Official Paper

KVS TGT Maths Official Paper (Held On 14 Feb 2023 Shift 1) (Previous Year Paper)

180 questions · 180 minutes · with answers · free

Language Proficiency (20 questions)

1

Rearrange the parts in correct order to make a meaningful sentence.

(a) tragedy on himself

(b) Hamlet brings

(c) at the right time

(d) by not taking the right decision

  1. ((a))

    (a) (d) (b) (c) 

  2. ((b))

    (c) (a) (b) (d) 

  3. ((c))

    (b) (a) (d) (c) 

  4. ((d))

    (d) (a) (c) (b) 

Show Answer
Answer: ((c))

(b) (a) (d) (c) 

The correct answer is Option 3.

 

Key Points

  • The sentence fragments need to be rearranged logically to form a meaningful sentence.
  • The correct arrangement is: (b) Hamlet brings (a) tragedy on himself (d) by not taking the right decision (c) at the right time.
  • This arrangement ensures proper flow and context, making the sentence grammatically correct and meaningful.
  • Thus, the correct order is: (b) (a) (d) (c).

Therefore, the correct answer is Option 3.

 

Correct Sentence: "Hamlet brings tragedy on himself by not taking the right decision at the right time."

 

Additional Information

  • (b) "Hamlet brings" – This is the beginning of the sentence and introduces the subject and action.
  • (a) "tragedy on himself" – This phrase follows logically as it explains what Hamlet brings upon himself.
  • (d) "by not taking the right decision" – This explains the cause of the tragedy mentioned earlier.
  • (c) "at the right time" – This adds detail about when the decision should have been made, completing the sentence meaningfully.
2

Change the following sentence from Active Voice to Passive Voice.

A volley of stones hit the police force.

  1. ((a))

    The police force is sure to be hit by a volley of stones. 

  2. ((b))

    It was a volley of stones that hit the police force. 

  3. ((c))

    The police force has been hit by a volley of stones. 

  4. ((d))

    The police force was hit by a volley of stones. 

Show Answer
Answer: ((d))

The police force was hit by a volley of stones. 

The correct answer is Option 4.

 

Key Points

  • To convert a sentence from active voice to passive voice, the subject and object of the sentence switch places.
  • In this case, the subject of the active voice sentence "A volley of stones" becomes the agent in the passive voice.
  • The object of the active voice sentence "the police force" becomes the subject in the passive voice.
  • The correct structure in the passive voice is "The police force was hit by a volley of stones."

Therefore, the correct answer is Option 4.

 

Correct Sentence: "The police force was hit by a volley of stones."

 

Additional Information

  • Option 1: "The police force is sure to be hit by a volley of stones." – This is incorrect because it changes the meaning of the original sentence by introducing the phrase "is sure to."
  • Option 2: "It was a volley of stones that hit the police force." – This is incorrect because it retains the active voice structure.
  • Option 3: "The police force has been hit by a volley of stones." – This is incorrect because it changes the tense of the sentence.
  • Option 4: "The police force was hit by a volley of stones." – This is correct because it is the accurate passive voice transformation of the original sentence.
3

Fill in the blank with the correct preposition.

The baby was clinging ________ her mother due to fear and anxiety.

  1. ((a))

    in

  2. ((b))

    from

  3. ((c))

    to

  4. ((d))

    with

Show Answer
Answer: ((c))

to

The correct answer is Option 3.

 

Key Points

  • The verb "clinging" is typically followed by the preposition "to."
  • This indicates attachment or holding on to someone or something for support or safety.
  • The context of the sentence suggests that the baby is seeking comfort and security from her mother.
  • Hence, "clinging to her mother" is the grammatically and contextually correct phrase.

Therefore, the correct answer is Option 3.

 

Correct Sentence: "The baby was clinging to her mother due to fear and anxiety."

 

Additional Information

  • Option 1: "in" – This preposition does not fit the context of the sentence. It does not convey the idea of attachment or holding on.
  • Option 2: "from" – This preposition typically indicates separation or origin, which is not appropriate here.
  • Option 4: "with" – While "with" indicates accompaniment, it does not convey the idea of physically holding on to someone or something.
4

Identify the correct tense form of the underlined part in the given sentence.

I had finished writing the letter when he arrived.

  1. ((a))

    Past Perfect Continuous 

  2. ((b))

    Simple Past 

  3. ((c))

    Present Perfect 

  4. ((d))

    Past Perfect 

Show Answer
Answer: ((d))

Past Perfect 

The correct answer is Option 4.

 

Key Points

  • The sentence contains two actions: "I had finished writing the letter" and "he arrived."
  • The action of finishing the letter occurred before the arrival, which makes it necessary to use the Past Perfect Tense to indicate the earlier action.
  • The structure of the Past Perfect tense is: had + past participle.
  • Here, "had finished" correctly represents the Past Perfect tense.

Therefore, the correct answer is Option 4.

 

Correct Explanation: The Past Perfect tense is used to emphasize that one action was completed before another action in the past. In this case, "I had finished writing the letter" happened before "he arrived."

 

Additional Information

  • Option 1: Past Perfect Continuous – This tense is used for actions that were ongoing in the past up to a certain point. However, "had finished" indicates a completed action, not a continuous one.
  • Option 2: Simple Past – This tense is used for actions completed in the past but does not show the sequence of two past events. Here, the sequence is important.
  • Option 3: Present Perfect – This tense is used for actions completed in the past with relevance to the present, which does not fit the context of the sentence.
  • Option 4: Past Perfect – This is the correct choice as it clearly shows the sequence of two actions in the past.
5

Change the following sentence from Direct Speech to Indirect Speech.

The wayfarer said to the policeman, “Which is the way to the railway station ?'

  1. ((a))

    The wayfarer asked the policeman which was the way to the railway station. 

  2. ((b))

    The wayfarer asked the policeman which the way to the railway station was. 

  3. ((c))

    The wayfarer asked the policeman the way to the railway station.  

  4. ((d))

    The wayfarer asked the policeman that which was the way to the railway station.  

Show Answer
Answer: ((b))

The wayfarer asked the policeman which the way to the railway station was. 

The correct answer is Option 2.

 

Key Points

  • When converting Direct Speech to Indirect Speech, interrogative sentences are transformed into assertive statements.
  • The question word "Which" is retained, but the sentence structure changes to follow the sequence of subject + verb.
  • In this case, the verb "is" changes to "was" to maintain tense consistency in Indirect Speech.
  • Option 2, "The wayfarer asked the policeman which the way to the railway station was," correctly follows these rules.

Therefore, the correct answer is Option 2.

 

Correct Sentence: "The wayfarer asked the policeman which the way to the railway station was."

 

Additional Information

  • Option 1: "The wayfarer asked the policeman which was the way to the railway station." – The placement of "was" is incorrect in this structure.
  • Option 3: "The wayfarer asked the policeman the way to the railway station." – This is correct grammatically but does not directly reflect the question format of the original sentence.
  • Option 4: "The wayfarer asked the policeman that which was the way to the railway station." – The inclusion of "that" is unnecessary and incorrect here.
6

Identify the part which contains an error.  

Beside being fined, (1) / the erring student (2) / was also expelled (3) / from the school. (4)

  1. ((a))

    1

  2. ((b))

    2

  3. ((c))

    3

  4. ((d))

    4

Show Answer
Answer: ((a))

1

The correct answer is Option 1.

 

Key Points

  • The error lies in the phrase "Beside being fined."
  • The word "Beside" means "next to" or "at the side of," which is incorrect in this context.
  • The correct word should be "Besides," which means "in addition to."
  • Thus, the error is located in part 1 of the sentence.

Therefore, the correct answer is Option 1.

 

Correct Sentence: "Besides being fined, the erring student was also expelled from the school."

 

Additional Information

  • Part 2: "the erring student" – This part of the sentence is grammatically correct and does not require any changes.
  • Part 3: "was also expelled" – This part of the sentence is grammatically correct and does not require any changes.
  • Part 4: "from the school" – This part of the sentence is grammatically correct and does not require any changes.
  • No error – This would be the correct option if there were no mistakes in the sentence, but there is an error in part 1.
7

Choose the word nearest in meaning to the given word. 

DERISIVE

  1. ((a))

    critical 

  2. ((b))

    emotional 

  3. ((c))

    angry 

  4. ((d))

    mocking 

Show Answer
Answer: ((d))

mocking 

The correct answer is Option 4.

 

Key Points

  • The word "derisive" refers to expressing contempt or ridicule.
  • Among the given options, the word "mocking" is closest in meaning to "derisive."
  • Other options, such as "critical," "emotional," and "angry," do not convey the same sense of ridicule or scorn.
  • Thus, the correct answer is Option 4.

 

Example Sentence: "The comedian’s derisive comments about the politician sparked controversy."

 

Additional Information

  • Critical: This refers to expressing disapproval or judgment, but it does not necessarily imply ridicule.
  • Emotional: This refers to being full of emotion or feelings, which is unrelated to the meaning of "derisive."
  • Angry: This refers to being filled with anger, which is different from the mocking or scornful tone of "derisive."
  • Mocking: This means making fun of someone or something in a scornful or contemptuous manner, which aligns with the meaning of "derisive."
8

Choose the word opposite in meaning to the given word. 

TRANQUIL

  1. ((a))

    rough 

  2. ((b))

    violent

  3. ((c))

    agitated

  4. ((d))

    peaceful

Show Answer
Answer: ((c))

agitated

The correct answer is Option 3.

 

Key Points

  • The word Tranquil means calm, peaceful, or free from disturbance.
  • An opposite of tranquil would convey a state of disturbance, agitation, or unrest.
  • Option 3: Agitated is the correct opposite of tranquil as it means disturbed or restless.
  • Other options, such as Rough or Violent, are not precise opposites of tranquil, while Peaceful is a synonym.

Therefore, the correct answer is Option 3.

 

Explanation: The word tranquil is used to describe a state of calm or serenity, and the opposite word, agitated, denotes a state of being disturbed or anxious.

 

Additional Information

  • Option 1: Rough – This describes a texture or surface and is not directly opposite to tranquil.
  • Option 2: Violent – While it suggests force or aggression, it does not directly contrast the calmness implied by tranquil.
  • Option 4: Peaceful – This is a synonym of tranquil, not an opposite.
9

Identify the Part of Speech of the underlined word.

Jogging is a not good exercise, especially for the senior citizens.

  1. ((a))

    Verb

  2. ((b))

    Adverb

  3. ((c))

    Noun

  4. ((d))

    Conjunction

Show Answer
Answer: ((c))

Noun

The correct answer is Option 3.

 

Key Points

  • In the given sentence, the underlined word "Jogging" is functioning as a noun.
  • When verbs like "jog" are used in their gerund form (adding "-ing"), they can function as nouns in a sentence.
  • In this case, "Jogging" is the subject of the sentence, and subjects are typically nouns.
  • Thus, the correct part of speech for "Jogging" is noun.

Therefore, the correct answer is Option 3.

 

Correct Explanation: In the sentence, "Jogging" is not functioning as a verb or an adverb. It is the subject of the sentence, which makes it a noun.

 

Additional Information

  • Option 1: Verb – This is incorrect because "Jogging" is not performing an action in the sentence.
  • Option 2: Adverb – This is incorrect because "Jogging" is not describing a verb, adjective, or another adverb.
  • Option 3: Noun – This is correct because "Jogging" is the subject of the sentence.
  • Option 4: Conjunction – This is incorrect because "Jogging" is not used to connect clauses or phrases.
10

Identify the clause in the underlined portion of the given sentence.

He who exercises daily leads a healthy life.

  1. ((a))

    Noun Clause 

  2. ((b))

    Adjective Clause 

  3. ((c))

    Principal Clause 

  4. ((d))

    Adverb Clause 

Show Answer
Answer: ((b))

Adjective Clause 

The correct answer is Option 2.

 

Key Points

  • The underlined portion of the sentence is "who exercises daily."
  • This clause provides additional information about the subject "He."
  • An Adjective Clause modifies a noun or pronoun, and here it describes the pronoun "He."
  • It begins with the relative pronoun "who", which is a marker of an Adjective Clause.

Therefore, the correct answer is Option 2 (Adjective Clause).

 

Explanation of Other Options:

  • Option 1 (Noun Clause): A Noun Clause acts as a noun in the sentence. However, the clause here describes a pronoun and does not function as a noun.
  • Option 3 (Principal Clause): The Principal Clause here is "He leads a healthy life." The underlined portion is a subordinate clause, not the principal one.
  • Option 4 (Adverb Clause): An Adverb Clause modifies verbs, adjectives, or adverbs, and usually provides information about time, reason, condition, or manner. The underlined clause does not fulfill this function.

 

Additional Information

  • Adjective Clauses are also called relative clauses, as they often begin with relative pronouns like who, which, that, whom, or whose.
  • They are used to provide more detail about a noun or pronoun in the sentence.
  • For example: "The book that she wrote is a bestseller."
  • In the given sentence, the Adjective Clause "who exercises daily" helps describe the pronoun "He."

निर्देशः नीचे दिए गए गद्यांश को ध्यानपूर्वक पढ़िए और उसके आधार पर दिए गए प्रश्न का उत्तर दीजिए :

समाचार-पत्रों की जनतंत्रीय व्यवस्था में विशेष भूमिका होती है। वे अभिव्यक्ति की स्वतंत्रता के जीवंत उदाहरण हैं । समाचार पत्र अपने संपादकीय तथा समसामयिक विषयों पर लिखे गए अन्य लेखों के द्वारा पाठकों के चिंतन को दिशा देते हैं, उसे जागरुक बनातें हैं, नागरिक के रूप में उत्तरदायित्व का बोध कराते हैं । इस प्रकार उसे जनतंत्र में सक्रिय सहभागी बनाते हैं ।

11

समाचार-पत्र से पाठक को क्या पढ़कर दिशा मिलती है? 

  1. ((a))

    पुस्तक समीक्षा

  2. ((b))

    खेल-समाचार

  3. ((c))

    संपादकीय

  4. ((d))

    विज्ञापन

Show Answer
Answer: ((c))

संपादकीय

समाचार-पत्र से पाठक को "संपादकीय" पढ़कर दिशा मिलती है।

Key Points

  • गद्यांश  के अनुसार  समाचार पत्र अपने संपादकीय तथा समसामयिक विषयों पर लिखे गए,
  • अन्य लेखों के द्वारा पाठकों के चिंतन को दिशा देते हैं।

Additional Information 

गद्यांश  के अनुसार -

  • जनतांत्रिक व्यवस्था में समाचार-पत्र की  विशेष भूमिका है।
  • संपादकीय और समसामयिक विषयों पर प्रकाशित समाचार-पत्र के लेख पाठक को "जागरुक" बनाते हैं।
  • समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में 'सक्रिय सहभागी" बनाते हैं।
12

संपादकीय और समसामयिक विषयों पर प्रकाशित समाचार-पत्र के लेख पाठक को बनाते हैं :  

  1. ((a))

    शांतिप्रिय

  2. ((b))

    निर्भीक

  3. ((c))

    बौद्धिक

  4. ((d))

    जागरुक

Show Answer
Answer: ((d))

जागरुक

संपादकीय और समसामयिक विषयों पर प्रकाशित समाचार-पत्र के लेख पाठक को "जागरुक" बनाते हैं। 

Key Points

  • गद्यांश  के अनुसार  समाचार पत्र अपने सम्पादकीय तथा समसामयिक विषयों पर लिखे,
  • अन्य लेखों के माध्यम से पाठकों की सोच को दिशा देते हैं, और जागरूक बनाते हैं।

Additional Information

गद्यांश  के अनुसार -

  • जनतांत्रिक व्यवस्था में समाचार-पत्र की  विशेष भूमिका है।
  • समाचार पत्र अपने सम्पादकीय तथा समसामयिक विषयों पर लिखे

अन्य लेखों के माध्यम से पाठकों की सोच को दिशा देते हैं, जागरूक करते हैं।

  • समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में 'सक्रिय सहभागी" बनाते हैं।
13

जनतांत्रिक व्यवस्था में निम्नलिखित में से किसकी विशेष भूमिका है ? 

  1. ((a))

    रेडियो

  2. ((b))

    टेलीविज़न

  3. ((c))

    समाचार-पत्र

  4. ((d))

    कंप्यूटर

Show Answer
Answer: ((c))

समाचार-पत्र

दिए गए विकल्पों में से जनतांत्रिक व्यवस्था में 'समाचार-पत्र' की विशेष भूमिका है।

Key Points

  • जनतांत्रिक व्यवस्था में समाचार पत्रों की विशेष भूमिका होती है।
  • वह अभिव्यक्ति की आजादी की जीती-जागती मिसाल हैं।
  • जनतांत्रिक का अर्थ- जनतंत्र संबंधी। ( जन - जनता )

Additional Information

गद्यांश  के अनुसार -

  • जनतांत्रिक व्यवस्था में समाचार-पत्र की  विशेष भूमिका है।
  • समाचार पत्र अपने सम्पादकीय तथा समसामयिक विषयों पर लिखे,
  • अन्य लेखों के माध्यम से पाठकों की सोच को दिशा देते हैं, जागरूक करते हैं।
  • समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में 'सक्रिय सहभागी" बनाते हैं।
14

समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में क्या बनाते हैं ? 

  1. ((a))

    मतदाता

  2. ((b))

    ईमानदार मतदाता

  3. ((c))

    राजनेता

  4. ((d))

    सक्रिय सहभागी

Show Answer
Answer: ((d))

सक्रिय सहभागी

समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में "सक्रिय सहभागी" बनाते हैं।  

Key Points

  • समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में 'सक्रिय सहभागी" बनाते हैं।
  • जनतंत्र का अर्थ - ऐसा शासन जो देश की जनता के प्रतिनिधियों द्वारा चलाया जाता है, लोकतंत्र।

Additional Information

गद्यांश  के अनुसार -

  • जनतांत्रिक व्यवस्था में समाचार-पत्र की  विशेष भूमिका है।
  • समाचार पत्र अपने सम्पादकीय तथा समसामयिक विषयों पर लिखे,
  • अन्य लेखों के माध्यम से पाठकों की सोच को दिशा देते हैं, जागरूक करते हैं।
  • समाचार-पत्र पाठकों को नागरिक के रूप में उत्तरदायित्व का बोध कराकर जनतंत्र में 'सक्रिय सहभागी" बनाते हैं।
15

निम्नलिखित में कौन-सा युग्म असंगत है ? 

  1. ((a))

    जीवंत - सजीव

  2. ((b))

    सामयिक - असामयिक

  3. ((c))

    उत्तरदायित्व - अनुत्तरदायित्व

  4. ((d))

    सक्रिय - निष्क्रिय

Show Answer
Answer: ((a))

जीवंत - सजीव

दिए गए विकल्पों में से "जीवंत - सजीव" युग्म असंगत है । 

Key Points

  • अन्य विकल्पों में विलोम शब्द युग्म है।
  • अतः 'जीवंत'  का विलोम शब्द 'सुस्त' या 'मृत' है।
  • जबकि 'सजीव' शब्द 'जीवंत' का पर्यायवाची शब्द है।

Additional Information

  • विलोम शब्द - जो शब्द किसी दूसरे शब्द का उल्टा अर्थ बताते हैं,
  • उन्हें विलोम शब्द या विपरीतार्थक शब्द या विरुद्धार्थी शब्द कहते है।

उदाहरण - 

शब्दविलोम शब्द
उत्थानपतन
आकर्षणविकर्षण
शीतऊष्ण
क्षणिकशाश्वत
हर्षशोक
16

निम्नलिखित तत्सम/तद्भव शब्द-युग्मों में असंगत है : 

  1. ((a))

    वायु - बयार 

  2. ((b))

    अक्षर - आखर

  3. ((c))

    कार्य - काज

  4. ((d))

    कर्ण - कर्म

Show Answer
Answer: ((d))

कर्ण - कर्म

दिए गए विकल्पों में से "कर्ण - कर्म" तत्सम/तद्भव शब्द-युग्मों में असंगत है।

Key Points

  • कर्ण तत्सम शब्द है, 'कर्ण' का तद्भव 'कान' होगा।
  • सही युग्म - कर्ण - कान
  • 'कर्म' तत्सम शब्द है, इसका तद्भव शब्द 'काम' है।

Additional Information

  • तत्सम शब्द- ऐसे शब्द जिनकी उत्पत्ति संस्कृत भाषा में हुई ओर वे हिन्दी भाषा में बिना,
  • किसी परिवर्तन के प्रयोग में आने लगे, ऐसे शब्द तत्सम शब्द कहलाते हैं।
  • जैसे- कवि, माता, विद्या, नदी, फल, पुष्प, पुस्तक, पृथ्वी, क्षेत्र, कार्य, मृत्यु आदि।
  • तद्भव शब्द- ऐसे शब्द जो संस्कृत भाषा से उत्पन्न होते हैं, लेकिन वो रूप बदलकर हिन्दी में आ गए हों, ऐसे शब्द तद्भव शब्द कहलाते हैं।
  • जैसे- दुग्ध —> दूध
  • अग्नि —-> आग
  • कार्य —> काम
  • कर्पूर —> कपूर
17

निम्नलिखित में गुणवाचक विशेषण नहीं है :

  1. ((a))

    गोल

  2. ((b))

    आधा

  3. ((c))

    बलवान

  4. ((d))

    रोगी

Show Answer
Answer: ((b))

आधा

दिए गए विकल्पों में से " आधा" गुणवाचक विशेषण नहीं है। 

Key Points

  • अतः "आधा" निश्चितसंख्या-वाचक ( गणनावाचक) विशेषण है।
  • जिससे किसी निश्र्चित संख्या का ज्ञान हो, वह निश्चित संख्यावाचक विशेषण है।
  • 'गणनावाचक' निश्चितसंख्या-वाचक विशेषण का एक प्रकार ( भेद ) है।
  • गणनावाचक विशेषण- जो विशेषण गिनती या गणना का बोध कराएँ।
  • गणनावाचक विशेषणों के दो भेद हैं-
  • पूणांक-बोधक - एक, दो, चार, सौ, हज़ार ।
  • अपूर्णांक-बोधक - पाव, आधा, पौन, सवा ।

Additional Information

  • विशेषण शब्द का अर्थ है- विशेषण की विशेषता को सूचित या प्रकट करने वाला शब्द।
  • संज्ञा या सर्वनाम शब्दों की विशेषता बताने वाले शब्दों को विशेषण कहते हैं।

विशेषण के भेद  -

गुणवाचक विशेषण - जिस विशेषण से संज्ञा या सर्वनाम के गुण या दोष का पता चलता है, उसे गुणवाचक विशेषण कहते हैं। ये विशेषण भाव, रंग, दशा, आकार, समय, स्थान, काल आदि से सम्बन्धित होते है। जैसे- अच्छा, बुरा, सफेद, काला, रोगी, मोटा, पतला, लंबा, चौड़ा, नया, पुराना, ऊँचा, मीठा, चीनी, नीचा, प्रातःकालीन आदि।
परिमाणवाचक विशेषण - जिन विशेषण शब्दों से किसी वस्तु के परिमाण, मात्रा, माप या तोल का पता चले, वे परिमाणवाचक विशेषण कहलाते हैं। इसके दो भेद हैं-
(1) निश्चित परिमाणवाचक - दस क्विंटल, तीन किलो, डेढ़ मीटर आदि।
(2) अनिश्चित परिमाणवाचक - थोड़ा, इतना, कुछ, ज्यादा, बहुत, अधिक, कम, तनिक, थोड़ा, इतना, जितना, ढेर सारा आदि।
संख्यावाचक विशेषण - जिन विशेषण शब्दों से संख्या का बोध हो वे संख्यावाचक विशेषण कहलाते हैं। इसके दो भेद हैं -
(1)  निश्चित संख्यावाचक - दो, तीन, ढाई, पहला, दूसरा, इकहरा, दुहरा, तीनों चारों, दर्ज���, जोड़ा, प्रत्येक आदि।
(2) अनिश्चित संख्यावाचक - कई, कुछ, काफी, कम, ज्यादा, बहुत आदि।
सार्वनामिक विशेषण -  जो सर्वनाम शब्द संज्ञा के पहले आकर विशेषण का काम करते हैं, उन्हे सार्वनामिक विशेषण कहते हैं। जैसे - यह विद्यालय, वह बालक, वह खिलाड़ी आदि।
18

निम्नलिखित में 'अंगूठा दिखाना' मुहावरे का सही अर्थ है : 

  1. ((a))

    चिढ़ाना

  2. ((b))

    धोखा देना

  3. ((c))

    मौके पर इंकार करना

  4. ((d))

    संकेत करना

Show Answer
Answer: ((c))

मौके पर इंकार करना

दिए गए विकल्पों में से 'अंगूठा दिखाना' मुहावरे का सही अर्थ "मौके पर इंकार करना"  है।

Key Points

  • वाक्य प्रयोग - जिस पर ‌‌‌मै सबसे ज्यादा भरोसा करता था मुसीबत मे उसी मित्र ने मुझे अंगुठा दिखा दिया ।

अन्य विकल्प - 

मुहावराअर्थवाक्य प्रयोग
अँगूठा नचानाचिढानाअपने गुरु के सामने अँगूठा नचाना ठीक नही है।
अन्धा बनानाधोखा देनामायामृग ने रामजी तक को अन्धा बनाया था। इस माया के पीछे मौजीलाल अन्धे बने तो क्या।
इशारा करनासंकेत करनायहां एक गंभीर बात की तरफ इशारा करना जरूरी है।

Additional Information

  • मुहावरा एक ऐसा वाक्य होता है जो वाक्य की रचना करने पर अपना एक अलग अर्थ या विशेष अर्थ प्रकट करता है,
  • इनका प्रयोग करने से भाषा,आकर्षक, प्रभावपूर्ण तथा रोचक बन जाती है।

