RRB Technician Grade III Official Paper (Held On: 06 March, 2026 Shift 3) (Previous Year Paper)

Shortcut Trick

For any regular polygon, the sum of an interior angle and an exterior angle at a vertex is always 180°.

Exterior angle = 180° − 156° = 24°

Since the polygon is regular, all its exterior angles are equal.

Sum of 7 exterior angles = 7 × 24° = 168°

∴ The correct answer is 168°.

Alternate Method

Given:

Interior angle of the regular polygon = 156°

Formula Used:

1. Exterior Angle = 180° − Interior Angle
2. Sum of 'k' exterior angles = k × Exterior Angle (for a regular polygon)

Calculations:

⇒ One Exterior angle = 180° − 156°

⇒ One Exterior angle = 24°

⇒ In a regular polygon, all exterior angles are of the same measure.

⇒ Measure of 7 exterior angles = 7 × 24°

⇒ Required Sum = 168°

∴ The correct answer is 168°.

Additional Information

Sum of Exterior Angles

The sum of the exterior angles of any convex polygon, regardless of the number of sides, is always 360°.

Number of Sides

The number of sides (n) of a regular polygon can be calculated using the formula: n = 360° ÷ Exterior Angle. Here, n = 360 ÷ 24 = 15 sides.

Interior Angle Sum

The sum of all interior angles of an n-sided polygon is given by (n − 2) × 180°.

Shortcut Trick

Solve using VBODMAS priority: Brackets → Of → Division → Addition → Subtraction.

Inner part: (1/2 ÷ (1/2 of 1/2) + 1/2) = (1/2 ÷ 1/4 + 1/2) = (2 + 1/2) = 2.5.

Outer part: (1/2 of 2.5) − 0.5 = 1.25 − 0.5 = 0.75.

∴ The correct answer is 0.75.

Alternate Method

Given Expression: (1/2) of ((1/2) ÷ (1/2) of (1/2) + (1/2)) − (1/2)

Method: Applying the BODMAS rule to simplify the operations step by step.

⇒ 1/2 of (1/2 ÷ (1/2 × 1/2) + 1/2) − 1/2

⇒ 1/2 of (1/2 ÷ 1/4 + 1/2) − 1/2

⇒ 1/2 of (1/2 × 4 + 1/2) − 1/2

⇒ 1/2 of (2 + 1/2) − 1/2

⇒ 1/2 × 5/2 − 1/2

⇒ 5/4 − 1/2

⇒ 1.25 − 0.5 = 0.75

∴ The correct answer is 0.75.

Additional Information

VBODMAS Rule

It stands for Vinculum, Bracket, Of, Division, Multiplication, Addition, and Subtraction. It defines the specific sequence of operations to solve any mathematical expression.

Priority of 'Of' Operator

The 'Of' operator represents multiplication but is prioritized higher than Division and Multiplication in the order of operations.

Fraction Division

To divide a number by a fraction, we multiply the number by the reciprocal of that fraction (e.g., a ÷ b/c = a × c/b).

Shortcut Trick

Radius (r) = Diameter ÷ 2 = 20 ÷ 2 = 10 cm.

Volume = πr²h = (22 ÷ 7) × 10 × 10 × 42.

Since 42 is a multiple of 7, the calculation becomes: 22 × 100 × 6.

Volume = 132 × 100 = 13200 cm³.

∴ The correct answer is 13200 cm³.

Alternate Method

Given:

Diameter of the cylinder (d) = 20 cm

Height of the cylinder (h) = 42 cm

π = 22 ÷ 7

Formula Used:

Volume of Cylinder = πr²h

Where r is the radius and h is the height.

Calculations:

⇒ Radius (r) = Diameter ÷ 2

⇒ Radius (r) = 20 ÷ 2 = 10 cm

⇒ Volume = (22 ÷ 7) × (10)² × 42

⇒ Volume = (22 ÷ 7) × 100 × 42

⇒ Volume = 22 × 100 × (42 ÷ 7)

⇒ Volume = 22 × 100 × 6

⇒ Volume = 132 × 100

⇒ Volume = 13200 cm³

∴ The correct answer is 13200 cm³.

Additional Information

Curved Surface Area (CSA) of Cylinder

The area of the side surface of the cylinder is given by the formula: CSA = 2 × π × r × h.

Total Surface Area (TSA) of Cylinder

The sum of the curved surface area and the areas of the two circular bases: TSA = 2πr(r + h).

Volume of a Hollow Cylinder

If R is the external radius and r is the internal radius, then Volume = π × (R² − r²) × h.

Shortcut Trick

Break the expression into four independent segments using the BODMAS rule.

Segment 1: 96 ÷ (4 × 4) = 96 ÷ 16 = 6

Segment 2: 36 ÷ (9 × 3) = 36 ÷ 27 = 4/3

Segment 3: (14 × 2 ÷ 4) = 28 ÷ 4 = 7

Segment 4: 18 ÷ (3 × 3) = 18 ÷ 9 = 2

Total = (6 + 4/3) + (7 + 2) = 15 + 4/3 = 49/3

∴ The correct answer is 49/3.

Alternate Method

Given Expression: [{(96 ÷ (4 × 4)) + (36 ÷ (9 × 3))} + {(14 × 2 ÷ 4) + (18 ÷ (3 × 3))}]

Method Used: BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction).

⇒ [{(96 ÷ 16) + (36 ÷ 27)} + {(28 ÷ 4) + (18 ÷ 9)}]

⇒ [{6 + 4/3} + {7 + 2}]

⇒ [{(18 + 4) / 3} + 9]

⇒ [22/3 + 9]

⇒ (22 + 27) / 3

⇒ 49/3

∴ The correct answer is 49/3.

Additional Information

The BODMAS/VBODMAS Rule

Always solve in the order: Vinculum (Bar), Brackets (), Of, Division, Multiplication, Addition, and Subtraction.

Types of Brackets

Standard order for solving nested brackets is: Small Brackets ( ) → Curly Brackets { } → Square Brackets [ ].

Fraction Simplification

To add a whole number and a fraction like x + a/b, use the formula (x × b + a) / b.

Shortcut Trick

Apply the successive percentage change formula: [x + y + (xy ÷ 100)]%

Where x = +30% (increase) and y = −35% (decrease).

Net Change = 30 − 35 + [(30 × −35) ÷ 100]

Net Change = −5 − 10.5 = −15.5%

Negative sign indicates a percentage decrease.

∴ The correct answer is 15.5% decrease.

Alternate Method

Given: Initial tourists increase = 30%; Subsequent monsoon decrease = 35%.

⇒ Let the initial number of tourists be 100.

⇒ Number of tourists after summer increase = 100 + (30% of 100) = 130.

⇒ Number of tourists after monsoon drop = 130 − (35% of 130).

⇒ Monsoon drop amount = (35 ÷ 100) × 130 = 45.5.

⇒ Final tourists count = 130 − 45.5 = 84.5.

⇒ Overall percentage change = 100 − 84.5 = 15.5%.

∴ The correct answer is 15.5% decrease.

Additional Information

Effective Percentage Change

For two successive changes of a% and b%, the net change is given by the formula [a + b + (ab ÷ 100)]%.

Multiplier Method

The final value can be calculated as Initial Value × (1 + r₁ ÷ 100) × (1 + r₂ ÷ 100). In this case: 1 × 1.30 × 0.65 = 0.845.

Profit and Loss Context

This same logic applies to successive discounts or a markup followed by a discount in Profit and Loss problems.

The logic followed to solve this problem is based on linear equations and basic arithmetic.

1. Formulating the Equation:

Let the original number be x.

According to the question, one-third of the number increased by 55 results in 77.

The equation is: (x / 3) + 55 = 77

2. Solving for the Original Number (x):

First, subtract 55 from both sides of the equation to isolate the term with x:

x / 3 = 77 − 55

x / 3 = 22

Now, multiply both sides by 3 to find the value of x:

x = 22 × 3

x = 66

So, the original number is 66.

Key Points

3. Calculating the Sum of the Digits:

The digits of the original number 66 are 6 and 6.

Sum of the digits = 6 + 6 = 12

Therefore, the sum of the digits of the original number is 12.

Shortcut Trick

Total Distance = Train Length + Bridge Length = 240 + 420 = 660 m

Speed in m/s = Total Distance ÷ Time = 660 ÷ 22 = 30 m/s

Convert to km/h: 30 × 18/5 = 6 × 18 = 108 km/h

∴ The correct answer is 108 km/h.

Alternate Method

Given:

Length of the Train (L₁) = 240 m

Length of the Bridge (L₂) = 420 m

Time taken (t) = 22 sec

Formula Used:

Speed = Total Distance ÷ Time

Total Distance = (Length of Train + Length of Bridge)

Calculations:

⇒ Total Distance = 240 + 420 = 660 m

⇒ Speed = 660 ÷ 22

⇒ Speed = 30 m/s

⇒ To convert m/s to km/h, multiply by 18/5

⇒ Speed = 30 × (18 ÷ 5)

⇒ Speed = 6 × 18 = 108 km/h

∴ The correct answer is 108 km/h.

Additional Information

Unit Conversion Rules

1 km/h = 5/18 m/s | 1 m/s = 18/5 km/h. Multiply by these factors to switch between units quickly.

Train Crossing a Static Object

When a train crosses a platform, bridge, or another stationary train, the distance is the sum of both lengths. When it crosses a pole or man, distance is just the train length.

Relative Speed

If two objects move in the opposite direction, relative speed = S₁ + S₂. If they move in the same direction, relative speed = |S₁ − S₂|.

