ESIC UDC Mains Memory Based Paper (30th April 2022) (Previous Year Paper)

1. D is sitting tenth from the left end and immediate neighbour of N.

(Here, we will have two cases, Case 1: When D is right of N and Case 2: When D is left of N.)      

2. K is sitting at the extreme right end.

3. P is fifth from the left of the D. (Here, we can eliminate case 1 as if statement 3 follows then statement 4 is not satisfied)

4. Three persons are between the P and N.

5. P is sitting between the A and S.

6. S is sitting fourth from the left end.

7. C is sitting tenth from the right end and immediate neighbour of D.

8. H sits immediate left of the S.

Hence, the final arrangement will be as follows:

Hence, four persons are sitting between S and N.

1. D is sitting tenth from the left end and immediate neighbour of N.

(Here, we will have two cases, Case 1: When D is right of N and Case 2: When D is left of N.)      

2. K is sitting at the extreme right end.

3. P is fifth from the left of the D. (Here, we can eliminate case 1 as if statement 3 follows then statement 4 is not satisfied)

4. Three persons are between the P and N.

5. P is sitting between the A and S.

6. S is sitting fourth from the left end.

7. C is sitting tenth from the right end and immediate neighbour of D.

8. H sits immediate left of the S.

Hence, the final arrangement will be as follows:

Hence, 20 persons are sitting in a row.

1. D is sitting tenth from the left end and immediate neighbour of N.

(Here, we will have two cases, Case 1: When D is right of N and Case 2: When D is left of N.)      

2. K is sitting at the extreme right end.

3. P is fifth from the left of the D. (Here, we can eliminate case 1 as if statement 3 follows then statement 4 is not satisfied)

4. Three persons are between the P and N.

5. P is sitting between the A and S.

6. S is sitting fourth from the left end.

7. C is sitting tenth from the right end and immediate neighbour of D.

8. H sits immediate left of the S.

Hence, the final arrangement will be as follows:

Hence, no one is sitting at the left end of the row.

1. D is sitting tenth from the left end and immediate neighbour of N.

(Here, we will have two cases, Case 1: When D is right of N and Case 2: When D is left of N.)      

2. K is sitting at the extreme right end.

3. P is fifth from the left of the D. (Here, we can eliminate case 1 as if statement 3 follows then statement 4 is not satisfied)

4. Three persons are between the P and N.

5. P is sitting between the A and S.

6. S is sitting fourth from the left end.

7. C is sitting tenth from the right end and immediate neighbour of D.

8. H sits immediate left of the S.

Hence, the final arrangement will be as follows:

Hence, D is sitting in the middle of the person N and C.

1. D is sitting tenth from the left end and immediate neighbour of N.

(Here, we will have two cases, Case 1: When D is right of N and Case 2: When D is left of N.)      

2. K is sitting at the extreme right end.

3. P is fifth from the left of the D. (Here, we can eliminate case 1 as if statement 3 follows then statement 4 is not satisfied)

4. Three persons are between the P and N.

5. P is sitting between the A and S.

6. S is sitting fourth from the left end.

7. C is sitting tenth from the right end and immediate neighbour of D.

8. H sits immediate left of the S.

Hence, the final arrangement will be as follows:

Hence, none of the above is correct.

Clearly, there is more than one meaningful word.

Hence, Y is the correct answer.

According to the English alphabet series and its positional value:

The logic follows here is:

only four pairs forming they are AC, CE, AE,TU.

Hence, There are four pairs of letters.

Person: A, B, C, D, E, F, G and H

Month: January, February, April, June, August, September, October and December

1. G goes on a month which has 31 days. G does not go on a vacation in January. 2. Only one person goes between A and G. 3. Three persons goes between A and F.

4. Five persons goes between H and C who does not go on a month which has 30 days 5. H does not go on a vacation which has 31 days

6. B goes next month after A 7. One person goes between B and E.

8. D goes before F.

Hence, The answer is Four.

