π8\frac{\pi}{8})222\frac{\sqrt{2-\sqrt{2}}}{2}2+22\frac{\sqrt{2+\sqrt{2}}}{2}21\sqrt{2}-12+1\sqrt{2}+1

Behavior & Signs of Trigonometric Functions

  • ASTC Quadrant Rule:
    • Quadrant I (0<θ<900 < \theta < 90^\circ): All functions are positive.
    • Quadrant II (90<θ<18090^\circ < \theta < 180^\circ): Only Sine (and Cosecant) are positive.
    • Quadrant III (180<θ<270180^\circ < \theta < 270^\circ): Only Tangent (and Cotangent) are positive.
    • Quadrant IV (270<θ<360270^\circ < \theta < 360^\circ): Only Cosine (and Secant) are positive.
Quadrantsinx\sin x / cscx\csc xcosx\cos x / secx\sec xtanx\tan x / cotx\cot x
I++++++
II++--
III--++
IV-++-
  • Ranges of Trigonometric Functions:
    • 1sinθ1-1 \le \sin\theta \le 1
    • 1cosθ1-1 \le \cos\theta \le 1
    • secθ1\sec\theta \ge 1 or secθ1\sec\theta \le -1
    • cscθ1\csc\theta \ge 1 or cscθ1\csc\theta \le -1
    • <tanθ<-\infty < \tan\theta < \infty
    • <cotθ<-\infty < \cot\theta < \infty

Fundamental Trigonometric Identities

  • Pythagorean Identities:
    1. sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1
    2. 1+tan2θ=sec2θ    sec2θtan2θ=1    (secθtanθ)=1secθ+tanθ1 + \tan^2\theta = \sec^2\theta \implies \sec^2\theta - \tan^2\theta = 1 \implies (\sec\theta - \tan\theta) = \frac{1}{\sec\theta + \tan\theta}
    3. 1+cot2θ=csc2θ    csc2θcot2θ=1    (cscθcotθ)=1cscθ+cotθ1 + \cot^2\theta = \csc^2\theta \implies \csc^2\theta - \cot^2\theta = 1 \implies (\csc\theta - \cot\theta) = \frac{1}{\csc\theta + \cot\theta}

Even-Odd (Negative Angle) Identities

  • sin(θ)=sinθ\sin(-\theta) = -\sin\theta
  • cos(θ)=cosθ\cos(-\theta) = \cos\theta
  • tan(θ)=tanθ\tan(-\theta) = -\tan\theta
  • csc(θ)=cscθ\csc(-\theta) = -\csc\theta
  • sec(θ)=secθ\sec(-\theta) = \sec\theta
  • cot(θ)=cotθ\cot(-\theta) = -\cot\theta

Allied and Complementary Angle Formulas

Functionθ-\theta90θ90^\circ - \theta90+θ90^\circ + \theta180θ180^\circ - \theta180+θ180^\circ + \theta270θ270^\circ - \theta270+θ270^\circ + \theta360θ360^\circ - \theta
sin\sinsinθ-\sin\thetacosθ\cos\thetacosθ\cos\thetasinθ\sin\thetasinθ-\sin\thetacosθ-\cos\thetacosθ-\cos\thetasinθ-\sin\theta
cos\coscosθ\cos\thetasinθ\sin\thetasinθ-\sin\thetacosθ-\cos\thetacosθ-\cos\thetasinθ-\sin\thetasinθ\sin\thetacosθ\cos\theta
tan\tantanθ-\tan\thetacotθ\cot\thetacotθ-\cot\thetatanθ-\tan\thetatanθ\tan\thetacotθ\cot\thetacotθ-\cot\thetatanθ-\tan\theta
csc\csccscθ-\csc\thetasecθ\sec\thetasecθ\sec\thetacscθ\csc\thetacscθ-\csc\thetasecθ-\sec\thetasecθ-\sec\thetacscθ-\csc\theta
sec\secsecθ\sec\thetacscθ\csc\thetacscθ-\csc\thetasecθ-\sec\thetasecθ-\sec\thetacscθ-\csc\thetacscθ\csc\thetasecθ\sec\theta
cot\cotcotθ-\cot\thetatanθ\tan\thetatanθ-\tan\thetacotθ-\cot\thetacotθ\cot\thetatanθ\tan\thetatanθ-\tan\thetacotθ-\cot\theta

Compound Angle Formulas

  • sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B
  • cos(A±B)=cosAcosBsinAsinB\cos(A \pm B) = \cos A \cos B \mp \sin A \sin B
  • tan(A±B)=tanA±tanB1tanAtanB\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A \tan B}
  • cot(A±B)=cotAcotB1cotB±cotA\cot(A \pm B) = \frac{\cot A \cot B \mp 1}{\cot B \pm \cot A}