कुछ मुहावरे -

मुहावरेअर्थवाक्य प्रयोग
खून का प्यासाजानी दुश्मन होनाउसकी क्या बात कर रहे हो, वह तो मेरे खून का प्यासा हो गया है।
गढ़ फतह करनाकठिन काम करनाआई.पी.एस पास करके दीक्षा ने सचमुच गढ़ फतह कर लिया।
डंका बजानाप्रभाव जमानाभारत ने सब देशों की टीमों को हरा कर अपना डंका बजा दिया।
घोड़े बेचकर सोनाबेफिक्र होनाबेटी तो ब्याह दी। अब क्या, घोड़े बेचकर सोओ।
दाल में काला होनासंदेह होनाहम लोगों की ओट में ये जिस तरह धीरे-धीरे बातें कर रहें है, उससे मुझे दाल में काला लग रहा है।
19

निम्नलिखित में व्यंजन-संधि वाला शब्द नहीं है :

  1. ((a))

    दिग्गज

  2. ((b))

    कपीश

  3. ((c))

    जगन्नाथ

  4. ((d))

    जगदीश

Show Answer
Answer: ((b))

कपीश

दिए गए विकल्पों में से "कपीश" व्यंजन-संधि वाला शब्द नहीं है।

Key Points

  • कपीश शब्द में 'स्वर संधि' है।
  • संधि विच्छेद =कपि + ईश ( इ + ई = ई)
  • अतः ( इ + ई = ई)  स्वर के साथ स्वर का मेल होता है,
  • तब जो परिवर्तन होता है वह स्वर संधि कहलाता है।

Additional Information

  • दो वर्णों के मेल से होने वाले विकार को संधि कहते हैं।
  • दो शब्दों के मेल से बने शब्द को पुनः अलग अलग करने को संधि विच्छेद कहते हैं।

संधि के तीन प्रकार होते हैं- 

संधिपरिभाषाउदाहरण
स्वर संधिजब स्वर के साथ स्वर का मेल होता है तब जो परिवर्तन होता है वह स्वर संधि कहलाता है।- विद्या+आलय -विद्यालय
व्यंजन संधिव्यंजन वर्ण के साथ स्वर वर्ण या व्यंजन वर्ण अथवा स्वर वर्ण के साथ व्यंजन वर्ण के मेल से जो विकार उत्पन हो, उसे ‘व्यंजन संधि’ कहते हैं।- दिक+अंबर-दिगंबर - अभी+सेक- अभिषेक
विसर्ग संधिजब  विसर्ग के साथ स्वर या व्यंजन आ जाए तब जो परिवर्तन होता है ,वह विसर्ग संधि कहलाता है।- मन: + अनुकूल = मनोनुकूल - नि: + पाप =निष्पाप
20

निम्नलिखित में जातिवाचक संज्ञा शब्द नहीं है : 

  1. ((a))

    महामंडल

  2. ((b))

    मनुष्य

  3. ((c))

    पक्षी

  4. ((d))

    पशु

Show Answer
Answer: ((a))

महामंडल

दिए गए विकल्पों में से "महामंडल" जातिवाचक संज्ञा शब्द नहीं है। 

Key Points

  • 'महामंडल' लोगों के एक ही समूह (सभा) का नाम है,
  • इस नाम से कोई दूसरा समूह सूचित नहीं होता।
  • अतः महामंडल  व्यक्तिवाचक संज्ञा है।
  • जिस शब्द से किसी विशेष व्यक्ति , वस्तु या स्थान के नाम का बोध हो,
  • उसे व्यक्तिवाचक संज्ञा कहते हैं।

Additional Information 

  • संज्ञा- संज्ञा उस विकारी शब्द को कहते हैं जिससे किसी वस्तु भाव और जीव के नाम का बोध हो,
  • मतलब कि किसी प्राणी, वस्तु, स्थान, भाव के नाम को संज्ञा कहते हैं।

संज्ञा के पांच भेद होते हैं- 

संज्ञापरिभाषाउदाहरण
व्यक्तिवाचक संज्ञाजिस शब्द से किसी विशेष व्यक्ति , वस्तु या स्थान के नाम का बोध हो उसे व्यक्तिवाचक संज्ञा कहते हैं।धर्मेश, सुरेश, गीता, रामायण, मुंबई, दिल्ली, ताजमहल, आदि।
भाववाचक संज्ञाजिन शब्दों से किसी प्राणी या पदार्थ के गुण, भाव, स्वभाव या अवस्था का बोध होता है, उन्हें भाववाचक संज्ञा कहते हैं।थकान, मिठास, बुढ़ापा, गरीबी, आजादी, हँसी, चढ़ाई, साहस, वीरता आदि।
जातिवाचक संज्ञाजिस शब्द से एक जाति के सभी प्राणियों अथवा वस्तुओं का बोध हो उसे जातिवाचक संज्ञा कहते हैं।बच्चा ,जानवर, नदी, अध्यापक, बाजार, पहाड़, खिड़की, मनुष्य, पशु, पक्षी,  आदि।
समूहवाचक संज्ञाजिस संज्ञा शब्द से वस्तुओं के समूह का या समुदाय का बोध हो उसे समूहवाचक संज्ञा कहते हैं।व्यक्तियों का समूह- भीड़, जनता, सभा, कक्षा। वस्तुओं का समूह- गुच्छा, कुंज, मण्डल, घौद।
द्रव्यवाचक संज्ञाजिन संज्ञा शब्दों से किसी धातु, द्रव या पदार्थ का बोध हो, उन्हें द्रव्यवाचक संज्ञा कहते है।ताम्बा, पीतल, चावल, घी, तेल, सोना, लोहा आदि।

GK, LR & Computer (20 questions)

21

Who among the following authors was been selected for the Sahitya Akademi Award, 2022 in Bodo language ? 

  1. ((a))

    Rashmi Choudhury 

  2. ((b))

    Sunil Phukan Basumatary 

  3. ((c))

    Nandeswar Daimary 

  4. ((d))

    Adaram Basumatary 

Show Answer
Answer: ((a))

Rashmi Choudhury 

The correct answer is Rashmi Choudhury.

Key Points

  • Sahitya Akademi Award 2022:
  • The Sahitya Akademi Award is one of the most prestigious literary honors in India, presented annually by the Sahitya Akademi (India's National Academy of Letters).
  • The award recognizes and honors outstanding literary works in the 24 recognized Indian languages, including Bodo.
  • Rashmi Choudhury:
  • Rashmi Choudhury was selected for the Sahitya Akademi Award 2022 in the Bodo language category.
  • She received the award for her notable contribution to Bodo literature, showcasing her exceptional talent in storytelling and creative writing.
  • Her work exemplifies the rich cultural heritage and linguistic diversity of the Bodo community.

Additional Information

  • Sunil Phukan Basumatary:
  • Although Sunil Phukan Basumatary is a recognized figure in Bodo literature, he was not selected for the Sahitya Akademi Award 2022.
  • His contributions are significant, but this year's honor was awarded to Rashmi Choudhury for her superior work.
  • Nandeswar Daimary:
  • Nandeswar Daimary is another prolific author in the Bodo literary community.
  • While he has made important contributions to Bodo literature, he was not the recipient of the Sahitya Akademi Award 2022.
  • Adaram Basumatary:
  • Adaram Basumatary is an influential writer in Bodo literature, but he was not recognized with the Sahitya Akademi Award for 2022.
  • His work remains celebrated, but Rashmi Choudhury's contribution stood out for this particular year.

Important Points

  • The Bodo language is one of the 22 scheduled languages of India and has a rich literary tradition.
  • The Sahitya Akademi Award plays a crucial role in promoting and preserving the linguistic and cultural heritage of India's diverse languages.
  • Rashmi Choudhury's recognition highlights the importance of regional languages and their contribution to India's literary landscape.
  • It serves as an encouragement for emerging writers in the Bodo language to contribute to literature and cultural preservation.
22

Which of the following cities in the world is also known as the ‘Peace Capital' ? 

  1. ((a))

    Athens 

  2. ((b))

    St Petersburg 

  3. ((c))

    Geneva 

  4. ((d))

    Jerusalem

Show Answer
Answer: ((c))

Geneva 

The correct answer is Geneva.

Key Points

  • Geneva:
  • Geneva, located in Switzerland, is often referred to as the 'Peace Capital' due to its historical role in fostering global diplomacy and peace initiatives.
  • The city hosts a significant number of international organizations, including the United Nations Office at Geneva (UNOG) and the International Committee of the Red Cross (ICRC).
  • It has been a center for human rights, humanitarian efforts, and multilateral negotiations, contributing to its reputation as a hub for international peace.
  • Geneva is also home to the Geneva Conventions, a series of treaties that set standards for international law regarding humanitarian treatment during wartime.
  • The presence of the World Health Organization (WHO) and World Trade Organization (WTO) further underscores its importance in global governance and peaceful collaboration.

Additional Information

  • Athens:
  • Athens, the capital of Greece, is renowned as the cradle of Western civilization and democracy.
  • It played a pivotal role in ancient philosophy, arts, and sciences but is not specifically associated with peace initiatives on a global scale.
  • While Athens contributed significantly to human thought and governance, its historical legacy is tied more to intellectual and cultural achievements than diplomacy.
  • St. Petersburg:
  • St. Petersburg, a major Russian city, is celebrated for its rich cultural heritage and architectural beauty.
  • It has a history of political and social significance but is not widely recognized as a center for peace or international diplomacy.
  • The city’s historical prominence is more closely linked to imperial Russia and artistic contributions rather than peace-building efforts.
  • Jerusalem:
  • Jerusalem, a city of immense religious significance, is central to Judaism, Christianity, and Islam.
  • While it is historically important, it has often been a site of conflict rather than a symbol of peace due to its contested status and geopolitical challenges.
  • Jerusalem’s identity is tied to its spiritual and historical heritage rather than its role in fostering global diplomacy or peace.

Important Points

  • Geneva’s reputation as the 'Peace Capital' is reinforced by its neutrality and commitment to global cooperation, which are hallmarks of Swiss foreign policy.
  • The city has hosted numerous peace talks, negotiations, and international conferences aimed at resolving global conflicts.
  • Key institutions like the United Nations Human Rights Council (UNHRC) and the World Economic Forum (WEF) further solidify Geneva’s standing as a center for peaceful dialogue and international collaboration.
23

The provision related to which of the following Commissions was inserted into the Indian Constitution through the Constitution (Ninety-ninth) Amendment Act, 2014, which was later struck down by the Supreme Court ? 

  1. ((a))

    Planning Commission 

  2. ((b))

    National Commission for Minorities 

  3. ((c))

    National Judicial Appointment Commission 

  4. ((d))

    Commission of Inquiry 

Show Answer
Answer: ((c))

National Judicial Appointment Commission 

The correct answer is National Judicial Appointment Commission (NJAC).

Key Points

  • National Judicial Appointment Commission (NJAC):
  • The NJAC was a body proposed to replace the existing Collegium System for the appointment of judges to the higher judiciary, i.e., the Supreme Court and High Courts of India.
  • The NJAC was introduced through the Constitution (Ninety-ninth Amendment) Act, 2014, along with the National Judicial Appointments Commission Act, 2014.
  • The NJAC aimed to bring transparency and accountability in the appointment process of judges.
  • It proposed a six-member commission comprising the Chief Justice of India, two senior-most Supreme Court judges, the Union Minister of Law and Justice, and two eminent persons appointed by a committee consisting of the Prime Minister, the Chief Justice of India, and the Leader of the Opposition in the Lok Sabha.
  • However, in 2015, the Supreme Court struck down the NJAC through a landmark judgment, declaring it unconstitutional. The Court ruled that the NJAC Act infringed upon the independence of the judiciary, a basic feature of the Constitution.
  • Following this judgment, the Collegium System, where senior judges recommend appointments and transfers of judges, was reinstated.

Additional Information

  • Planning Commission:
  • The Planning Commission was an institution in the Government of India responsible for formulating India's Five-Year Plans and allocating resources to different sectors for economic development.
  • It was established in 1950 and replaced by the NITI Aayog in 2015 to bring greater flexibility, decentralization, and focus on cooperative federalism.
  • It had no connection with the Constitution (Ninety-ninth) Amendment Act, 2014.
  • National Commission for Minorities:
  • The National Commission for Minorities (NCM) was established in 1992 under the National Commission for Minorities Act, 1992, to safeguard the interests of religious and linguistic minorities in India.
  • It is a statutory body, not a constitutional body, and has no relevance to the NJAC or the Constitution (Ninety-ninth) Amendment Act, 2014.
  • Commission of Inquiry:
  • The Commission of Inquiry refers to investigative bodies constituted under the Commission of Inquiry Act, 1952, to investigate specific matters of public importance.
  • These commissions are temporary and issue reports on various issues but are unrelated to the Constitution (Ninety-ninth) Amendment Act, 2014.

Important Points

  • The Collegium System, reinstated after the NJAC was struck down, has been criticized for its lack of transparency and accountability, though it is considered essential to maintaining judicial independence.
  • The Supreme Court’s judgment striking down the NJAC reinforced the concept of the "basic structure doctrine," which prohibits Parliament from amending the Constitution in a way that destroys its fundamental features.
  • The debate surrounding the NJAC highlights the ongoing tension between the independence of the judiciary and the need for greater transparency in judicial appointments.
24

Consider the following statements :

(a) A Government of India initiative - India International Skill Centre (IISC) Network - is fee-based market driven model.

(b) IISC Network caters to the needs of Indian Companies demanding foreign manpower and expertise.

Choose the correct answer from the codes below :

  1. ((a))

    (a) is correct but (b) is wrong 

  2. ((b))

    (a) is wrong but (b) is correct 

  3. ((c))

    Both (a) and (b) are correct 

  4. ((d))

    Neither (a) nor (b) are correct  

Show Answer
Answer: ((a))

(a) is correct but (b) is wrong 

The Correct Answer is Option 1: (a) is correct but (b) is wrong 

Key Points

  • Statement (a): A Government of India initiative - India International Skill Centre (IISC) Network - is fee-based market-driven model:
  • This statement is correct.
  • The India International Skill Centre (IISC) Network is an initiative by the Government of India aimed at providing skill training and certification to enhance the employability of Indians in the global workforce.
  • The program operates on a fee-based and market-driven model, meaning that participants pay for the training and certification services, and the courses are designed based on the demand for specific skills in the international market.
  • This model ensures that the training provided aligns with global labor market requirements, increasing the chances of employment for Indian workers overseas.
  • Statement (b): IISC Network caters to the needs of Indian Companies demanding foreign manpower and expertise:
  • This statement is incorrect.
  • The IISC Network primarily focuses on equipping Indian workers with skills required for international employment opportunities. It does not cater to the needs of Indian companies seeking foreign manpower or expertise.
  • Instead, it is designed to address the skill gaps in Indian workers and prepare them for jobs in foreign countries, thereby contributing to India's global workforce mobility.
  • The program aims to enhance the global employability of Indians rather than addressing domestic requirements for foreign manpower or expertise.

Additional Information

  • India International Skill Centre (IISC) Network:
  • The IISC Network is part of the Skill India Mission, which was launched to improve the skill levels of Indian workers and prepare them for global employment opportunities.
  • It serves as a bridge between skilled Indian manpower and international employers, ensuring the workforce meets global standards.
  • Objectives of IISC Network:
  • Provide internationally relevant skill training to Indian workers.
  • Facilitate certification that is recognized globally.
  • Enhance the mobility of Indian workers to international labor markets.
  • Key Features:
  • Training programs are aligned with international standards.
  • Focus on sectors like healthcare, construction, hospitality, and others where there is a global demand for skilled manpower.
  • Operates in collaboration with industry partners and international employers.
25

Consider the following statements regarding states in India

(a) Nagaland was created as a separate state in 1963

(b) Manipur and Mizoram were granted statehood in 1987

(c) Tripura and Meghalaya were granted statehood in 1972

Choose the correct answer from the codes below :

  1. ((a))

    only (a) 

  2. ((b))

    only (a) and (b) 

  3. ((c))

    only (a) and (c)  

  4. ((d))

    only (c) 

Show Answer
Answer: ((c))

only (a) and (c)  

The Correct answer is Option 3 - only (a) and (c)

Key Points

  • (a) Nagaland was created as a separate state in 1963:
  • This statement is correct.
  • Nagaland was officially recognized as the 16th state of India on December 1, 1963.
  • Prior to its statehood, Nagaland was a district within Assam, and due to longstanding demands by the Naga people for autonomy, it was granted statehood.
  • The creation of Nagaland was aimed at addressing the unique cultural identity and aspirations of the Naga people.
  • (b) Manipur and Mizoram were granted statehood in 1987:
  • This statement is incorrect.
  • While Mizoram was granted statehood in 1987, Manipur became a full-fledged state much earlier, in 1972.
  • Mizoram transitioned from being a Union Territory to a state on February 20, 1987, following the Mizoram Accord of 1986.
  • On the other hand, Manipur was part of the North-Eastern Frontier Agency (NEFA) and became a Union Territory in 1956 before being elevated to statehood on January 21, 1972.
  • (c) Tripura and Meghalaya were granted statehood in 1972:
  • This statement is correct.
  • Tripura and Meghalaya were both officially granted statehood on January 21, 1972, along with Manipur.
  • Before statehood, Tripura was a Union Territory, and Meghalaya was part of Assam with partial autonomy as an Autonomous State.
  • The creation of these states was part of efforts to address the unique cultural and administrative needs of the northeastern region of India.

Additional Information

  • State Formation in India:
  • India underwent significant reorganization of its states post-independence, largely influenced by linguistic, cultural, and administrative factors.
  • The States Reorganization Act of 1956 marked a major milestone, reorganizing states based on linguistic lines.
  • Northeastern Region Statehood:
  • The northeastern region of India saw the creation of several states to address the distinct cultural and ethnic identities of its communities.
  • States like Nagaland, Manipur, Meghalaya, Mizoram, and Tripura were created to ensure better governance and preserve the unique heritage of the region.
  • Timeline of Statehood in Northeast:
  • 1963: Nagaland became a state.
  • 1972: Manipur, Meghalaya, and Tripura gained statehood.
  • 1987: Mizoram and Arunachal Pradesh became states.
  • Impact of Statehood:
  • Statehood allowed these regions greater administrative autonomy and representation in India's federal structure.
  • It also provided a platform for addressing regional aspirations and developmental needs.
26

What are jet streams ? 

  1. ((a))

    One of the techniques of land formation within the shelter belt method of soil conservation 

  2. ((b))

    An apparant force caused by the earths rotation 

  3. ((c))

    Tidal force experienced by mangrove vegetation  

  4. ((d))

    Narrow belt of high altitude westerly winds 

Show Answer
Answer: ((d))

Narrow belt of high altitude westerly winds 

The correct answer is Narrow belt of high altitude westerly winds.

Key Points

  • Jet Streams:
  • Jet streams are narrow bands of strong winds that flow from west to east at high altitudes in the Earth's atmosphere, typically in the upper troposphere and lower stratosphere.
  • These winds can reach speeds of up to 200-400 km/h and play a crucial role in influencing global weather patterns and the movement of weather systems.
  • The main types of jet streams are the polar jet stream and the subtropical jet stream, both of which occur in different regions of the atmosphere.
  • Jet streams are caused by the temperature contrast between polar and tropical regions, which generates pressure differences and results in the formation of these high-speed winds.
  • They are critical for aviation, as flying with or against these winds can significantly impact fuel consumption and flight duration.

Additional Information

  • Incorrect Options:
  • One of the techniques of land formation within the shelter belt method of soil conservation:
  • This is incorrect as jet streams are atmospheric phenomena and have no direct connection to soil conservation or shelter belts.
  • Shelter belts are rows of trees or shrubs planted to reduce wind erosion and protect soil, crops, and settlements. They are a part of land management practices, not atmospheric processes.
  • An apparent force caused by the Earth's rotation:
  • This refers to the Coriolis force, which is a pseudo-force caused by the Earth's rotation. While the Coriolis force influences the direction of jet streams, it is not what defines a jet stream itself.
  • Jet streams are formed due to temperature gradients, not directly by the Coriolis effect.
  • Tidal force experienced by mangrove vegetation:
  • This is incorrect as tidal forces are gravitational forces exerted by celestial bodies (like the Moon and Sun) on Earth's water bodies and have no relation to jet streams.
  • Mangrove vegetation adapts to tidal forces in coastal areas, but this is unrelated to high-altitude atmospheric winds.

Important Points

  • Jet streams significantly influence weather systems, including the formation and movement of cyclones, anticyclones, and monsoons.
  • They are also a vital factor in the development of the El Niño and La Niña phenomena, which affect global climate patterns.
  • Jet streams are most prominent during the winter months when the temperature contrast between polar and tropical regions is greatest.
  • Understanding jet streams is essential for weather forecasting and climate studies, as they can affect precipitation patterns, storm tracks, and temperature variations.
  • In aviation, pilots use jet streams for faster travel on eastward routes, while avoiding them on westward routes to conserve fuel and time.
27

Consider the following statements regarding Nayan Moni Saikia :

(a) She is an Arjuna Awardee, 2022

(b) She is a Gold Medal (Team) winner in Commonwealth Games 2022

(c) She is a Silver Medal (Team) winner in Asian Championship, 2018

Identify the correct answer from the codes given below :

  1. ((a))

    (a) only 

  2. ((b))

    (a) and (b) only 

  3. ((c))

    (b) and (c) only 

  4. ((d))

    (a) and (c) only 

Show Answer
Answer: ((b))

(a) and (b) only 

The Correct answer is option 2: (a) and (b) only.

Key Points

  • (a) She is an Arjuna Awardee, 2022:
  • This statement is correct.
  • Nayan Moni Saikia, an accomplished lawn bowls player, was conferred the prestigious Arjuna Award in 2022. The Arjuna Award is one of the highest honors in Indian sports, recognizing outstanding achievements by athletes in their respective fields.
  • Her contributions to the sport, especially her remarkable performances at international tournaments, made her a deserving recipient of this honor.
  • (b) She is a Gold Medal (Team) winner in Commonwealth Games 2022:
  • This statement is correct.
  • Nayan Moni Saikia was part of the Indian Women's Lawn Bowls team that created history by winning the Gold Medal at the 2022 Commonwealth Games held in Birmingham, UK.
  • This victory marked a significant milestone for India, as it was the country's first-ever medal in lawn bowls at the Commonwealth Games.
  • The team defeated South Africa in the final match to secure the gold medal, showcasing excellent teamwork and skill.
  • (c) She is a Silver Medal (Team) winner in Asian Championship, 2018:
  • This statement is incorrect.
  • While Nayan Moni Saikia has participated in various international tournaments, there is no verified record of her winning a Silver Medal in the Team event at the Asian Championship in 2018.
  • It is essential to cross-check such details with credible sources to ensure accuracy.
  • Her most notable achievements are associated with the Commonwealth Games and the Arjuna Award.

Additional Information

  • About Nayan Moni Saikia:
  • Nayan Moni Saikia hails from Assam, India, and is a professional lawn bowls player.
  • She has been an integral part of the Indian Women's Lawn Bowls team and has represented the country in multiple international events.
  • Arjuna Award:
  • The Arjuna Award is presented annually by the Ministry of Youth Affairs and Sports, Government of India, to recognize exceptional performances by Indian athletes in various sports disciplines.
  • The award includes a bronze statuette of Arjuna, a certificate, and a cash prize.
  • India's Historic Gold Medal in Lawn Bowls:
  • The Indian Women's Lawn Bowls team, comprising Nayan Moni Saikia, Rupa Rani Tirkey, Lovely Choubey, and Pinki Singh, made history by winning the gold medal in the Women's Fours event at the 2022 Commonwealth Games.
  • This achievement brought significant recognition to the sport of lawn bowls in India, which had previously received limited attention.
28

Which of the following is not a factor responsible for storage losses in agricultural produce ? 

  1. ((a))

    Mites 

  2. ((b))

    Bacteria 

  3. ((c))

    Fumigation using chemical 

  4. ((d))

    Inappropriate moisture and temperature in the place of storage 

Show Answer
Answer: ((c))

Fumigation using chemical 

The correct answer is Fumigation using chemical.

Key Points

  • Fumigation using chemical:
  • Fumigation involves the use of chemicals to eliminate pests, insects, and microbial infestations in stored agricultural produce.
  • This process is a preventive and protective measure rather than a cause of storage losses.
  • When done correctly, fumigation ensures the safety and longevity of stored produce by eliminating harmful organisms.
  • Therefore, it cannot be considered a factor responsible for storage losses.

Additional Information on Other Factors

  • Mites:
  • Mites are tiny pests that infest stored grains and other agricultural produce, causing physical damage and contamination.
  • Their presence can lead to reduced quality, weight loss, and spoilage of produce.
  • They thrive in warm and humid conditions, making proper storage critical to prevent infestations.
  • Bacteria:
  • Bacteria are a major cause of spoilage in stored agricultural products, particularly perishable items like fruits and vegetables.
  • They lead to decomposition and the production of toxins, rendering the produce unfit for consumption.
  • Proper hygiene, storage conditions, and temperature control are essential to minimize bacterial activity.
  • Inappropriate moisture and temperature in the place of storage:
  • High moisture content and unsuitable temperatures create an ideal environment for microbial growth, pest infestations, and spoilage.
  • Excess moisture can also lead to the development of molds and fungi, further degrading the stored produce.
  • Maintaining optimal storage conditions is crucial to minimize losses due to these factors.

Important Points

  • Storage losses in agricultural produce can have significant economic and food security implications.
  • Implementing proper storage techniques, such as controlled temperature and humidity, pest management, and regular inspections, can reduce these losses.
  • Fumigation, when used appropriately, is an essential tool for mitigating infestations and safeguarding the quality of stored produce.
  • Awareness and training for farmers and storage facility operators are crucial in minimizing factors that contribute to storage losses.
29

Which of the following examples most appropriately represents the “Versatility” characteristic of the computer ?  

