Find out the total number of students who have cleared the entrance exam from 2016 to 2020 in State A.
- ((a))
355460
- ((b))
364420
- ((c))
360890
- ((d))
358660
Show Answer
364420
Given:
There are the number of candidates (in lakhs) appearing for a University Entrance examination for state A and the percentage (P) of candidates who have cleared the exam.
Calculation:
For state A,
The number of candidates appearing in 2016 = 2.31 (in lakhs) = 2.31 × 100000 = 231000
The percentage of clearing candidates in 2016 = 32%
The number of candidates who cleared the exam in 2016 = 231000 × (32/100) = 73920
The number of candidates appearing in 2017 = 2.02 (in lakhs) = 2.02 × 100000 = 202000
The percentage of clearing candidates in 2017 = 44%
The number of candidates who cleared the exam in 2017 = 202000 × (44/100) = 88880
The number of candidates appearing in 2018 = 1.98 (in lakhs) = 1.98 × 100000 = 198000
The percentage of clearing candidates in 2018 = 39%
The number of candidates who cleared the exam in 2018 = 198000 × (39/100) = 77220
The number of candidates appearing in 2019 = 2.31 (in lakhs) = 1.85 × 100000 = 185000
The percentage of clearing candidates in 2019 = 28%
The number of candidates who cleared the exam in 2019 = 185000 × (28/100) = 51800
The number of candidates appearing in 2020 = 2.31 (in lakhs) = 2.20 × 100000 = 220000
The percentage of clearing candidates in 2020 = 33%
The number of candidates who cleared the exam in 2020 = 220000 × (33/100) = 72600
The total number of candidates who cleared the entrance exam = 73920 + 88880 + 77220 + 51800 + 72600 = 364420
∴ The total number of students who have cleared the entrance exam from 2016 to 2020 in State A is 364420