Shortcut Trick

Total numbers in the range [11, 19] = 9.

Total possible pairs = ⁹C₂ = (9 × 8) / 2 = 36.

Non-coprime pairs from even numbers {12, 14, 16, 18} = ⁴C₂ = 6.

Non-coprime pairs from multiples of 3 {12, 15, 18} = (12, 15) and (15, 18) = 2 unique pairs.

Total non-coprime pairs = 6 + 2 = 8.

∴ The correct answer is 28 pairs.

Alternate Method

Given: The range of numbers is from 11 to 19 (both inclusive).

Formula: Two numbers are coprime if their Highest Common Factor (HCF) or Greatest Common Divisor (GCD) is 1.

⇒ Total numbers (n) = 9

⇒ Total possible pairs = n(n − 1) / 2 = (9 × 8) / 2 = 36

⇒ Identifying non-coprime pairs (GCD > 1):

⇒ Pairs with factor 2: (12, 14), (12, 16), (12, 18), (14, 16), (14, 18), (16, 18) = 6 pairs

⇒ Pairs with factor 3: (12, 15), (15, 18) = 2 pairs

⇒ Total non-coprime pairs = 6 + 2 = 8

⇒ Number of coprime pairs = Total pairs − Non-coprime pairs

⇒ Coprime pairs = 36 − 8 = 28

∴ The correct answer is 28 pairs.

Additional Information

Coprime Numbers

Two numbers are coprime if their only common factor is 1. This means HCF(a, b) = 1.

Consecutive Integers

Any two consecutive integers are always coprime to each other (e.g., 14 and 15).

Prime Numbers and Coprimality

A prime number is coprime to every other number that is not a multiple of itself.

Twin Primes

Prime numbers that have a difference of 2 are called twin primes (e.g., 11 and 13, 17 and 19).

Shortcut Trick

Base Average = 20

Deviation of 11 = 11 − 20 = −9

Deviation of 21 = 21 − 20 = +1

Net deviation for first two numbers = −9 + 1 = −8

To maintain the average, 3^rd number deviation must be +8 ⇒ 20 + 8 = 28

∴ The correct answer is 28.

Alternate Method

Given:

Average of three numbers = 20

First number = 11

Second number = 21

Formula Used:

Sum of numbers = Average × Total count of numbers

Calculations:

⇒ Sum of three numbers = 20 × 3

⇒ Sum of three numbers = 60

⇒ Sum of the two given numbers = 11 + 21

⇒ Sum of two numbers = 32

⇒ Third number = (Sum of three numbers) − (Sum of two numbers)

⇒ Third number = 60 − 32

⇒ Third number = 28

∴ The correct answer is 28.

Additional Information

Arithmetic Mean Formula

The average or mean is calculated as the sum of all observations divided by the total number of observations: A = (Σx_i) ÷ n.

Concept of Net Deviation

The sum of deviations of all observations from their arithmetic mean is always zero. This is a powerful property used to find missing values in a dataset.

Weighted Average

When two groups with averages A₁ and A₂ and sizes n₁ and n₂ are combined, the combined average is (n₁A₁ + n₂A₂) ÷ (n₁ + n₂).

Shortcut Trick

Interest for 12 months = 8%, so Interest for 6 months = 4%.

Total repayment Amount = 100% (Principal) + 4% (Interest) = 104%.

Total amount = 1.04 × 14,750 = 15,340.

∴ The correct answer is ₹ 15340.

Alternate Method

Given: Principal (P) = ₹14,750, Rate (R) = 8% p.a., Time (T) = 6 months.

Formula Used: SI = (P × R × T) / 100; Amount (A) = P + SI

⇒ Time (T) in years = 6 / 12 = 0.5 years

⇒ Simple Interest (SI) = (14750 × 8 × 0.5) / 100

⇒ SI = (14750 × 4) / 100 = 147.5 × 4 = 590

⇒ Total Amount (A) = Principal + Simple Interest

⇒ Total Amount = 14750 + 590 = 15340

∴ The correct answer is ₹ 15340.

Additional Information

Simple Interest (SI)

It is calculated only on the principal amount of a loan or deposit. SI = (P × R × T) / 100.

Time Conversion Rule

While calculating interest, the time (T) must always be in years. Months are divided by 12, and days are usually divided by 365.

Amount in SI

The total repayable amount is the sum of the original principal and the interest earned: A = P[1 + (RT/100)].

Shortcut Trick

The equation (sin²θ − 3sinθ + 2) / cos²θ = 1 simplifies to (2 − sinθ) / (1 + sinθ) = 1.

⇒ 2 − sinθ = 1 + sinθ ⇒ 2sinθ = 1 ⇒ sinθ = 1/2.

For sinθ = 1/2 in the range 0° < θ < 90°, we get θ = 30°.

Substitute θ = 30° into the required expression: cot(1.5 × 30°) + cos(3 × 30°) = cot 45° + cos 90°.

⇒ 1 + 0 = 1.

∴ The correct answer is 1.

Alternate Method

Given: (sin²θ − 3sinθ + 2) / cos²θ = 1 where 0° < θ < 90°.

Formula Used: cos²θ = 1 − sin²θ | Quadratic Factorization

⇒ sin²θ − 3sinθ + 2 = cos²θ

⇒ sin²θ − 3sinθ + 2 = 1 − sin²θ

⇒ 2sin²θ − 3sinθ + 1 = 0

⇒ 2sin²θ − 2sinθ − sinθ + 1 = 0

⇒ 2sinθ(sinθ − 1) − 1(sinθ − 1) = 0

⇒ (2sinθ − 1)(sinθ − 1) = 0

⇒ sinθ = 1/2 or sinθ = 1

⇒ Since 0° < θ < 90°, θ = 30°

⇒ Value = cot(3/2 × 30°) + cos(3 × 30°)

⇒ Value = cot 45° + cos 90° = 1 + 0 = 1

∴ The correct answer is 1.

Additional Information

Trigonometric Quadrant Rule

In the first quadrant (0° to 90°), all trigonometric ratios are positive.

Standard Value of cot 45°

The value of cot 45° is always 1, as it is the reciprocal of tan 45°.

Complementary Angle Identities

sin(90° − θ) = cosθ and tan(90° − θ) = cotθ.

Shortcut Trick

Total daily work of (A + B + C) = 1/6 + 1/42 = 8/42 = 4/21.

Given A = B + C, so total daily work = A + (B + C) = 2A.

2A = 4/21 ⇒ A efficiency = 2/21.

B efficiency = (A + B) − A = 1/6 − 2/21 = 3/42 = 1/14.

∴ The correct answer is 14 days.

Alternate Method

Given:

Time taken by (A + B) = 6 days

Time taken by C = 42 days

Efficiency condition: Efficiency of A = Efficiency of (B + C)

Calculations:

⇒ Total Efficiency of (A + B + C) = 7 + 1 = 8 units/day

⇒ Since Efficiency A = B + C, then A + (B + C) = 8 becomes 2 × A = 8

⇒ Efficiency of A = 8 ÷ 2 = 4 units/day

⇒ Efficiency of B = Efficiency of (A + B) − Efficiency of A

⇒ Efficiency of B = 7 − 4 = 3 units/day

⇒ Time taken by B alone = Total Work ÷ Efficiency of B

⇒ Time taken by B = 42 ÷ 3 = 14 days

∴ The correct answer is 14 days.

Additional Information

Efficiency and Time Relation

Efficiency is inversely proportional to the time taken. If a person is twice as efficient as another, they will take half the time to complete the same work.

Combined Work Formula

If X takes 'a' days and Y takes 'b' days, they together take (a × b) ÷ (a + b) days.

Work and Wages

Wages are distributed in the ratio of work done or the ratio of efficiencies when all persons work for the same duration.

Shortcut Trick

The relationship a : b = c : x represents a proportion where x is the fourth proportional.

Logic: Product of Extremes (a × x) = Product of Means (b × c).

⇒ 12 × x = 18 × 27

⇒ x = (18 × 27) ÷ 12 = 486 ÷ 12 = 40.5

∴ The correct answer is 40.5.

Alternate Method

Given:

Values: a = 12, b = 18, c = 27

Formula Used:

For a proportion a : b = c : d, the ratio of the first two terms equals the ratio of the last two terms: a/b = c/d

Calculations:

⇒ a/b = c/x

⇒ 12/18 = 27/x

⇒ 2/3 = 27/x (Simplifying 12/18 by dividing by 6)

⇒ 2 × x = 3 × 27

⇒ 2x = 81

⇒ x = 81 ÷ 2

⇒ x = 40.5

∴ The correct answer is 40.5.

Additional Information

Fourth Proportional

When four quantities a, b, c, d are in proportion (a:b = c:d), d is the fourth proportional given by d = (b × c) ÷ a.

Third Proportional

In a continued proportion a:b = b:c, c is called the third proportional and is calculated as c = b² ÷ a.

Mean Proportional

The mean proportional between two numbers a and b is √(a × b), such that a:x = x:b.

Compounded Ratio

The compounded ratio of two ratios a:b and c:d is defined as (a × c) : (b × d).

Shortcut Trick

Total Area (m²) = 2,500 × (1/2 × 0.50 × 0.35) = 2,500 × 0.0875 = 218.75 m².

Total Cost = 218.75 × ₹5 = ₹1093.75.

Courtyard Area = 218.75 + 6.25 = 225 m².

Side of Square = √225 = 15 m.

∴ The correct answer is ₹1093.75, 15 m.

