Find the average marks in Sociology and IT respectively obtained by all the students (A to G).
- AOption (a)
84, 28
- BOption (b)
82, 30
- COption (c)
80, 28
- DOption (d)
83, 30
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Correct answer
84, 28
Why this answer is correct
Given:
Total Students = 7
Sociology M.M = 120
IT M.M = 40
Formula used:
Marks = \(\dfrac{Percentage}{100} \times Maximum\ Marks\)
Average = \(\dfrac{Total\ Marks}{Number\ of\ Students}\)
Calculation:
Sociology:
A = 80 × 120 / 100 = 96
B = 70 × 120 / 100 = 84
C = 70 × 120 / 100 = 84
D = 80 × 120 / 100 = 96
E = 80 × 120 / 100 = 96
F = 60 × 120 / 100 = 72
G = 50 × 120 / 100 = 60
Total = 96 + 84 + 84 + 96 + 96 + 72 + 60 = 588
⇒ Average = 588 / 7 = 84
IT:
A = 80 × 40 / 100 = 32
B = 70 × 40 / 100 = 28
C = 70 × 40 / 100 = 28
D = 60 × 40 / 100 = 24
E = 80 × 40 / 100 = 32
F = 60 × 40 / 100 = 24
G = 70 × 40 / 100 = 28
Total = 32 + 28 + 28 + 24 + 32 + 24 + 28 = 196
⇒ Average = 196 / 7 = 28
∴ Average Sociology = 84 and Average IT = 28
∴ The correct option is 1.