  1. ((a))

    Calculation and generation of salary slips of thousands of employees of an organisation 

  2. ((b))

    Result of division of any two numbers up to 10 decimal places 

  3. ((c))

    Performing long and complex calculations with the same speed and accuracy from the start till the end  

  4. ((d))

    At one moment one can use the computer to prepare a letter document and in the next moment one may play music or print a document 

Show Answer
Answer: ((d))

At one moment one can use the computer to prepare a letter document and in the next moment one may play music or print a document 

The correct answer is: 'At one moment one can use the computer to prepare a letter document and in the next moment one may play music or print a document'

Key Points

  • Versatility:
  • Versatility refers to the ability of a computer to perform a wide range of tasks effectively, switching between different functions or applications seamlessly.
  • Computers are not limited to a single operation or purpose; they can handle diverse activities such as document editing, playing multimedia, printing files, managing databases, and much more.
  • The versatility characteristic is most accurately represented by the ability to use a computer for one task (e.g., creating a letter document) and immediately switch to another task (e.g., playing music or printing a document).
  • This dynamic capability is enabled by the advanced hardware and software integration within a computer system, such as multitasking operating systems.
  • Thus, the correct answer highlights the core feature of versatility by showcasing the computer's ability to handle multiple, diverse tasks in rapid succession.

Additional Information

  • Incorrect Options:
  • Calculation and generation of salary slips of thousands of employees of an organisation:
  • This example showcases the computer's ability to process large amounts of data and automate repetitive tasks, which is more related to its speed and accuracy rather than versatility.
  • While this demonstrates the efficiency and productivity of a computer, it does not emphasize its ability to switch between different types of tasks.
  • Result of division of any two numbers up to 10 decimal places:
  • This example highlights the computer's capability for performing precise calculations, which relates more to its accuracy rather than versatility.
  • It does not reflect the computer's ability to handle a variety of tasks or switch between different applications.
  • Performing long and complex calculations with the same speed and accuracy from the start till the end:
  • This example represents the computer's consistency and ability to maintain speed and accuracy during complex operations.
  • Although impressive, it does not demonstrate the computer's ability to perform a wide range of tasks, which is the essence of versatility.

Important Points

  • Versatility in computers is powered by multitasking operating systems that allow users to run multiple applications simultaneously.
  • Hardware components like CPUs (Central Processing Units) and RAM (Random Access Memory) enable quick switching between tasks without compromising performance.
  • Examples of versatility include using a computer for entertainment (e.g., playing games or watching videos), professional work (e.g., coding or creating presentations), and personal tasks (e.g., browsing the internet or managing finances).
  • This characteristic is one of the key reasons computers are indispensable in modern-day life, both in personal and professional domains.
30

Which among the following is not correctly matched regarding Indian Navy's exercises with Foreign Navies ? 

List-I (Name of the exercise)List-II (Countries involved)
(1)BongosagarIndia and Bangladesh
(2)SLINEX 22India and Sri Lanka
(3)Exercise Varuna 2022India and Australia
(4)JIMEX 22India and Japan
  1. ((a))

    (1)

  2. ((b))

    (2)

  3. ((c))

    (3)

  4. ((d))

    (4)

Show Answer
Answer: ((c))

(3)

The correct answer is Exercise Varuna 2022 – India and Australia.

Key Points

  • India's Bilateral Naval Exercises
  • India conducts several bilateral naval exercises with different countries to strengthen maritime cooperation, enhance interoperability, and foster strategic partnerships.
  • Each naval exercise is designed to address mutual security concerns, boost coordination at sea, and test naval capabilities across various operational scenarios.
  • Exercise Varuna – France
  • This is Incorrect: Exercise Varuna is not conducted with Australia.
  • It is the bilateral naval exercise between India and France.
  • Initiated in 2001, it aims to bolster naval cooperation between the Indian Navy and the French Navy.
  • The exercise includes advanced surface and anti-submarine warfare operations, air defense, and maritime interdiction operations.

Additional Information

  • Bongosagar – India and Bangladesh
  • Correct: Exercise Bongosagar is conducted between the navies of India and Bangladesh.
  • It emphasizes coordinated patrols, interoperability, and strengthening defense ties in the Bay of Bengal region.
  • SLINEX – India and Sri Lanka
  • Correct: SLINEX (Sri Lanka–India Naval Exercise) is a bilateral naval drill involving India and Sri Lanka.
  • It focuses on maritime security cooperation, anti-piracy operations, and enhancing mutual understanding between the two navies.
  • JIMEX – India and Japan
  • Correct: JIMEX (Japan-India Maritime Exercise) is conducted between the Indian Navy and the Japan Maritime Self-Defense Force.
  • The exercise includes surface warfare, air defense, and maritime domain awareness operations.
  • It symbolizes growing defense and strategic ties between India and Japan in the Indo-Pacific region.
31

The given question is based on the following information :

A # B means 'A is father of B;

A & B means ‘A is mother of B';

A @ B means ‘A is son of B’;

A ⊕ B means ‘A is wife of B'.

Which of the following means ‘H is the grandson of R' ?

  1. ((a))

    P & R ⊕ Q # H

  2. ((b))

    H & R @ G @ P

  3. ((c))

    H & J @ P # R

  4. ((d))

    G & H @ J @ R

Show Answer
Answer: ((d))

G & H @ J @ R

Family tree

Decoding the Symbols:

  • A # B means 'A is father of B'
  • A & B means ‘A is mother of B’
  • A @ B means ‘A is son of B’
  • A ⊕ B means ‘A is wife of B’

Analyzing each option to find which means ‘H is the grandson of R’:

Option 1: P & R ⊕ Q # H

​So, this option is incorrect.

Option 2: H & R @ G @ P

So, this option is incorrect.

Option 3: H & J @ P # R

So, this option is incorrect.

Option 4: G & H @ J @ R

From this, R is the father of J, and J is the father of H. Therefore, H is the grandson of R. So, this option is correct.

Family Chart for Option 4:

R (Father) → J (Father) → H (Son)

Hence, the correct answer is Option 4.

32

Three statements showing relationships have been given, which are followed by two conclusions (I) and (II). Assuming that the given statements are true, find out which of the conclusions is/are definitely true.

Statements :

[1] Q < K

[2] K > J

[3] S ≥ Q

Conclusions :

(I) S < K

(II) J > Q

  1. ((a))

    Only conclusion (I) is true  

  2. ((b))

    Only conclusion (II) is true 

  3. ((c))

    Both conclusions (I) and (II) are true 

  4. ((d))

    Neither conclusion (I) nor (II) is true 

Show Answer
Answer: ((d))

Neither conclusion (I) nor (II) is true 

Given Statements:

[1] Q < K

[2] K > J

[3] S ≥ Q

Conclusions:

I. S < K → False (From [1] we know Q < K and from [3] we know S ≥ Q. We cannot definitively say that S < K. Therefore, this conclusion is not definitely true.)

II. J > Q → False (From [1] we know Q < K and from [2] we know K > J. This means K is greater than both Q and J, but it does not establish a definite relationship between J and Q. J could be greater than, less than, or equal to Q. Therefore, this conclusion is not definitely true.)

Hence, the correct answer is Neither conclusion (I) nor (II) is true  is true.

33

Seven friends M, N, J, K, P, Q and R, are sitting in a circle facing at the centre but not necessarily in the same order. ‘Q’ is to the immediate right of 'M’. ‘R is not between 'J' and ‘Q’. ‘P’ is neighbour of ‘M' and 'K’.

Which of the following persons are sitting adjacent to each other from left to right in the order as shown ?

  1. ((a))

    P K R

  2. ((b))

    N R J

  3. ((c))

    J K R

  4. ((d))

    Q N J

Show Answer
Answer: ((d))

Q N J

Given, Seven friends M, N, J, K, P, Q and R, are sitting in a circle facing at the centre but not necessarily in the same order.

‘Q’ is to the immediate right of 'M’.

‘P’ is neighbour of ‘M' and 'K’.

‘R is not between 'J' and ‘Q’. 

Then possible sitting arrangement will be,

So, Q N J are sitting adjacent to each other from left to right in order.

Hence, the correct answer is "Option 4".

34

Three statements are given followed by three conclusions (I), (I) and (III). You have to consider these statements to be true, even if they seem to be at variance from commonly known facts. You are to decide which of the given conclusions logically follow(s) from the given statements.

Statements :

[1] All fruits are vegetables

[2] No apple is vegetable

[3] Some apples are bananas 

Conclusions :

(I) Some bananas are fruits

(II) No apple is fruit

(III) No fruit is banana

  1. ((a))

    Only conclusion (III) follows 

  2. ((b))

    Only either conclusion (I) or (II) follows 

  3. ((c))

    Only either conclusion (I) or (III), and (II) follow 

  4. ((d))

    None follows 

Show Answer
Answer: ((c))

Only either conclusion (I) or (III), and (II) follow 

Given Statements:

[1] All fruits are vegetables

[2] No apple is vegetable

[3] Some apples are bananas

Venn Diagram Representation of the Statements:

Let's represent the statements using a Venn diagram to visualize the relationships:

Now,

Conclusion (I): Some bananas are fruits → False (We know apples are bananas and no apples are fruits. This tells us nothing for sure about bananas being fruits.)

Conclusion (II): No apple is fruit → True (Since all fruits are vegetables, and no apples are vegetables, then logically, no apples can be fruits.)

Conclusion (III): No fruit is banana → False (Statement [1] says "All fruits are vegetables". Statement [3] says "Some apples are bananas". We know that apples and fruits are mutually exclusive. The fact that some apples are bananas doesn't give us any definitive information about the relationship between fruits and bananas.)

As conclusion I and III contradict to each other so, either I or III will follow.

So, Only either conclusion (I) or (III), and (II) follow.

Hence, the correct answer is "Option 3".

35

Choose the Venn diagram from the options which represents the correct relationship amongst the given classes :

Females, Mothers, Lawyers

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((d))

Logic followed here is,

Logic:

All mothers are females. This is represented by the smaller circle (Mothers) being entirely contained within the larger circle (Females).

Some females can be lawyers, and some may not be. This is shown by the circle representing Lawyers overlapping with the circle representing Females.

Hence, the correct answer is "Option 4".

36

Fila Gulati is planning to connect 25 computers of her training center using Ethernet Cable. Which one of the following devices should she use for the same ? 

  1. ((a))

    Switch 

  2. ((b))

    UPS 

  3. ((c))

    HDMI Splitter 

  4. ((d))

    Repeater 

Show Answer
Answer: ((a))

Switch 

The correct answer is 'Switch'

Key Points

  • Switch:
  • A switch is a networking device that connects multiple devices such as computers, printers, and servers within a local area network (LAN).
  • It operates at the data link layer (Layer 2) of the OSI model, but some switches can also operate at the network layer (Layer 3).
  • Switches use MAC (Media Access Control) addresses to forward data to the correct destination within the network, ensuring efficient communication between connected devices.
  • In this scenario, Fila Gulati should use a switch to connect the 25 computers in her training center, as it allows all devices to communicate seamlessly and avoids network collisions.
  • Switches are scalable, meaning additional devices can be connected as needed, making them an ideal choice for managing multiple devices in a LAN.

Additional Information

  • UPS:
  • A UPS (Uninterruptible Power Supply) is an electrical device that provides backup power during power outages or fluctuations.
  • While important for maintaining uninterrupted power to computers and networking devices, a UPS cannot connect computers or facilitate data communication between them.
  • Its purpose is to prevent data loss and hardware damage due to sudden power failures, not to manage a network.
  • HDMI Splitter:
  • An HDMI splitter is a device that takes one HDMI input signal and duplicates it to multiple output devices such as monitors, TVs, or projectors.
  • It is used for video and audio distribution, not for networking or connecting computers within a LAN.
  • In the context of connecting computers, an HDMI splitter is irrelevant as it does not facilitate data communication or network functionality.
  • Repeater:
  • A repeater is a networking device that amplifies and retransmits signals over long distances to prevent signal loss.
  • Repeaters are used in scenarios where the network cable's length exceeds its signal transmission limit, but they do not connect multiple devices within a LAN.
  • While repeaters are helpful for extending the range of a network, they cannot replace a switch for managing communication between multiple computers.

Important Points

  • Switches are more efficient than hubs because they intelligently forward data to specific devices based on MAC addresses, reducing network congestion.
  • They also support full-duplex communication, allowing devices to send and receive data simultaneously.
  • For a training center with multiple computers, using a switch ensures better performance, reliability, and scalability compared to other devices.
  • Managed switches provide additional features such as VLANs (Virtual LANs), QoS (Quality of Service), and traffic monitoring for more advanced network configurations.
37

Which of the following ports is the most primitive for connecting a Video output device on a PC/ a laptop ? 

  1. ((a))

    HDMI 

  2. ((b))

    PS2 

  3. ((c))

    VGA 

  4. ((d))

    USB 

Show Answer
Answer: ((c))

VGA 

The correct answer is 'VGA'

Key Points

  • VGA (Video Graphics Array):
  • Introduced by IBM in 1987, VGA is one of the earliest and most primitive video output standards used to connect display devices to computers.
  • It uses an analog signal to transmit video data, which is prone to signal degradation over long distances or poor-quality cables.
  • The VGA connector is a 15-pin D-sub connector that was widely adopted for connecting monitors to PCs and laptops.
  • While VGA was revolutionary during its time, it has largely been replaced by more advanced digital standards such as HDMI and DisplayPort, which offer higher resolutions and better signal quality.
  • Despite its obsolescence, VGA connectors can still be found in older monitors and projectors, making them relevant for legacy compatibility.

Additional Information

  • HDMI (High-Definition Multimedia Interface):
  • HDMI is a modern digital interface introduced in 2003 that supports both video and audio transmission, making it a versatile option for connecting devices like TVs, monitors, and projectors.
  • It provides high-resolution video output, including support for 4K and 8K resolutions, with superior audio quality.
  • HDMI is widely used in contemporary devices and is not considered primitive compared to VGA.
  • PS/2:
  • PS/2 is a connector primarily used for connecting keyboards and mice to computers, not for video output.
  • It was introduced by IBM in 1987 alongside VGA but serves a completely different purpose unrelated to video transmission.
  • Due to its specific functionality, PS/2 is irrelevant to the question of video output standards.
  • USB (Universal Serial Bus):
  • USB is a versatile interface used for data transfer, power delivery, and connecting peripherals to computers.
  • While USB can support video output through standards like USB-C with DisplayPort Alt Mode, it is not inherently a dedicated video output interface like VGA or HDMI.
  • USB is a more recent technology and does not qualify as primitive compared to VGA.

Important Points

  • VGA was widely adopted during the late 1980s and 1990s but has been phased out in favor of more advanced digital interfaces.
  • Modern laptops and PCs often omit VGA ports altogether, relying on HDMI, DisplayPort, or USB-C for video output.
  • VGA’s analog nature makes it less suitable for high-definition video compared to digital interfaces like HDMI, which offer lossless transmission.
  • Understanding the evolution of video output standards helps in appreciating the advancements in display technology and connectivity.
38

Which of the following is not an input device ?

  1. ((a))

    Touchpad 

  2. ((b))

    Speaker 

  3. ((c))

    Scanner 

  4. ((d))

    Light Pen 

Show Answer
Answer: ((b))

Speaker 

The correct answer is 'Speaker'

Key Points

  • Speaker:
  • A speaker is classified as an output device, not an input device. This is because it takes audio signals generated by the computer and converts them into audible sound for the user.
  • Speakers are used for audio output tasks such as playing music, system sounds, or communication in video calls. They do not send information back to the computer, unlike input devices.
  • Examples of output devices include monitors, printers, and projectors, which perform similar functions of presenting information generated by the computer to the user.

Additional Information

  • Touchpad:
  • A touchpad is a pointing device typically found on laptops. It acts as an input device, allowing users to navigate and interact with the computer interface using finger gestures.
  • It replaces the traditional mouse and provides functionalities such as scrolling, clicking, and multi-touch gestures.
  • Scanner:
  • A scanner is an input device used to digitize physical documents, photographs, or images into electronic format.
  • It captures the visual information and converts it into a digital file that the computer can process and store.
  • Scanners are widely used in offices, libraries, and educational institutions for document management and archival purposes.
  • Light Pen:
  • A light pen is an input device that allows users to interact with the computer screen by pointing directly at the display surface.
  • It is often used for drawing, sketching, or selecting items, particularly in graphic design and CAD applications.
  • Light pens work by detecting the light emitted from the screen and sending positional data to the computer.

Important Points

  • An input device is defined as hardware that sends data or signals to the computer for processing. Examples include keyboards, mice, and microphones.
  • Output devices, on the other hand, display or reproduce the results of computer processes, such as speakers, monitors, and printers.
  • Some devices, like touchscreens, can function as both input and output devices, enabling bidirectional communication between the user and the computer.
  • Understanding the distinction between input and output devices is crucial for comprehending computer system functionality and designing efficient workflows.
39

_______ is a file extension of an image file. 

  1. ((a))

    mp3 

  2. ((b))

    mov

  3. ((c))

    tiff

  4. ((d))

    mpeg

Show Answer
Answer: ((c))

tiff

The correct answer is 'tiff'

Key Points

  • TIFF (Tagged Image File Format):
  • TIFF is a widely used file format for storing raster graphics and images.
  • It is commonly used in professional photography, graphic design, and publishing industries due to its ability to store high-resolution images.
  • One of the key features of TIFF is its support for lossless compression, ensuring that image quality is not compromised during file storage.
  • TIFF files can store multiple layers and a large amount of metadata, making them suitable for complex image editing tasks.
  • It is compatible with various software applications, including Adobe Photoshop and other image editing tools.

Additional Information

  • MP3 (Incorrect):
  • MP3 is a file format specifically designed for audio files and is widely used for compressing music and sound recordings.
  • It employs lossy compression to reduce file size while maintaining acceptable audio quality.
  • MP3 files are not suitable for storing image data as they are exclusively meant for audio content.
  • MOV (Incorrect):
  • MOV is a multimedia file format developed by Apple for storing video, audio, and text files.
  • It is commonly used with QuickTime Player and supports high-quality video playback.
  • While MOV files can store multimedia content, they do not support image-specific formats like TIFF.
  • MPEG (Incorrect):
  • MPEG stands for Moving Picture Experts Group and is a file format primarily used for video compression and playback.
  • It is widely used for streaming and sharing videos online due to its efficient compression techniques.
  • MPEG files do not support storing static images, making them unsuitable for image file formats.

Important Points

  • TIFF files are particularly useful for printing and publishing because they retain image quality even at high resolutions.
  • Compared to formats like JPEG, which use lossy compression, TIFF ensures no data loss, making it ideal for professional use.
  • While TIFF files are versatile, their larger file size can be a drawback for casual use or sharing online.
  • Other image formats like JPEG, PNG, and BMP also exist, but TIFF is preferred for tasks requiring high fidelity and detailed editing capabilities.
40

Which of the following is the correct full form of TCP ? 

  1. ((a))

    Transmission Control Protocol 

  2. ((b))

    Transportation Control Protocol 

  3. ((c))

    Transmission Central Protocol 

  4. ((d))

    Transport Control Protocol 

Show Answer
Answer: ((a))

Transmission Control Protocol 

The correct answer is 'Transmission Control Protocol'

Key Points

  • Transmission Control Protocol (TCP):
  • TCP is one of the core protocols of the Internet protocol suite and is commonly used to establish and maintain a reliable connection between two devices for data exchange.
  • It operates at the transport layer (Layer 4) of the OSI model and ensures that data packets are delivered accurately and in the correct sequence.
  • TCP provides error checking, flow control, and congestion control to ensure reliable communication over the network.
  • It is widely used in applications such as web browsing (HTTP/HTTPS), email (SMTP, IMAP, POP3), and file transfer (FTP).
  • TCP uses a three-way handshake mechanism to establish a connection between the sender and receiver, ensuring synchronization and readiness for data transfer.

Additional Information

  • Transportation Control Protocol:
  • This term is incorrect because "Transportation" is not the relevant term in the context of network communication.
  • The correct term is "Transport," which refers to the transport layer of the OSI model where TCP operates.
  • Transmission Central Protocol:
  • This option is incorrect because "Central" does not describe the functionality of TCP.
  • TCP is not a central protocol but a transport protocol responsible for reliable communication between devices.
  • Transport Control Protocol:
  • While this option may seem partially correct, it is not the official full form of TCP.
  • The accurate term is "Transmission Control Protocol," as TCP's primary role is to ensure the reliable transmission of data.

Important Points

  • TCP is often paired with the Internet Protocol (IP) to form the TCP/IP suite, which is the foundation of modern internet communication.
  • TCP is connection-oriented, meaning it establishes a connection before data is sent and ensures its integrity and order.
  • Its counterpart, User Datagram Protocol (UDP), is connectionless and does not guarantee reliable delivery, making it suitable for real-time applications like video streaming and online gaming.
  • TCP is widely regarded for its robustness and reliability, making it suitable for critical data transmission applications.

Education and Leadership (40 questions)

41

A child is born in a morally honest and socially committed family. Over the time, the child imbibe these values through : 

  1. ((a))

    Experiential learning

  2. ((b))

    Reflection

  3. ((c))

    Insight learning

  4. ((d))

    Vicarious learning

Show Answer
Answer: ((d))

Vicarious learning

Values such as honesty, social commitment, and integrity are not typically taught through formal instruction alone. Instead, children often acquire these values through continuous observation, interaction, and experience in their home and social environments.

Key Points

  • When a child is raised in a morally honest and socially responsible family, they naturally observe the consistent actions, decisions, and behaviors of family members.
  • Over time, without direct teaching, the child starts to internalize these behaviors by watching and imitating them. This form of learning is known as vicarious learning, where knowledge and values are gained indirectly through the experiences of others.
  • The child does not need to engage in the actions themselves to understand their value; instead, observing others is sufficient.

Hint

  • Experiential learning involves gaining knowledge through direct experience or active participation, which differs from simply observing others.
  • Reflection refers to thinking deeply about one's experiences to derive meaning, which is a more conscious and deliberate process.
  • Insight learning is a sudden realization or understanding of a problem or concept, often without prior direct experience or step-by-step learning.

Hence**, the correct answer is vicarious learning.**

42

A student of which one of the following type of school will prefer homeschooling ? 

  1. ((a))

    A school that acknowledges diversity

  2. ((b))

    A school that considers disability 

  3. ((c))

    A school that adheres to social exclusion 

  4. ((d))

    A school that follows social inclusion 

Show Answer
Answer: ((c))

A school that adheres to social exclusion 

Homeschooling is an educational approach where parents or guardians take primary responsibility for educating their child at home rather than sending them to a formal school.

Key Points

  • A student is more likely to prefer homeschooling when they feel excluded, discriminated against, or marginalized in the school environment.
  • A school that adheres to social exclusion creates barriers for students based on factors like caste, religion, ability, or economic background.
  • Such an environment can lead to emotional distress, lack of participation, and unequal treatment.
  • Feeling unsafe or unwelcome, a student or their family may opt for homeschooling as an alternative that allows for learning in a more accepting and personalized environment.

Hint

  • A school that acknowledges diversity values different backgrounds and promotes inclusiveness.
  • A school that considers disability ensures accommodations and support for learners with special needs.
  • A school that follows social inclusion works actively to include all students and reduce discrimination.

Hence**, the correct answer is a school that adheres to social exclusion.**

43

Which one of the following character pertaining to the cognitive development of adolescents is correct ? 

  1. ((a))

    Adolescents learn by social interaction. 

  2. ((b))

    Adolescents can use deductive logic.

  3. ((c))

    Adolescents are capable of theoretical reasoning.

  4. ((d))

    Adolescents can think upto abstract level. 

Show Answer
Answer: ((d))

Adolescents can think upto abstract level. 

Cognitive development during adolescence is marked by significant growth in thinking abilities, as described in Jean Piaget's theory of cognitive development.

Key Points

  • One of the key cognitive abilities that emerge during adolescence is the ability to think abstractly.
  • Unlike younger children who rely on concrete information and direct experiences, adolescents can consider hypothetical situations, future possibilities, and complex concepts that are not directly observable.
  • This ability marks a shift from concrete operational thought to formal operational thought, enabling them to grasp abstract ideas in subjects like mathematics, philosophy, and science.
  • Abstract thinking also allows adolescents to form and test hypotheses, consider multiple perspectives, and understand metaphorical or symbolic content.

Hint

  • Learning through social interaction is more prominent in younger children and aligns with Vygotsky’s theory, but it is not the most distinct cognitive trait of adolescence.
  • Using deductive logic and theoretical reasoning are indeed part of cognitive advancement in adolescence, but they are subsets of the broader and more defining ability—abstract thinking.

Hence, the correct answer is adolescents can think up to abstract level.

44

Amar is a 15 year old school going student. Which one of the following now can be answered or responded by Amar which he could not answer or might face difficulty in answering/ responding five years ago ?

  1. ((a))

    'Describe the most crowded place of your city in your own words’ 

  2. ((b))

    ‘Describe the cleanliness and beauty of your city’ 

  3. ((c))

    ‘Describe the most crowded place of your city as if you are flying in the sky’ 

  4. ((d))

    ‘Describe the beauty of your city as you saw in a dream’ 

Show Answer
Answer: ((c))

‘Describe the most crowded place of your city as if you are flying in the sky’ 

According to Piaget’s stages of cognitive development, by the age of 11 or 12, most children enter the formal operational stage, which enables them to think abstractly, imagine hypothetical situations, and use creative and symbolic reasoning.

Key Points

  • At the age of 15, Amar has likely developed the ability to think abstractly and imaginatively, which was limited when he was around 10.
  • Therefore, he may find it easier to respond to prompts that require him to use creative thinking and perspective-taking, such as describing a crowded place from the viewpoint of flying in the sky.
  • This task involves imagining a different perspective and using descriptive language, which may have been more challenging for him five years ago.