Double Angle Formulas

  • sin2θ=2sinθcosθ=2tanθ1+tan2θ\sin 2\theta = 2\sin\theta\cos\theta = \frac{2\tan\theta}{1+\tan^2\theta}
  • cos2θ=cos2θsin2θ=2cos2θ1=12sin2θ=1tan2θ1+tan2θ\cos 2\theta = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta = \frac{1-\tan^2\theta}{1+\tan^2\theta}
    • 1cos2θ=2sin2θ    sin2θ=1cos2θ21 - \cos 2\theta = 2\sin^2\theta \implies \sin^2\theta = \frac{1-\cos 2\theta}{2}
    • 1+cos2θ=2cos2θ    cos2θ=1+cos2θ21 + \cos 2\theta = 2\cos^2\theta \implies \cos^2\theta = \frac{1+\cos 2\theta}{2}
  • tan2θ=2tanθ1tan2θ\tan 2\theta = \frac{2\tan\theta}{1-\tan^2\theta}

Triple Angle Formulas

  • sin3θ=3sinθ4sin3θ\sin 3\theta = 3\sin\theta - 4\sin^3\theta
  • cos3θ=4cos3θ3cosθ\cos 3\theta = 4\cos^3\theta - 3\cos\theta
  • tan3θ=3tanθtan3θ13tan2θ\tan 3\theta = \frac{3\tan\theta - \tan^3\theta}{1-3\tan^2\theta}

Half-Angle Formulas

  • sinθ2=±1cosθ2\sin\frac{\theta}{2} = \pm\sqrt{\frac{1-\cos\theta}{2}}
  • cosθ2=±1+cosθ2\cos\frac{\theta}{2} = \pm\sqrt{\frac{1+\cos\theta}{2}}
  • tanθ2=±1cosθ1+cosθ=1cosθsinθ=sinθ1+cosθ\tan\frac{\theta}{2} = \pm\sqrt{\frac{1-\cos\theta}{1+\cos\theta}} = \frac{1-\cos\theta}{\sin\theta} = \frac{\sin\theta}{1+\cos\theta}

Sum, Difference & Product Conversion Formulas

  • Product to Sum/Difference:
    • 2sinAcosB=sin(A+B)+sin(AB)2\sin A \cos B = \sin(A + B) + \sin(A - B)
    • 2cosAsinB=sin(A+B)sin(AB)2\cos A \sin B = \sin(A + B) - \sin(A - B)
    • 2cosAcosB=cos(A+B)+cos(AB)2\cos A \cos B = \cos(A + B) + \cos(A - B)
    • 2sinAsinB=cos(AB)cos(A+B)2\sin A \sin B = \cos(A - B) - \cos(A + B)
  • Sum/Difference to Product:
    • sinx+siny=2sin(x+y2)cos(xy2)\sin x + \sin y = 2\sin\left(\frac{x+y}{2}\right)\cos\left(\frac{x-y}{2}\right)
    • sinxsiny=2cos(x+y2)sin(xy2)\sin x - \sin y = 2\cos\left(\frac{x+y}{2}\right)\sin\left(\frac{x-y}{2}\right)
    • cosx+cosy=2cos(x+y2)cos(xy2)\cos x + \cos y = 2\cos\left(\frac{x+y}{2}\right)\cos\left(\frac{x-y}{2}\right)
    • cosxcosy=2sin(x+y2)sin(xy2)\cos x - \cos y = -2\sin\left(\frac{x+y}{2}\right)\sin\left(\frac{x-y}{2}\right)

Maximum and Minimum of acosθ+bsinθa\cos\theta + b\sin\theta

  • For the expression f(θ)=acosθ+bsinθf(\theta) = a\cos\theta + b\sin\theta:
    • Maximum Value: a2+b2\sqrt{a^2 + b^2}
    • Minimum Value: a2+b2-\sqrt{a^2 + b^2}
    • Range: [a2+b2,a2+b2][-\sqrt{a^2 + b^2}, \sqrt{a^2 + b^2}]

Trigonometric Equations & General Solutions

For nZn \in \mathbb{Z}:

  • sinθ=0    θ=nπ\sin\theta = 0 \implies \theta = n\pi
  • cosθ=0    θ=(2n+1)π2\cos\theta = 0 \implies \theta = (2n+1)\frac{\pi}{2}
  • tanθ=0    θ=nπ\tan\theta = 0 \implies \theta = n\pi
  • sinθ=sinα    θ=nπ+(1)nα\sin\theta = \sin\alpha \implies \theta = n\pi + (-1)^n\alpha
  • cosθ=cosα    θ=2nπ±α\cos\theta = \cos\alpha \implies \theta = 2n\pi \pm \alpha
  • tanθ=tanα    θ=nπ+α\tan\theta = \tan\alpha \implies \theta = n\pi + \alpha
  • sin2θ=sin2α    θ=nπ±α\sin^2\theta = \sin^2\alpha \implies \theta = n\pi \pm \alpha
  • cos2θ=cos2α    θ=nπ±α\cos^2\theta = \cos^2\alpha \implies \theta = n\pi \pm \alpha
  • tan2θ=tan2α    θ=nπ±α\tan^2\theta = \tan^2\alpha \implies \theta = n\pi \pm \alpha