Person: A, B, C, D, E, F, G and H

Month: January, February, April, June, August, September, October and December

1. G goes on a month which has 31 days. G does not go on a vacation in January. 2. Only one person goes between A and G. 3. Three persons goes between A and F.

4. Five persons goes between H and C who does not go on a month which has 30 days 5. H does not go on a vacation which has 31 days

6. B goes next month after A 7. One person goes between B and E.

8. D goes before F.

Hence, The person who goes vacation in September is E.

Person: A, B, C, D, E, F, G and H

Month: January, February, April, June, August, September, October and December

1. G goes on a month which has 31 days. G does not go on a vacation in January. 2. Only one person goes between A and G. 3. Three persons goes between A and F.

4. Five persons goes between H and C who does not go on a month which has 30 days 5. H does not go on a vacation which has 31 days

6. B goes next month after A 7. One person goes between B and E.

8. D goes before F.

The number of people going before B is three, The number of people going after G is also three.

Hence, the answer is G.

Person: A, B, C, D, E, F, G and H

Month: January, February, April, June, August, September, October and December

1. G goes on a month which has 31 days. G does not go on a vacation in January. 2. Only one person goes between A and G. 3. Three persons goes between A and F.

4. Five persons goes between H and C who does not go on a month which has 30 days 5. H does not go on a vacation which has 31 days

6. B goes next month after A 7. One person goes between B and E.

8. D goes before F.

All the persons except A is going on vacantion on the month which have 31 numbers of days.

Only A is going in a month which have 30 days.

Hence the correct answer is A.

Person: A, B, C, D, E, F, G and H

Month: January, February, April, June, August, September, October and December

1. G goes on a month which has 31 days. G does not go on a vacation in January. 2. Only one person goes between A and G. 3. Three persons goes between A and F.

4. Five persons goes between H and C who does not go on a month which has 30 days 5. H does not go on a vacation which has 31 days

6. B goes next month after A 7. One person goes between B and E.

8. D goes before F.

Hence, The person who goes immediately before A after exchanging is E.

Statement:

Z = X > C < V ≤ B = N = M ≤ D ≤ Y = I > K < F > G

Conclusions:

I. Z < D → False (Z = X > C < V ≤ B = N = M ≤ D → No definite relation between the two can be determined)

II. I ≥ V → True (V ≤ B = N = M ≤ D ≤ Y = I → V ≤ I → I ≥ V)

Hence, Only conclusion II follows

Statement:

Q > W < E = R > T ≤ Y ≤ U ≥ I < O = P < Z < D > J

Conclusions:

I. Q > T → False (Q > W < E = R > T → There is no definite relation between the two elements)

II. R > O → False (R > T ≤ Y ≤ U ≥ I < O →There is no definite relation between the two elements)

Hence, Neither conclusion I nor II follows

Given statements: T ≥ U > W < S = V ≤ X; X < P = Q ≥ R > Y 

On combining: T ≥ U > W < S = V ≤ X < P = Q ≥ R > Y

I. T > Q → False (T ≥ U > W < S = V ≤ X < P = Q → relation between them cannot be determined)

II. Y < S → False (Y < R ≤ Q = P > X ≥ V = S → relation between them cannot be determined)

Hence, correct answer is neither conclusion I nor II follows.

Given Statements:  T ≤ R = F < P = D; Q < M ≤ S > C ≥ T 

On combining above two statements: Q < M ≤ S > C ≥ T ≤ R = F < P = D

Conclusions:

I. M > R False ( as M ≤ S > C ≥ T ≤ R, hence no clear direct relation can be established between M and R )

II. M ≤ R False ( as M ≤ S > C ≥ T ≤ R hence no clear direct relation can be established between M and R )

Here conclusion I and II forms complementary pair.

Hence either conclusion I or II follows.