Hint

  • Describing crowded places or the city's cleanliness and beauty relies more on direct observation and concrete thinking, which are typically manageable for a 10-year-old.
  • Describing the city as seen in a dream also involves imagination, but it may not demand the same spatial abstraction and perspective shift as imagining flight over a cityscape.

Hence**, the correct answer is 'Describe the most crowded place of your city as if you are flying in the sky'.**

45

A teacher wants to ensure complete learning on the part of the students. So, the teacher should focus on the : 

  1. ((a))

    Philosophical implication of learning,  

  2. ((b))

    Psychological implication of learning. 

  3. ((c))

    Social implication of learning. 

  4. ((d))

    Moral implication of learning. 

Show Answer
Answer: ((b))

Psychological implication of learning. 

For effective teaching and complete learning, it is crucial to understand how students think, feel, and process information.

Key Points

  • To ensure complete learning, a teacher must focus on the psychological implications of learning, which include understanding individual differences, developmental stages, memory, attention, and motivation.
  • By aligning teaching strategies with how students mentally process content, the teacher can create an environment where all learners are supported.
  • This includes using feedback, scaffolding, reinforcement, and a variety of instructional methods that match learners' needs.
  • Such an approach helps overcome barriers to learning and ensures that learning is deep, retained, and transferable.

Hint

  • Philosophical implications explore the nature and goals of education but do not directly guide how students learn.
  • Social implications involve the impact of learning on society and group behavior, while moral implications focus on values and ethics.
  • These are important but secondary to the psychological basis when aiming for complete student learning.

Hence, the correct answer is psychological implication of learning.

46

Among humans, which one of the following activity does not require gross motor skills ? 

  1. ((a))

    Standing alone 

  2. ((b))

    Grasping a toy 

  3. ((c))

    Walking upstairs with help and support 

  4. ((d))

    Jumping at a place 

Show Answer
Answer: ((b))

Grasping a toy 

Motor skills are divided into two main types: gross motor skills and fine motor skills. Gross motor skills involve the movement and coordination of large muscles and are used for actions like walking, jumping, or standing. Fine motor skills involve smaller muscle groups and are used for more precise movements like writing or grasping.

Key Points

  • Grasping a toy primarily involves the use of small muscles in the fingers and hands, which is a fine motor skill.
  • It requires precision, hand-eye coordination, and control, but it does not engage large muscle groups used in movement and balance.
  • In contrast, actions like standing, walking upstairs, or jumping require the coordination of the legs, arms, and torso, making them gross motor activities.
  • Therefore, grasping does not fit under the category of gross motor skills.

Hint

  • Standing alone involves balance and leg strength, walking upstairs uses leg and core muscles with coordination, and jumping in place requires strong control of the whole body each is clearly a gross motor skill.

Hence, the correct answer is grasping a toy.

47

Kohlberg describes the context of moral development within : 

  1. ((a))

    Emotional and cognitive development 

  2. ((b))

    Social and emotional development 

  3. ((c))

    Physical and cognitive development 

  4. ((d))

    Social and cognitive development 

Show Answer
Answer: ((d))

Social and cognitive development 

Lawrence Kohlberg’s theory of moral development builds upon Jean Piaget’s work and emphasizes how individuals develop a sense of right and wrong through reasoning. 

Key Points

  • Kohlberg framed moral development within the context of social and cognitive development.
  • He proposed that as children's cognitive abilities grow, they become capable of understanding increasingly complex moral issues.
  • At the same time, their social interactions with peers, parents, and society at large play a vital role in shaping their moral judgments. This means moral growth depends not just on individual thinking, but also on experiences and conversations that challenge and expand a person's understanding of justice, rights, and responsibilities.

Hint

  • Emotional development is important in overall personality growth but was not the main focus of Kohlberg's theory.
  • Physical development has little direct relevance to moral reasoning.
  • While emotions can influence decisions, Kohlberg's model is centered on cognitive and social reasoning.

Hence, the correct answer is social and cognitive development.

48

The human development pattern is ________

  1. ((a))

    Spiral 

  2. ((b))

    Linear 

  3. ((c))

    Parabolic 

  4. ((d))

    Cyclical 

Show Answer
Answer: ((a))

Spiral 

Human development refers to the physical, cognitive, emotional, and social growth individuals undergo from birth through adulthood. Understanding its pattern helps educators and caregivers support learners appropriately at different stages.

Key Points

  • The spiral pattern of human development means that growth is progressive but not strictly linear.
  • Individuals revisit similar skills and concepts at more advanced levels over time.
  • For example, a child may learn basic communication in early years, but refines and expands this ability as they grow.
  • This pattern reflects a gradual, building process, where previous experiences lay the foundation for higher-level development, and learning loops back with deeper understanding.

Hint

  • Linear development suggests straight, unidirectional progress, which doesn't reflect the complexities and regressions seen in real human growth.
  • Parabolic and cyclical imply more fixed or repetitive trajectories, not accounting for the forward-moving and building nature of development.

Hence, the correct answer is spiral.

49

In the context of human development, which one of the following is an incorrect statements ? 

  1. ((a))

    Development proceeds at different rates. 

  2. ((b))

    Development patterns are predictable.  

  3. ((c))

    Development is synonym to maturation. 

  4. ((d))

    Later development is more specific than early development. 

Show Answer
Answer: ((c))

Development is synonym to maturation. 

Human development is a dynamic process involving physical, emotional, cognitive, and social changes. It follows general patterns but also exhibits significant variability, with later stages often being more specialized and specific compared to earlier stages.

Key Points

  • Development progresses at different rates: This is true. Each individual develops at their own unique pace. Some children might walk earlier than others, while others might develop language skills more quickly.
  • Development patterns are predictable: This is generally true. While the rate varies, the sequence of development tends to follow a predictable pattern (like cephalocaudal and proximodistal). We can generally anticipate the order in which certain milestones will be reached.
  • Development is synonymous with maturation: This is incorrect. While maturation (the biological unfolding of an individual according to a genetic plan) is a crucial aspect of development, development encompasses more than just physical and biological changes. It also includes cognitive, social, emotional, and behavioral changes that result from the interaction between maturation and experience/learning.
  • Later development is more specific than early development: This is generally true. Early development often involves more generalized skills, while later development involves the refinement and specialization of these skills. For example, an infant's early motor movements are broad, while later they develop fine motor skills for tasks like writing or buttoning.

Hence, the statement that development is synonym to maturation is incorrect.

50

The terms ‘cephalocaudal’ and ‘proximodistal” are associated with : 

  1. ((a))

    Growth. 

  2. ((b))

    Aging.

  3. ((c))

    Maturation. 

  4. ((d))

    Development. 

Show Answer
Answer: ((d))

Development. 

The terms cephalocaudal and proximodistal are related to the patterns of growth and development in humans. These terms describe the direction and order in which physical changes and skills emerge from infancy through childhood.

Key Points

  • Cephalocaudal development refers to the pattern of growth and development that proceeds from the head downwards. For example, infants gain control of their head and neck before they can control their torso and legs.
  • Proximodistal development refers to the pattern of growth and development that proceeds from the center of the body outwards. For instance, infants develop control of their arms and legs before they develop fine motor skills in their hands and fingers.

These two principles describe fundamental directions in which physical and motor development occur during infancy and early childhood.

 Hint

  • While growth and maturation are components of development, 'development' is the overarching term that encompasses these directional patterns.
  • Aging, on the other hand, refers to the process of growing old and is not described by these terms.

Hence, the correct answer is the terms ‘cephalocaudal’ and ‘proximodistal” are associated with development.

51

A limitation of constructivist approach is that : 

  1. ((a))

    Standardized curriculum is ignored. 

  2. ((b))

    Teacher acts as a facilitator. 

  3. ((c))

    Collaborative learning takes place. 

  4. ((d))

    Self learning is emphasized. 

Show Answer
Answer: ((a))

Standardized curriculum is ignored. 

The constructivist approach to teaching and learning is based on the idea that learners actively construct their own understanding and knowledge of the world, through experiences and reflecting on those experiences.

Key Points

  • ​A limitation of the constructivist approach is that standardized curriculum is ignored.
  • Since constructivism focuses on personalized learning, exploration, and inquiry, it may not always align with standardized curricula that require students to meet specific, predetermined learning objectives.
  • This approach can sometimes result in learning experiences that are less uniform and might not cover all the required content in a set time frame, making it challenging for teachers to ensure consistency across different groups of students.

Hint

  • Teacher acting as a facilitator is actually a strength of the constructivist approach, as it encourages students to take charge of their own learning.
  • Collaborative learning is promoted in constructivism, fostering social interaction and teamwork, which is seen as a positive feature.
  • Self-learning being emphasized is also a strength, as it encourages independence and critical thinking.

Hence, the correct answer is standardized curriculum is ignored.

52

What is the way of modifying behaviour through Operent Conditioning ? 

  1. ((a))

    Repetition through drill 

  2. ((b))

    Variation of providing reinforcements 

  3. ((c))

    Refinement of existing behaviours 

  4. ((d))

    Developing liking for some behaviour 

Show Answer
Answer: ((b))

Variation of providing reinforcements 

Operant Conditioning is a learning theory developed by B.F. Skinner, which suggests that behavior is influenced by the consequences that follow it.

Key Points

  • The way of modifying behavior through Operant Conditioning is by the variation of providing reinforcements.
  • Reinforcements can be either positive (adding something pleasant) or negative (removing something unpleasant), and they are used to increase the likelihood of a desired behavior being repeated.
  • The type and timing of reinforcement are key in effectively modifying behavior over time.
  • For example, rewarding a student for completing a task encourages them to repeat that behavior in the future.

Hint

  • Repetition through the drill can be part of behavior modification but is not the central method in Operant Conditioning. It focuses more on practice than on the use of consequences.
  • Refinement of existing behaviors might happen over time, but it is an outcome of reinforcement rather than the method itself.
  • Developing liking for some behavior is an indirect effect of reinforcement but not the primary mechanism of behavior modification in Operant Conditioning.

Hence, the correct answer is variation of providing reinforcements.

53

Employing project method is not suitable when :  

  1. ((a))

    real life experiences are considered important. 

  2. ((b))

    teacher finds it difficult to ensure participation of all students in it. 

  3. ((c))

    development of self confidence among students is a priority. 

  4. ((d))

    no external persuation is needed to attract the students toward learning, 

Show Answer
Answer: ((b))

teacher finds it difficult to ensure participation of all students in it. 

The project method is an active learning strategy where students engage in investigating a problem or topic in depth, often involving real-world issues.

Key Points

  • The project method may not be suitable when the teacher finds it difficult to ensure participation of all students in it.
  • Since the project method relies heavily on group work, collaboration, and individual contributions, a lack of participation can hinder its effectiveness.
  • If the teacher is unable to involve all students meaningfully in the project, it can lead to unequal learning outcomes, and some students may not engage as deeply with the material.

Hint

  • Real-life experiences being considered important is actually a strength of the project method, as it encourages students to connect their learning to real-world contexts.
  • Development of self-confidence is often a goal of the project method, as it allows students to take initiative and responsibility for their work.
  • No external persuasion needed to attract students toward learning is also a benefit, as the project method often increases student motivation by focusing on topics of interest and relevance to them.

Hence, the correct answer is the teacher finds it difficult to ensure participation of all students in it.

54

Extrinsic motivation is preferred over intrinsic motivation because : 

  1. ((a))

    It helps foster creativity. 

  2. ((b))

    Parents and teachers often reward children for successful completion of learning tasks. 

  3. ((c))

    It is longer lasting. 

  4. ((d))

    It is based on taking pleasure in an activity. 

Show Answer
Answer: ((b))

Parents and teachers often reward children for successful completion of learning tasks. 

Extrinsic motivation refers to the drive to perform an activity in order to receive external rewards or avoid negative outcomes, while intrinsic motivation is driven by the inherent enjoyment or satisfaction of the activity itself.

Key Points

  • Extrinsic motivation is preferred over intrinsic motivation because parents and teachers often reward children for successful completion of learning tasks.
  • External rewards such as praise, grades, or prizes encourage students to complete tasks and achieve goals.
  • These rewards can provide an immediate incentive for action, helping students stay focused and motivated, especially when the task itself may not be inherently interesting or enjoyable.

Hint

  • Fostering creativity is more often associated with intrinsic motivation, as people tend to be more creative when they are internally motivated by passion or interest.
  • Extrinsic motivation being longer-lasting is generally not true. Intrinsic motivation is often more sustainable because it is driven by internal satisfaction, while extrinsic rewards can lose their effectiveness over time.
  • Based on taking pleasure in an activity describes intrinsic motivation, not extrinsic.

Hence, the correct answer is parents and teachers often reward children for successful completion of learning tasks.

55

Important factors for development and sharpening of existing curricula do not include : 

  1. ((a))

    Globalization 

  2. ((b))

    Uniformity 

  3. ((c))

    National Goals 

  4. ((d))

    Natural and man made Calamities 

Show Answer
Answer: ((b))

Uniformity 

Curriculum development is an ongoing process that adapts to changing educational needs, societal goals, and global trends.

Key Points

  • An important factor for the development and sharpening of existing curricula does not include uniformity.
  • While curricula are designed to provide consistent standards across various educational institutions, an emphasis on uniformity can limit the flexibility and adaptability needed for addressing local, cultural, and regional needs.
  • The goal is to ensure a well-rounded, relevant education that accommodates diverse student needs rather than simply adhering to uniform content across all contexts.

Hint

  • Globalization plays a significant role in shaping curricula by encouraging international awareness and a global perspective, especially in subjects like economics, politics, and environmental studies.
  • National goals are a fundamental factor as curricula are often designed to meet national objectives in education, such as developing critical thinking skills or preparing students for the workforce.
  • Natural and man-made calamities can significantly impact curriculum development, especially in terms of preparing students to respond to such events or understanding their effects on society.

Hence, the correct answer is uniformity.

56

Which one of the following does not act as a limitation of Competency Based approach to learning ? 

  1. ((a))

    Designing activities and test items for such competencies may not always be practicable. 

  2. ((b))

    Learning climates in all schools are not conducive for optimising learning, 

  3. ((c))

    Remedial teaching is helpful for improving grades of low achievers. 

  4. ((d))

    Outreach of teacher to all students is not possible due to varied pace of learning for each student. 

Show Answer
Answer: ((c))

Remedial teaching is helpful for improving grades of low achievers. 

The Competency-Based Approach (CBA) focuses on ensuring that students master specific skills or competencies before moving on to the next level of learning.

Key Points

  • The statement "Remedial teaching is helpful for improving grades of low achievers" does not act as a limitation of the Competency-Based Approach.
  • Remedial teaching is actually a supportive feature within CBA, helping students who may be struggling to master specific competencies.
  • It allows teachers to address individual learning gaps and ensure that all students have the opportunity to achieve the desired learning outcomes.

Hint

  • Designing activities and test items for such competencies may not always be practicable can be a limitation, as creating tailored assessments for each competency can be time-consuming and complex.
  • Learning climates in all schools are not conducive for optimizing learning is also a limitation, as CBA often requires a supportive environment where students can learn at their own pace and receive adequate guidance.
  • Outreach of teacher to all students is not possible due to varied pace of learning for each student is a valid limitation, as CBA often requires individualized attention, which can be difficult for teachers to manage in large or diverse classrooms.

Hence, the correct answer is remedial teaching is helpful for improving grades of low achievers.

57

Which one of the following statements is correct ? 

  1. ((a))

    Mother tongue must be made the medium of instruction at Primary stage as children come to school with enhanced vocabulary and it may help their quality of learning.

  2. ((b))

    Implementing three language formula may create complex problems. 

  3. ((c))

    It is difficult to find suitable teachers to be able to use multilingualism.  

  4. ((d))

    Children can not learn two or more languages at a time.

Show Answer
Answer: ((a))

Mother tongue must be made the medium of instruction at Primary stage as children come to school with enhanced vocabulary and it may help their quality of learning.

Language plays a crucial role in a child's learning process, particularly in the early stages of education.

Key Points

  • The statement Mother tongue must be made the medium of instruction at the Primary stage as children come to school with enhanced vocabulary and it may help their quality of learning is correct.
  • Research suggests that when children are taught in their mother tongue, they are more likely to understand and retain new information effectively.
  • Since children are more comfortable with their first language, it enhances their ability to grasp new concepts and fosters a better learning environment.
  • This approach also supports cognitive development and ensures that children are not held back by language barriers.

Hint

  • Implementing the three-language formula may create complex problems is a valid concern, as the three-language formula can sometimes result in logistical challenges, particularly in multilingual regions where students may struggle with learning multiple languages simultaneously.
  • It is difficult to find suitable teachers to be able to use multilingualism is true in some contexts, but it’s not a universal limitation. While multilingual teachers may be scarce in certain areas, teacher training programs can address this issue.
  • Children cannot learn two or more languages at a time is incorrect. Research shows that children are capable of learning multiple languages simultaneously, especially in their early years, without hindering cognitive development.

Hence, the correct answer is Mother tongue must be made the medium of instruction at Primary stage as children come to school with enhanced vocabulary and it may help their quality of learning.

58

Which is not a feature of "Experiential Learning’ ? 

  1. ((a))

    Learning lies in the process 

  2. ((b))

    Learning is a continuous process 

  3. ((c))

    Learning takes place through logical arguments 

  4. ((d))

    Learning is a holistic process 

Show Answer
Answer: ((c))

Learning takes place through logical arguments 

Experiential learning is a process through which students learn by doing, reflecting, and applying their experiences. 

Key Points

  • The statement "Learning takes place through logical arguments" is not a feature of experiential learning.
  • While logical arguments may be part of reflective or critical thinking in the learning process, experiential learning focuses on hands-on experiences and personal reflection rather than theoretical reasoning or logical arguments.
  • It’s more about engaging with tasks, reflecting on those tasks, and learning from the practical experience, rather than through purely abstract or logical analysis.

Hint

  • Learning lies in the process is a central feature of experiential learning, emphasizing the importance of the learning journey, not just the final outcome.
  • Learning is a continuous process is true for experiential learning as it involves ongoing reflection, adaptation, and improvement over time.
  • Learning is a holistic process aligns with experiential learning as it integrates cognitive, emotional, and practical experiences, making learning more well-rounded.

Hence, the correct answer is Learning takes place through logical arguments.

59

Which one of the following is not a feature of ‘Continuous and Comprehensive evaluation” ? 

  1. ((a))

    Formative evaluation is done informally using multiple techniques. 

  2. ((b))

    Assessment of personal-social qualities is done on the basis of indicators of assessment and checklist. 

  3. ((c))

    Assessment of Scholastic areas is done in a formal way only to arrive at reliable decisions.  

  4. ((d))

    School based evaluation of students covers all aspects of students' development. 

Show Answer
Answer: ((c))

Assessment of Scholastic areas is done in a formal way only to arrive at reliable decisions.  

Continuous and Comprehensive Evaluation (CCE) is an educational assessment system introduced to improve the overall learning and development of students. 

Key PointsThe statement "Assessment of Scholastic areas is done in a formal way only to arrive at reliable decisions" is not a feature of Continuous and Comprehensive Evaluation (CCE).

  • CCE emphasizes both formal and informal assessments to track a student's progress.
  • Scholastic assessment, under CCE, is not just formal but also incorporates continuous informal techniques, such as regular observations, quizzes, projects, and discussions, to ensure a holistic understanding of a student's abilities.

Hint

  • Formative evaluation is done informally using multiple techniques is a key feature of CCE, as it aims to assess students continuously through various informal techniques like discussions, quizzes, assignments, and projects.
  • Assessment of personal-social qualities is done on the basis of indicators of assessment and checklist is also part of CCE, as it ensures that the overall development of the student is considered, including their behavior, attitude, and social interaction.
  • School-based evaluation of students covers all aspects of students' development is a feature of CCE as it not only focuses on academic learning but also takes into account other developmental areas such as emotional, social, and physical growth.

Hence, the correct answer is Assessment of Scholastic areas is done in a formal way only to arrive at reliable decisions.

60

Which one of the following is not associated with unit test ? 

  1. ((a))

    Standardized achievement tests 

  2. ((b))

    Diagnostic tests 

  3. ((c))

    Summative assessment 

  4. ((d))

    Prognostic tests 

Show Answer
Answer: ((a))

Standardized achievement tests 

Unit tests are typically associated with assessing specific knowledge or skills within a particular unit of study.

Key Points

  • Standardized achievement tests are typically large-scale assessments that are the same for all students within a specific group, such as a state or nationwide.
  • They are designed to measure a broad range of knowledge across different schools or districts and follow a set format that is not specific to a single unit or classroom.
  • Unit tests, on the other hand, are smaller, teacher-made assessments that focus on one unit's content, often used to measure short-term learning outcomes.

Hint

  • Diagnostic tests aim to identify specific learning gaps, and while they are not the same as unit tests, they are closely related as they help inform teachers about students' needs, which unit tests may also reveal.
  • Summative assessment is associated with unit tests when they are used to evaluate overall understanding after the completion of a unit.
  • Prognostic tests are used to predict a student's future learning or abilities.

Hence, the correct answer is Standardized achievement tests.

61

Which of the following is not an example of ‘assessment of learning’ ?  

  1. ((a))

    Scholarship examination 

  2. ((b))

    Recruitment tests 

  3. ((c))

    Assessment of homework  

  4. ((d))

    Annual examination 

Show Answer
Answer: ((c))

Assessment of homework  

Assessment of learning refers to assessments that are used to evaluate a student's learning after a certain period or at the end of an instructional segment.

Key Points

  • Homework is usually a form of formative assessment, which focuses on monitoring student progress during the learning process.
  • It helps teachers identify areas where students need further support and allows for ongoing improvement, rather than being a final evaluation of what a student has learned.

Hint

  • Scholarship examination is an example of assessment of learning because it evaluates a student's overall knowledge or performance to determine eligibility for a scholarship.
  • Recruitment tests also fit under assessment of learning as they are used to assess a candidate’s knowledge and abilities for a specific job role.
  • Annual examination is a classic example of assessment of learning, as it evaluates the accumulated knowledge of students over an academic year.

Hence, assessment of homework is not an example of assessment of learning.

62

Which one of the following is not a characteristic of “Assessment for learning’ ?  

  1. ((a))

    It is descriptive in nature. 

  2. ((b))

    It expects students not to make errors. 

  3. ((c))

    It provides for peer examination of their work. 

  4. ((d))

    It identifies areas of strengths and of need for each student. 

Show Answer
Answer: ((b))

It expects students not to make errors. 

Assessment for learning (AfL) refers to a formative approach to assessment that focuses on supporting and guiding students' learning.

Key Points

  • The statement "It expects students not to make errors" is not a characteristic of "Assessment for learning."
  • AfL encourages a growth mindset, where making mistakes is seen as a natural part of the learning process.
  • The focus is on providing constructive feedback to help students improve, rather than expecting them to be error-free.

Hint

  • It is descriptive in nature: AfL provides descriptive feedback rather than just giving a grade or score, helping students understand their progress.
  • It provides for peer examination of their work: Peer assessment is a common component of AfL, as it allows students to engage with each other's work and learn from one another.
  • It identifies areas of strengths and of need for each student: AfL is focused on identifying both strengths and areas for improvement, guiding future learning efforts.

Hence**, It expects students not to make errors is not a characteristic of Assessment for learning.**

63

A teacher first gives some examples related to the concept and then asks about the rule/principle governing it. She/he is adopting : 

  1. ((a))

    Inductive approach 

  2. ((b))

    Deductive approach 

  3. ((c))

    Investigatory approach 

  4. ((d))

    Explanatory approach 

Show Answer
Answer: ((a))

Inductive approach 

In teaching, there are various approaches to introduce and explain concepts. Two common approaches are the inductive and deductive approaches, both of which guide the learning process in different ways.

Key Points

  • The teacher is adopting the Inductive approach. In this approach, the teacher presents specific examples first, allowing students to observe patterns or relationships.
  • Afterward, the students are encouraged to infer the general rule or principle that governs the examples they have seen.
  • The process moves from specific to general, which is characteristic of the inductive method.

Hint

  • Deductive approach: This approach starts with a general rule or principle, and then examples are provided to illustrate the rule. It's a general to specific process.
  • Investigative approach: Involves students exploring and discovering the concept on their own, often through guided inquiry.
  • Explanatory approach: Focuses on explaining concepts, often involving lectures or direct instruction, but doesn't necessarily follow the specific example-to-rule pattern.

Hence, the teacher is adopting the Inductive approach by first providing examples and then asking students to deduce the rule or principle.

64

Individual attention is important in teaching-learning process because :  

  1. ((a))

    Teacher training programmes emphasize it. 

  2. ((b))

    It helps teachers to maintain discipline. 

  3. ((c))

    Children develop at different rate and learn differently. 

  4. ((d))

    Learners always learn better in group. 

Show Answer
Answer: ((c))

Children develop at different rate and learn differently. 

Individual attention in the teaching-learning process is essential to cater to the diverse needs of students. Each child is unique and has their own pace of learning.

Key Points

  • "Children develop at different rates and learn differently" is the correct reason for why individual attention is important.
  • Since students learn at varying paces and have different learning styles, providing personalized attention allows teachers to address specific needs, helping each child progress effectively.
  • This ensures that all students, regardless of their abilities, are supported and able to achieve their full potential.

Hint

  • Teacher training programs emphasize it: While teacher training programs may address the importance of individual attention, this is not the primary reason why it is important in the learning process.
  • It helps teachers to maintain discipline: While individual attention may help in managing classrooms, it is not the main reason for its importance in the learning process.
  • Learners always learn better in groups: This is not true for every student, as some may benefit more from individual attention, depending on their learning needs.

Hence, individual attention is important because children develop at different rates and learn differently, and tailored support helps them succeed.

65

If the students are not taking interest in the studies, the teacher should :

  1. ((a))

    report the matter to the principal and convey to the parents. 

  2. ((b))

    advise students to take interest in studies for their own benefit.  

  3. ((c))

    ask the students as to why are they not taking interest.  