Alternate Method

Given:

Number of slabs = 2,500

Diagonals of rhombus (d₁, d₂) = 50 cm, 35 cm

Polishing rate = ₹5 per m²

Additional area = 6.25 m²

Calculations:

⇒ Area of 1 rhombus slab = 1/2 × d₁ × d₂

⇒ Area of 1 slab = 1/2 × 50 × 35 = 875 cm²

⇒ Total area of 2,500 slabs = 2,500 × 875 = 2,187,500 cm²

⇒ Total area in m² = 2,187,500 ÷ 10,000 = 218.75 m²

⇒ Total polishing cost = 218.75 × 5 = ₹1093.75

⇒ Area of square courtyard = Total area + 6.25

⇒ Area of square = 218.75 + 6.25 = 225 m²

⇒ Side of square = √Area = √225 = 15 m

∴ The correct answer is ₹1093.75, 15 m.

Additional Information

Area of Rhombus

The area of a rhombus can also be calculated as Base × Height if the side and altitude are given.

Unit Conversion

1 m² = 10,000 cm². Always convert units to a common system (SI) before calculating costs.

Properties of Square

Area of a square = side². Therefore, the side length is the square root of the total area.

Shortcut Trick

If John is twice as old as 10 years ago, then the 10-year gap represents half his current age.

⇒ John's present age = 10 × 2 = 20 years.

Sum of ages 5 years ago was 25, so the present sum increases by 5 for each person (5 × 2 = 10).

⇒ Present sum = 25 + 10 = 35 years.

⇒ Jane's age = 35 − 20 = 15 years.

Difference = 20 − 15 = 5 years.

∴ The correct answer is 5 years.

Alternate Method

Given: Sum of John and Jane 5 years ago = 25 years. John's current age = 2 × (Age 10 years ago).

Formula Used: Present Age = Past Age + Time Interval; Difference = Age₁ − Age₂.

⇒ Let John's present age be x.

⇒ According to the condition: x = 2(x − 10)

⇒ x = 2x − 20 ⇒ x = 20 years.

⇒ Let Jane's present age be y.

⇒ Sum 5 years ago: (x − 5) + (y − 5) = 25

⇒ (20 − 5) + (y − 5) = 25

⇒ 15 + y − 5 = 25 ⇒ y + 10 = 25

⇒ y = 15 years.

⇒ Difference between present ages = 20 − 15 = 5 years.

∴ The correct answer is 5 years.

Additional Information

Constant Age Difference

The difference between the ages of two individuals remains the same throughout their lives, regardless of how many years pass.

Sum of Ages in the Future/Past

If the sum of ages of 'n' people is S now, then after 't' years, the sum will be S + (n × t).

Age Ratios

When ages are given in ratios, always use a constant multiplier 'k' (e.g., 3k and 4k) to represent the actual ages before applying time shifts.

Shortcut Trick

The Effective Rate of Interest for 2 years at 10% per annum = 10% × 2 = 20%.

Given that 20% of the Principal (P) = ₹700.

To find the total Principal (100%), we multiply by 5.

⇒ P = 700 × 5 = 3500.

∴ The correct answer is ₹3500.

Alternate Method

Given:

Simple Interest (SI) = ₹700

Time (T) = 2 years

Rate of Interest (R) = 10% per annum

Formula Used:

SI = (P × R × T) ÷ 100

Calculations:

⇒ 700 = (P × 10 × 2) ÷ 100

⇒ 700 = (P × 20) ÷ 100

⇒ 700 = P ÷ 5

⇒ P = 700 × 5

⇒ P = 3500

∴ The correct answer is ₹3500.

Additional Information

Total Amount Formula

The total sum returned after adding interest is Amount (A) = P + SI = P × (1 + RT/100).

Constant Nature of SI

Unlike compound interest, Simple Interest remains the same every year because it is always calculated on the original Principal.

SI vs CI Difference

For a period of 2 years, the difference between Compound Interest and Simple Interest is given by D = P × (R/100)².

Shortcut Trick

Relative cost per ratio set = (280 × 3) + (180 × 4) + (105 × 7) = 840 + 720 + 735 = 2295

Value of 1 ratio unit = Total cost ÷ Relative cost = 6885 ÷ 2295 = 3

Number of type Q articles = 4 units × 3 = 12

∴ The correct answer is 12.

Alternate Method

Given:

Prices of type P, Q, R = ₹280, ₹180, ₹105

Quantity ratio = 3 : 4 : 7

Total amount spent = ₹6,885

Formula Used:

Total Cost = (Price_P × Quantity_P) + (Price_Q × Quantity_Q) + (Price_R × Quantity_R)

Calculations:

⇒ Let the number of articles of type P, Q, and R be 3x, 4x, and 7x respectively.

⇒ Total spending = (280 × 3x) + (180 × 4x) + (105 × 7x)

⇒ 6885 = 840x + 720x + 735x

⇒ 6885 = 2295x

⇒ x = 6885 ÷ 2295

⇒ x = 3

⇒ Number of articles of type Q = 4x = 4 × 3 = 12

∴ The correct answer is 12.

Additional Information

Ratio Scaling Factor

When a ratio A : B : C is given, the actual values can be expressed as Ax, Bx, and Cx, where 'x' is the constant of proportionality or scaling factor.

Weighted Average Cost

The total cost of different items is the sum of products of their individual prices and their respective quantities: Total = Σ(Price_i × Quantity_i).

Unitary Method in Ratios

To find the value of one part, divide the total quantity by the sum of the ratio parts weighted by their respective values.

Shortcut Trick

To simplify quickly, substitute a convenient value for the variable n. Let n = 0.

Expression = (2⁰⁺³ − 2 × 2⁰) ÷ (2 × 2⁰⁺²)

Expression = (2³ − 2 × 1) ÷ (2 × 2²) = (8 − 2) ÷ (2 × 4)

Expression = 6 ÷ 8 = 3/4

∴ The correct answer is 3/4.

Alternate Method

Given: (2ⁿ⁺³ − 2 × 2ⁿ) ÷ (2 × 2ⁿ⁺²)

Method: Factor out the common term 2ⁿ from both the numerator and the denominator using the Law of Exponents (a^m+n = a^m × aⁿ).

⇒ (2ⁿ × 2³ − 2 × 2ⁿ) ÷ (2 × 2ⁿ × 2²)

⇒ [2ⁿ × (2³ − 2)] ÷ [2ⁿ × (2 × 2²)]

⇒ (2³ − 2) ÷ (2 × 2²)

⇒ (8 − 2) ÷ (2 × 4)

⇒ 6 ÷ 8

⇒ 3/4

∴ The correct answer is 3/4.

Additional Information

Product Rule of Exponents

When multiplying terms with the same base, add their powers: a^m × aⁿ = a^m+n.

Quotient Rule of Exponents

When dividing terms with the same base, subtract their powers: a^m ÷ aⁿ = a^m−n.

Zero Exponent Property

Any non-zero base raised to the power of zero is always equal to 1: a⁰ = 1.

Shortcut Trick

Let the total cast votes be 100%.

Candidate X got 40%, so the remaining 60% is shared by 3 candidates → 20% each.

Difference between Candidate X and others = 40% − 20% = 20%.

20% of cast votes = 480 → 100% of cast votes = 480 × 5 = 2400.

Given 60% of registered voters = 2400, then 100% = (2400 ÷ 60) × 100 = 4000.

∴ The correct answer is 4000.

Alternate Method

Given:

⇒ Total Registered Voters = 100%

⇒ Cast Votes = 60% of Registered Voters

⇒ Candidate X = 40% of Cast Votes

⇒ Others = Equal split of remaining (100% − 40%) = 20% of Cast Votes each

Calculations:

⇒ Let Total Registered Voters = V

⇒ Cast Votes = 0.60V

⇒ Votes for X = 0.40 × (0.60V) = 0.24V

⇒ Total remaining cast votes = 0.60V − 0.24V = 0.36V

⇒ Votes for each other candidate = 0.36V ÷ 3 = 0.12V

⇒ Given difference: 0.24V − 0.12V = 480

⇒ 0.12V = 480

⇒ V = 480 ÷ 0.12

⇒ V = 4000

∴ The correct answer is 4000.

Additional Information

Percentage of a Percentage

When a value is a percentage of another percentage, the effective percentage of the original base is (A × B) ÷ 100.

Registered vs Cast Votes

Registered voters (Voter List) is the 100% base. Cast votes are the actual subset used for candidate distribution.

Base Change Rule

To find the total from a part: Total = (Value ÷ Percentage) × 100.

Shortcut Trick

Selling Price (SP) of X = 2000 + 322 = 2322.

Multiplication factor for X after 28% and 90% discounts = 0.72 × 0.10 = 0.072.

Marked Price (MP) = 2322 ÷ 0.072 = 32250.

SP of Y after 88% discount = 32250 × 0.12 = 3870.

Profit % on Y = [(3870 − 2000) ÷ 2000] × 100 = (1870 ÷ 20) = 93.5%.

∴ The correct answer is 93.5%.

Alternate Method

Given:

Cost Price (CP) of X and Y = ₹2,000 each.

Profit on X = ₹322.

Discounts on X = 28% and 90% (successive).

Discount on Y = 88% (single).