Important Points 

For complimentary pair to form three conditions must be present.

i) Both conclusions must be individually false.

II) Elements in both conclusions must be the same.

III) All the three symbol <, >, = must be present after combining the two conclusions.

Given statements: A = C > D ≤ E ≤ H, C > I ≥ J > K = F, E ≥ D = P ≥ Q = G

Conclusions:

I A > F → True (Because A = C so A > 𝐼 ≥ 𝐽 > 𝐾 =𝐹  → A > F )

II G ≤ H → True (Because E ≤ H and E ≥ D so by combining H ≥ E ≥ D = P ≥ Q = G  → G ≤ H)

Hence, Both conclusion I and II follows.

1. Two people are sitting between E and F.

2. Neither E nor F is sitting at any of the extreme ends.

3. O is sitting second to the right of N who is facing E.

(It is only possible if E is sitting at the second seat from the right end in his row and F is sitting third to his left.)

4. A is an immediate neighbour of the person who is facing O.

(Implies, A is sitting to the immediate left of E as we can’t place A to the other side of the person facing O because F is there.)

5. Two people are sitting between M and P.

6. P is facing neither A nor B.

(Implies, M is sitting to the immediate left of O and P is sitting at the rightmost seat in his row.)

7. B is sitting at one of the extreme ends.

(As B is not sitting opposite P, implies, B must be sitting on the other extreme end.)

8. Q is not facing F.

(Q must be facing B as it is the only other option. Also, L is facing F as L is the only person left to be placed in the north-facing row.)

9. D is sitting second to the right of C.

(Implies, C is sitting to the immediate left of F and D is sitting to the immediate right of F.)

Clearly, A is facing M.

1. Two people are sitting between E and F.

2. Neither E nor F is sitting at any of the extreme ends.

3. O is sitting second to the right of N who is facing E.

(It is only possible if E is sitting at the second seat from the right end in his row and F is sitting third to his left.)

4. A is an immediate neighbour of the person who is facing O.

(Implies, A is sitting to the immediate left of E as we can’t place A to the other side of the person facing O because F is there.)

5. Two people are sitting between M and P.

6. P is facing neither A nor B.

(Implies, M is sitting to the immediate left of O and P is sitting at the rightmost seat in his row.)

7. B is sitting at one of the extreme ends.

(As B is not sitting opposite P, implies, B must be sitting on the other extreme end.)

8. Q is not facing F.

(Q must be facing B as it is the only other option. Also, L is facing F as L is the only person left to be placed in the north-facing row.)

9. D is sitting second to the right of C.

(Implies, C is sitting to the immediate left of F and D is sitting to the immediate right of F.)

Clearly, M is sitting second to the right of Q.

1. Two people are sitting between E and F.

2. Neither E nor F is sitting at any of the extreme ends.

3. O is sitting second to the right of N who is facing E.

(It is only possible if E is sitting at the second seat from the right end in his row and F is sitting third to his left.)

4. A is an immediate neighbour of the person who is facing O.

(Implies, A is sitting to the immediate left of E as we can’t place A to the other side of the person facing O because F is there.)

5. Two people are sitting between M and P.

6. P is facing neither A nor B.

(Implies, M is sitting to the immediate left of O and P is sitting at the rightmost seat in his row.)

7. B is sitting at one of the extreme ends.

(As B is not sitting opposite P, implies, B must be sitting on the other extreme end.)

8. Q is not facing F.

(Q must be facing B as it is the only other option. Also, L is facing F as L is the only person left to be placed in the north-facing row.)

9. D is sitting second to the right of C.

(Implies, C is sitting to the immediate left of F and D is sitting to the immediate right of F.)

Clearly, P is sitting opposite C.

1. Two people are sitting between E and F.

2. Neither E nor F is sitting at any of the extreme ends.

3. O is sitting second to the right of N who is facing E.

(It is only possible if E is sitting at the second seat from the right end in his row and F is sitting third to his left.)