  4. ((d))

    ponder over the causes for lack of interest and take remedial measure. 

Show Answer
Answer: ((d))

ponder over the causes for lack of interest and take remedial measure. 

When students show a lack of interest, the teacher needs to identify the root causes and take appropriate steps to address the issue. Instead of jumping to conclusions or taking immediate external actions, teachers need to explore the reasons behind the lack of interest.

Key Points

  • Ponder over the causes for lack of interest and take remedial measures is the most effective approach.
  • By reflecting on the possible reasons for students' lack of interest, whether it’s related to teaching methods, classroom environment, personal issues, or curriculum relevance, the teacher can adopt strategies to re-engage students.
  • This might include using more interactive teaching methods, linking lessons to real-life contexts, or offering personalized support.

Hint

  • Report the matter to the principal and convey to the parents: While it’s important to involve parents and school management, this should not be the first step without first understanding and addressing the root cause in the classroom.
  • Advise students to take interest in studies for their own benefit: Simply advising students may not be effective if the underlying reasons for their disengagement are not addressed.
  • Ask the students as to why they are not taking interest: While it’s useful to ask students, this approach alone may not lead to effective solutions if the teacher doesn't follow up with strategies to improve engagement.

Hence, the correct answer is the teacher should ponder over the causes for lack of interest and take remedial measures.

66

Integrated Education of the Disabled Children (IEDC) has been merged with :  

  1. ((a))

    DPEP 

  2. ((b))

    RUSA 

  3. ((c))

    RMSA 

  4. ((d))

    RTE, 2009 

Show Answer
Answer: ((c))

RMSA 

The Integrated Education of the Disabled Children (IEDC) program was designed to provide educational opportunities for children with disabilities in a regular school setup.

Key Points

  • The IEDC has been merged with **RMSA (**Rashtriya Madhyamik Shiksha Abhiyan).
  • RMSA is a centrally sponsored scheme aimed at improving the quality of secondary education in India.
  • It includes the provisions for students with disabilities, ensuring their inclusion in mainstream secondary education.

Hint

  • DPEP (District Primary Education Programme): DPEP focused on primary education and was not specifically merged with IEDC.
  • RUSA: This is not directly linked with the IEDC program.
  • RTE, 2009 (Right to Education Act): While the RTE ensures free and compulsory education for all children, including those with disabilities, it does not specifically merge with IEDC.

Thus, Integrated Education of the Disabled Children (IEDC) has been merged with RMSA.

67

Famous scientists Stephen Hawking was suffering from :  

  1. ((a))

    Parkinson's disease 

  2. ((b))

    Amyotrophic Lateral sclerosis 

  3. ((c))

    Sickle cell disease 

  4. ((d))

    Multiple sclerosis 

Show Answer
Answer: ((b))

Amyotrophic Lateral sclerosis 

Stephen Hawking was a renowned theoretical physicist and cosmologist, famous for his work on black holes and the theory of relativity. Despite being diagnosed with a debilitating disease at a young age, he continued to make significant contributions to science.

Key Points

  • Stephen Hawking was suffering from Amyotrophic Lateral Sclerosis (ALS), also known as Lou Gehrig's disease.
  • ALS is a progressive neurodegenerative disease that affects nerve cells in the brain and spinal cord, leading to loss of muscle control and paralysis.
  • Despite the diagnosis, Hawking defied the prognosis and continued his groundbreaking work in physics for decades.

Hint

  • Parkinson's disease: A neurodegenerative disorder, but not the disease Hawking had.
  • Sickle cell disease: A genetic blood disorder, unrelated to ALS.
  • Multiple sclerosis: Another neurological condition, but different from ALS.

Thus, it is concluded that Stephen Hawking was suffering from Amyotrophic Lateral Sclerosis (ALS).

68

Which one of the following case needs guidance ? 

  1. ((a))

    An academically bright student, who has failed in class XI after opting science. 

  2. ((b))

    Class XI student of science stream who is not able to perform / do laboratory activities / practical’s. 

  3. ((c))

    After opting science in class XI, a student who is showing the symptoms of academic anxiety. 

  4. ((d))

    Class XI student of science stream who crams the scientific laws and formula. 

Show Answer
Answer: ((c))

After opting science in class XI, a student who is showing the symptoms of academic anxiety. 

Guidance plays a crucial role in the educational journey of students, particularly when they face challenges related to academics, personal growth, or emotional well-being. 

Key Points

  • The case where a student is showing the symptoms of academic anxiety after opting for science in class XI clearly needs guidance.
  • Academic anxiety is a serious issue that affects a student’s performance and well-being.
  • Guidance can help the student manage stress, understand coping mechanisms, and build confidence in their abilities.

Hint

  • An academically bright student who has failed in class XI after opting for science: This situation also needs guidance, but it's more related to academic counseling and reassessing the student's choices, not necessarily dealing with emotional stress.
  • A student who is not able to perform laboratory activities/practicals: This might require more hands-on support and training rather than guidance in the traditional sense.
  • A student who crams scientific laws and formulas: This may point to a lack of conceptual understanding rather than a need for emotional guidance.

Hence, after opting science in class XI, a student who is showing the symptoms of academic anxiety is the correct answer.

69

Which one of the following is not a psychological stressor ? 

  1. ((a))

    Catastrophic event 

  2. ((b))

    Social discrimination  

  3. ((c))

    Sedentary lifestyle  

  4. ((d))

    Poverty

Show Answer
Answer: ((c))

Sedentary lifestyle  

Psychological stressors are events or situations that challenge an individual’s mental and emotional well-being, leading to stress.

Key Points

  • A sedentary lifestyle is not typically categorized as a psychological stressor.
  • It is more related to physical health and lifestyle choices rather than a direct emotional or mental challenge.
  • While a sedentary lifestyle can lead to physical health issues that may contribute to stress, it is not inherently a psychological stressor.

Hint

  • Catastrophic event: A sudden, traumatic event, such as a natural disaster or personal tragedy, can be a significant psychological stressor.
  • Social discrimination: Being discriminated against based on race, gender, or other factors can create ongoing psychological stress.
  • Poverty: Living in poverty can lead to constant financial worry and emotional strain, making it a significant psychological stressor.

Hence, A sedentary lifestyle is not considered a psychological stressor.

70

In a school library, the book stock should consist of curriculum - related non-fiction resources which must be : 

  1. ((a))

    Up to 50% of the total stock 

  2. ((b))

    Up to 75% of the total stock 

  3. ((c))

    atleast 40% of the total stock 

  4. ((d))

    at least 60% of the total stock 

Show Answer
Answer: ((d))

at least 60% of the total stock 

In a school library, it is essential to have a balanced collection of resources that support the curriculum while also offering opportunities for students to explore other interests.

Key Points

  • The curriculum-related non-fiction resources should make up at least 60% of the total stock.
  • This ensures that students have access to materials directly aligned with their academic needs while still having some variety in other genres.

Hint

  • Up to 50% of the total stock: This would limit the availability of curriculum-related resources, which may not be sufficient for comprehensive learning.
  • Up to 75% of the total stock: While this is a higher percentage, it may restrict the inclusion of diverse reading materials for leisure or broader educational purposes.
  • At least 40% of the total stock: This might not be enough to meet the curriculum needs effectively, as more focus would be needed on academic resources.

Hence, the correct answer is at least 60% of the total stock.

71

Which one of the following topic cannot be taught, to the school students, through ‘community as a learning resource’ ? 

  1. ((a))

    Soap - preparation procedure  

  2. ((b))

    Laws of reflection and refraction  

  3. ((c))

    Concept of chemical bonding 

  4. ((d))

    Concept of friction 

Show Answer
Answer: ((c))

Concept of chemical bonding 

The idea of using the community as a learning resource is rooted in experiential learning. It encourages real-world engagement and allows students to understand academic concepts by observing or interacting with elements in their immediate environment.

Key Points

  • The concept of chemical bonding involves the study of atomic structures, electron configurations, and the invisible interactions between atoms.
  • This topic is highly theoretical and cannot be directly observed in daily life or community settings.
  • Chemical bonding requires molecular-level understanding and abstract representation, typically taught using models and diagrams in the classroom.

Hint

  • Soap preparation can be demonstrated by involving local artisans or through household soap-making practices, making it an ideal community-linked activity.
  • Laws of reflection and refraction can be illustrated using mirrors, water, and lenses available in the local environment, helping students see these phenomena in action.
  • Friction can be taught by observing how different surfaces affect movement in daily life, such as slipping on smooth tiles or gripping rubber shoes on a rough path, making it highly relatable.

Hence, the correct answer is concept of chemical bonding.

72

Who, among the following teachers is a reflective practitioner ? 

  1. ((a))

    A teacher who is an expert in repairing electronic gadgets 

  2. ((b))

    A teacher who always asks students to reflect on their future life 

  3. ((c))

    A teacher who draws implications for his/her teaching from all kinds of life experiences 

  4. ((d))

    A teacher who blindly follows the teaching methods learnt during teacher training course 

Show Answer
Answer: ((c))

A teacher who draws implications for his/her teaching from all kinds of life experiences 

Reflective practice refers to a teacher's ability to think critically about their own teaching methods, student responses, and educational outcomes to improve future instruction. 

Key Points

  • A teacher who draws implications for their teaching from all kinds of life experiences embodies the core of reflective practice.
  • This means they do not limit their learning to formal settings but integrate insights from personal experiences, student interactions, and everyday situations to enhance classroom instruction.
  • Such a teacher continuously analyzes what works and what doesn't, modifying strategies to better support learning. By connecting life experiences with pedagogy, the teacher becomes more responsive, adaptive, and thoughtful—hallmarks of a reflective practitioner.

Hint

  • Being skilled at repairing gadgets reflects technical expertise but not pedagogical reflection.
  • Encouraging students to reflect on their lives is valuable, but it does not indicate that the teacher themselves engages in reflective teaching.
  • Following training methods without questioning or adapting them suggests a lack of critical engagement, which is contrary to reflective practice.

Hence, the correct answer is a teacher who draws implications for his or her teaching from all kinds of life experiences.

73

A good teacher as a leader should :

  1. ((a))

    Involve all his students through participatory group activities to get best results  

  2. ((b))

    Try to make balance between students and the advice of the principal 

  3. ((c))

    Try to improve his teaching skills 

  4. ((d))

    Try to attain the best degrees in education  

Show Answer
Answer: ((a))

Involve all his students through participatory group activities to get best results  

In the classroom, a teacher is not just an instructor but also a leader who guides, motivates, and influences students toward achieving their fullest potential.

Key Points

  • Involving all students through participatory group activities reflects the essence of leadership in the classroom. It empowers learners, promotes teamwork, and ensures active engagement of every student.
  • A good teacher-leader understands that learning is most effective when students collaborate, share perspectives, and solve problems together.
  • This participatory approach builds a democratic and inclusive classroom culture, enabling students to learn not just content but also social and communication skills.

Hint

  • Balancing between students and the principal’s advice is more about management than leadership, and it does not directly focus on student learning.
  • Improving personal teaching skills is important for professional growth but does not by itself demonstrate leadership qualities.
  • Earning higher degrees may enhance subject knowledge but does not guarantee active leadership or classroom impact.

Hence**, the correct answer is involve all his students through participatory group activities to get best results.**

74

Which of the following combinations help a teacher build a vision for better school education ?

(i) Logical and abstract thinking ability

(ii) Exposure to varied life situations

(iii) A degree in philosophy

(iv) Thirty years of teaching experience

(v) Experience of visiting the worst and best teacher education institutions

  1. ((a))

    (i), (ii), (iii) and (v) 

  2. ((b))

    (i), (ii), (iv) and (v)

  3. ((c))

    (i), (ii) and (v)

  4. ((d))

    (ii), (iv) and (v)

Show Answer
Answer: ((c))

(i), (ii) and (v)

Creating a meaningful vision for school education requires more than just experience or qualifications. It involves a thoughtful combination of cognitive abilities, exposure to diverse experiences, and a willingness to reflect on both best and worst practices.

Key Points

  • Logical and abstract thinking ability allows a teacher to conceptualize long-term goals and understand complex educational systems.
  • Exposure to varied life situations brings in real-world perspectives, helping the teacher empathize with different student backgrounds.
  • Visiting both the best and worst teacher education institutions gives a comparative insight into effective and ineffective practices.
  • Together, these three elements provide intellectual capacity, grounded understanding, and critical insight forming a strong foundation for building a clear and meaningful vision for better school education.

Hint

  • Having a degree in philosophy may support deep thinking but is not essential by itself for practical vision-building.
  • Thirty years of teaching experience reflects longevity but may not necessarily involve reflection or innovation without complementary insight and learning.

Hence, the correct answer is (i), (ii) and (v).

75

Which one of the following will help maximum in enhancing the teaching learning ethos in a school ? 

  1. ((a))

    Making books other than text books reading compulsory 

  2. ((b))

    Having open dialogue sessions on every educational and social issue with every teacher 

  3. ((c))

    Strictly following the set time table and no wastage of time on field visits 

  4. ((d))

    Mastering the course prescribed 

Show Answer
Answer: ((b))

Having open dialogue sessions on every educational and social issue with every teacher 

The teaching-learning ethos of a school refers to the underlying culture, values, and attitudes that shape how teaching and learning take place. 

Key Points

  • Engaging in open dialogue sessions on educational and social issues with every teacher contributes most significantly to nurturing a progressive ethos.
  • Such sessions create a culture of trust, shared understanding, and professional collaboration.
  • They allow teachers to voice their concerns, share ideas, and collectively find solutions, which leads to a deeper commitment to the school’s goals.
  • Through dialogue, teachers become reflective practitioners, stay updated on current issues, and align their teaching with real-world challenges.

Hint

  • Making non-textbook reading compulsory can promote reading habits but may feel forced without student interest or choice.
  • Strictly following a timetable and avoiding field visits may ensure discipline but can limit experiential learning and student engagement.
  • Mastering the prescribed course focuses only on content delivery, not on the overall learning experience or school culture.

Hence, the correct answer is having open dialogue sessions on every educational and social issue with every teacher.

76

Who among the following be preferred to make the school time table ? 

  1. ((a))

    The Physical education teacher 

  2. ((b))

    The drawing and painting teacher 

  3. ((c))

    The mathematics teacher 

  4. ((d))

    The vice principal 

Show Answer
Answer: ((d))

The vice principal 

Creating a school timetable is a complex task that requires an understanding of the school's overall functioning, curriculum requirements, teacher availability, classroom management, and resource allocation.

Key Points

  • The vice principal is best suited for preparing the school timetable because they typically have a broad view of the school's administrative and academic framework.
  • They are aware of the subject-wise teaching hours, classroom logistics, teacher specializations, and the needs of both students and staff.
  • This position allows them to coordinate effectively across departments and ensure that the timetable supports balanced learning without conflicts.
  • Their leadership role and access to institutional data make them ideal for designing a practical, efficient, and inclusive schedule.

Hint

  • The physical education teacher and drawing and painting teacher usually focus on specific domains and may not have insight into the overall academic demands.
  • The mathematics teacher, while potentially organized, may not have the administrative overview or authority required to coordinate all subject areas and manage scheduling constraints.

Hence, the correct answer is the vice principal.

77

Subjects like Maths and English should be taught in which period ? 

  1. ((a))

    First period 

  2. ((b))

    Period just before recess 

  3. ((c))

    Second period 

  4. ((d))

    Last period 

Show Answer
Answer: ((a))

First period 

The timing of subjects in a school day can significantly influence students' ability to concentrate, grasp concepts, and perform well academically.

Key Points

  • Core subjects like Mathematics and English require high levels of attention, cognitive engagement, and mental freshness, which vary throughout the school day based on students' energy and concentration levels.
  • Teaching subjects like Maths and English in the first period is generally considered the most effective because students are mentally fresh, well-rested, and most attentive at the beginning of the school day.
  • This period offers the best opportunity for engaging with difficult concepts, solving problems, and developing language skills.
  • Utilizing this peak cognitive window enhances understanding and retention, especially for subjects that demand logical reasoning, comprehension, and focus.

Hint

  • Scheduling these subjects just before recess may lead to reduced concentration due to fatigue and anticipation of the break.
  • The second period can also be effective but may slightly reduce attentiveness compared to the very first period.
  • Teaching them in the last period is least advisable as students are often tired and less focused by the end of the day.

Hence**, the correct answer is first period.**

78

Which document discussed Multilingualism and the power of language ? 

  1. ((a))

    Kothari Commission 

  2. ((b))

    Ram Murti Committee  

  3. ((c))

    NPE-1986 

  4. ((d))

    NEP-2020 

Show Answer
Answer: ((d))

NEP-2020 

Language is not only a medium of instruction but also a carrier of culture, identity, and cognitive development. Educational policies in India have long emphasized the role of language in shaping a child’s learning journey.

Key Points

  • The National Education Policy 2020 gives a detailed and renewed focus on multilingualism and the power of language.
  • It recognizes that children learn best in their home language or mother tongue, especially in the foundational years.
  • NEP 2020 promotes the use of the local language as the medium of instruction at least till Grade 5 and preferably till Grade 8.
  • It also highlights how multilingual exposure strengthens cognitive abilities and cultural understanding.

Hint

  • The Kothari Commission (1964–66) introduced the idea of the three-language formula but did not deeply explore multilingualism in the way NEP 2020 does.
  • The Ram Murti Committee reviewed aspects of the NPE 1986 but did not focus specifically on the power of multilingualism.
  • The National Policy on Education 1986 emphasized language to some extent, but its approach was more structural and less holistic than that of NEP 2020.

Hence, the correct answer is NEP 2020.

79

In whose context we talk specifically of safe and secure environment for children in schools ? 

  1. ((a))

    Deprived children 

  2. ((b))

    Tribal children 

  3. ((c))

    Rural children 

  4. ((d))

    Handicapped children 

Show Answer
Answer: ((d))

Handicapped children 

A safe and secure school environment is essential for the holistic development of every child. It ensures physical safety, emotional well-being, and freedom from fear, abuse, or discrimination.

Key Points

  • Handicapped children, or children with disabilities, are particularly at risk of neglect, isolation, bullying, and physical barriers in schools.
  • Creating a safe and secure environment for them means ensuring not just protection from harm but also providing accessible infrastructure, emotional support, inclusive teaching strategies, and respect for their dignity.
  • Laws like the Rights of Persons with Disabilities Act and guidelines under inclusive education stress this need.
  • Thus, in policy and practice, when we specifically talk about safe environments in schools, this group is given special focus to ensure equity and inclusion.

Hint Deprived, tribal, and rural children also face educational challenges, but the emphasis for them often lies in access, cultural inclusion, and resource availability rather than physical or infrastructural safety as a core concern.

Hence**, the correct answer is handicapped children.**

80

In which field of education, maximum innovations have been done ? 

  1. ((a))

    Primary school education

  2. ((b))

    Middle school education 

  3. ((c))

    Secondary school education 

  4. ((d))

    Senior secondary school education 

Show Answer
Answer: ((a))

Primary school education

Educational innovations refer to new ideas, methods, or tools introduced to improve teaching and learning processes. These can range from activity-based learning to the use of technology, curriculum reforms, and inclusive practices. 

Key Points

  • Primary school education has seen the highest level of innovation, as this stage lays the foundation for a child’s cognitive, social, and emotional development.
  • Governments and educational bodies worldwide, including in India, have focused heavily on improving learning outcomes at this level through joyful learning, play-based and experiential methods, use of storytelling, multilingual strategies, and child-centric pedagogies.
  • Programs like ECCE (Early Childhood Care and Education), NIPUN Bharat, and foundational literacy and numeracy missions are prime examples of concentrated innovation efforts in the primary stage.

Hint

  • Middle and secondary education focus more on subject knowledge and exam preparation, leaving less room for experimentation.
  • Senior secondary education often adheres strictly to standardized curricula and board examination formats, which limits flexibility for innovations.

Hence, the correct answer is primary school education.

Subject Specific (100 questions)

81

If n = 23 × 34 × 7 × (15)6, then number of consecutive zeros in n are :

  1. ((a))

    4

  2. ((b))

    3

  3. ((c))

    5

  4. ((d))

    6

Show Answer
Answer: ((b))

3

Calculations:

To determine the number of consecutive zeros in the given number n, we need to consider the prime factors of n and their corresponding powers.

The prime factors of n are 2, 3, and 5, as these are the prime factors of the number 15.

The power of 2 in n is 3, which means there are three 2's in the prime factorization of n.

The power of 5 in n is 6, which means there are six 5's in the prime factorization of n.

To obtain a zero at the end of a number, we need to have pairs of 2's and 5's in the prime factorization.

 we have 2 × 5, 2 × 5, 2 × 5 (3 pairs)

we will have three zeros at the end of the number n.

Hence, the number of consecutive zeros in n is 3.

82

H.C.F. of 210 and 55 is expressed as 210 × 5 + 55x. Then value of x is : 

  1. ((a))

    21011\rm -\frac{210}{11}

  2. ((b))

    -20

  3. ((c))

    21111\rm -\frac{211}{11}

  4. ((d))

    20911\rm -\frac{209}{11}

Show Answer
Answer: ((d))

20911\rm -\frac{209}{11}

Concept use:

HCF (Highest Common Factor): HCF of two numbers is the highest factor that can divide the two numbers.

Calculations:

210 = 5 × 6 × 7 

55 = 5 × 11

HCF (210. 55) = 5 

so, 5 can be written as an expression 210 × 5 + 55 (- 209/11)

Compare with given expression 210 × 5 + 55x 

We get x = -209/11

Hence, the Correct Option is 4.

83

The number 2+727\rm \frac{\sqrt2+\sqrt7}{\sqrt2-\sqrt7} is:

  1. ((a))

    an irrational number 

  2. ((b))

    a rational number  

  3. ((c))

    an integer 

  4. ((d))

    a natural number 

Show Answer
Answer: ((a))

an irrational number 

Concept use:

Any number of the Form √p where p is not a perfect square.

Calculations:

2+727\rm \frac{√2+√7}{√2-√7}

⇒ 2+727×2+72+7\rm \frac{√2+√7}{√2-√7} × \rm \frac{√2+√7}{√2+√7}

⇒ (√2 + √7)2/ (√2)2 - (√7)2

⇒ {(√2)2 + (√7)2 + 2×√2×√7} / (2 - 7)

⇒ (2 + 7 + 2√14) / (-5)

⇒ -(9 + 2√14) / 5 

The above number is an irrational number.

Hence, option 1 is correct.

84

By Fundamental theorem of Arithmetic, if p is a prime number and it divides q2, q > 0 then:

  1. ((a))

    p divides q 

  2. ((b))

    p2 divides q2

  3. ((c))

    q divides p 

  4. ((d))

    q2 divides p2

Show Answer
Answer: ((a))

p divides q 

Explanations:

Fundamental Theorem of Arithmetic:

If p is a prime number and it divides q^2, where q is a positive integer, then according to the Fundamental Theorem of Arithmetic, p must divide q.

The Fundamental Theorem of Arithmetic states that every positive integer greater than 1 can be uniquely expressed as a product of prime numbers, up to the order of the factors. In other words, the prime factorization of any positive integer is unique.

Hence, we can conclude that if p is a prime number and it divides q^2, where q is a positive integer, then p must also divide q.

85

Choose the number which has non-terminating repeating decimal expansion. 

  1. ((a))

    1180\frac{11}{80}

  2. ((b))

    45360\frac{45}{360}

  3. ((c))

    63240\frac{63}{240}

  4. ((d))

    93420\frac{93}{420}

Show Answer
Answer: ((d))

93420\frac{93}{420}

Calculation:

1) 11/80:

To find the decimal representation of this fraction, divide 11 by 80. The result is 0.1375, which terminates and does not have a repeating decimal.

2) 45/360:

Dividing 45 by 360 gives us 0.125, which also terminates and does not have a repeating decimal.

3) 63/240:

When we divide 63 by 240, we get 0.2625, which terminates and does not have a repeating decimal.

4) 93/420:

Dividing 93 by 420 gives us 0.2214285714..., where the digits 142857 repeat indefinitely. This indicates a repeating decimal.

Hence, the number 93/420 has a non-terminating repeating decimal expansion.

86

Which of the following numbers is a prime number ? 

  1. ((a))

    233

  2. ((b))

    253

  3. ((c))

    247

  4. ((d))

    377

Show Answer
Answer: ((a))

233

Concept use:

The number which is divisible by 1 and itself then it is known as the prime number.

Calculations:

253 is divisible by 11 

377 is divisible by 13 

247 is divisible by 13 

Hence, only 233 is the number which is not divisible by any number except 1 and itself .