Formula Used:

SP = CP + Profit

SP = MP × (100 − D₁)/100 × (100 − D₂)/100

Profit % = (Profit ÷ CP) × 100

Calculations:

⇒ Selling Price of X (SP_X) = CP + Profit = 2000 + 322 = ₹2,322

⇒ SP_X = MP × (1 − 0.28) × (1 − 0.90)

⇒ 2322 = MP × 0.72 × 0.10

⇒ 2322 = MP × 0.072

⇒ MP = 2322 ÷ 0.072 = ₹32,250

⇒ Selling Price of Y (SP_Y) = MP × (1 − 0.88)

⇒ SP_Y = 32250 × 0.12 = ₹3,870

⇒ Profit on Y = SP_Y − CP = 3870 − 2000 = ₹1,870

⇒ Profit % on Y = (1870 ÷ 2000) × 100 = 93.5%

∴ The correct answer is 93.5%.

Additional Information

Successive Discounts

If two successive discounts are d₁% and d₂%, the single equivalent discount is (d₁ + d₂ − d₁d₂/100)%.

Marked Price and Discount

Discount is always calculated on the Marked Price (MP). SP = MP − Discount.

Profit Percentage

Profit % is always calculated on the Cost Price (CP). Profit % = [(SP − CP) ÷ CP] × 100.

Shortcut Trick

Profit per kg = (Selling Price ÷ Selling Quantity) − (Cost Price ÷ Buying Quantity)

Profit per kg = (50 ÷ 5) − (15 ÷ 3) = 10 − 5 = ₹5

Required Quantity = Total Profit ÷ Profit per kg

Required Quantity = 125 ÷ 5 = 25 kg

∴ The correct answer is 25 kg.

Alternate Method

Given:

Cost Price (CP) of 3 kg Mangoes = ₹15

Selling Price (SP) of 5 kg Mangoes = ₹50

Target Profit = ₹125

Formula Used:

Profit = Selling Price (SP) − Cost Price (CP)

Quantity = Total Profit ÷ Profit per unit

Calculations:

⇒ CP of 1 kg Mangoes = 15 ÷ 3 = ₹5

⇒ SP of 1 kg Mangoes = 50 ÷ 5 = ₹10

⇒ Profit on 1 kg Mangoes = 10 − 5 = ₹5

⇒ Let the Quantity to be sold be 'x' kg

⇒ Total Profit = Profit per kg × Quantity

⇒ 125 = 5 × x

⇒ x = 125 ÷ 5

⇒ x = 25 kg

∴ The correct answer is 25 kg.

Additional Information

Profit Percentage

It is the profit expressed as a percentage of the Cost Price: Profit% = (Profit ÷ CP) × 100.

Relationship between SP and CP

When there is a profit, Selling Price (SP) = CP × (100 + Profit%) ÷ 100.

Marked Price and Discount

Discount is always calculated on the Marked Price (MP). SP = MP − Discount.

Shortcut Trick

Total Work = LCM(16, 24) = 48 units.

Efficiencies: A = 3 units/day, B = 2 units/day.

Work done together in 5 days = (3 + 2) × 5 = 25 units.

Remaining work = 48 − 25 = 23 units.

Additional days for B = 23 ÷ 2 = 11.5 days.

∴ The correct answer is 11.5 days.

Alternate Method

Given:

Time taken by A = 16 days

Time taken by B = 24 days

Working together duration = 5 days

Formula Used:

Total Work = Efficiency × Time

Calculations:

⇒ Total Work (LCM of 16 and 24) = 48 units

⇒ Efficiency of A = 48 ÷ 16 = 3 units/day

⇒ Efficiency of B = 48 ÷ 24 = 2 units/day

⇒ Combined Efficiency of (A + B) = 3 + 2 = 5 units/day

⇒ Work completed by A and B in 5 days = 5 × 5 = 25 units

⇒ Remaining Work = 48 − 25 = 23 units

⇒ Time taken by B to complete remaining work = Remaining Work ÷ Efficiency of B

⇒ Time = 23 ÷ 2 = 11.5 days

∴ The correct answer is 11.5 days.

Additional Information

Efficiency and Time Relation

Efficiency is inversely proportional to the time taken to complete the work (E ∝ 1/T). If ratio of time is x:y, the ratio of efficiency is y:x.

Pipes and Cisterns

This concept follows the same logic where inlet pipes have positive efficiency and outlet (leakage) pipes have negative efficiency.

Combined Work Formula

If A completes work in 'a' days and B in 'b' days, they together complete it in (a × b) ÷ (a + b) days.

Work and Wages

Wages are always distributed in the ratio of the actual work done by each individual, which is (Efficiency × Time Active).

Shortcut Trick

Use the Successive Division Method: Divide the larger number by the smaller one until the remainder is zero.

148 ÷ 64 → Remainder = 20

64 ÷ 20 → Remainder = 4

20 ÷ 4 → Remainder = 0

The last divisor which leaves a remainder of zero is the HCF.

∴ The correct answer is 4.

Alternate Method

Given: The numbers are 64 and 148.

Formula: HCF is the product of the lowest powers of common prime factors.

⇒ Prime factorization of 64 = 2 × 2 × 2 × 2 × 2 × 2 = 2⁶

⇒ Prime factorization of 148 = 2 × 2 × 37 = 2² × 37

⇒ Common prime factor is 2.

⇒ Lowest power of common factor = 2²

⇒ HCF = 2 × 2 = 4

∴ The correct answer is 4.

Additional Information

HCF and LCM Relation

For any two numbers a and b, the product of the numbers is equal to the product of their HCF and LCM: a × b = HCF(a, b) × LCM(a, b).

Co-prime Numbers

Two numbers are called co-prime if their Highest Common Factor (HCF) is 1. Example: 8 and 15 are co-prime numbers.

HCF of Fractions

The HCF of fractions is calculated as: HCF of Numerators ÷ LCM of Denominators.

Shortcut Trick

Use the algebraic identity: (a + b)² − (a − b)² = 4ab.

Here, let a = 2pq and b = 11q.

Applying the values into the formula: 4 × (2pq) × (11q).

⇒ 4 × 2 × 11 × p × q × q = 88pq².

∴ The correct answer is 88pq².

Alternate Method

Given: (2pq + 11q)² − (2pq − 11q)²

Formula Used: (a + b)² = a² + 2ab + b² and (a − b)² = a² − 2ab + b²

⇒ Expansion of (2pq + 11q)² = (2pq)² + 2(2pq)(11q) + (11q)² = 4p²q² + 44pq² + 121q²

⇒ Expansion of (2pq − 11q)² = (2pq)² − 2(2pq)(11q) + (11q)² = 4p²q² − 44pq² + 121q²

⇒ Subtracting the two results: (4p²q² + 44pq² + 121q²) − (4p²q² − 44pq² + 121q²)

⇒ 4p²q² − 4p²q² + 121q² − 121q² + 44pq² + 44pq²

⇒ 88pq²

∴ The correct answer is 88pq².

Additional Information

Sum of squares identity

(a + b)² + (a − b)² = 2(a² + b²). This identity simplifies expressions involving the addition of symmetric squared binomials.

Difference of two squares

(a + b)(a − b) = a² − b². This is a fundamental algebraic identity used for factoring and simplification.

Square of a binomial

(a + b)² = a² + 2ab + b². The middle term (2ab) is key when performing algebraic expansion or finding roots.

Shortcut Trick

Use the Empirical Relationship formula: Mode = 3 × Median − 2 × Mean.

Direct substitution: Mode = 3 × 61 − 2 × 78.

Mode = 183 − 156 = 27.

∴ The correct answer is 27.

Alternate Method

Given:

Mean = 78

Median = 61

Formula Used:

The relationship between the measures of central tendency for a moderately skewed distribution is:

Mode = 3 × Median − 2 × Mean

Calculations:

⇒ Mode = 3(61) − 2(78)

⇒ Mode = 183 − 156

⇒ Mode = 27

∴ The correct answer is 27.

Additional Information

Empirical Relationship

This formula (Mode = 3 Median − 2 Mean) is specifically applicable to moderately skewed distributions.

Symmetric Distribution

In a perfectly symmetrical distribution (like the Normal Distribution), the Mean, Median, and Mode are all equal: Mean = Median = Mode.

Skewness Identification

If Mean > Median > Mode, the distribution is Positively Skewed. If Mean < Median < Mode, it is Negatively Skewed.

Mean Formula

Mean = (∑ f_ix_i) ÷ (∑ f_i), which represents the arithmetic average of the data set.

1. Since all persons face the centre: right = counterclockwise, left = clockwise. Fix Aw at pos(1). Bt sits second to the right of Aw (counterclockwise): Aw(1) → pos(2) → Bt(3).

2. Ck sits third to the left of Aw (clockwise): Aw(1) → pos(7) → pos(6) → Ck(5).

3. Er sits to the immediate right of Gy (counterclockwise). Dv sits second to the right of Er. The only available adjacent slots fitting this chain Gy → Er → skip → Dv are pos(6), pos(7), and pos(2). So, Gy(6), Er(7), and Dv(2).

4. The only remaining person Fn (Fe) occupies the last vacant position, pos(4). Final: Aw(1), Dv(2), Bt(3), Fn(4), Ck(5), Gy(6), Er(7).

To find the position of Fe (Fn) with respect to Er, we count from Er at pos(7) to Fn at pos(4). Moving clockwise (left): Er(7) → Gy(6) → Ck(5) → Fn(4). This is third to the left.

Hence, the correct answer is 'Option 4'.

The logic followed here is that each letter in the term is obtained by subtracting 11 from the positional value of the corresponding letter of the previous term in the English alphabetical series.

The term completing the series is HRN.

Hence, the correct answer is "Option 2".

Logic:

Given Equation:

71 S 45 P 5 R 15 Q 5 P 6 S 13 R 74 S 69 = ?

After replacing the letters with their respective signs, we get:

= 71 + 45 × 5 − 15 ÷ 5 × 6 + 13 − 74 + 69

= 71 + 45 × 5 − 3 × 6 + 13 − 74 + 69

= 71 + 225 - 18 + 13 - 74 + 69

= 378 - 92

= 286

Therefore, the value that will come in place of the question mark is 286.

