Shortcut Trick
Put θ = 45° to find the value of the expression directly.
First term: √[ (sec245° + cosec245°) ÷ (tan245° − sin245°) ] = √[ (2 + 2) ÷ (1 − 1/2) ] = √[ 4 ÷ (1/2) ] = √8 = 2√2
Second term: [ (1 + tan245°) sin245° ] ÷ [ (cosec 45° − cot 45°)(1 + cos 45°) ] = [ 2 × (1/2) ] ÷ [ (√2 − 1)(1 + 1/√2) ] = 1 ÷ [ (√2 − 1)(√2 + 1)/√2 ] = 1 ÷ [ (2 − 1)/√2 ] = √2
Multiplying both terms: 2√2 × √2 = 4
Checking options for θ = 45°: cosec245° sec245° = 2 × 2 = 4
∴ The correct answer is cosec2θ sec2θ.
Alternate Method
Given:
The trigonometric expression is: \(\sqrt {\frac{{{\rm{se}}{{\rm{c}}^{\rm{2}}}{\rm{\theta }},,{\rm{ + }},,{\rm{cose}}{{\rm{c}}^2}{\rm{\theta }}}}{{{{\tan }^2}{\rm{\theta }} - ,{{\sin }^2}{\rm{\theta }}}}} , \times ,,\frac{{\left( {1 + {{\tan }^2}{\rm{\theta }}} \right),{{\sin }^2}{\rm{\theta }}}}{{\left( {{\rm{cosec}},{\rm{\theta }},{\rm{ - }},{\rm{cot}},{\rm{\theta }}} \right)\left( {1 + \cos ,{\rm{\theta }}} \right)}}\)
Formula Used:
- sec2θ + cosec2θ = sec2θ cosec2θ
- tan2θ − sin2θ = tan2θ sin2θ
- 1 + tan2θ = sec2θ
- cosec θ − cot θ = (1 − cos θ) ÷ sin θ
Calculations:
⇒ Simplify the term inside the square root:
⇒ Num = sec2θ + cosec2θ = 1/cos2θ + 1/sin2θ = (sin2θ + cos2θ)/(sin2θ cos2θ) = 1/(sin2θ cos2θ) = sec2θ cosec2θ
⇒ Den = tan2θ − sin2θ = sin2θ/cos2θ − sin2θ = sin2θ (1/cos2θ − 1) = sin2θ tan2θ
⇒ Square root term = √[ (sec2θ cosec2θ) ÷ (sin2θ tan2θ) ] = (sec θ cosec θ) ÷ (sin θ tan θ) = [ (1/cos θ)(1/sin θ) ] ÷ [ sin θ (sin θ/cos θ) ] = 1/(sin3θ)
⇒ Simplify the second term:
⇒ Num = (1 + tan2θ) sin2θ = sec2θ sin2θ = sin2θ/cos2θ = tan2θ
⇒ Den = (cosec θ − cot θ)(1 + cos θ) = [ (1 − cos θ)/sin θ ] × (1 + cos θ) = (1 − cos2θ)/sin θ = sin2θ/sin θ = sin θ
⇒ Second term = tan2θ ÷ sin θ = sin2θ/(cos2θ sin θ) = sin θ/cos2θ
⇒ Multiplying both simplified terms:
⇒ Result = [ 1/(sin3θ) ] × [ sin θ/cos2θ ] = 1/(sin2θ cos2θ) = cosec2θ sec2θ
∴ The correct answer is cosec2θ sec2θ.
Additional Information
Trigonometric Identity for Sum and Product
The sum of squares of secant and cosecant is equal to their product: sec2θ + cosec2θ = sec2θ cosec2θ.
Trigonometric Identity for Difference and Product
The difference of squares of tangent and sine is equal to their product: tan2θ − sin2θ = tan2θ sin2θ.
Reciprocal Conjugate Property
cosec θ − cot θ is the reciprocal of cosec θ + cot θ, which helps simplify rational expressions containing trigonometric ratios.