87

If α, β are zeroes of the polynomial f(x) = x2 - p(x + 1) - 9, then value of (α + 1) (β + 1) is :

  1. ((a))

    7

  2. ((b))

    10

  3. ((c))

    -8

  4. ((d))

    8

Show Answer
Answer: ((c))

-8

Concept use:

Sum of the roots of Quadratic Equation is -b/a

Product of the roots of Quadratic Equation is c/a

Calculations:

f(x) = x2 - p(x + 1) - 9  = x2 - px - p  - 9 compare this with ax2 + bx + c 

a = 1, b = -p and c = -(p + 9)

sum of the roots = -b/a = p = α + β

product of the roots = c/a = -(p + 9) =  α × β

Now, (α + 1) (β + 1)  = α × β + 1 + α + β = p + 1 - p - 9 = -8

Hence, the Correct answer is -8

88

If (4)2x-1 - (16)x-1 = 384, then value of x is:

  1. ((a))

    94\frac{9}{4}

  2. ((b))

    2

  3. ((c))

    114\frac{11}{4}

  4. ((d))

    2.5

Show Answer
Answer: ((c))

114\frac{11}{4}

Calculations:

Apologies for the confusion caused. Let's continue solving the equation using the correct next step:

Given equation: (22)(2x-1) - (24)(x-1) = 384

Next step: 2(2(2x-1)) - 2(4(x-1)) = 384

Now let's simplify further:

2(4x-2) - 2(4x-4) = 384

⇒2(4x-4)[22 - 1] = 384

⇒2(4x-4)[3] = 384

⇒2(4x-4) = 128

To proceed, let's rewrite 128 as a power of 2:

128 = 27

Now the equation becomes:

2(4x-4) = 27

We can observe that the bases are the same (2), so we can equate the exponents:

4x - 4 = 7

4x = 7 + 4

4x = 11

x = 11/4

Hence, the Correct answer is 11/4

89

x and y are two positive real numbers such that 8x3 +27y3 = 730 and 2x2y + 3xy2 = 15, then value of 2x + 3y is :

  1. ((a))

    9

  2. ((b))

    10

  3. ((c))

    11

  4. ((d))

    8

Show Answer
Answer: ((b))

10

Concept use:

a3 + b+ 3ab(a + b) = (a + b)3

Calculations:

8x3 +27y3 = 730

2x2y + 3xy2 = 15

⇒ (2x + 3y)(4x2 - 6xy + 9y2) = 730           -----(1)

⇒ xy(2x + 3y) = 15              -----(2)

⇒ (2x + 3y) = 730 / (4x2 - 6xy + 9y2)

substitute the value of (2x + 3y) in the second equation:

xy ×  (730 / (4x2 - 6xy + 9y2)) = 15

Simplifying, we have:

730xy = 15(4x2 - 6xy + 9y2)

730xy = 60x2 - 90xy + 135y2

Rearranging the terms, we get:

60x2 - 820xy + 135y2 = 0, which is quadratic equation in terms of x and y

the root of this  equation is given by b±b24ac2a {-b \pm \sqrt{b^2-4ac} \over 2a}

Here, a = 60, b = -820, and c = 135.

Hence, the Root of the given equation 10.027 or -13.193.

Hence, the value of 2x + 3y is approximately 10. 

Hence, Option 2 is correct.

90

If x=123\rm x = \frac{1}{2-\sqrt3}, then value of x3 - 6x2 + 12x - 8 is:

  1. ((a))

    2√3

  2. ((b))

    6

  3. ((c))

    3√3

  4. ((d))

    4√3

Show Answer
Answer: ((c))

3√3

Explanation:

first, we  factorize the polynomial

⇒ \(\begin{equation} P(x) = x^3 - 6x^2 + 12x - 8 \end{equation}\)

By checking possible integer roots , we test x=2\text{By checking possible integer roots , we test $x = 2$}

⇒ \(\begin{equation} P(2) = 2^3 - 6(2^2) + 12(2) - 8 \end{equation}\)

=824+248=0 = 8 - 24 + 24 - 8 = 0

Since x=2 is a root, (x2) is a factor\text{Since $x = 2$ is a root, $(x - 2)$ is a factor}

We divide x36x2+12x8 by x2 using synthetic division\text{We divide $x^3 - 6x^2 + 12x - 8$ by $x - 2$ using synthetic division}

\(\begin{align*} & 2 , | , 1 \quad -6 \quad 12 \quad -8 \ & \quad | \quad 2 \quad -8 \quad 8 \ & \hline 1 \quad -4 \quad 4 \quad 0 \end{align*}\)

The quotient is x24x+4, so\text{The quotient is $x^2 - 4x + 4$, so}

⇒ \(\begin{equation} x^3 - 6x^2 + 12x - 8 = (x - 2)(x^2 - 4x + 4) \end{equation}\)

⇒ \(\begin{equation} x^2 - 4x + 4 = (x - 2)(x - 2) = (x - 2)^2 \end{equation}\)

⇒ (x2)3 (x - 2)^3------------(1)

Now given x=123\frac{1}{2-\sqrt{3}}

rationalise it we get

⇒ x=123×2+32+3=2+343=2+3x= \frac{1}{2-\sqrt{3}}\times \frac{2+\sqrt{3}}{2+\sqrt{3}} = \frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}

put in equation 1, we get

⇒ (2+32)3=(3)3=33(2+\sqrt{3}-2)^3 = (\sqrt{3})^3 = 3\sqrt{3}

Hence option 2 is correct

91

One of the factors of (25x2 - 1) + (1 + 5x)2 is :

  1. ((a))

    x + 5

  2. ((b))

    5 - x

  3. ((c))

    5x - 1

  4. ((d))

    5x + 1

Show Answer
Answer: ((d))

5x + 1

Calculations:

(25x2 - 1) + (1 + 5x)2 

⇒ 25x2 - 1 + 1 + 25x2 + 10x 

⇒ 50x+ 10x 

⇒ 10x(5x + 1)

One of the factors of (25x2 - 1) + (1 + 5x)2 is : 10x & 5x + 1

Hence, option 4 is correct.

92

If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 2 and -3, then :

  1. ((a))

    a = 0, b = -6

  2. ((b))

    a = 2, b = -6

  3. ((c))

    a = 5, b = -1

  4. ((d))

    a = -7, b = -1

Show Answer
Answer: ((a))

a = 0, b = -6

Concept use:

sum of the roots = -b/a  and Product of the roots = c/a 

Calculations:

sum of the roots = -b/a 

-(a + 1)/1 = 2 - 3 

-a - 1 = -1 

-a = 0, a = 0 

Product of the roots = c/a 

b/1 = 2 × -3 

b = -6 

Hence, the Correct option is 1.

93

If in a polynomial x2 - (k + 6) x + 2 (2k - 1), sum of zeroes is equal to half their product, then value of k is:

  1. ((a))

    6

  2. ((b))

    7

  3. ((c))

    83\frac{8}{3}

  4. ((d))

    4

Show Answer
Answer: ((b))

7

Concept use:

Sum of the Zeroes = -b/a 

Product of the Zeroes = c/a 

Calculations:

given polynomial x2 - (k + 6) x + 2 (2k - 1) compare with ax2 + bx + c

a = 1, b = -(k + 6) and c = 2(2k - 1)

sum of zeroes is equal to half their product

-(-(k + 6))  = 2(2k -1)

k +  6 = 1/2 × (4k - 2) 

2k + 12 = 4k - 2 

14 = 2k, k = 7

Hence, The Correct option is 2.

94

If a linear equation has solutions (-3, 3), (-2, 2) and (4, -4) then it is of the form : 

  1. ((a))

    y - x = 0

  2. ((b))

    y + x = 0

  3. ((c))

    2x + y + 3 = 0

  4. ((d))

    x + 2y - 3 = 0

Show Answer
Answer: ((b))

y + x = 0

Shortcut Trick

Notice the relationship between the x and y coordinates in the given points: (-3, 3), (-2, 2) and (4, -4).

For every point, the sum of the x-coordinate and the y-coordinate is exactly zero.

⇒ (-3) + 3 = 0

⇒ (-2) + 2 = 0

⇒ 4 + (-4) = 0

Thus, the equation satisfying all given points is y + x = 0.

∴ The correct answer is y + x = 0.

Alternate Method

Given:

Three points on a line: (-3, 3), (-2, 2) and (4, -4)

Formula Used:

Two-point form of a linear equation: (y − y1) = m(x − x1)

Where slope m = (y2 − y1) ÷ (x2 − x1)

(-3, 3)

(-2, 2)

(4, -4)

x-axis y-axis

y + x = 0

Calculations:

⇒ Let (x1, y1) = (-3, 3) and (x2, y2) = (-2, 2)

⇒ Calculate the slope (m) = (2 − 3) ÷ (-2 − (-3))

⇒ m = -1 ÷ (-2 + 3) = -1 ÷ 1 = -1

⇒ Substitute m and (x1, y1) into the line equation:

⇒ y − 3 = -1 × (x − (-3))

⇒ y − 3 = -1 × (x + 3)

⇒ y − 3 = -x − 3

⇒ y + x = 0

⇒ Verify the obtained equation with the third point (4, -4):

⇒ (-4) + 4 = 0 (Condition satisfied)

∴ The correct answer is y + x = 0.

Additional Information

General Form of a Linear Equation

The standard form of a linear equation in two variables is ax + by + c = 0, where a and b are not both zero. Its graph represents a straight line.

Slope-Intercept Form

The equation can also be written as y = mx + c, where m is the slope of the straight line and c is the y-intercept.

Collinear Points

Three or more points are considered collinear if they lie exactly on the same straight line. In such a case, the slope between any two pairs of these collinear points must be equal.

95

The graph of the linear equation 2x +3y = 8 cuts y-axis at the point :

  1. ((a))

    (83,0)\left(\frac{8}{3}, 0\right)

  2. ((b))

    (4, 0)

  3. ((c))

    (0, 4)

  4. ((d))

    (0,83)\left(0,\frac{8}{3}\right)

Show Answer
Answer: ((d))

(0,83)\left(0,\frac{8}{3}\right)

Concept use:

If the graph of linear equation cut on y axis at a point then the point having x - coordinate is zero.

Calculations:

The graph of the linear equation 2x +3y = 8 cuts y-axis at the point :

put x = 0 in the equation 

2(0) + 3y = 8 

⇒ 3y = 8, y = 8/3

Hence, the Co-ordinates of the point is (0, 8/3)

Hence, option 4 is correct.

96

Which of the following option expresses 5y - 8x = 7 (x + y) - 9 in the from ax + by + c = 0: 

  1. ((a))

    -x + 12y - 9 = 0

  2. ((b))

    15x + 2y - 9 = 0

  3. ((c))

    15x - 4y - 9 = 0

  4. ((d))

    -x + 6y - 9 = 0

Show Answer
Answer: ((b))

15x + 2y - 9 = 0

Calculations:

5y - 8x = 7(x + y)  - 9 

⇒ 5y - 8x = 7x + 7y - 9 

⇒ 7x + 8x + 7y - 5y - 9 = 0

⇒ 15x + 2y - 9 = 0

Hence, The Correct option is 2.

97

If the point (2k -3, k + 1) lies on the linear equation 2x - 3y + 12 = 0 then value of k is : 

  1. ((a))

    2

  2. ((b))

    3

  3. ((c))

    -3

  4. ((d))

    -1

Show Answer
Answer: ((c))

-3

Concept use:

If a point (2k - 3, k + 1) lies on the linear equation 2x - 3y + 12 = 0 

then it satisfies the equation of line.

Calculations:

⇒ 2(2k - 3) - 3(k + 1) + 12 = 0 

⇒ 4k - 6 - 3k - 3 + 12 = 0 

⇒ k - 9 + 12 = 0 

⇒ k + 3 = 0 , k = -3 

Hence, the correct option is 3.

98

Graphically, the two linear equation 3x + y - 6 = 0 and 3x - y + 6 = 0, with x-axis will enclose a :

  1. ((a))

    equilateral triangular region 

  2. ((b))

    isosceles triangular region 

  3. ((c))

    scalene triangular region 

  4. ((d))

    right angle triangular region 

Show Answer
Answer: ((b))

isosceles triangular region 

Concept use:

y = mx + b form, Slope Intercept form

which gives us the slope and the y-intercept of each line.

Calculations:

 

To understand what kind of triangular region these lines with the x-axis would enclose,

let's first rewrite the equations in the y = mx + b form, which gives us the slope and the y-intercept of each line.

The first equation is: 

3x + y - 6 = 0      ----(1) which simplifies to y = -3x + 6.

3x - y + 6 = 0      ----(2)  which simplifies to y = 3x - 6.

Both these lines have the same absolute value of the slope (3), but different signs, which means they are mirror images of each other with respect to the x-axis.

They will meet the x-axis at points where y = 0.

For the line y = -3x + 6, setting y = 0, we get x = 2.

For the line y = 3x - 6, setting y = 0, we get x = -2.

So, the two lines intersect the x-axis at (-2, 0) and (2, 0) respectively. The lines also intersect each other x = 0 and y = 6

Hence, the point of intersection of the lines is (0, 6), 

So, the lines along with the x-axis enclose an isosceles triangle with a vertex at (0,0) and the other two vertices at (-2,0) and (2,0).

Hence, the Correct option is (2) Isosceles triangular region.

99

If pair of linear equations

ax + 3y + (3 - a) = 0,

12x + ay - a = 0

has infinitely many solutions, then value of a is :

  1. ((a))

    6, -6

  2. ((b))

    0, 6

  3. ((c))

    6

  4. ((d))

    -6

Show Answer
Answer: ((c))

6

Concept use:

if a pair of the linear equations has infinitely many solutions then 

a1/a2 = b1/b2 = c1/c2

Calculations:

ax + 3y + (3 - a) = 0,

12x + ay - a = 0

For infinitely Many Solutions 

⇒ a1/a2 = b1/b2 = c1/c2

⇒ a/12 = 3/a 

⇒ a2 = 36 

⇒ a = +6 and a = -6

Now if we take a = -6 then 

The Equation becomes

-6x + 3y = -9 

12x - 6y = -6 

⇒ a1/a2 = b1/b2  ≠ c1/c2

it has no solution Since, the Lines are Parallel 

Hence the value of  a = +6.

Hence, option 3 is correct.

100

Cost of 15 pens and 8 pencils is Rs. 289, whereas cost of 8 pens and 15 pencils is Rs. 240. The cost of 3 pens and 3 pencils (in Rs) will be.  

  1. ((a))

    76

  2. ((b))

    96

  3. ((c))

    69

  4. ((d))

    49

Show Answer
Answer: ((c))

69

Calculations:

Let the cost of a pen is 'P' and the cost of a pencil is 'Q'. 

 15 pens and 8 pencils cost Rs. 289:

⇒ 15P + 8Q = 289      ----(1)

8 pens and 15 pencils cost Rs. 240:

⇒ 8P + 15Q = 240      ----(2)

Multiplying the first equation by 8 and the second equation by 15 to eliminate 'P'

120P + 64Q = 2312         -----(3)

120P + 225Q = 3600       -----(4)

161Q = 1288 ⇒ Q = 8

⇒ 15P + 8(8) = 289 ⇒ 15P + 64 = 289 

⇒ 15P = 289 - 64 ⇒ 15P = 225 ⇒ P = 15

Hence, The cost of a pen (P) is Rs. 15, and the cost of a pencil (Q) is Rs. 8.

Now, we can find the cost of 3 pens and 3 pencils:

3P + 3Q = 3(15) + 3(8) = 45 + 24 = 69

Hence, the cost of 3 pens and 3 pencils will be Rs. 69 is Correct.

101

Solution (x, y) of pair of linear equations :

(a + c) x - (a - c) y = 2ab

(a + b) x - (a - b) y = 2ab, is :

  1. ((a))

    (a, -a)

  2. ((b))

    (-c, c)

  3. ((c))

    (-b, b)

  4. ((d))

    (b, -b)

Show Answer
Answer: ((d))

(b, -b)

Solution:

To solve the system of linear equations:

(a + c) x - (a - c) y = 2ab . . .(i)

(a + b) x - (a - b) y = 2ab . . .(ii)

we can use the method of elimination. To eliminate y, we can multiply equation (i) by (a - b) and equation (ii) by (a - c):

(a + c)(a - b) x - (a - c)(a - b) y = 2ab(a - b) . . . (iii)

(a + b)(a - c) x - (a - b)(a - c) y = 2ab(a - c) . . . (iv)

Equation (iii) - equation (iv), we get

[(a + c)(a - b) - (a + b)(a - c)]x = 2ab(a - b - a + c)

⇒ (a- ab + ac - bc - a+ ac - ab + bc)x = 2ab(c - b)

⇒ (-2ab +2ac)x = 2ab(c - b)

⇒ 2a(-b + c)x = 2ab(c - b)

⇒ x = b

Putting x = b, in equation (i)

(a + c)b - (a - c) y = 2ab

⇒ ab + bc -(a - c)y = 2ab

⇒ -(a - c)y = ab - bc

⇒ -(a - c)y = (a - c)b

⇒ y = -b

Thus, the solution of the given equation pair is (b, -b).

102

If x = 3, y = 1 is a solution of a pair of lines x - 4y + p = 0 and 2x + y - q - 2 = 0, then the relation between p and q is: 

  1. ((a))

    2p = q

  2. ((b))

    p = 2q

  3. ((c))

    5p = q

  4. ((d))

    p = 5q

Show Answer
Answer: ((c))

5p = q

Solution:

x - 4y + p = 0 . . .(1)

2x + y - q - 2 = 0 . . .(2)

We are given that (x,y) = (3,1) satisfies these two equations.

So, substituting x = 3 and y = 1 in equations (1), we get:

3 - 4(1) + p = 0

⇒ p -1 = 0 

⇒ p = 1

So, substituting x = 3 and y = 1 in equations (2), we get:

2(3) + 1 - q - 2 = 0

⇒ 5 - q = 0

⇒ q = 5

Therefore, the relation between p and q is 5p = q.

103

The area of a rectangle gets increased by 45 m2, if its length is reduced by 4 m and breadth is increased by 5 m. If length of rectangle is increased by 3 m and breadth is reduced by 4 m then area decreases by 67 m2. Length of rectangle (in metres) is :

  1. ((a))

    21

  2. ((b))

    26

  3. ((c))

    22

  4. ((d))

    25

Show Answer
Answer: ((d))

25

Solution:

Let's assume the length of the rectangle be L and the breadth be B.

Area = LB

According to the first condition,

(L - 4)(B + 5) = LB + 45

⇒ LB + 5L - 4B - 20 = LB + 45

⇒ 5L - 4B = 65 . . . (1)

Similarly, according to the second condition,

(L + 3)(B - 4) = LB -67

⇒ LB - 4L + 3B - 12 = LB - 67

⇒ -4L + 3B = -55 . . . (2)

equation (1) × 4 + equation (2) × 5, we get

20L - 16B - 20L + 15B = 260 - 275

⇒ -B = -15

⇒ B = 15

Put B = 15 in equation (i), we get

⇒ 5L - 4 × 15 = 65

⇒ 5L = 65 + 60 = 125

⇒ L = 25

Therefore, the length of the rectangle is 25 meters.

104

The pair of linear equations;

3y = -4x +1

and 3x = 4y - 18

represents two lines which are :

  1. ((a))

    parallel 

  2. ((b))

    intersecting at (-2, 3) 

  3. ((c))

    coincident 

  4. ((d))

    intersecting at (3, -2)  

Show Answer
Answer: ((b))

intersecting at (-2, 3) 

Concept Used:

The ratio condition for general lines in the form of Ax + By + C = 0 and Dx + Ey + F = 0 is:

If A/D≠ B/E, then the lines are intersecting.

If  A/D = B/E ≠ C/F, then the lines are parallel.

If  A/D = B/E = C/F, then the lines are coincident.

Calculation:

Given equations, 3y = -4x +1and 3x = 4y - 18 can be rewritten as 

4x + 3y =1 and 3x - 4y = -18

Comparing with Ax + By + C = 0 and Dx + Ey + F = 0, we get

A = 4, B = 3 and C = 1 

Also, D = 3, E = -4 and F = -18

So, A/D = 4/3, B/E = 3/-4 = -3/4

as A/D ≠ B/E 

Thus, lines are intersecting lines.

3y = -4x +1 ⇒ y = (-4x + 1)/3

Putting y = (-4x + 1)/3 in 3x = 4y - 18, we get

⇒ 3x = 4[(-4x + 1)/3] -18

⇒ 9x = 4(-4x + 1) -54

⇒ 9x = -16x + 4 - 54

⇒ 25x = -50

⇒ x = -2

Putting, x = -2, in value of y = (-4x + 1)/3

⇒ y = (-4×(-2) + 1)/3

⇒ y = (8 + 1)/3 = 3

Thus, given lines represent intersecting lines through (-2, 3).

105

If the roots of the quadratic equation 9x2 + 6kx + 4 = 0 are equal, then the value of k is :

  1. ((a))

    -2 or 0

  2. ((b))

    2 or 0

  3. ((c))

    2 or -2

  4. ((d))

    3 or -3

Show Answer
Answer: ((c))

2 or -2

Shortcut Trick

For a quadratic equation to have equal roots, the discriminant condition b2 = 4ac must be satisfied.

Given 9x2 + 6kx + 4 = 0, here a = 9, b = 6k, and c = 4.

Applying the trick: (6k)2 = 4 × 9 × 4

36k2 = 144 ⇒ k2 = 4

k = √4 = 2 or −2

∴ The correct answer is 2 or -2.

Alternate Method

Given:

The quadratic equation is 9x2 + 6kx + 4 = 0.

The roots of the equation are equal.

Comparing with the standard form ax2 + bx + c = 0, we identify:

a = 9, b = 6k, c = 4

Formula Used:

For a quadratic equation to have equal roots, the discriminant (D) must be zero.

D = b2 − 4ac = 0

Calculations:

⇒ (6k)2 − 4 × 9 × 4 = 0

⇒ 36k2 − 144 = 0

⇒ 36k2 = 144

⇒ k2 = 144 / 36

⇒ k2 = 4

⇒ k = √4

⇒ k = 2 or −2

This confirms the values of k that satisfy the condition of having equal roots.

∴ The correct answer is 2 or -2.

Additional Information

Nature of Roots based on Discriminant (D)

If D > 0, the roots are real and distinct. If D = 0, the roots are real and equal. If D < 0, the roots are imaginary (complex).

Quadratic Formula

The roots of ax2 + bx + c = 0 can be found using x = (−b ± √D) / 2a, where D = b2 − 4ac.

Relation between Roots and Coefficients

For the equation ax2 + bx + c = 0, the sum of roots is −b/a and the product of roots is c/a.

106

The roots of the quadratic equation x2 + x - p (p + 1) = 0 are:

  1. ((a))

    -p, -(p + 1)

  2. ((b))

    p, p + 1

  3. ((c))

    -p, p + 1

  4. ((d))

    p, -(p + 1)

Show Answer
Answer: ((d))

p, -(p + 1)

Solution:

x2 + x - p (p + 1) = 0

⇒ x2 + (p + 1 - p)x - p (p + 1) = 0

⇒ x2 + (p + 1)x - px - p (p + 1) = 0

⇒ x(x + (p + 1)) - p(x + (p + 1)) = 0

⇒ (x + (p + 1))(x - p) = 0

⇒ (x + (p + 1))= 0 or (x - p) = 0

⇒ x = - (p + 1)= 0 or x  = p

Thus, -(p+1) and p are roots of the given quadratic equation.

107

If -2 is a common root of the quadratic equations ay2 + ay + 3 = 0 and y2 + y + b = 0 then a2b is :

  1. ((a))

    3

  2. ((b))

    92-\frac{9}{2}

  3. ((c))

    92\frac{9}{2}

  4. ((d))

    -6

Show Answer
Answer: ((b))

92-\frac{9}{2}

Solution:

As -2 is root of ay2 + ay + 3 = 0,

⇒ a × (-2)2 + a(-2) + 3 = 0

⇒ 4a - 2a + 3 = 0

⇒ 2a + 3 = 0

⇒ 2a = -3

⇒ a = -3/2

and -2 also root of y2 + y + b = 0

⇒ (-2)2 + (-2) + b =0 

⇒ 4 - 2 + b = 0

⇒ 2 + b = 0

⇒ b = -2

⇒ a2b = (-3/2)2 × (-2) = 9/4 × (-2) = -9/2

Thus, value of  a2b is -9/2.

108

Which constant must be added and subtracted to solve the quadratic equation 9x2+34x2=0\rm 9x^2+\frac{3}{4}x-\sqrt2=0, by the method of completing the square ?

  1. ((a))

    964\frac{9}{64}

  2. ((b))

    14\frac{1}{4}

  3. ((c))

    164\frac{1}{64}

  4. ((d))

    18\frac{1}{8}

Show Answer
Answer: ((c))

164\frac{1}{64}

Solution:

9x2+34x2=0\rm 9x^2+\frac{3}{4}x-\sqrt2=0

⇒ (3x)² + 2(3x)(1/8) - √2 = 0

To make a complete square, using identity a+ 2ab + b2

we can see (1/8) is be here, thus adding and subtracting (1/8)2 to complete square.

⇒(3x)² + 2(3x)(1/8) + (1/8)2 - (1/8)2- √2 = 0

⇒(3x + 1/8)² - (1/8)2- √2 = 0

Thus, we added and subtracted (1/8)2 = 1/64.

109

Which of the following is a quadratic equation ?  

  1. ((a))

    2x2=(5x)(2x25)\rm -2x^2=(5-x)\left(2x-\frac{2}{5}\right)

  2. ((b))

    x3 - x2 = (x - 1)3

  3. ((c))

    (k+1)x2+32x=7,k=1\rm (k+1)x^2+\frac{3}{2}x=7, k=-1

  4. ((d))

    x2 + 2x + 1 = (4 - x)2 + 3

Show Answer
Answer: ((b))

x3 - x2 = (x - 1)3

Solution:

Option (1) : 2x2=(5x)(2x25)\rm -2x^2=(5-x)\left(2x-\frac{2}{5}\right)

⇒ -2x2 = (5 - x)(2x - 2/5)

⇒ -2x2 = 10x - 2x2 - 2 + x/5

⇒ - 10x - x/5 = -2

⇒ -51x/5 = -2

⇒ x = 10/51

Which is a linear equation.

Option (2) : x3 - x2 = (x - 1)3

x3 - x2 = x3 - 3x2 + 3x - 1

⇒ 2x2 - 3x + 1 = 0

Which is a quadratic equation.

Option (3) : (k+1)x2+32x=7,k=1\rm (k+1)x^2+\frac{3}{2}x=7, k=-1

⇒ (-1 + 1)x2 + (3/2)x = 7

⇒ 0x2 + (3/2)x = 7

⇒ (3/2)x = 7

Which is a linear equation.

Option (4) : x2 + 2x + 1 = (4 - x)2 + 3

⇒ x2 + 2x + 1 = 16 - 8x + x2 + 3 

 ⇒ x2 + 2x + 1= x2 - 8x + 19

⇒ 2x + 1 = -8x + 19

⇒ 10x + 1 = 19

⇒ 10x = 18

Which is also a linear equation.