Hence, the correct answer is "Option 3".

The logic followed in this pattern is a series of alphabetical shifts where each consecutive letter in the term is decreased by a progressively increasing integer.

For 'WRT' related to 'VPQ':

For 'GUA' related to 'FSX':

Applying the same logic to 'NXR' from the options:

Thus, the pair NXR : MVO follows the same pattern.

Hence, the correct answer is 'Option 2'.

Given:

The logic followed in the series is as follows:

CK 34 → BL 68:

HP 42 → GQ 84:

Similarly, for NV 23:

NV 23 → MW 46:

Hence, the correct answer is 'Option 2'.

The logic followed here is:

Logic: Each letter in the second cluster is obtained by adding 4 to the alphabetical position of the corresponding letter in the first cluster.

Option 1) MD - QH,

Option 2) SJ - WN,

Option 3) VL - YO

This pair does not follow the +4 rule.

Option 4) PG - TK,

Therefore, the letter-cluster pair that is different from the others is VL - YO.

Hence, the correct answer is 'Option 3'.

Signs Interchanged:

Given Equation: 7 ÷ 2 + 64 × 8 − 8

After interchanging the signs, the new equation is:

= 7 × 2 − 64 ÷ 8 + 8

= 7 × 2 - 8 + 8

= 14 - 8 + 8

= 14

Therefore, the value that will come in place of the question mark is 14.

Hence, the correct answer is "Option 1".

Given:

Let us first decode the given symbols and then draw a family tree.

On checking: Z o C ge L @ M × N

1. Z o C - 'Z o C' means 'Z is the father of C'.

2. C ge L - 'C ge L' means 'C is the wife of L'.

3. L @ M - 'L @ M' means 'L is the brother of M'.

4. M × N - 'M × N' means 'M is the daughter of N'.

Therefore, L is the son of N, and C is the wife of L. Since Z is the father of C, Z is the father of N's son's wife.

Hence, the correct answer is "Option 3".

The logic followed here is:

Logic: Second Number = (First Number × 2) + 1

For the first set 29, 59

⇒ (29 × 2) + 1

⇒ 58 + 1 = 59.

For the second set 35, 71

⇒ (35 × 2) + 1

⇒ 70 + 1 = 71.

Applying the same logic to the options:

Checking Option 2: 41, 83

⇒ (41 × 2) + 1

⇒ 82 + 1 = 83.

Hence, the correct answer is 'Option 2'.

Given:

Seven boxes (A, B, C, D, E, F, G) are kept one over the other from 1 (bottom) to 7 (top).

1) D is kept fifth from the bottom.

2) G is kept below B but above D.

3) Exactly five boxes are kept between E and B.

Since D is at position 5, G must be at position 6 and B must be at position 7 (top) to satisfy the condition that G is below B and above D. Since B is at position 7 and there are five boxes between B and E, E must be at position 1 (bottom).

4) F is kept immediately below A but above E.

5) C is not kept below A. (This implies C is kept above A)

The remaining positions are 2, 3, and 4. If A is at position 3, F will be at position 2 (immediately below A). Then C must occupy position 4, which is above A, satisfying all conditions.

Final Arrangement:

From the final arrangement, we can see that box D is kept between C and G.

Thus, there is only one box kept between C and G.

Hence, the correct answer is 'Option 2'.

Given Series:

(Left) L F Q T G P S C I O E R Y B M J X D K N H (Right)

Required letters:

• 5^th from the left = G
• 3^rd from the right = K

English alphabetical order:

G H I J K

Letters between G and K are:

H, I, J

Total letters between them = 3.

Hence, the correct answer is "Option 4".

Given Word:

WAMBLES

Rule:

• Each vowel is changed to the next letter in the English alphabet.
• Each consonant is changed to the previous letter in the English alphabet.

Transformation:

New group of letters:

V, B, L, A, K, F, R

Every letter appears only once.

Therefore, the number of letters appearing exactly twice = 0.

Hence, the correct answer is "Option 4 — Zero".

1. Six friends are sitting around a circular table facing the centre. Right direction is counterclockwise and Left direction is clockwise. Fix B at position (1). Only three people sit between B and M from the right of B: B(1) → pos(2) → pos(3) → pos(4) → M(5).

2. B sits second to the left of O. Left of O is clockwise. So O must be at position (3): O(3) → pos(2) → B(1).

3. N is an immediate neighbor of both M and O. Since O is at (3) and M is at (5), N must be at position (4).

4. L sits second to the left of C. Left is clockwise. Remaining positions are (2) and (6). If C is at (2), then clockwise: C(2) → pos(1) → L(6). This fits the arrangement.

To find how many people sit between B and N when counted from the right of B (counterclockwise from B): B(1) → C(2) → O(3) → N(4). There are two people (C and O) between them.

Hence, the correct answer is 'Option 4'.

Logic followed here is to track the Displacement of Mr. O in the North-South and East-West directions starting from Point L.

Given:

1. Mr. O starts from Point L and drives 7 km towards the south. 2. He then takes a left turn, drives 2 km, turns right and drives 4 km.  3. He then takes a left turn and drives 6 km. 4. He then takes a left turn and drives 13 km. 5. He takes a final left turn, drives 8 km and stops at Point M.

Step-by-step Movement:

Therefore, the shortest distance is 2 km towards the South.

Hence, the correct answer is "Option 1".

The logic followed in this pattern is a consistent alphabetical shift applied to each letter in the group.

For 'BYR' related to 'ZWP':

For 'HEZ' related to 'FCX':

Checking Option 2 'SIV : QGT' using the same logic:

Thus, the pair SIV : QGT follows the same pattern as the given pairs.

Hence, the correct answer is 'Option 2'.

Logic followed here is.

Logic: In the given letter-clusters, the first letter is increased by 5 to obtain the second letter, and the second letter is decreased by 2 to obtain the third letter of the cluster.

For UHG:

For EJH:

For QVT:

For PUS:

The pattern observed in EJH, QVT, and PUS is (+5, −2). However, UHG does not follow this pattern.

Therefore, the odd letter-cluster is UHG.

Hence, the correct answer is "Option 1".

The logic followed in this series is that each letter of the term is shifted by a constant value of +8 to obtain the corresponding letter of the next term.

Pattern:

The term completing the series is SLE.

Hence, the correct answer is "Option 2".

The logic followed here is:

Logic: Second Number = (First Number + Third Number) × 2

For the first set (5, 16, 3)

⇒ (5 + 3) × 2

⇒ 8 × 2 = 16.

For the second set (6, 18, 3)

⇒ (6 + 3) × 2

⇒ 9 × 2 = 18.

Applying the same logic to the options, we evaluate (8, 40, 12)

⇒ (8 + 12) × 2

⇒ 20 × 2 = 40.

Hence, the correct answer is 'Option 4'.

Given:

Based on the given information, let us draw a family tree to understand the relationships between the individuals.

1. Suraj is the brother of Ganesh - This means both Suraj and Ganesh are males and belong to the same generation.

2. Ganesh is the father of Harshita - Ganesh is the male parent of Harshita.

3. Harshita is the sister of Vidhi - Both Harshita and Vidhi are daughters of Ganesh, making them females and siblings.

4. Vidhi is the wife of Bheem - Vidhi is the female spouse of Bheem (who is male).

Legend: S: Suraj, G: Ganesh, H: Harshita, V: Vidhi, B: Bheem.

Therefore, Suraj is the brother of Ganesh, who is the father of Bheem's wife (Vidhi) → Suraj is the Wife's father's brother of Bheem.

Hence, the correct answer is 'Option 1'.

The logic followed here is based on the common word comparison method between the given coded statements.

Analysis of the given phrases:

1. 'lamp of wisdom' → 'nh rz vk'
2. 'light the lamp' → 'rz bw mt'

Therefore, the code for lamp in the given language is rz.

Hence, the correct answer is "Option 3".

Logic followed here is comparison of sentences to find common words and their corresponding codes.

Given:

Sentence 1: 'take my share' is coded as 'tn dp bk'

Sentence 2: 'share or perish' is coded as 'ps tn hv'

Therefore, the code for 'share' must be 'tn'.

Hence, the correct answer is "Option 1".

Given:

Let us first decode the given symbols and then draw a family tree.

On checking: W ¥ X ~ Y le Z £ T

1. W ¥ X - 'W ¥ X' means 'W is the daughter of X'.

2. X ~ Y - 'X ~ Y' means 'X is the father of Y'.

3. Y le Z - 'Y le Z' means 'Y is the sister of Z'.

4. Z £ T - 'Z £ T' means 'Z is the son of T'.

Therefore, W is the sister of Z, who is the son of T → W is the Daughter of T.

Hence, the correct answer is 'Option 3'.

Given Word:

ALTERING

Original Positions:

Arrange the letters in alphabetical order:

Comparison:

Only one letter remains in its original position.

Hence, the correct answer is "Option 3".

Given Series:

(Left) B E X Q K P X I O R G J M Y H M S M O T T (Right)

Required pattern:

Consonant → Vowel → Consonant

Checking the series:

(Left) B E X Q K P X I O R G J M Y H M S M M O T T (Right)

Vowels satisfying the condition:

→ E in (B E X)

→ O in (M O T)

Therefore, there are 2 such vowels.

Hence, the correct answer is "Option 3".

