Find the length of the longest pole that can be placed in a room of dimensions 30 m × 15 m × 10 m.
- AOption (a)
31 m
- BOption (b)
33 m
- COption (c)
35 m
- DOption (d)
18 m
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Correct answer
35 m
Why this answer is correct
Shortcut Trick
The longest pole in a rectangular room is always the diagonal of the cuboid.
Diagonal = √(Length2 + Breadth2 + Height2)
Diagonal = √(302 + 152 + 102) = √(900 + 225 + 100) = √1225 = 35 m.
∴ The correct answer is 35 m.
Alternate Method
Given:
Length (L) = 30 m
Breadth (B) = 15 m
Height (H) = 10 m
Formula Used:
Length of the longest pole = Diagonal of the room = √(L2 + B2 + H2)
Calculations:
⇒ Longest pole = √(302 + 152 + 102)
⇒ Longest pole = √(900 + 225 + 100)
⇒ Longest pole = √1225
⇒ Longest pole = 35 m
∴ The correct answer is 35 m.
Additional Information
Total Surface Area of Cuboid
The total area covering all faces is given by 2(LB + BH + LH).
Volume of Cuboid
The space occupied by the cuboid is calculated as Length × Breadth × Height.
Lateral Surface Area
Area of the four walls of the room = 2 × Height × (Length + Breadth).





















