Factors of 2240 are numbers that, when multiplied in pairs give the product as 2240. There are overall 28 factors of 2240, of which 2, 5, 7 are its prime factors.
The prime factorization of 2240 is 26 × 51 × 71.
All factors of 2240 are: 1, 2, 4, 5, 7, 8, 10, 14, 16, 20, 28, 32, 35, 40, 56, 64, 70, 80, 112, 140, 160, 224, 280, 320, 448, 560, 1120 and 2240.
Sum of all factors = 1 + 2 + 4 + 5 + 7 + 8 + 10 + 14 + 16 + 20 + 28 + 32 + 35 + 40 + 56 + 64 + 70 + 80 + 112 + 140 + 160 + 224 + 280 + 320 + 448 + 560 + 1120 + 2240 = 6096
⇒ Sum of all factors = 6096
Hence, option 3 is the correct answer.

Alternate Method Concept:
If N = ap × bq × cr where a, b, and c are prime numbers then,
Sum of factors of N = (a0 + a1 + ...ap) × (b0 + b1 + ....bq) × (c0 + c1 +...cr)
Calculation:
The prime factorization of 2240 = 26 × 51 × 71
The sum of factors = (20 + 21 + ....+ 26) × (50 + 51) × (70 + 71)
⇒ (1 + 2 + 4 + 8 + 16 + 32 + 64) × (1 + 5) × (1 + 7)
⇒ (127) × (6) × (8)
⇒ 6096
∴ The correct answer is 6096.