Properties of Triangles (For NDA/CDS/JEE)

In any triangle ABCABC with sides a,b,ca, b, c opposite to angles A,B,CA, B, C:

  • Sine Rule: asinA=bsinB=csinC=2R(R=circumradius)\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = 2R \quad (R = \text{circumradius})
  • Cosine Rule:
    • cosA=b2+c2a22bc\cos A = \frac{b^2 + c^2 - a^2}{2bc}
    • cosB=a2+c2b22ac\cos B = \frac{a^2 + c^2 - b^2}{2ac}
    • cosC=a2+b2c22ab\cos C = \frac{a^2 + b^2 - c^2}{2ab}
  • Projection Formula:
    • a=bcosC+ccosBa = b\cos C + c\cos B
    • b=ccosA+acosCb = c\cos A + a\cos C
    • c=acosB+bcosAc = a\cos B + b\cos A
  • Napier's Analogy (Law of Tangents):
    • tan(AB2)=aba+bcot(C2)\tan\left(\frac{A-B}{2}\right) = \frac{a-b}{a+b}\cot\left(\frac{C}{2}\right)
    • tan(BC2)=bcb+ccot(A2)\tan\left(\frac{B-C}{2}\right) = \frac{b-c}{b+c}\cot\left(\frac{A}{2}\right)
    • tan(CA2)=cac+acot(B2)\tan\left(\frac{C-A}{2}\right) = \frac{c-a}{c+a}\cot\left(\frac{B}{2}\right)
  • Mollweide's Equation: abc=sin(AB2)cos(C2)\frac{a-b}{c} = \frac{\sin\left(\frac{A-B}{2}\right)}{\cos\left(\frac{C}{2}\right)}

Inverse Trigonometric Functions

FunctionDomainPrincipal Value Branch (Range)
sin1x\sin^{-1}x[1,1][-1, 1][π2,π2][-\frac{\pi}{2}, \frac{\pi}{2}]
cos1x\cos^{-1}x[1,1][-1, 1][0,π][0, \pi]
tan1x\tan^{-1}xR\mathbb{R}(π2,π2)(-\frac{\pi}{2}, \frac{\pi}{2})
csc1x\csc^{-1}xR(1,1)\mathbb{R} \setminus (-1, 1)[π2,π2]0[-\frac{\pi}{2}, \frac{\pi}{2}] \setminus {0}
sec1x\sec^{-1}xR(1,1)\mathbb{R} \setminus (-1, 1)[0,π]π2[0, \pi] \setminus {\frac{\pi}{2}}
cot1x\cot^{-1}xR\mathbb{R}(0,π)(0, \pi)

Typical Exam Weightage

ExamTypical Questions
SSC (CGL / CHSL / MTS)3–4 questions
Defense (NDA / CDS)2–3 questions

Heavily formula-dependent — a small set of standard-angle values and identities covers the large majority of questions asked.

Figures are typical ranges based on recent-year patterns, not a guarantee for any specific upcoming paper — always cross-check against the latest official syllabus and previous-year papers for Trigonometry.

Solved Examples

1Example 1: Easy

Question: If cosθ=45\cos\theta = \frac{4}{5} where 0<θ<900^\circ < \theta < 90^\circ, find the value of 3sinθ+2tanθ5cotθcscθ\frac{3\sin\theta + 2\tan\theta}{5\cot\theta - \csc\theta}.

2Example 2: Moderate

Question: Evaluate the expression: cos(90A)sec(90A)tanAcsc(90A)sin(90A)cot(90A)+tan(90A)cotA\frac{\cos(90^\circ - A)\cdot\sec(90^\circ - A)\cdot\tan A}{\csc(90^\circ - A)\cdot\sin(90^\circ - A)\cdot\cot(90^\circ - A)} + \frac{\tan(90^\circ - A)}{\cot A}

3Example 3: Hard

Question: The angle of elevation of a cloud from a point hh meters above a lake is α\alpha, and the angle of depression of its reflection in the lake is β\beta. Prove that the height of the cloud above the lake is h(tanβ+tanαtanβtanα)h\left(\frac{\tan\beta + \tan\alpha}{\tan\beta - \tan\alpha}\right).