
Shortcut Trick
Milk parts are constant in both ratios (7 : 4 and 7 : 6).
Difference in Water parts = 6 − 4 = 2 units.
2 units corresponds to 20 litres added ⇒ 1 unit = 10 litres.
New total quantity of mixture = 7 + 6 = 13 units.
Total New Quantity = 13 × 10 = 130 litres.
∴ The correct answer is 130 Litres.

Alternate Method
Given: Ratio of Milk and Water = 7 : 4. 55L mixture sold, 20L water added. New ratio = 7 : 6.
Remaining Mix
M : W = 7 : 4
+20L Water
New Mixture
M : W = 7 : 6
Milk parts (7) remain same. Only water changes.
⇒ Let the quantity of milk and water in the remaining mixture be 7x and 4x respectively.
⇒ According to the question, 20 litres of water is added to the mixture.
⇒ New ratio of Milk : Water = 7x : (4x + 20)
⇒ 7x ÷ (4x + 20) = 7 ÷ 6
⇒ 6x = 4x + 20
⇒ 2x = 20
⇒ x = 10
⇒ New quantity of mixture = 7x + (4x + 20) = 11x + 20
⇒ New quantity = 11 × 10 + 20 = 110 + 20 = 130 Litres.
∴ The correct answer is 130 Litres.

Additional Information
Ratio Stability Principle
When a part of a mixture is removed, the ratio of components in the remaining mixture remains exactly the same as the initial ratio.
Constant Component Method
If only one component (e.g., water) is added or removed, the quantity of the other component (e.g., milk) must be equated across the ratios to solve the problem quickly.
Alligation Rule
Quantity of cheaper ÷ Quantity of dearer = (CP of dearer − Mean price) ÷ (Mean price − CP of cheaper).