The logic followed here is:

Rank of Mr. Kell from the top = 37^th

Rank of Mr. Kell from the bottom = 155^th

To find the total number of students in the class, the following formula is used:

Total number of students = (Position from the top + Position from the bottom) − 1

= (37 + 155) − 1

= 192 − 1

= 191

So, there are 191 students in the class.

Hence, the correct answer is 'Option 1'.

The correct answer is Involuntary.

Key Points

• The analogy compares muscle types based on their functional control mechanism. Skeletal muscles are attached to the skeleton and are controlled by the somatic nervous system, meaning they are under conscious or voluntary control.
• Cardiac muscle, specifically located in the myocardium (the middle layer of the heart wall), functions automatically to pump blood throughout the body without conscious intervention.
• The contraction of cardiac tissue is regulated by the autonomic nervous system and specialized pacemaker cells (like the SA node), which classifies its movement as involuntary.
• While both skeletal and cardiac muscles exhibit striations due to the organized arrangement of sarcomeres, the defining functional difference in this analogy is the nature of their neural regulation.

 Additional Information

• Muscle Tissue Characteristics:
• Cardiac Muscle:
• Structurally, these cells are branched and typically contain only one or two central nuclei.
• They possess unique intercalated discs containing gap junctions and desmosomes, which allow for rapid electrical communication and synchronized contraction (functional syncytium).
• Skeletal Muscle:
• These are long, cylindrical, and unbranched fibers.
• They are multinucleate, with nuclei located at the periphery of the cell to accommodate the dense packing of myofibrils.
• Smooth Muscle:
• Found in the walls of hollow organs like the stomach and intestines; these are non-striated, spindle-shaped, and also involuntary.

The correct answer is 14 m/s.

Key Points

• The problem provides the maximum height (h) as 1000 cm. To maintain consistency with the SI unit of acceleration due to gravity (g), which is 9.8 m/s², the height must be converted to meters. Thus, 1000 cm ÷ 100 = 10 meters.
• In vertical motion, when an object reaches its maximum height, its final velocity (v) becomes 0 m/s instantaneously before it begins its descent.
• To find the initial velocity (u), we apply the third equation of motion under gravity: v² = u² − 2gh. The negative sign is used because the object is moving upward against the force of gravity.
• Substituting the known values into the equation: 0² = u² − (2 × 9.8 × 10). This simplifies to 0 = u² − 196.
• Rearranging the equation gives u² = 196. Taking the square root of both sides, we get u = √196, which equals 14 m/s.

 Additional Information

• Equations of Motion under Gravity:
• v = u ± gt: Relates velocity and time (t).
• h = ut ± (1/2)gt²: Relates displacement and time.
• v² = u² ± 2gh: Relates velocity and displacement without requiring time.
• The sign is positive (+) when the object falls downward and negative (−) when projected upward.
• Acceleration due to Gravity (g):
• Standard value is 9.80665 m/s² at sea level.
• It is a vector quantity always directed toward the center of the Earth.
• The value of g decreases with altitude and increases slightly from the equator to the poles due to the Earth's ellipsoidal shape.

Lymph is a fluid connective tissue that is similar to blood plasma but lacks red blood cells, platelets, and large plasma proteins. While lymph contains white blood cells (specifically lymphocytes), it does not contain platelets, which are essential for blood clotting and are found in blood.

The correct answer is It is equal to twice the atomic number for all elements..

Key Points

• Isotopes are defined as atoms of the same element that possess the same atomic number but different mass numbers. This variation occurs because isotopes have different quantities of neutrons in their nuclei. Hence, statement 1 is correct.
• The mass number (denoted by the symbol A) represents the total count of protons and neutrons located within the nucleus of an atom. These particles are collectively referred to as nucleons. Hence, statement 2 is correct.
• The relationship where the mass number is exactly twice the atomic number (A = 2Z) applies to some light stable nuclides like Helium-4 or Carbon-12, but it is not a universal rule. For example, in Hydrogen-1 (Protium), the mass number is 1 while the atomic number is 1, and in Sodium, the atomic number is 11 while the mass number is 23. Hence, statement 3 is incorrect.
• The mass number is a count of discrete subatomic particles (protons and neutrons); therefore, it must always be a whole number. This is distinct from relative atomic mass, which can be fractional. Hence, statement 4 is correct.

 Additional Information

• Mass Number vs. Atomic Mass:
• Mass Number is the integer sum of nucleons.
• Atomic Mass is the weighted average of the masses of all naturally occurring isotopes of an element, often resulting in non-integers, such as Chlorine having an atomic mass of approximately 35.5.
• Atomic Notation: In standard chemical notation, an element is represented as \( _{Z}^{A}X \), where A is the mass number and Z is the atomic number.
• Neutron Calculation: The number of neutrons (n) in an atom is determined by the formula \( n = A − Z \).

The correct answer is Nitrogen.

Key Points

• Fertilisers are chemical substances supplied to the soil or plant tissues to provide one or more nutrients essential to plant growth. The most common commercial fertilisers are centered around the NPK triad, which stands for Nitrogen (N), Phosphorus (P), and Potassium (K).
• Nitrogen is the most critical element for plant growth as it is a major component of chlorophyll, the green pigment in plants responsible for photosynthesis, converting sunlight into chemical energy.
• Scientifically, nitrogen is a core part of amino acids, which form proteins, and nucleic acids like DNA and RNA, which allow plants to grow and reproduce.
• The Haber-Bosch process is the primary industrial method used to produce ammonia, the precursor to most nitrogenous fertilisers like Urea and Ammonium Nitrate.
• While Phosphorus is vital for energy transfer (ATP) and root development, and Potassium regulates osmosis and enzyme activation, Nitrogen promotes rapid vegetative growth and lush green foliage.
• Statistical data indicates that Urea is the most widely used nitrogenous fertiliser globally, typically containing about 46% nitrogen by weight.

 Additional Information

• Secondary Macronutrients:
• Calcium: Essential for cell wall structure and transport of other nutrients; a deficiency often leads to blossom end rot in fruits.
• Magnesium: The central atom of the chlorophyll molecule; without it, plants cannot capture sun energy for photosynthesis.
• Micronutrients:
• Zinc: Needed in trace amounts for hormone production (specifically auxins) and internode elongation.
• NPK Ratio: This is a labeling convention found on fertiliser bags (e.g., 10-20-10), representing the percentage of available Nitrogen, Phosphate (P₂O₅), and Potash (K₂O).

The correct answer is Statement 1 is false but Statement 2 is true.

Key Points

• The chemical structure CH₃−CH₂−CHO consists of a three-carbon chain with a terminal carbonyl group bonded to a hydrogen atom, identifying it as an aldehyde. Under IUPAC nomenclature, a three-carbon aldehyde is named propanal, whereas propanone is a ketone with the formula CH₃−CO−CH₃. Hence, statement 1 is incorrect.
• The IUPAC system for naming organic compounds dictates that the presence of an aldehyde functional group is indicated by replacing the terminal '-e' of the parent alkane name with the suffix -al. For instance, ethane becomes ethanal and propane becomes propanal. Hence, statement 2 is correct.

 Additional Information

• Aldehydes:
• These are compounds containing the −CHO functional group, where the carbon atom is double-bonded to oxygen and single-bonded to hydrogen.
• The aldehyde group is always located at the terminal position (end) of a carbon chain, meaning the carbon in this group is always assigned carbon-1 in numbering.
• Common examples include methanal (formaldehyde) and ethanal (acetaldehyde), which are used extensively in industrial synthesis.
• Ketones:
• These feature a carbonyl group (C=O) located at a non-terminal position, meaning it is bonded to two other carbon atoms.
• They are named using the suffix -one.
• Propanone, also known as acetone, is the simplest ketone and is widely used as a solvent in laboratory and industrial applications.

The correct answer is Covering unequal distances in equal intervals of time.

Key Points

• Non-uniform motion is defined as the type of motion where an object covers unequal distances in equal intervals of time, indicating that the velocity of the object is not constant.
• In this type of motion, the speed of the object changes at different points during its journey, which means the instantaneous speed fluctuates rather than remaining steady.
• The distance-time graph for an object in non-uniform motion is represented by a curved line, showing that the slope (which represents speed) varies over time.
• Because the velocity (magnitude or direction) is changing, the object is always subjected to acceleration or deceleration.
• A real-world example is a car moving in heavy traffic, where the driver frequently applies brakes and accelerates, causing the car to cover different distances in each consecutive minute.

 Additional Information

• Uniform Motion:
• Characterized by an object covering equal distances in equal intervals of time.
• The velocity remains constant, and the direction of motion does not change.
• The acceleration in uniform motion is strictly zero because there is no change in velocity.
• Its distance-time graph is a straight line with a constant slope.
• Acceleration:
• It is the rate of change of velocity with respect to time, measured in meters per second squared (m/s²).
• Positive acceleration occurs when the speed increases, while negative acceleration (retardation) occurs when the speed decreases.
• In non-uniform motion, acceleration can be uniform (velocity changes at a constant rate) or non-uniform (velocity changes at varying rates).

The correct answer is It is used as a strong acid..

Key Points

• Sodium Hydrogen Carbonate (NaHCO₃), commonly known as baking soda, is used as a leavening agent in baking because it reacts with acidic components to release carbon dioxide gas, which causes dough to rise. Hence, statement 1 is correct.
• Sodium hydrogen carbonate is a basic salt derived from a strong base (NaOH) and a weak acid (H₂CO₃); it has a pH of approximately 8.3 and does not behave as a strong acid. Hence, statement 2 is incorrect.
• It is a crucial component in soda-acid fire extinguishers, where it reacts with an acid to produce a heavy blanket of carbon dioxide gas that cuts off the oxygen supply to the fire. Hence, statement 3 is correct.
• Due to its mildly alkaline nature, it is widely used as an antacid to neutralize the excess hydrochloric acid produced in the stomach, thereby relieving acidity and heartburn. Hence, statement 4 is correct.