4. A is an immediate neighbour of the person who is facing O.

(Implies, A is sitting to the immediate left of E as we can’t place A to the other side of the person facing O because F is there.)

5. Two people are sitting between M and P.

6. P is facing neither A nor B.

(Implies, M is sitting to the immediate left of O and P is sitting at the rightmost seat in his row.)

7. B is sitting at one of the extreme ends.

(As B is not sitting opposite P, implies, B must be sitting on the other extreme end.)

8. Q is not facing F.

(Q must be facing B as it is the only other option. Also, L is facing F as L is the only person left to be placed in the north-facing row.)

9. D is sitting second to the right of C.

(Implies, C is sitting to the immediate left of F and D is sitting to the immediate right of F.)

Except for N, all are sitting on extreme ends.

Hence, N does not belong to the group.

1. Two people are sitting between E and F.

2. Neither E nor F is sitting at any of the extreme ends.

3. O is sitting second to the right of N who is facing E.

(It is only possible if E is sitting at the second seat from the right end in his row and F is sitting third to his left.)

4. A is an immediate neighbour of the person who is facing O.

(Implies, A is sitting to the immediate left of E as we can’t place A to the other side of the person facing O because F is there.)

5. Two people are sitting between M and P.

6. P is facing neither A nor B.

(Implies, M is sitting to the immediate left of O and P is sitting at the rightmost seat in his row.)

7. B is sitting at one of the extreme ends.

(As B is not sitting opposite P, implies, B must be sitting on the other extreme end.)

8. Q is not facing F.

(Q must be facing B as it is the only other option. Also, L is facing F as L is the only person left to be placed in the north-facing row.)

9. D is sitting second to the right of C.

(Implies, C is sitting to the immediate left of F and D is sitting to the immediate right of F.)

Clearly, no one is sitting second to the left of F as he is sitting at the second seat from the left end in his row.

The logic followed here is:

So, LATE is coded as KYQA.

And,

So, TEAR is coded as SCXN.

Similarly,

So, RATTLE is coded as QYQPGY.

Six friends P, Q, R, S, T and U are sitting in a row facing north.

(1) P is sitting at one extreme end.

Case (I)

Case (II)

(2) Q is sitting second to the right of S.

(3) R is sitting exactly between U and Q.

Case (I)

Case (II)

(4) T is not second to the right of P. Case I eliminates here. Thus, the final arrangement is as follows:

Case (II)

​

Hence, Q sits to the immediate right of T

Six friends P, Q, R, S, T and U are sitting in a row facing north.

(1) P is sitting at one extreme end.

Case (I)

Case (II)

(2) Q is sitting second to the right of S.

(3) R is sitting exactly between U and Q.

Case (I)

Case (II)

(4) T is not second to the right of P. Case I eliminates here. Thus, the final arrangement is as follows:

Case (II)

​

Hence, SP is the correct answer.

1. Age of P is the square of the 3^rd prime number
2. The sum of the ages of S and P is 86.

That means, the third prime number is 5 and its square is 25.

Hence, age of S will be 86 - 25 = 61

3. S is older than P

4. The sum of the ages of P and R is 81.

Hence, Age of R = 81 - 25 = 56

5. Q is older than S and U is younger than T who is not older than R.

Hence, Q is the eldest person in the group.

6.Age of U is less than P whose age is less than T.

Hence, Age of U can be 13 years as per the given combination.

1. Age of P is the square of the 3^rd prime number
2. The sum of the ages of S and P is 86.

That means, the third prime number is 5 and its square is 25.

Hence, age of S will be 86 - 25 = 61

3. S is older than P

4. The sum of the ages of P and R is 81.

Hence, Age of R = 81 - 25 = 56

5. Q is older than S and U is younger than T who is not older than R.

Hence, Q is the eldest person in the group.

6.Age of U is less than P whose age is less than T.

Hence, only two people born after T.