Thus, x3 - x2 = (x - 1)3  is the only quadratic equation.

110

Solution of the quadratic equation;  

2x2 + 6√3x - 60 = 0 is given by:

  1. ((a))

    2√3, -5√3

  2. ((b))

    5√3, -2√3

  3. ((c))

    5, -3√3

  4. ((d))

    -3, 5√3

Show Answer
Answer: ((a))

2√3, -5√3

Formula Used:

The solution of quadratic equation ax+ bx + c = 0 is given by:

x=b±b24ac2ax = {-b \pm \sqrt{b^2-4ac} \over 2a}

Calculation:

Comparing given equation with ax2 + bx + c = 0,

we get, a = 2, b = 6√3, and c = -60.

Substituting these values into the formula, we get:

x=63±(63)24(2)(60)2(2)x = \frac{-6√3 \pm \sqrt{(6√3)^2 - 4(2)(-60)}}{2(2)}

x=63±108+4804x = \frac{-6√3 \pm \sqrt{108 + 480}}{4}

x=63±5884x = \frac{-6√3 \pm \sqrt{588}}{4}

x=63±1434x = \frac{-6√3 \pm14 \sqrt{3}}{4}

Taking positive sign, we get

x=63+1434=834=23x = \frac{-6√3 + 14\sqrt{3}}{4} = \frac{8\sqrt{3}}{4} =2\sqrt{3}

Taking negative sign, we get

x=631434=2034=53x = \frac{-6√3 - 14\sqrt{3}}{4}= \frac{-20\sqrt{3}}{4}= -5\sqrt{3}

Thus, solution of given quadratic equation is 2√3, -5√3.

111

If the zeroes of the quadratic polynomial ax+ bx + c, where c ≠ 0 are equal, then :

  1. ((a))

    c and a have same signs 

  2. ((b))

    c and a have opposite signs 

  3. ((c))

    c and b have opposite signs 

  4. ((d))

    c and b have same signs 

Show Answer
Answer: ((a))

c and a have same signs 

Concept Used:

If the zeroes of the quadratic polynomial ax2 + bx + c are equal, then the discriminant of the quadratic equation is zero.

i.e., b2 - 4ac = 0

Solution:

For equal zeros of ax+ bx + c, b- 4ac = 0

⇒ b2 = 4ac

Now, as c ≠ 0,

as b2 > 0, So 4ac > 0

⇒ ac > 0,

Thus, a and c both can be either positive or negative.

Thus, c and a both have the same sign.

112

The sum of n terms of A.P. is n+ 3n, then common difference of A.P is :

  1. ((a))

    2

  2. ((b))

    3

  3. ((c))

    1.5

  4. ((d))

    0.5

Show Answer
Answer: ((a))

2

Concept Used:

Sn = a1 + a2 + a3 + . . . + an

and common difference = an - an-1

Calculation:

Given Sn = n2 + 3n

⇒ S1 = 12 + 3 × 1 = 1 + 3 = 4

As S1 = a= 4

Now, S2 = 22 + 3 × 2 = 4 + 6 = 10

As S2 = a1 + a2 = 10

⇒ 4 + a2 = 10 

⇒ a2 = 6

Thus, d = a2 - a1 = 6  - 4 = 2

Thus, a common difference of the given series is 2.

113

In the sequence an given by 114, 109, 104, .... the first negative term will be :

  1. ((a))

    21

  2. ((b))

    23

  3. ((c))

    24

  4. ((d))

    22

Show Answer
Answer: ((c))

24

Formula Used:

The nth term of an arithmetic progression (AP) can be found using the formula:

an = a + (n - 1)d

where,

an = nth term of the AP

a = first term of the AP

d = common difference between any two consecutive terms of the AP

n = position of the term.

Calculation:

For sequence, 114, 109, 104, ...

a = 114, d = 109 -114 = -5

Let an be the first negative term of the sequence.

i.e., an < 0

⇒ 114 + (n - 1)(-5) < 0

⇒ (n - 1)(-5) < - 114

⇒ (n - 1)(5) > 114

⇒ n-1 > 114/5

⇒ n > 114/5 + 1

⇒ n > (114 + 5)/5 = 119/5

⇒ n > 23.8

As n should be a natural number.

Thus, the first negative number of the sequence is 24th.

114

The 7th term from the end of the sequence -8, -5, -2, ...., 88 is:

  1. ((a))

    67

  2. ((b))

    70

  3. ((c))

    73

  4. ((d))

    72

Show Answer
Answer: ((b))

70

Formula Used:

The nth term of an arithmetic progression (AP) can be found using the formula:

an = a + (n - 1)d

where,

an = nth term of the AP

a = first term of the AP

d = common difference between any two consecutive terms of the AP

n = position of the term.

Calculation:

Given sequence is -8, -5, -2, ...., 88

We need to find 7th term from last, so switch the order of sequence.

88, . . ., -2, -5, -8

For new sequence, a = 88, d = -5 -(-2) = -3

a7 = 88 + (7 - 1)(-3)

⇒ a7 = 88 + 6×(-3)

⇒ a7 = 88 - 18

⇒ a7 = 70

Thus, 7th term from the last is 70.

115

The sum of all two digit numbers which when divided by 4, leave 1 as remainder is :  

  1. ((a))

    1254

  2. ((b))

    1166

  3. ((c))

    2420

  4. ((d))

    1210

Show Answer
Answer: ((d))

1210

Formula Used:

an = a + (n - 1)d and

Sn = (n/2)(a + l)

where S is the sum of the progression, an is the nth terms of the progression, n is the number of terms, a is the first term, and l is the last term.

Calculation:

Series of two digit number divisible by 4 is:

12, 16, 20, . . ., 96

As we want all two digit number when divided by 4, leave remainder 1,

So adding 1 to all terms of the above series we will get the required series, i.e.,

13, 17, 21, . . ., 97

Let an = 97, and given is a = 13 and d = 4

⇒ 97 = 13 + (n - 1) × 4

⇒ 84 = (n - 1) × 4

⇒ 21 = n - 1

⇒ n = 22

Thus, there are 22 terms in the required series.

So, Sn = (22/2) × (13 + 97) = 11 × 110 = 1210

Thus, the required sum is 1210.

116

Sum of p terms of A.P. is q and sum of q terms of AP is p. Common difference of AP. is: 

  1. ((a))

    2q2p\rm \frac{2}{q}-\frac{2}{p}

  2. ((b))

    2(p+q)pq\rm \frac{-2(p+q)}{pq}

  3. ((c))

    2(p+q)pq\rm \frac{2(p+q)}{pq}

  4. ((d))

    2q+2p\rm \frac{2}{q}+\frac{2}{p}

Show Answer
Answer: ((b))

2(p+q)pq\rm \frac{-2(p+q)}{pq}

Formula Used:

Sn = (n/2)(2a + (n-1)d)

where Sn is the sum of the progression, n is the number of terms, a is the first term, and d is a common difference.

Calculation:

Let the first term of the AP be 'a' and the common difference be 'd'. Then, we have:

Sp=p2×[2a+(p1)d]=q (i) \mathrm{S}_{\mathrm{p}}=\frac{\mathrm{p}}{2} \times[2 \mathrm{a}+(\mathrm{p}-1) \mathrm{d}]=\mathrm{q} \ldots\text { (i) }

Sq=q2×[2a+(q1)d]=p (ii)  \mathrm{S}_{\mathrm{q}}=\frac{\mathrm{q}}{2} \times[2 \mathrm{a}+(\mathrm{q}-1) \mathrm{d}]=\mathrm{p} \ldots \text { (ii) }

From equation (i), we get

p2×[2a+(p1)d]=q \frac{p}{2} \times[2 a+(p-1) d]=q

2a+(p1)d=2qp (iii)  \Rightarrow 2 a+(p-1) d=\frac{2 q}{p} \ldots \text { (iii) }

From equation (ii), we get

and q2×[2a+(q1)d]=p\frac{q}{2} \times[2 a+(q-1) d]=p

2a+(q1)d=2pq (iv)  \Rightarrow 2 a+(q-1) d=\frac{2 p}{q} \ldots \text { (iv) }

Subtracting (iii) and (iv), we get,

2pq2qp=(qp)d \frac{2 p}{q}-\frac{2 q}{p}=(q-p) d

2(p+q)(pq)pq=(qp)d \Rightarrow \frac{2(p+q)(p-q)}{p q}=(q-p) d

d=2(p+q)pq \Rightarrow d=\frac{-2(p+q)}{p q}

Thus, the common difference is -2(p+q)/pq.

117

The fourth term of an A.P. is three times the first term and seventh term exceeds twice the third term by 1. Tenth term of A.P. will be : 

  1. ((a))

    22

  2. ((b))

    23

  3. ((c))

    21

  4. ((d))

    29

Show Answer
Answer: ((c))

21

Formula Used:

The nth term of an arithmetic progression (AP) can be found using the formula:

an = a + (n - 1)d

where,

an = nth term of the AP

a = first term of the AP

d = common difference between any two consecutive terms of the AP

n = position of the term.

Calculation:

Let the first term of the AP be 'a' and the common difference be 'd'. Then, we have:

The fourth term is 3a, so we can write: a + 3d = 3a

⇒ 2a = 3d . . .(i)

Also, seventh term exceeds twice the third term by 1

⇒ a + 6d = 2(a + 2d) + 1

⇒ a + 6d = 2a + 4d + 1

⇒ 2d = a + 1

⇒ 4d = 2a + 2

⇒ 4d = 3d + 2 [using equation (i)]

⇒ d = 2

Putting d = 2 in equation (i), we get

a = 3

Thus, tenth term is a10 = a + 9d

⇒ a10 = 3 + 9×2

⇒ a10 = 3 + 18 = 21

Hence, the tenth term of the AP is 21.

118

Two points having same abscissa but different ordinates lie on : 

  1. ((a))

    x-axis 

  2. ((b))

    line parallel to x-axis 

  3. ((c))

    y-axis 

  4. ((d))

    line parallel to y-axis 

Show Answer
Answer: ((d))

line parallel to y-axis 

Concept Used:

In Coordinate Geometry, any point is represented by an ordered pair i.e., (x, y). Where x represents the horizontal position and y represents the vertical position and respectively called abscissa and ordinate.

If two points have the same abscissa, they have the same horizontal position, and if they have a different ordinate, they must lie on a vertical line parallel to the y-axis.

119

The number of linear equations in x and y which satisfy x = 1 and y = 5 is :

  1. ((a))

    only one

  2. ((b))

    Two

  3. ((c))

    Three

  4. ((d))

    Infinitely many

Show Answer
Answer: ((d))

Infinitely many

Concept Used:

There can be infinite possible lines that can pass through any given point.

Solution:

x = 1 and y = 5 represents a point on a coordinate plane.

Thus there can infinity possible lines that can pass through the given point.

120

If the point P (2, 1) lies on the line segment joining points A (-1, 7) and B (4, -3), then : 

  1. ((a))

    BP=35AB\rm BP=\frac{3}{5}AB

  2. ((b))

    AP=25AB\rm AP=\frac{2}{5}AB

  3. ((c))

    AP=32BP\rm AP=\frac{3}{2}BP

  4. ((d))

    PB=32AP\rm PB=\frac{3}{2}AP

Show Answer
Answer: ((c))

AP=32BP\rm AP=\frac{3}{2}BP

Formula Used:

The distance formula is used to find the distance between two points in a coordinate plane. It is given by:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

where d is the distance between the two points, (x1, y1) and (x2, y2) are the coordinates of the two points.

Calculation:

Let's first find the distance between points A and B using the distance formula:

AB=(4(1))2+(37)2=52+(10)2=125 AB = \sqrt{(4 - (-1))^2 + (-3 - 7)^2} = \sqrt{5^2 + (-10)^2} = \sqrt{125}

Now, let's find the distance between points P and A:

AP=(2(1))2+(17)2=32+(6)2=45 AP = \sqrt{(2 - (-1))^2 + (1 - 7)^2} = \sqrt{3^2 + (-6)^2} = \sqrt{45}

Similarly, let's find the distance between points P and B:

BP=(24)2+(1(3))2=(2)2+42=20 BP = \sqrt{(2 - 4)^2 + (1 - (-3))^2} = \sqrt{(-2)^2 + 4^2} = \sqrt{20}

Thus, APAB=45125=925=35\frac{AP}{AB} = \frac{\sqrt{45}}{\sqrt{125}} = \sqrt\frac{9}{25} = \frac{3}{5},

 BPAP=20125=425=25 \frac{BP}{AP} = \frac{\sqrt{20}}{\sqrt{125}} = \sqrt\frac{4}{25} = \frac{2}{5},

and APBP=4520=94=32 \frac{AP}{BP} = \frac{\sqrt{45}}{\sqrt{20}} = \sqrt\frac{9}{4} = \frac{3}{2}

Therefore, AP = (3/2)BP is the only correct option.

121

The coordinates of a point which is equidistant from O (0, 0), A (0, 22) and B (8, 0) is : 

  1. ((a))

    (112,4)\rm \left(\frac{11}{2}, 4\right)

  2. ((b))

    (11, 4)

  3. ((c))

    (4, 11)

  4. ((d))

    (4,112)\rm \left(4,\frac{11}{2}\right)

Show Answer
Answer: ((c))

(4, 11)

Formula Used:

The distance formula is used to find the distance between two points in a coordinate plane. It is given by:

d=(x2x1)2+(y2y1)2 d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

where d is the distance between the two points, (x1, y1) and (x2, y2) are the coordinates of the two points.

Calculation:

Let the coordinates of the required point be (x, y).

Since the point is equidistant from O (0, 0), A (0, 22) and B (8, 0), we have:

Distance from (x, y) to O = Distance from (x, y) to A = Distance from (x, y) to B,

Taking two at a time, we get

Distance from (x, y) to O = Distance from (x, y) to A 

x2 + y2 = (0 - x)2 + (22 - y)2

⇒ x2 + y2 =  x2 + y2 + 484 - 44y

⇒ 484 - 44y = 0

⇒ 44y = 484

⇒ y = 11

Distance from (x, y) to O = Distance from (x, y) to B

x2 + y2 = (8 - x)2 + (y - 0)2

⇒ x2 + y2 =  x2 + 82 - 16x + y2

⇒  82 - 16x = 0

⇒ 16x = 64

⇒ x = 4

Hence, the coordinates of the required point are (4,11).

122

Point which is equidistant from point A (4, 5) and B (-2, 3) lies on the linear equation : 

  1. ((a))

    3x - y - 7 = 0

  2. ((b))

    3x + y - 7 = 0

  3. ((c))

    2x - y + 7 = 0

  4. ((d))

    3x + 2y + 7 = 0

Show Answer
Answer: ((b))

3x + y - 7 = 0

Formula Used:

Distance formula is given by

d = √[(x2 - x1)² + (y2 - y1)²]

where d is the distance between the points (x1, y1) and (x2, y2)

Calculation:

Let the point equidistant from A(4,5) and B(-2,3) be (x, y).

Then, by the distance formula, we have:

√[(x - 4)² + (y - 5)²] = √[(-2 - x)² + (3 - y)²]

⇒ (x - 4)² + (y - 5)² = (-2 - x)² + (3 - y)²

⇒ x² +16- 8x + y² + 25 - 10y = 4 + x²+ 4x + 9 + y² - 6y

⇒ 12x + 4y = 28

⇒ 3x + y = 7

Therefore, the point (x, y) lies on the linear equation3x + y - 7=0.

123

If the mid point of the line segment joining (α, β + 1) and (α + 1, β + 2) is (32,52)\rm \left(\frac{3}{2}, \frac{5}{2}\right), then the mid point of line segment joining (α - 1, β + 1) and (α + 1, β - 1) is:

  1. ((a))

    (1, 1)

  2. ((b))

    (1, -2)

  3. ((c))

    (2, 1)

  4. ((d))

    (3, 1)

Show Answer
Answer: ((a))

(1, 1)

Formula Used:

The coordinates of M can be found using the midpoint formula:

M = ((x1 + x2)/2, (y1 + y2)/2),

where (x1, y1) and (x2, y2) are the coordinates of A and B respectively and M is the midpoint of the line joining A and B.

Calculation:

Let (α, β + 1) be point A and (α + 1, β + 2) be point B.

The midpoint M of AB is given as (3/2, 5/2).

3/2 = (α + (α + 1))/2

⇒ 3 = 2α + 1 

⇒ α = 1

and 5/2 = (β + 1 + (β + 2))/2

⇒ 5 = 2β + 3 

⇒ β = 1

Now, let (α - 1, β + 1) be point C and (α + 1, β - 1) be point D.

Putting value of α and β in coordinate of C and D, we get C(0,2) and D(2,0)

Let midpoint of CD be O.

O(x, y) = ((0+2)/2, (2+0)/2)

⇒ O(x, y) =  (1, 1)

Therefore, the midpoint of CD is (1, 1).

Hence, the midpoint of the line segment joining (α - 1, β + 1) and (α + 1, β - 1) is (1, 1).

124

Euclid stated that “all right angles are equal to each other” in the form of : 

  1. ((a))

    an axiom 

  2. ((b))

    a definition 

  3. ((c))

    a postulate 

  4. ((d))

    a theorem  

Show Answer
Answer: ((c))

a postulate 

Fact:

Euclid's 5 postulates are as follows:

  • A straight line segment can be drawn joining any two points.
  • Any straight line segment can be extended indefinitely in a straight line.
  • Given any straight lines segment, a circle can be drawn having the segment as radius and one endpoint as center.
  • All Right Angles are congruent.
  • If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two Right Angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the Parallel Postulate.

Thus, all right angles are equal is given by Euclid in the form of postulate.

125

Boundaries of solids are : 

  1. ((a))

    surfaces 

  2. ((b))

    curves

  3. ((c))

    lines

  4. ((d))

    points

Show Answer
Answer: ((a))

surfaces 

Fact:

Boundaries of solids refer to the surfaces that define the outer edges or limits of the solid object.

126

The angles (30 - a)° and (125 + 2a)° are supplement to each other. Value of ‘a’ is :  

  1. ((a))

    20°

  2. ((b))

    35°

  3. ((c))

    40° 

  4. ((d))

    25°

Show Answer
Answer: ((d))

25°

Concept Used:

If two angles are supplementary, their sum is 180°.

Calculation:

As given angles (30 - a)° and (125 + 2a)° are supplement to each other.

(30 - a)° + (125 + 2a)° = 180°

⇒ 155 + a = 180

⇒ a = 25

Therefore, the value of ‘a’ is 25.

127

Which of the following statements is true ?  

  1. ((a))

    If x° is the measure of an angle that is equal to its complement and y° is the measure of an angle that is equal to its supplement, then xy=0.5\frac{x^{\circ}}{y^{\circ}}=0.5

  2. ((b))

    In a triangle ABC, if ∠B > ∠C then AB > AC.  

  3. ((c))

    The length of the median in a triangle to a side is less than the corresponding altitude. 

  4. ((d))

    d

Show Answer
Answer: ((a))

If x° is the measure of an angle that is equal to its complement and y° is the measure of an angle that is equal to its supplement, then xy=0.5\frac{x^{\circ}}{y^{\circ}}=0.5

Concept use:

Calculations:

Option 1)

y°  = 180°- y°  (Supplementary angles)

⇒ 2y° = 180° , y°  = 90° 

x°  = 90° - x° (Complementary angles)

⇒ 2x° = 90° , x° = 45° 

x°/ y° = 45°/ 90° = 1/2° = 0.5° 

Hence, If x° is the measure of an angle that is equal to its complement and y° is the measure of an angle that is equal to its supplement, then x°/ y°  = 0.5° is correct

option 2)

In a triangle ABC, if ∠B > ∠C then AB > AC is incorrect

side opposite to Larger angle is Larger  ∠B > ∠C then AC > AB.

option 3)

128

In the figure, AB || PO and BC || OQ. Value of 2x - y is:

  1. ((a))

    50°

  2. ((b))

    80°

  3. ((c))

    130°

  4. ((d))

    100°

Show Answer
Answer: ((a))

50°

Shortcut Trick

When two angles have their corresponding arms parallel to each other, the two angles are equal.

Here, since AB || PO and BC || OQ, the corresponding angles ∠ABC and ∠POQ must be equal.

⇒ ∠POQ = ∠ABC

⇒ 2x − y = 50°

∴ The correct answer is 50°.

Alternate Method

Solution:

Since AB ∥ PO and BC is a transversal,

⇒ x = y   (Corresponding angles) ......(i)

Also, BC is a straight line. Therefore, the sum of angles on one side of a straight line is always 180°.

⇒ y + ∠PCB = 180°

⇒ ∠PCB = 180° − y ......(ii)

Also, BC ∥ OQ and PO is a transversal.

⇒ ∠PCB = 130°   (Corresponding angles)

From equation (ii),

⇒ 180° − y = 130°

⇒ 180° − 130° = y

⇒ y = 50°

From equation (i), x = y = 50°.

Therefore,

⇒ 2x − y = 2 × 50° − 50°

⇒ 2x − y = 100° − 50°

⇒ 2x − y = 50°

∴ The value of 2x − y is 50°.

129

The angles of a triangle are in the ratio 4 ∶ 5 ∶ 6. The difference of largest and smallest angle is : 

  1. ((a))

    48°

  2. ((b))

    30°

  3. ((c))

    24°

  4. ((d))

    36°

Show Answer
Answer: ((c))

24°

Solution:

Let the three angles of the triangle be 4x, 5x, and 6x.

The sum of the angles of any triangle is 180 degrees, so we can write:

4x + 5x + 6x = 180°

⇒ 15x = 180°

⇒ x = 12°

Now we can find the three angles of the triangle:

4x = 4(12) = 48°

5x = 5(12) = 60°

6x = 6(12) = 72°

The difference between the largest and smallest angle is 72° - 48° = 24°.

Therefore, the difference between the largest and smallest angle in the triangle is 24°.

130

In the figure, AB || CD. If ∠ABE = 105°, ∠BED = 30°, then value of ∠CDE = a is : 

  1. ((a))

    105°

  2. ((b))

    135°

  3. ((c))

    115°

  4. ((d))

    75° 

Show Answer
Answer: ((b))

135°

Concept Used:

Sum of all interior angles of triangle is 180°.

Sum of all angles to the same side of straight lines is also 180°.

Calculation:

In triangle BEF, 

using angle sum property of triangle,

∠B+∠E+∠F = 180°

⇒ 105° + 30° + ∠E = 180°

 ⇒ ∠E = 180° - 135° = 45°

as AFB is straight line, 

∠AFD + ∠DFB = 180° 

⇒ a + 45° = 180° 

⇒ a = 180°- 45°

⇒ a = 135° = ∠CDE

Thus, the value of a is 135°.

131

In the figure, AB = AC, ∠ACD = 115°. ∠A is equal to: 

  1. ((a))

    45°

  2. ((b))

    55°

  3. ((c))

    50°

  4. ((d))

    40°

Show Answer
Answer: ((c))

50°

Solution:

For any triangle angle opposite to equal sides are also equal.

AB = AC ⇒ ∠C = ∠B . . .(i)

BCD is straight line, then sum of angles on one side of line is 180°.

∠BCA + ∠ACD = 180°

⇒ ∠BCA + 115°= 180° 

⇒ ∠BCA = 65° = ∠C in triangle ABC.

⇒ ∠C = ∠B = 65°

In triangle ABC, ∠A +∠B + ∠C = 180°

⇒ ∠A + 65° +  65° = 180°

⇒ ∠A  = 180°-130° = 50°

Thus, value of angle A is 50°.

132

Which of the following statements is wrong ?

  1. ((a))

    If the corresponding sides of two similar triangles are in the ratio 5 ∶ 7, then their perimeters are in the ratio 5 ∶ 7. 

  2. ((b))

    If the corresponding sides of two similar triangles are in the ratio 4 ∶ 3, then their area are in the ratio 4 ∶ 3. 

  3. ((c))

    If the ratio of the corresponding sides of two similar triangles is 3 ∶ 5, then the ratio of their corresponding altitudes is 3 ∶ 5. 

  4. ((d))

    In two similar triangles, if the ratio of their corresponding medians is 7 ∶ 5, then the ratio of their corresponding altitudes is 7 ∶ 5. 

Show Answer
Answer: ((b))

If the corresponding sides of two similar triangles are in the ratio 4 ∶ 3, then their area are in the ratio 4 ∶ 3. 

Concept Used:

If two triangles ABC and PQR are similar, then

AB/PQ = BC/QR = AC/PR

ar(ABC) is the area of triangle ABC, and ar(PQR) is the area of triangle PQR, then

ar(ABC)/ar(PQR) = (AB/PQ)2 = (BC/QR)2 = (AC/PR)2 

Solution:

Option (2) : If the corresponding sides of two similar triangles are in the ratio 4 ∶ 3, then their area are in the ratio 4 ∶ 3, is wrong as the ratio of area of similar triangles is in the ratio of square of their sides.

Thus, option (2) is the incorrect statement.

133

In Δ ABC, AC2 = 2AB2 and AB = BC, then ∠C equals :

  1. ((a))

    90°

  2. ((b))

    60°

  3. ((c))

    45°

  4. ((d))

    30°

Show Answer
Answer: ((c))

45°

Formula Used:

The Law of Cosines for sides AB, BC, and AC of triangle ABC is:

AC² = AB² + BC² - 2AB × BC × cos(∠B)

AB² = AC² + BC² - 2AC × BC × cos(∠C)

BC² = AB² + AC² - 2AB × AC × cos(∠A)

Where ∠A, ∠B, and ∠C are the angles opposite to sides BC, AC, and AB respectively.

Calculation:

We have AC² = 2AB² and AB = BC.