 Additional Information

• Sodium Hydrogen Carbonate Characteristics:
• Chemical Formula: NaHCO₃, also referred to as sodium bicarbonate.
• Production: It is manufactured using the Solvay process, involving the reaction of sodium chloride, ammonia, and carbon dioxide in water.
• Decomposition: When heated above 50°C, it decomposes into sodium carbonate (Na₂CO₃), water, and carbon dioxide.
• Strong Acids vs. Weak Bases: Strong acids like HCl or H₂SO₄ fully ionize in water, whereas NaHCO₃ is a weak base used to neutralize such acids in chemical spills and medical applications.

The correct answer is Both statements are false.

Key Points

• Statement 1 suggests that metals and non-metals react by sharing electrons. However, in chemical reactions between these two groups, metals (which have low ionization energy) typically lose electrons to form positive cations, while non-metals (which have high electron affinity) gain those electrons to form negative anions. This process is defined as electron transfer rather than sharing. Hence, statement 1 is incorrect.
• Statement 2 posits that the bond formed between a metal and a non-metal is covalent. A covalent bond involves the mutual sharing of electron pairs, which generally occurs between two non-metals. The bond resulting from the strong electrostatic force of attraction between oppositely charged ions (formed by electron transfer) is known as an ionic bond or electrovalent bond. Hence, statement 2 is incorrect.

 Additional Information

• Ionic Compounds:
• These compounds, such as Sodium Chloride (NaCl) or Magnesium Chloride (MgCl₂), typically exist as crystalline solids.
• They possess high melting and boiling points due to the strong inter-ionic attraction.
• They are generally soluble in polar solvents like water but insoluble in organic solvents like kerosene or petrol.
• They conduct electricity in the molten state or in aqueous solution due to the movement of free ions.
• Covalent Compounds:
• Formed by atoms of non-metals to achieve a stable noble gas configuration.
• Examples include Methane (CH₄), Water (H₂O), and Carbon Dioxide (CO₂).
• These substances usually have low melting and boiling points because the intermolecular forces (like Van der Waals forces) are relatively weak compared to ionic bonds.
• Octet Rule: Atoms tend to gain, lose, or share electrons to have eight electrons in their outermost shell, ensuring maximum chemical stability.

The correct answer is Enlarged, real, inverted.

Key Points

• When an object is positioned between the first principal focus (F₁) and the center of curvature (2F₁) of a convex lens, the rays of light originating from the object undergo refraction to form an image on the opposite side of the lens.
• According to the rules of ray diagrams, a ray incident parallel to the principal axis passes through the second principal focus (F₂) after refraction.
• Another ray passing through the optical center (O) of the convex lens travels straight without any angular deviation.
• These refracted rays actually intersect at a specific point located beyond 2F₂ on the other side, characterizing the image as real and inverted.
• Since the image is formed further away from the lens than the object is (image distance v > object distance u), the linear magnification (m = v/u) is greater than 1, resulting in an enlarged or magnified image.

 Additional Information

• Convex Lens Image Characteristics:
• Object at 2F₁: The image is formed exactly at 2F₂, is real, inverted, and the same size as the object.
• Object beyond 2F₁: The image is formed between F₂ and 2F₂ and is diminished, real, and inverted.
• Object at F₁: The rays emerge parallel after refraction, meaning the image is formed at infinity and is highly enlarged.
• Object between F₁ and Optical Center: This is the only case where a convex lens produces a virtual, erect, and enlarged image, which appears on the same side as the object.
• Thin Lens Formula: The relationship between object distance (u), image distance (v), and focal length (f) is given by 1/f = 1/v − 1/u.

The correct answer is Oxygen has 8 protons and 8 electrons.

Key Points

• The atomic number (represented by the symbol Z) of a chemical element is defined as the total number of protons found in the nucleus of an atom.
• For Oxygen, an atomic number of 8 signifies that every oxygen atom contains exactly 8 protons in its central core.
• In any electrically neutral atom, the number of negatively charged electrons must equal the number of positively charged protons to balance the net charge.
• As a result, a neutral oxygen atom possesses 8 electrons arranged in its electron shells (2 in the first shell and 6 in the second shell).

 Additional Information

• Subatomic Particles and Structure:
• Protons: These are positively charged particles that define the identity of the element. They are located inside the nucleus, not in the orbits.
• Electrons: These are negatively charged particles that move around the nucleus in specific energy levels or orbitals.
• Neutrons: These are uncharged particles located in the nucleus. The number of neutrons is determined by the Mass Number (A) minus the Atomic Number (Z). While the most common isotope of oxygen (Oxygen-16) has 8 neutrons, other isotopes like Oxygen-18 have 10 neutrons.
• Molecular Structure:
• The number of atoms in a molecule is known as atomicity. Oxygen usually exists as a diatomic molecule (O₂), which means it has 2 atoms per molecule, whereas Ozone (O₃) has 3.

The correct answer is CuO + H₂ → Cu + H₂O.

Key Points

• A combination reaction (also known as a synthesis reaction) occurs when two or more reactants (elements or compounds) combine chemically to form a single product. The general form is represented as A + B → AB.
• The reaction NH₃ + HCl → NH₄Cl involves ammonia and hydrogen chloride gas reacting to form a single solid product, ammonium chloride. Since there is only one product, it is a combination reaction.
• In 2Cu + O₂ → 2CuO, elemental copper reacts with oxygen upon heating to produce copper(II) oxide. As multiple reactants form one product, this is a combination reaction.
• The reaction CaO + H₂O → Ca(OH)₂ involves calcium oxide (quicklime) reacting vigorously with water to produce calcium hydroxide (slaked lime). This is a classic example of a combination reaction.
• The equation CuO + H₂ → Cu + H₂O shows copper oxide reacting with hydrogen to produce copper and water. Because there are two distinct products formed, it does not meet the criteria of a combination reaction.

 Additional Information

• Redox and Displacement: The reaction CuO + H₂ → Cu + H₂O is categorized as a Redox Reaction.
• Reduction: The CuO is reduced to Cu because it loses oxygen.
• Oxidation: The H₂ is oxidized to H₂O because it gains oxygen.
• Displacement: This can also be viewed as a displacement reaction where hydrogen displaces copper from its oxide due to the reactivity series.
• Exothermic Nature: Many combination reactions, such as the formation of slaked lime, are highly exothermic, releasing significant amounts of thermal energy during the process.

The correct answer is It has a very high melting point..

Key Points

• Tungsten, also known as Wolfram, is used for bulb filaments because it possesses the highest melting point of any pure metal, recorded at approximately 3422 degrees Celsius.
• Incandescent bulbs operate by heating a filament to extremely high temperatures (around 2500 degrees Celsius) so that it glows and emits visible light; tungsten can withstand this heat without melting or losing structural integrity.
• The metal exhibits very low vapor pressure at high temperatures, which minimizes the rate of sublimation and prevents the filament from thinning out too quickly during operation.
• Tungsten has high tensile strength, allowing it to be drawn into extremely thin coiled wires that are durable enough to survive the mechanical stresses within a glass envelope.
• Its resistivity is sufficient to generate the necessary heat energy through Joule heating (H = I²Rt) when an electric current passes through the thin wire.

 Additional Information

• Inert Gas Filling:
• To prevent the filament from oxidizing at high temperatures, bulbs are filled with chemically inactive gases such as Argon or Nitrogen.
• This environment suppresses tungsten evaporation, thereby increasing the lifespan of the electric bulb.
• Properties of Tungsten:
• Atomic Number: It has an atomic number of 74 and belongs to the d-block of the periodic table.
• Thermal Conductivity: It possesses good thermal conductivity, which helps in the distribution of heat along the filament length.
• Efficiency: While effective, tungsten bulbs are less efficient than LEDs as most energy is lost as Infrared radiation (heat) rather than light.

The correct answer is Sodium donates one electron to chlorine, forming oppositely charged ions held by strong electrostatic forces..

Key Points

• Sodium (Na), with an atomic number of 11, has a single valence electron ([Ne] 3s¹) which it donates to Chlorine (Cl) to achieve a stable Octet, resulting in the formation of Na⁺ and Cl⁻ ions bonded by Coulombic attraction. Hence, statement 1 is correct.
• Covalent bonds are formed by the mutual sharing of electron pairs between atoms, typically occurring between non-metals with low electronegativity differences, which does not characterize the metal-nonmetal bond in NaCl. Hence, statement 2 is incorrect.
• A metallic lattice consists of metal cations surrounded by a sea of delocalized electrons; this structure is found in pure Sodium metal but is replaced by an ionic crystal structure once the reaction with Chlorine occurs. Hence, statement 3 is incorrect.
• In this redox reaction, Sodium undergoes oxidation by losing an electron to become a positive cation, while Chlorine undergoes reduction by gaining that electron; sodium never gains electrons from chlorine. Hence, statement 4 is incorrect.

 Additional Information

• Ionic Bond Stability:
• Octet Rule: The transfer allows both atoms to reach the electronic configuration of Noble Gases (Neon for Sodium and Argon for Chlorine).
• Lattice Energy: The stability is significantly enhanced by the Lattice Energy, which is the energy released when gaseous ions pack together to form a solid ionic crystal.
• Crystal Structure: Sodium Chloride forms a Face-Centered Cubic (FCC) lattice where each ion is coordinated by six ions of the opposite charge.
• Electronegativity: The large difference in Electronegativity (Sodium ≈ 0.9, Chlorine ≈ 3.0) ensures that the bond is purely Ionic rather than covalent.

