Quantitative Aptitude

Simplification Guide & Practice

Practice BODMAS rule, fraction simplification, square root approximation, and surds with solved examples and free Banking/SSC mock tests. Explore dynamic solver blueprints, master fundamental equations, examine step-by-step solved examples, and practice with real exam-grade mock test sets.

Practice Question Papers

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Simplification - Set 5 Practice Test

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Quantitative Aptitude

Simplification - Set 5 Practice Test

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15 Qs
22 min
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Simplification - Set 3 Practice Test

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15 Qs
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Quantitative Aptitude

Simplification - Set 2 Practice Test

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15 Qs
22 min
Medium
Quantitative Aptitude

Simplification - Set 4 Practice Test

Jun 2026
15 Qs
22 min
Hard
Quantitative Aptitude

Simplification - Set 3 Practice Test

Jun 2026
15 Qs
22 min
Hard
Quantitative Aptitude

Simplification - Set 2 Practice Test

Jun 2026
15 Qs
22 min
Hard
Quantitative Aptitude

Simplification - Set 1 Practice Test

Jun 2026
15 Qs
22 min
Hard
Quantitative Aptitude

Simplification - Set 4 Practice Test

Jun 2026
15 Qs
22 min
Easy
Quantitative Aptitude

Simplification - Set 3 Practice Test

Jun 2026
15 Qs
22 min
Easy

1. Fundamentals & Definitions

  • Simplification: The process of reducing a complex mathematical expression containing multiple arithmetic operations into a single, exact numerical value. It requires strict adherence to order-of-operation rules without any rounding.
  • Approximation: The process of finding a value closest to the exact numerical value of a mathematical expression by rounding the constituent numbers to the nearest whole numbers or convenient equivalents. It is applied when calculating exact answers is computationally expensive or when decimal terms are very close to integers.
  • Order of Operations (VBODMAS): A sequential hierarchy of mathematical operations used to solve multi-operational expressions.
    • V (Vinculum/Bar): A horizontal bar (x‾\overline{x}) indicating that the operations under it must be performed first.
    • B (Brackets): Grouping punctuation solved in the sequence: Parentheses (), Braces {}, and Square Brackets [].
    • O (Of / Order): Represents multiplication associated with percentages or terms grouped with "of" (e.g., a%a\% of bb). It holds a higher precedence than standard division.
    • D (Division): Division operation (÷\div or //).
    • M (Multiplication): Basic multiplication operation (×\times or ∗*).
    • A (Addition): Addition operation (++).
    • S (Subtraction): Subtraction operation (−-).
  • Surd: An irrational number that cannot be expressed as a ratio of integers and is written with a root symbol (e.g., 3\sqrt{3}, 53\sqrt[3]{5}).
  • Index (Plural: Indices): The exponent or power to which a base number is raised, representing how many times the base is multiplied by itself (e.g., in xnx^n, nn is the index).
  • Fraction: A numerical representation of a part of a whole, written as a numerator over a denominator (a/ba/b).
  • Mixed Fraction: A number composed of a whole number and a proper fraction (e.g., abca \frac{b}{c}).
  • Perfect Square: An integer that is the square of another integer (e.g., 1,4,9,16,25,…1, 4, 9, 16, 25, \dots).
  • Perfect Cube: An integer that is the cube of another integer (e.g., 1,8,27,64,125,…1, 8, 27, 64, 125, \dots).

2. Core Concepts & Formulas

A. VBODMAS Precedence Hierarchy

When evaluating expressions, operations must be performed in the following order:

HierarchyOperationSymbolEvaluation Rule
1Vinculum (Bar)x±y‾\overline{x \pm y}Evaluate the terms under the bar line first.
2Brackets(), {}, []Solve inside-out: Parentheses () →\rightarrow Braces {} →\rightarrow Square Brackets [].
3Of / Orderof, %\%Compute percentages or direct "of" terms next. (x%x\% of y=x100×yy = \frac{x}{100} \times y).
4Division÷\div, //Divide terms from left to right.
5Multiplication×\times, ∗*Multiply terms.
6Addition++Add positive values together.
7Subtraction−-Subtract negative values.