1. Age of P is the square of the 3^rd prime number
2. The sum of the ages of S and P is 86.

That means, the third prime number is 5 and its square is 25.

Hence, age of S will be 86 - 25 = 61

3. S is older than P

4. The sum of the ages of P and R is 81.

Hence, Age of R = 81 - 25 = 56

5. Q is older than S and U is younger than T who is not older than R.

Hence, Q is the eldest person in the group.

6.Age of U is less than P whose age is less than T.

Hence, the incorrect statement is ‘Q’s age is 55 years’ as Age of S is 61 years and S is younger than Q.

1. Age of P is the square of the 3^rd prime number
2. The sum of the ages of S and P is 86.

That means, the third prime number is 5 and its square is 25.

Hence, age of S will be 86 - 25 = 61

3. S is older than P

4. The sum of the ages of P and R is 81.

Hence, Age of R = 81 - 25 = 56

5. Q is older than S and U is younger than T who is not older than R.

Hence, Q is the eldest person in the group.

6.Age of U is less than P whose age is less than T.

As age of R is 56 years and sum of U and R is 75 years so age of U is 75 - 56 = 19 years.

1. Age of P is the square of the 3^rd prime number
2. The sum of the ages of S and P is 86.

That means, the third prime number is 5 and its square is 25.

Hence, age of S will be 86 - 25 = 61

3. S is older than P

4. The sum of the ages of P and R is 81.

Hence, Age of R = 81 - 25 = 56

5. Q is older than S and U is younger than T who is not older than R.

Hence, Q is the eldest person in the group.

6.Age of U is less than P whose age is less than T.

Hence, R is the third eldest person and his age is 56 years.

1. Equal number of persons are elder and younger than Swati.

2. Shweta was born in an even numbered year after 1987 but before 2006

Case 1

Case 2

3. Only one person is elder to Vaibhav.

4. Age of Soniya is an even number

5. Only one person was born between Swati and Raman

Case 1

Case 2

6. Sakshi was neither born in the year 1992 nor is the eldest among all → Case 2 gets canceled.

So, the final arrangement will be

Case 1

Hence, Shweta is 29 years old.

1. Equal number of persons are elder and younger than Swati.

2. Shweta was born in an even numbered year after 1987 but before 2006

Case 1

Case 2

3. Only one person is elder to Vaibhav.

4. Age of Soniya is an even number

5. Only one person was born between Swati and Raman

Case 1

Case 2

6. Sakshi was neither born in the year 1992 nor is the eldest among all → Case 2 gets canceled.

So, the final arrangement will be

Case 1

Hence, Nikhil is the eldest among all.

1. Equal number of persons are elder and younger than Swati.

2. Shweta was born in an even numbered year after 1987 but before 2006

Case 1

Case 2

3. Only one person is elder to Vaibhav.

4. Age of Soniya is an even number

5. Only one person was born between Swati and Raman

Case 1

Case 2

6. Sakshi was neither born in the year 1992 nor is the eldest among all → Case 2 gets canceled.

So, the final arrangement will be

Case 1

Hence, Raman was born after Sakshi but before Soniya.

1. Equal number of persons are elder and younger than Swati.

2. Shweta was born in an even numbered year after 1987 but before 2006

Case 1

Case 2

3. Only one person is elder to Vaibhav.

4. Age of Soniya is an even number

5. Only one person was born between Swati and Raman

Case 1

Case 2

6. Sakshi was neither born in the year 1992 nor is the eldest among all → Case 2 gets canceled.

So, the final arrangement will be

Case 1

Hence, Sakshi was born in the year 2000.

1. Equal number of persons are elder and younger than Swati.

2. Shweta was born in an even numbered year after 1987 but before 2006

Case 1

Case 2

3. Only one person is elder to Vaibhav.

4. Age of Soniya is an even number

5. Only one person was born between Swati and Raman

Case 1

Case 2

6. Sakshi was neither born in the year 1992 nor is the eldest among all → Case 2 gets canceled.

So, the final arrangement will be

Case 1

Hence, Shweta was born is the year 1995 is false. Correct statement is: Shweta was born in the year 1992.