The correct answer is 200 kg.

Key Points

• Identify the given physical quantities: The Unbalanced Force (F) is 100 N, the Initial Velocity (u) is 0 m/s (since the body is at rest), the Final Velocity (v) is 5 m/s, and the Time Interval (t) is 10 s.
• Calculate the Acceleration (a) of the body using the first equation of motion or the definition of acceleration, which is the rate of change of velocity. The formula is a = (v − u) / t.
• Substituting the values: a = (5 − 0) / 10, which results in a = 0.5 m/s².
• Apply Newton's Second Law of Motion, which mathematically states that Force (F) = Mass (m) × Acceleration (a).
• To find the Mass (m), rearrange the formula to m = F / a.
• Substituting the known values into the equation: m = 100 / 0.5. This calculation yields a result of 200 kg.

 Additional Information

• Newton's Second Law of Motion:
• It establishes a quantitative relationship between Force, Mass, and Acceleration.
• The law states that the acceleration of an object is directly proportional to the Net Force acting on it and inversely proportional to its Mass.
• The SI unit of force is the Newton (N), which is equivalent to 1 kg·m/s².
• Inertia and Mass:
• Mass is a fundamental property of matter that quantifies the amount of Inertia an object possesses.
• Higher mass results in greater resistance to changes in the state of Motion or Rest.
• Unlike weight, mass is a Scalar Quantity and remains constant regardless of gravitational changes.

The correct answer is Boiling point of a liquid increases with an increase in atmospheric pressure and decreases with a decrease in atmospheric pressure..

Key Points

• The boiling point of a liquid is defined as the temperature at which its vapor pressure equals the external atmospheric pressure surrounding the liquid.
• At high altitudes, such as hill stations, the atmospheric pressure is significantly lower than at sea level due to the thinner air column above. Because the external pressure is lower, water requires less heat to match its vapor pressure with the environment, causing it to boil at temperatures below 100°C.
• In a pressure cooker, the steam produced is trapped inside a sealed container, which rapidly increases the internal pressure. This elevated pressure prevents water molecules from escaping into the gas phase until a much higher temperature is reached, typically around 120°C.
• The physical principle involved is that the boiling point is directly proportional to the external pressure; as pressure increases, more thermal energy is needed to facilitate the phase change from liquid to gas.

 Additional Information

• Vapor Pressure:
• It is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature in a closed system.
• As temperature increases, the kinetic energy of molecules increases, thereby increasing the vapor pressure.
• Clausius-Clapeyron Equation:
• This equation characterizes the phase transition between two states of matter and mathematically relates the dependence of boiling point on pressure.
• Practical Implications:
• In mountainous regions, food takes longer to cook in open vessels because the water cannot exceed its low boiling point (e.g., 92°C), providing less heat to the food.
• Autoclaves used in hospitals for sterilization operate on the same principle as a pressure cooker to reach temperatures high enough to kill resistant bacteria and spores.

The correct answer is Larger pressure.

Key Points

• Pressure is defined as the thrust acting perpendicularly per unit area of a surface.
• The mathematical relationship between these physical quantities is expressed by the formula: Pressure = Thrust / Area.
• According to this formula, pressure is inversely proportional to the area on which the force (thrust) acts, provided the magnitude of the force remains constant.
• Therefore, if a force acts on a smaller area, the pressure generated is larger because the force is concentrated over a limited space.
• In contrast, if the same force acts on a larger area, the pressure becomes smaller as the force is distributed across a wider surface.

 Additional Information

• Concept of Thrust:
• Thrust is the total perpendicular force exerted by an object on a surface.
• The SI unit for thrust is the Newton (N), the same as for any other force.
• Units of Pressure:
• The SI unit of pressure is the Pascal (Pa), where 1 Pa = 1 N/m².
• It is named in honor of the French mathematician and physicist Blaise Pascal.
• Real-World Applications:
• Sharp Tools: Needles, nails, and knives have pointed or sharp edges to reduce the contact area, thereby exerting larger pressure to penetrate surfaces easily.
• Broad Foundations: High-rise buildings and dams have very wide bases to increase the area and reduce the pressure exerted on the ground to prevent sinking.
• Heavy Vehicles: Tractors and tanks use wide tires or caterpillar tracks to distribute weight over a larger area, minimizing pressure on soft ground.

The correct answer is Against gravity.

Key Points

• Gravitational Potential Energy (GPE) is the energy an object possesses due to its position in a gravitational field, typically relative to the Earth's surface.
• To lift an object of mass m to a height h, an external force must be applied to counteract the object's weight. The weight of an object is the downward force exerted by gravity, calculated as Weight = m × g, where g is the acceleration due to gravity (approximately 9.8 m/s²).
• Work is mathematically defined as the product of force and displacement. When lifting an object, the displacement is upward, while the gravitational force acts downward.
• Because the lifting force acts in the opposite direction to the gravitational pull, the process is described as doing work against gravity.
• This work done is stored in the object as potential energy, expressed by the formula U = mgh. If no other forces (like friction) are present and the object is moved at a constant velocity, the work performed by the external agent exactly equals the gain in Potential Energy.

 Additional Information

• Conservative Forces and Paths:
• Gravity is a conservative force, which means the work done to move an object between two points is independent of the path taken. Whether the object is lifted vertically or along a curved path, the GPE depends only on the vertical displacement.
• Direction of Movement:
• If an object moves in the direction of gravity (falls downward), the potential energy is converted into kinetic energy, and the work done by gravity is positive while the GPE decreases.
• Work-Energy Theorem:
• According to this principle, the total work done on an object is equal to its change in Kinetic Energy. When lifting an object with constant velocity, there is no change in kinetic energy, so the external work done against gravity translates entirely into potential energy.

The correct answer is The atmosphere bends the starlight due to gradual changes in refractive index.

Key Points

• This phenomenon occurs due to Atmospheric Refraction, which is the deviation of light from a straight line as it passes through the Earth's atmosphere.
• As starlight enters the atmosphere, it travels from a vacuum (rarer medium) into layers of air with increasing density (denser medium).
• The refractive index of the Earth's atmosphere gradually increases as we move closer to the surface because the air becomes denser near the ground.
• According to the laws of refraction, when light travels from a rarer to a denser medium, it bends towards the normal. Since the atmosphere consists of layers with varying indices, the light bends continuously.
• The human eye perceives light as traveling in a straight line. Therefore, when we trace the refracted ray backward, the apparent position of the star appears slightly higher than its actual position, especially when observed near the horizon.

 Additional Information

• Atmospheric Refraction Effects:
• Advanced Sunrise and Delayed Sunset: The Sun is visible to us about 2 minutes before the actual sunrise and 2 minutes after the actual sunset due to the same bending of light.
• Twinkling of Stars: The stars act as point sources of light. As the physical conditions of the atmosphere change, the refractive index fluctuates, causing the apparent position and intensity of light to change, resulting in a twinkling effect.
• Apparent Flattening of the Sun: At sunrise and sunset, the bottom part of the Sun's disc is closer to the horizon and refracted more than the upper part, making the Sun appear oval or flattened.
• Refractive Index: It is the ratio of the speed of light in a vacuum to the speed of light in a specific medium. For air at sea level, the refractive index is approximately 1.00029.

The correct answer is Weeds compete with crops for resources.

Key Points

• Weeds are defined as undesirable and unwanted plants that grow alongside cultivated crops, often possessing more aggressive growth characteristics than the main crop.
• The primary reason for weed management is that these plants engage in interspecific competition for vital limiting resources, specifically soil nutrients (nitrogen, phosphorus, potassium), irrigation water, sunlight, and physical space.
• Since weeds consume the fertilizers and moisture intended for the crops, their presence leads to nutrient deficiency, causing stunted growth and a significant reduction in the overall crop yield.
• Uncontrolled weed growth can harbor pests and pathogens, further indirectly damaging the health of the primary agricultural produce.
• Managing weeds early in the crop life cycle is critical to ensuring that the crop establishes a canopy and utilizes available resources efficiently for biomass production.

 Additional Information

• Common Weed Examples:
• Xanthium (Gokhroo), Parthenium (Gajar ghas), and Cyperinus rotundus (Motha) are some of the most prevalent weeds found in Indian agriculture.
• Control Strategies:
• Mechanical Methods: Includes uprooting weeds by hand, ploughing, and using tools like the khurpi for weeding.
• Chemical Methods: The application of herbicides or weedicides, such as 2,4-D, Atrazine, and Butachlor, which are designed to selectively eliminate weeds.
• Biological Control: Utilizing natural enemies like insects or specific bio-herbicides to suppress the growth of specific weed species.
• Cultural Methods: Practicing crop rotation, intercropping, and timely sowing of seeds to provide the crop a competitive advantage over weeds.

The correct answer is Both statements I and II are true..

Key Points

• Evaporation is the process of a liquid changing into a gas or vapour at any temperature below its boiling point. It differs from boiling as it is a surface phenomenon, where only the particles at the surface gain enough kinetic energy to break the forces of attraction and escape. Hence, statement I is correct.
• The rate of evaporation depends heavily on the amount of surface area exposed to the atmosphere. Because evaporation is a surface-based process, increasing the area allows a larger number of molecules to transition from the liquid phase to the vapour phase simultaneously. Hence, statement II is correct.