B. Standard Fraction to Percentage Conversions

Using fractional equivalents for percentages streamlines simplification. The table below lists standard equivalences:

PercentageFractionPercentageFraction
100%100\%119.09%9.09\% (9111%9 \frac{1}{11}\%)1/111/11
50%50\%1/21/28.33%8.33\% (8112%8 \frac{1}{12}\%)1/121/12
33.33%33.33\% (3313%33 \frac{1}{3}\%)1/31/37.69%7.69\%1/131/13
25%25\%1/41/47.14%7.14\% (717%7 \frac{1}{7}\%)1/141/14
20%20\%1/51/56.67%6.67\% (623%6 \frac{2}{3}\%)1/151/15
16.67%16.67\% (1623%16 \frac{2}{3}\%)1/61/66.25%6.25\% (614%6 \frac{1}{4}\%)1/161/16
14.28%14.28\% (1427%14 \frac{2}{7}\%)1/71/75%5\%1/201/20
12.5%12.5\% (1212%12 \frac{1}{2}\%)1/81/84%4\%1/251/25
11.11%11.11\% (1119%11 \frac{1}{9}\%)1/91/937.5%37.5\%3/83/8
62.5%62.5\%5/85/887.5%87.5\%7/87/8
66.67%66.67\% (6623%66 \frac{2}{3}\%)2/32/357.14%57.14\% (5717%57 \frac{1}{7}\%)4/74/7
35.71%35.71\% (3557%35 \frac{5}{7}\%)5/145/1477.78%77.78\% (7779%77 \frac{7}{9}\%)7/97/9

C. Rules of Indices & Powers

These properties are essential for solving base-comparison equations (e.g., ax=ay⇒x=ya^x = a^y \Rightarrow x = y):

  • Product Rule: am×an=am+na^m \times a^n = a^{m+n}
  • Quotient Rule: am÷an=am−na^m \div a^n = a^{m-n}
  • Power of a Power Rule: (am)n=am⋅n(a^m)^n = a^{m \cdot n}
  • Power of a Product Rule: (ab)n=an⋅bn(ab)^n = a^n \cdot b^n
  • Power of a Quotient Rule: (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}
  • Negative Exponent Rule: a−n=1ana^{-n} = \frac{1}{a^n}
  • Zero Exponent Rule: a0=1a^0 = 1 (a≠0a \neq 0)
  • Fractional Index (Surd): an=a1/n\sqrt[n]{a} = a^{1/n}
  • Product of Surds: an×bn=abn\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{ab}
  • Quotient of Surds: anbn=abn\frac{\sqrt[n]{a}}{\sqrt[n]{b}} = \sqrt[n]{\frac{a}{b}}

D. Perfect Squares (1 to 30) & Perfect Cubes (1 to 15)

Memorizing powers speeds up square/cube root estimation:

NumberSquareCubeNumberSquareCube
111111625625640964096
244881728928949134913
39927271832432458325832
4161664641936136168596859
525251251252040040080008000
636362162162144144192619261
74949343343224844841064810648
86464512512235295291216712167
98181729729245765761382413824
1010010010001000256256251562515625
1112112113311331266766761757617576
1214414417281728277297291968319683
1316916921972197287847842195221952
1419619627442744298418412438924389
1522522533753375309009002700027000

E. Algebraic Simplification Identities

  • (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
  • (a−b)2=a2−2ab+b2(a - b)^2 = a^2 - 2ab + b^2
  • a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b)
  • (a+b)3=a3+b3+3ab(a+b)(a + b)^3 = a^3 + b^3 + 3ab(a + b)
  • (a−b)3=a3−b3−3ab(a−b)(a - b)^3 = a^3 - b^3 - 3ab(a - b)
  • a3+b3=(a+b)(a2−ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2)
  • a3−b3=(a−b)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2)

F. Approximation Principles

  1. Decimal Rounding:
    • If the digit in the tenths place is less than 55 (<0.5< 0.5), truncate the decimal part (e.g., 14.15≈1414.15 \approx 14, 119.94≈120119.94 \approx 120).
    • If the digit in the tenths place is 55 or more (≥0.5\ge 0.5), round up to the next integer (e.g., 51.89≈5251.89 \approx 52, 10.98≈1110.98 \approx 11).
  2. Root Estimation:
    • For roots of non-perfect numbers, round the value inside the radical to the nearest perfect square or cube (e.g., 360≈361=19\sqrt{360} \approx \sqrt{361} = 19; 1090≈1089=33\sqrt{1090} \approx \sqrt{1089} = 33; 21983≈21973=13\sqrt[3]{2198} \approx \sqrt[3]{2197} = 13).
  3. Percentage Approximation:
    • Convert complex decimal percentages to their nearest integer percentages or fractional equivalents (e.g., 39.95%≈40%39.95\% \approx 40\%; 77.78%≈7/977.78\% \approx 7/9).