The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. Some chairs are cupboard → False (It is possible but not definite)

II. All table can be cupboard is a possibility → True (Possibility is true as shown below)

III. No chair is a cupboard → False (It is possible but not definite)

Conclusion I and III forms complementary pairs.

Thus, Only conclusion II and Either I or III follow.

The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. Some tasty not being sweet is a possibility → True (Possibility is true as shown below)

II. Some salt are not sweet → False (It is possible but not definite)

III. All tasty can never be salt → False (It is possible but not definite)

Thus, only conclusions I follows.

The least Possible Venn diagram is shown below:

Conclusions:

I. Some Tax can never be Rate → False (as only a few pay is tax is given)

II. No Rent is Rate→ False (The possibility is true hence definite is false)

III. Some Pays cannot be Rent→ False.

IV. Some Tax can be Rate → True.

Hence, the correct answer is only IV follows.

The least Possible Venn diagram is shown below:

Conclusions:

I. Some Line are not Pink → False.

II. Some Pink can never be Table → False. (It is possible)

III. Some college are not Line → False. (No direct relationship is given)

Hence, the correct answer none follows.

The least Possible Venn diagram is shown below:

Conclusions:

I. All Curd being Beans is a possibility → False (Only a few curd is bean means some curd is bean and some curd is not bean so, so all curd can’t be beans.)

II. Some Curd are not Office → True. (only a few curd is bean and no bean is office so, the part of curd that is bean are not office

III. Some Curd are not Beans → True. (Only a few curd is bean means some curd is bean and some curd is not bean)

Hence, the correct answer is II and III follows.

Companies of mobiles - Iphone, Oppo, Samsung, Xperia, One plus and Nokia.

Number of mobiles – 1, 2, 3, 4, 5 and 6.

1. Box of Nokia is three boxes above the box containing 3 mobiles.

2. The bottommost box contains 6 mobiles.

3. There is one box between the box of Nokia and box of Iphone.

4. There are 4 Samsung mobiles and the box of Samsung is just above the box containing 2 mobiles.

5. There are odd number of Nokia phones.

6. The box of Xperia is just above box of Oppo.

7. The box of One plus contains one less mobile than that of box of Iphones. So, there is only (1) One plus mobile. And, case 2 would be rejected.

There is one box above the box of Nokia.

Hence, one is the correct answer.

Companies of mobiles - Iphone, Oppo, Samsung, Xperia, One plus and Nokia.

Number of mobiles – 1, 2, 3, 4, 5 and 6.

1. Box of Nokia is three boxes above the box containing 3 mobiles.

2. The bottommost box contains 6 mobiles.

3. There is one box between the box of Nokia and box of Iphone.

4. There are 4 Samsung mobiles and the box of Samsung is just above the box containing 2 mobiles.

5. There are odd number of Nokia phones.

6. The box of Xperia is just above box of Oppo.

7. The box of One plus contains one less mobile than that of box of Iphones. So, there is only (1) One plus mobile. And, case 2 would be rejected.

There are 6 Oppo phones.

Hence, 6 is the correct answer.

Companies of mobiles - Iphone, Oppo, Samsung, Xperia, One plus and Nokia.

Number of mobiles – 1, 2, 3, 4, 5 and 6.

1. Box of Nokia is three boxes above the box containing 3 mobiles.

2. The bottommost box contains 6 mobiles.

3. There is one box between the box of Nokia and box of Iphone.

4. There are 4 Samsung mobiles and the box of Samsung is just above the box containing 2 mobiles.

5. There are odd number of Nokia phones.

6. The box of Xperia is just above box of Oppo.

7. The box of One plus contains one less mobile than that of box of Iphones. So, there is only (1) One plus mobile. And, case 2 would be rejected.