Typical Exam Weightage

ExamTypical Questions
Banking (IBPS / SBI)5–10 questions (often the opening set in Prelims)
SSC (CGL / CHSL / MTS)2–3 questions

The highest-volume, lowest-difficulty quant topic in Banking Prelims — speed here is what separates strong and average scorers, since accuracy is rarely the bottleneck.

Figures are typical ranges based on recent-year patterns, not a guarantee for any specific upcoming paper — always cross-check against the latest official syllabus and previous-year papers for Simplification.

Solved Examples

1Example 1: Easy (Simplification)

Question: What value should come in place of the question mark (??) in the following equation? 38×560+25×350−34×200=?\frac{3}{8} \times 560 + \frac{2}{5} \times 350 - \frac{3}{4} \times 200 = ?

View Detailed Solution & Explanation
Step-by-Step Explanation
  1. Step 1: Solve the first term: 38×560=3×70=210\frac{3}{8} \times 560 = 3 \times 70 = 210
  2. Step 2: Solve the second term: 25×350=2×70=140\frac{2}{5} \times 350 = 2 \times 70 = 140
  3. Step 3: Solve the third term: 34×200=3×50=150\frac{3}{4} \times 200 = 3 \times 50 = 150
  4. Step 4: Substitute the values back into the expression: 210+140−150210 + 140 - 150
  5. Step 5: Complete addition and subtraction in order: 350−150=200350 - 150 = 200

Answer: 200200

2Example 2: Moderate (Simplification with Powers & Percentages)

Question: Solve the exact value of xx in the following equation: 58% of 1450−16% of 650+7396=x\sqrt{58\% \text{ of } 1450} - 16\% \text{ of } 650 + \sqrt{7396} = x

View Detailed Solution & Explanation
Step-by-Step Explanation
  1. Step 1: Calculate the percentage inside the radical: 58% of 1450=58100×1450=58×14510=841010=84158\% \text{ of } 1450 = \frac{58}{100} \times 1450 = \frac{58 \times 145}{10} = \frac{8410}{10} = 841 Now find the square root of 841841: 841=29(since 292=841)\sqrt{841} = 29 \quad (\text{since } 29^2 = 841)
  2. Step 2: Calculate 16%16\% of 650650: 16% of 650=16100×650=1.6×65=10416\% \text{ of } 650 = \frac{16}{100} \times 650 = 1.6 \times 65 = 104
  3. Step 3: Evaluate 7396\sqrt{7396}: Observe that 802=640080^2 = 6400 and 902=810090^2 = 8100. Since 73967396 ends in 66, its square root must end in either 44 or 66. Testing 8686: 86×86=7396⇒7396=8686 \times 86 = 7396 \Rightarrow \sqrt{7396} = 86
  4. Step 4: Substitute the simplified components back into the equation: x=29−104+86x = 29 - 104 + 86
  5. Step 5: Solve the arithmetic operations: x=(29+86)−104=115−104=11x = (29 + 86) - 104 = 115 - 104 = 11

Answer: 1111

3Example 3: Hard (Multi-step Approximation)

Question: What approximate value should come in place of the question mark (??) in the following equation? (4179.91÷360)−(627.09÷1090)×10.98=?(4179.91 \div \sqrt{360}) - (627.09 \div \sqrt{1090}) \times 10.98 = ?

View Detailed Solution & Explanation
Step-by-Step Explanation
  1. Step 1: Round off the decimal values to the nearest integer/perfect values:
    • 4179.91≈41804179.91 \approx 4180
    • 360≈361=19\sqrt{360} \approx \sqrt{361} = 19 (since 192=36119^2 = 361)
    • 627.09≈627627.09 \approx 627
    • 1090≈1089=33\sqrt{1090} \approx \sqrt{1089} = 33 (since 332=108933^2 = 1089)
    • 10.98≈1110.98 \approx 11
  2. Step 2: Rewrite the equation using these approximated values: (4180÷19)−(627÷33)×11=?(4180 \div 19) - (627 \div 33) \times 11 = ?
  3. Step 3: Evaluate division terms according to VBODMAS:
    • First term division: 4180÷19=2204180 \div 19 = 220
    • Second term division: 627÷33=19627 \div 33 = 19 The equation simplifies to: 220−19×11=?220 - 19 \times 11 = ?
  4. Step 4: Perform the multiplication before subtraction: 19×11=20919 \times 11 = 209 The equation simplifies to: 220−209=?220 - 209 = ?
  5. Step 5: Compute the final subtraction: ?=11? = 11

Answer: 1111