There are 3 Xperia mobiles.

Hence, option 3 is correct answer.

Companies of mobiles - Iphone, Oppo, Samsung, Xperia, One plus and Nokia.

Number of mobiles – 1, 2, 3, 4, 5 and 6.

1. Box of Nokia is three boxes above the box containing 3 mobiles.

2. The bottommost box contains 6 mobiles.

3. There is one box between the box of Nokia and box of Iphone.

4. There are 4 Samsung mobiles and the box of Samsung is just above the box containing 2 mobiles.

5. There are odd number of Nokia phones.

6. The box of Xperia is just above box of Oppo.

7. The box of One plus contains one less mobile than that of box of Iphones. So, there is only (1) One plus mobile. And, case 2 would be rejected.

There is 1 mobile in the topmost box.

Hence, 1 is the correct answer.

Companies of mobiles - Iphone, Oppo, Samsung, Xperia, One plus and Nokia.

Number of mobiles – 1, 2, 3, 4, 5 and 6.

1. Box of Nokia is three boxes above the box containing 3 mobiles.

2. The bottommost box contains 6 mobiles.

3. There is one box between the box of Nokia and box of Iphone.

4. There are 4 Samsung mobiles and the box of Samsung is just above the box containing 2 mobiles.

5. There are odd number of Nokia phones.

6. The box of Xperia is just above box of Oppo.

7. The box of One plus contains one less mobile than that of box of Iphones. So, there is only (1) One plus mobile. And, case 2 would be rejected.

There are two boxes between the box of Samsung and box of Oppo.

Hence, two is the correct answer.

Given: Eight persons – A, B, C, D, E, F, G and H

Their designation – GM, DGM, AGM, Manager, Assistance Manager, Probationary Officer, Cashier and Clerk.

1. Only two persons are senior to D. Only three designations are there between A and F. G is senior to C. A is senior to the Assistant Manager of the company.

2. Number of persons who are senior to E is same as number of persons who are junior to H. E is senior to D. As more than four designations are there between H and B. So case-2 and case - 3 are eliminated.

As G is senior to C.

The final arrangement is:

Hence, A  is manager.

Given: Eight persons – A, B, C, D, E, F, G and H

Their designation – GM, DGM, AGM, Manager, Assistance Manager, Probationary Officer, Cashier and Clerk.

1. Only two persons are senior to D. Only three designations are there between A and F. G is senior to C. A is senior to the Assistant Manager of the company.

2. Number of persons who are senior to E is same as number of persons who are junior to H. E is senior to D. As more than four designations are there between H and B. So case-2 and case - 3 are eliminated.

As G is senior to C.

The final arrangement is:

Hence, C is just senior to H.

Given: Eight persons – A, B, C, D, E, F, G and H

Their designation – GM, DGM, AGM, Manager, Assistance Manager, Probationary Officer, Cashier and Clerk.

1. Only two persons are senior to D. Only three designations are there between A and F. G is senior to C. A is senior to the Assistant Manager of the company.

2. Number of persons who are senior to E is same as number of persons who are junior to H. E is senior to D. As more than four designations are there between H and B. So case-2 and case - 3 are eliminated.

As G is senior to C.

The final arrangement is:

Hence, D – AGM is the correct answer.

Given: Eight persons – A, B, C, D, E, F, G and H

Their designation – GM, DGM, AGM, Manager, Assistance Manager, Probationary Officer, Cashier and Clerk.

1. Only two persons are senior to D. Only three designations are there between A and F. G is senior to C. A is senior to the Assistant Manager of the company.

2. Number of persons who are senior to E is same as number of persons who are junior to H. E is senior to D. As more than four designations are there between H and B. So case-2 and case - 3 are eliminated.

As G is senior to C.

The final arrangement is:

Hence, 4 persons are senior to G.