Using the Law of Cosines, we have:

AB² = AC² + BC² - 2AC × BC × cos(∠C)

Substituting AB = BC, we get:

AB² = 2AB² + AB² - 2AC·AB.cos(∠C)

⇒ 0 = 2AB² - 2AC·AB.cos(∠C)

⇒ 2AB² = 2AC·AB.cos(∠C)

⇒ AB/AC = cos(∠C)

AC = √2 AB

⇒ AB/AC = 1/√2 

⇒ cos(∠C) = AB/AC = 1/√2 

Therefore, ∠C = 45°

Hence, the angle ∠C is 45 degrees.

134

In figure, line l is the bisector of ∠A. If AO = 5 cm and AP = 4 cm, then OQ is equal to : 

  1. ((a))

    4 cm

  2. ((b))

    3 cm

  3. ((c))

    5 cm

  4. ((d))

    2 cm

Show Answer
Answer: ((b))

3 cm

Solution:

As line l bisects ∠A.

⇒ ∠QAO = ∠OAP . . .(i)

∠AQO = ∠APO = 90° (given in diagram)

⇒ ∠AOQ = ∠AOP (as if two angles of any triangle are equal, then third angle is also equal.) . . .(ii)

In triangle AOQ and AOP,

∠QAO = ∠OAP  [From (i)]

 ∠AOQ = ∠AOP   [From (ii)]

AO = AO (common in both triangles)

AOQAOP\triangle AOQ \cong \triangle AOP (by ASA congruence rule)

⇒ OQ = OP (by CPCT)

In triangle, AOP using Pythagoras theorem,

AO2 = AP2 + OP2

⇒ 52 = 42 + OP2

⇒  OP2 = 9

⇒ OP = 3 cm

Thus, OP = OQ = 3 cm.

135

In triangle ABC and DEC (see figure) if AB || ED, then Δ ABC and Δ DEC are : 

  1. ((a))

    similar 

  2. ((b))

    congruent 

  3. ((c))

    both similar and congruent 

  4. ((d))

    neither similar nor congruent 

Show Answer
Answer: ((a))

similar 

Solution:

AB∥ ED, and AD and BD are the transversal lines.

then, ∠BAC = ∠CDE and ∠ABC = ∠DEC are the alternate interior angles. 

For two triangle if all three angles are equal then triangles are similar.

For two triangles  ABC and DEC 

∠ABC = ∠DEC (Alternate Interior Angles)

∠BAC = ∠CDE (Alternate Interior Angles)

∠ACB = ∠DCE (Vertical Opposite angle)

Therefore, we can say that ΔABC ~ ΔDEC.

136

Two buildings are standing opposite to each other on either side of the road. From a point on the road, ladder reaches building's window which is 12 m high from the ground. Keeping the foot of the ladder at the same point, the ladder is turned on the other side of the road and it reaches a window which is 9 m high from the ground. If the length of the ladder is 15 m, then the width of the road (in m) is :  

  1. ((a))

    18

  2. ((b))

    24

  3. ((c))

    21

  4. ((d))

    25

Show Answer
Answer: ((c))

21

Concept Used:

In mathematical notation, the Pythagorean theorem can be expressed as:

c2 = a2 + b2

where c is the length of the hypotenuse and a and b are the lengths of the other two sides

Calculation:

Let's denote the distance between the foot of the ladder and the point on the road as x and with other point on the road as y.

When ladder is placed on first building

In triangle OAP, using Pythagoras Theorem

x2 + 122 = 152

⇒ x2 + 144 = 225

⇒ x2 = 81

⇒ x = 9 (as -9 can't be the value of x)

W hen the ladder is placed against the second building,

In triangle, OQC

y2 + 9^2 = 15^2

⇒ y2 + 81 = 225

⇒ y2 = 144

⇒ y = 12 (as -12 can't be the value of y)

Since, x + y represents the distance between both buildings.

Thus, width of road is 12+9 = 21 m.

137

In a triangle ABC, PQ is drawn parallel to BC such that points P and Q lie on AB and AC respectively, If PQ ∶ BC = 2 ∶ 5, then AP ∶ PB is:  

  1. ((a))

    23\frac{2}{3}

  2. ((b))

    25\frac{2}{5}

  3. ((c))

    35\frac{3}{5}

  4. ((d))

    32\frac{3}{2}

Show Answer
Answer: ((a))

23\frac{2}{3}

Concept Used:

We know If a line is drawn through the any point of one side of a triangle and parallel to another side, then this line divides the third side of the triangle into two segments that are proportional to the first two sides and smaller formed triangle is similar to the original triangle.

i.e., ratio of sides of both triangles are same,

Calculation:

Formed triangle APQ is similar to triangle ABC.

So, PQ ∶ BC = AP ∶ AB

⇒ 2 ∶ 5 = AP ∶ (AP + PB)

⇒ 2(AP + PB) = 5AP

⇒ 2AP + 2PB = 5AP

⇒ 3AP = 2PB

⇒ AP/PB = 2/3

Therefore, the ratio of AP to PB is 2 ∶ 3.

138

Which of the following statements is not true ?  

  1. ((a))

    A square is a rectangle.  

  2. ((b))

    If an angle of a parallelogram is one right angle, then each of the remaining angles is also a right angle. 

  3. ((c))

    If the diagonals of a parallelogram divides it into two isosceles triangle, then the parallelogram is a rhombus 

  4. ((d))

    The diagonals. of a parallelogram are bisect each other

Show Answer
Answer: ((c))

If the diagonals of a parallelogram divides it into two isosceles triangle, then the parallelogram is a rhombus 

Explanation:

1) A square is always a rectangle is Correct. (Rectangle having two sides equal & square having all sides equal) 

2) If an angle of a parallelogram is one right angle, then each of the remaining angles is also a right angle is Correct because Sum of opposite angle of a Parallelogram is 180° 

3) A rhombus is a special type of parallelogram where all four sides are equal in length.

In a rhombus, the diagonals are perpendicular bisectors of each other, meaning they divide the rhombus into four congruent right-angled triangles.

 For example, a rectangle is a parallelogram where the diagonals divide it into two congruent isosceles triangles, but it is not a rhombus.

Hence, option 3 is incorrect.

4) The diagonals. of a parallelogram are bisect each other is correct

139

In a quadrilateral PQRS, ∠P + ∠R = 3 (∠Q + ∠S). If ∠P = 120°, then measure of ∠R is: 

  1. ((a))

    120°

  2. ((b))

    130°

  3. ((c))

    150°

  4. ((d))

    100°

Show Answer
Answer: ((c))

150°

Solution:

We are given that ∠P + ∠R = 3 (∠Q + ∠S) and ∠P = 120°.

Using the fact that the sum of the angles in a quadrilateral is 360°, we can write:

∠P + ∠Q + ∠R + ∠S = 360°

⇒ 120° + ∠Q + ∠R + ∠S = 360°

⇒ ∠Q + ∠R + ∠S = 240°

⇒ ∠Q + ∠S = 240° - ∠R 

Now, using the given relationship, we have:

∠P + ∠R = 3 (∠Q + ∠S)

⇒ 120° + ∠R = 3 (240° - ∠R)

⇒ 120° + ∠R = 720° - 3∠R

⇒ 4∠R = 600°

⇒ ∠R = 150°

Therefore, the measure of ∠R is 150°.

140

Two consecutive angles of a parallelogram are (x + 60)° and (2x + 30)°. This parallelogram can be called : 

  1. ((a))

    square 

  2. ((b))

    rectangle 

  3. ((c))

    rhombus 

  4. ((d))

    kite 

Show Answer
Answer: ((b))

rectangle 

Solution:

Given: The consecutive angles of the parallelogram be (x + 60)° and (2x + 30)°.

In a parallelogram, opposite angles are equal.

Since opposite angles of a parallelogram are equal, the opposite angles to (x + 60)° and (2x + 30)° are (x + 60)° and (2x + 30)° respectively.

and sum of all angles in any quadrilateral is 360°.

 (x + 60)°+ (2x + 30)° + (x + 60)° + (2x + 30)° = 360°

⇒ 6x + 180° = 360°

⇒ 6x = 180°

⇒ x = 30°

Substituting x = 30 into (x + 60)°, we get:

(x + 60)° = 90°

Substituting x = 30 into (2x + 30)°, we get:

(2x + 30)° = 90°

Therefore, the consecutive angles of the parallelogram are 90° and 90°.

A parallelogram with consecutive angles of 90° and 90° is a rectangle. So the parallelogram in question is a rectangle.

141

ABCD is a quadrilateral in which AB = BC and AD = DC. If ∠ABC = 100° and ∠ADC = 40°, then ∠BCD will measure.  

  1. ((a))

    140°

  2. ((b))

    100°

  3. ((c))

    110°

  4. ((d))

    105°

Show Answer
Answer: ((c))

110°

In triangle ABC, given:

AB = BC 

Opposite angles to the equal sides of the triangles are also equal.

∠BAC = ∠BCA = x (say)

again, using angle sum property of triangle.

∠B + ∠BCA + ∠BAC = 180°

⇒ x + x = 180° - 100° 

⇒ 2x = 80° 

⇒ x = 40° 

In triangle ADC, given:

AD = DC 

Opposite angles to the equal sides of the triangles are also equal.

∠DAC = ∠DCA = y (say)

again, using angle sum property of triangle.

∠D + ∠DCA + ∠DAC = 180°

⇒ y + y = 180° - 40° 

⇒ 2y = 140° 

⇒ y = 70° 

∠BCD = ∠BCA + ∠DCA = 40° + 70°= 110°

Thus, value of required angle ∠BCD is 110°

142

If Δ ABC ~ Δ QRP, ar(ΔABC)ar(PQR)=94\rm \frac{ar(\Delta ABC)}{ar(PQR)}=\frac{9}{4}, AB = 18 cm and BC = 15 cm, then PR is equal to:

  1. ((a))

    8 cm

  2. ((b))

    214\frac{21}{4} cm

  3. ((c))

    10 cm

  4. ((d))

    12 cm

Show Answer
Answer: ((c))

10 cm

Shortcut Trick

For similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides.

Ratio of areas = ar(Δ ABC) ÷ ar(Δ QRP) = 9 ÷ 4

Ratio of corresponding sides = √(9 ÷ 4) = 3 ÷ 2

Since Δ ABC ~ Δ QRP, the side BC corresponds to PR.

BC ÷ PR = 3 ÷ 2 ⇒ 15 ÷ PR = 3 ÷ 2 ⇒ PR = 10 cm.

∴ The correct answer is 10 cm.

Alternate Method

Given:

Δ ABC ~ Δ QRP

ar(Δ ABC) ÷ ar(Δ PQR) = 9 ÷ 4

AB = 18 cm

BC = 15 cm

Formula Used:

According to the Area Ratio Theorem of similar triangles, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides:

ar(Δ ABC) ÷ ar(Δ QRP) = (AB ÷ QR)2 = (BC ÷ PR)2 = (AC ÷ QP)2

Calculations:

Since Δ ABC ~ Δ QRP, the corresponding sides are:

⇒ AB corresponds to QR

⇒ BC corresponds to RP (or PR)

Using the area ratio relation:

⇒ ar(Δ ABC) ÷ ar(Δ QRP) = (BC ÷ PR)2

Substitute the given values:

⇒ 9 ÷ 4 = (15 ÷ PR)2

Taking the square root on both sides:

⇒ √(9 ÷ 4) = 15 ÷ PR

⇒ 3 ÷ 2 = 15 ÷ PR

Cross-multiplying to solve for PR:

⇒ 3 × PR = 15 × 2

⇒ 3 × PR = 30

⇒ PR = 30 ÷ 3

⇒ PR = 10 cm

Verification of Options:

Option 1 (8 cm): If PR = 8 cm, then (BC ÷ PR)2 = (15 ÷ 8)2 = 225 ÷ 64 ≈ 3.52, which does not equal the given area ratio of 9 ÷ 4 (2.25). Thus, this option is incorrect.

Option 2 (21/4 cm): If PR = 5.25 cm, then (BC ÷ PR)2 = (15 ÷ 5.25)2 ≈ 8.16, which does not equal 2.25. Thus, this option is incorrect.

Option 4 (12 cm): If PR = 12 cm, then (BC ÷ PR)2 = (15 ÷ 12)2 = 1.5625, which does not equal 2.25. Thus, this option is incorrect.

Option 3 (10 cm): If PR = 10 cm, then (BC ÷ PR)2 = (15 ÷ 10)2 = 1.52 = 2.25, which exactly matches the given area ratio of 9 ÷ 4 (2.25). Thus, this is the correct option.

∴ The correct answer is 10 cm.

Additional Information

Properties of Similar Triangles

If two triangles are similar, their corresponding angles are equal and their corresponding sides are in the same ratio.

Area Ratio Theorem

The ratio of the areas of two similar triangles is equal to the square of the ratio of any two corresponding sides, or the square of the ratio of their corresponding altitudes, medians, or angle bisectors.

Perimeter Ratio of Similar Triangles

The ratio of the perimeters of two similar triangles is equal to the ratio of their corresponding sides: Perimeter(Δ1) ÷ Perimeter(Δ2) = Side1 ÷ Side2.

143

In the figure, ABCD is a rectangle. Sum of lengths of the two diagonals is 100 cm and E is a point on AB such that OE ⊥AB. If OE = 7 cm, then length of rectangle (in cm) is :  

  1. ((a))

    24

  2. ((b))

    48

  3. ((c))

    36

  4. ((d))

    40

Show Answer
Answer: ((b))

48

Concept Used:

Both the digonals of a rectangle figure are equal in measure. Also, these digonals bisect each other. 

Explanation:-

Given that ABCD is a rectangle.

In this rectange BD and AC are the digonals. Thus,

⇒ AC = BD

But, the sum of digonals is 100 cm. Thus,

⇒ AC + BD = 100

⇒ AC + AC = 100

⇒ AC = 50 cm

Therefore,

⇒ BD = 50 cm 

Since, digonal bisecto each other. Thus,

⇒ AO = (AC / 2)

⇒ AO = (50 / 2)

⇒ AO = 25 cm

Now, in right angle triangle AOE, using the Pythgouras theorem,

AE2=AO2OE2RightarrowAE2=25272 AE2=576 AE=24 cm\Rightarrow {AE}^2=\mathrm{AO}^2-\mathrm{OE}^2 \\Rightarrow {AE}^2=25^2-7^2\ \Rightarrow {AE}^2=576\ \Rightarrow {AE}=24 \mathrm{~cm}

Since, OE bisect AE. Thus, 

⇒ AE = BE = 24 cm

Thus, the length of rectangle,

⇒ AE + AE = 24 +24 = 48 cm

Thus, the length of the rectangle is 48 cm.

Hence, the correct option is 2.

144

In a circle of radius 5 cm, two tangents are drawn from on external point A. If these two tangents are inclined to each other at an angle of 60°, then length of each tangent is : 

  1. ((a))

    53\rm \frac{5}{\sqrt3} cm

  2. ((b))

    5√2 cm

  3. ((c))

    5√3 cm

  4. ((d))

    52\rm \frac{5}{\sqrt2} cm

Show Answer
Answer: ((c))

5√3 cm

Concept use:

The tangents through an external point to a circle are equal.

the radius of a circle is perpendicular to the tangent at the point of contact.

Calculations:

From the figure,

Let PA and PC be the tangents drawn to a circle

PA and PC inclined at 60°

So, ∠APC = 60°

So, PA = PC ( The tangents through an external point to a circle are equal.)

In triangle OAP and triangle OCP,

PA = PC

OA = OC = radius of circle

OP = OP = common side

By SSS criterion, triangles OAP and OCP are Congruent.

So, ∠OAP = ∠OCP = 90°(the radius of a circle is perpendicular to the tangent at the point of contact.)

Since OA = OC = radius

∠OAP = ∠OCP

∠APC = ∠OPA + ∠OPC

So, 2∠OPA = 60°

∠OPA = 60°/2

∠OPA = 30°

In triangle OAP,

OAP is a right triangle with A at right angle.

tan 30° = OA/AP

By a trigonometric ratio of angles,

tan 30° = 1/√3

So, 1/√3 = 5/AP

AP = 5√3 cm

We know, AP = CP = 5√3 cm

Hence, the length of each tangent is 5√3 cm.

145

In a circle of radius 5 cm, point P is at a distance of 13 cm from centre O. Pair of tangents PQ and PR are drawn to the circle. Area of quadrilateral PQOR (in cm2) is :

  1. ((a))

    60

  2. ((b))

    30

  3. ((c))

    65

  4. ((d))

    75

Show Answer
Answer: ((a))

60

Concept Use:

Pythagorus theorem:

(Perpendicular)2+ (Base)2 = (Hypotenuse)2

Area of triangle = 1/2 × base × height.

Calculations:

note that OPQ and OPR are right-angled triangles (since the radius is perpendicular to the tangent at the point of contact), with hypotenuse OP = 13 cm and one side (radius) OQ = OR = 5 cm.

By the Pythagorean theorem, we can find PQ = PR = 12 cm.

The area of triangle OPQ is (1/2) ×  base ×  height = (1/2) ×  5 cm × 12 cm = 30 cm². Similarly, the area of triangle OPR is also 30 cm².

The quadrilateral PQOR consists of these two triangles OPQ and OPR, so its total area is 30 cm² + 30 cm² = 60 cm².

Hence, the correct answer option 1.

146

In the given figure, O is centre of a circle. PQ is a chord and PR is tangent at point P on circle. If ∠RPQ = 40° , then ∠POQ is :

  1. ((a))

    110°

  2. ((b))

    90°

  3. ((c))

    100°

  4. ((d))

    80°

Show Answer
Answer: ((d))

80°

Concept Used:

At the circumference of a circle, the radius and tangnet of circle are perpendicular at the point of contact. 

Explanation:-

In the given figure, we have

O = Centre of a circle

PQ = Chord of circle

PR = Tangent at point P on circle

∠RPQ = 40°

Since, at the circumference of a circle, the radius and tangnet of circle are perpendicular at the point of contact. Thus,

⇒ OP ⊥ PR

⇒ ∠OPQ = 90∘ - 40∘

⇒ ∠OPQ = 50∘ 

Also, the radius of a circle are equal. Thus,

⇒ OP = OQ

Therefore,

⇒ ∠OPQ = ∠OQP = 50∘ 

Now, in triangle OPQ using the angle sum property, we have,

POQ+OPQ+OQP=180 POQ+50+50=180 POQ=180100=80\begin{aligned} & \Rightarrow \angle P O Q+\angle O P Q+\angle O Q P=180^{\circ} \ & \Rightarrow \angle P O Q+50^{\circ}+50^{\circ}=180^{\circ} \ & \Rightarrow \angle P O Q=180^{\circ}-100^{\circ}=80^{\circ} \end{aligned}

Thus, the value of ∠POQ is 80 degree. 

Hence, the correct option is 4.

147

In the figure, AB and CD are equal chords of a circle with centre O. If AB = (7x + 6) cm, CD = (4x + 9) cm, ∠AOB = (12y - 4x + 3)° and ∠COD = (10y + 11)°, then value of x and y are : 

  1. ((a))

    x = 2, y = 3

  2. ((b))

    x = 1, y = 6

  3. ((c))

    x = 1, y = 4

  4. ((d))

    x = 3, y = 6

Show Answer
Answer: ((b))

x = 1, y = 6

Concept Used:

When the two chords of the circle are equal, then the angle subtended by the chords of the circle at the centre are equal.

Explanation:-

In the figure, AB and CD are equal chords of a circle with centre O.

Given that

AB = (7x + 6) cm,

CD = (4x + 9) cm,

Since, AB and CD are equal chords of the circle. Thus,

⇒ AB = CD

⇒ (7x + 6) = (4x + 9) 

⇒ 3x = 3

⇒ x = 1 cm 

Since, chords are equal. Thus, the angle made on centre by it will also be equal. Thus,

⇒ ∠AOB = ∠COD 

⇒ (12y - 4x + 3)° = (10y + 11)°

⇒ (12y - 4 × 1 + 3)° = (10y + 11)°

⇒ 2y = 12

⇒ y = 6

Thus, the value of x and y are 1 and 6 respectively. 

Hence, the correct option is 2.

148

In a cyclic quadrilateral ABCD, if ∠ADB = 30° and ∠DCA = 70°, then ∠DAB is :

  1. ((a))

    80°

  2. ((b))

    90°

  3. ((c))

    100°

  4. ((d))

    110°

Show Answer
Answer: ((a))

80°

Concept Used:

The sum of all the three angles of a triangle is equal to 180 degrees.

Explanation:-

In the given cyclic quadrilateral ABCD, we have,

∠ADB = 30° and ∠DCA = 70°

We know that the angle subtended by the same chord are equal. Thus,

⇒ ∠DCA = ∠DBA =80∘ 

Now, In triangle ADB using the angle sum property we have, ⇒ ∠ADB + ∠DBA + ∠DAB = 180∘

⇒ ∠DAB = 180∘ − 70∘ − 30∘ = 80∘.

Thus, the measure of ∠DAB is 80∘. 

Hence, the correct option is 1.

149

In the figure, O is the centre of a circle and AB, BC are two chords of a circle. If ∠BCO = 40° and OE || BC, the values of x and y are :

  1. ((a))

    x = 50°. y = 40°

  2. ((b))

    x = 40°. y = 30°

  3. ((c))

    x = 25°. y = 20°

  4. ((d))

    x = 25°. y = 25°

Show Answer
Answer: ((c))

x = 25°. y = 20°

Concept Used:

The angle at the centre of a circle subtended by a chord is double of that at the circumference

Explanation:-

In the given figure,

AD ⊥ BC and OE ⊥ AD 

Also, ∠BCO = 40°

Then 

∠DOC = 180° - 90° - 40° = 50°

⇒ ∠DOC + ∠EOC = 90°

⇒ ∠EOC = 90° - 50° = 40°

⇒ ∠EOC = 40°

Then

⇒ ∠EBC = y = 20° [The angle at the centre of a circle subtended by a chord is double that at the circumference]

⇒ ∠DOC = 50° = ∠BOD [In △BOC, BO = CO]

So

 ∠BOD = 50°

So

∠BAD = x = 50/2 = 25°  [The angle at the centre of a circle subtended by a chord is double that at the circumference]

Thus, the values of x and y are 25° and 20° respectively.

Hence, the correct option is 3.

150

Area of an isosceles right triangle is 8 cm2. Length of hypotenuse (in cm) is :

  1. ((a))

    16\sqrt{16}

  2. ((b))

    32\sqrt{32}

  3. ((c))

    48\sqrt{48}

  4. ((d))

    24\sqrt{24}

Show Answer
Answer: ((b))

32\sqrt{32}

Concept Used:

According to the Pythgours theorem, for a right-angled triangle, the square of its hypotenuse is equal to addition of the squares of the remaining two sides. 

Explanation:-

Suppose, that there is isoscales right angle triangle ABC, where

⇒ AB = BC           ......(1)

⇒ AC = hypontenuse side

Now, we know that, area of triangle ABC,

⇒ A = (1 / 2) × base × height

⇒ 8 = (1 / 2) × AB × BC

⇒ 8 = (1 / 2) × AB × AB    (From equation 1)

⇒ 16 = AB2

⇒ AB = 4 cm

Now, in the above triangle from the pythagours theorem,

⇒ AC2 = AB2 + BC2

⇒ AC2 = AB2 + AB2

⇒ AC2 = 42 + 42

⇒ AC2 = 32

⇒ AC = √(32) cm 

Thus, the length of hypotenuse is √(32) cm.

Hence, the correct option is 1.

151

The side of a rhombus is 30 m and its one diagonal is 48 m. Area of rhombus (in m2) is :

  1. ((a))

    648

  2. ((b))

    864

  3. ((c))

    432

  4. ((d))

    718

Show Answer
Answer: ((b))

864

Concept Used:

The area of a rhombus when one of its side (a) and one f its digonal (p) is given can be calculated with following formula.

A=12p4a2p2A=\frac{1}{2} p \sqrt{4 a^2-p^2}

Explanation:-

Given side of the rhombus, a = 30 m

Length of its one diagonal p = 48 m.

So, the area of rhombus,

A=12p4a2p2 A=12(48)4(30)2(48)2 A=2436002304 A=24×36 A=864 m2\Rightarrow A=\frac{1}{2} p \sqrt{4 a^2-p^2}\ \Rightarrow A=\frac{1}{2} (48) \sqrt{4 (30)^2-(48)^2}\ \Rightarrow A=24 \sqrt{3600-2304}\ \Rightarrow A=24 \times36\ \Rightarrow A=864\ \rm m^2

Thus, the area of rhombus (in m2) is 864 m2

Hence, the correct option is 2.

152

Two circular parks are of radius 16 m and 12 m. A third park is to be built such that its area is equal to the sum of earlier parks. The diameter of new park (in m) is :  

  1. ((a))

    28

  2. ((b))

    40

  3. ((c))

    34

  4. ((d))

    30

Show Answer
Answer: ((b))

40

Concept Used:

The area of circle is equal to the value which is obtained after multipling π with square of the radius of circle. The area of circle can be obtained with following formula,

⇒ A = πr2

Here, r is the radius of the circle.

Explanation:-

Given information,

Radius of first park, r1 = 16 m

Radius of second park, r2 = 12 m

Since, the area of third park is sum of these two parks. So, area of third park,

⇒ A = π (r1)+ π (r2)2 

⇒ A = π [ 162 + 122 ] 

⇒ A = π [ 256 +144 ] 

⇒ A = 400π m2

Suppose, the diameter of third park is D m. Thus,

 ⇒ A = (πD2) / 4

⇒ 4× 400π= πD2

⇒ D2 = 402

⇒ D = 40 m

Thus, the diameter of new park is 40 m. 

Hence, the correct option is 2.

153

In a circle of radius 14 cm, the length of the arc is 22 cm. The area of segment corresponding to this arc (in cm2) is :

  1. ((a))

    48

  2. ((b))

    98

  3. ((c))

    56

  4. ((d))

    66

Show Answer
Answer: ((c))

56

Concept Used:

The following formula is used to find the area of the segment of a circle.

 Area of segment = Arc length  Perimeter of circle × Area of circle \text { Area of segment }=\frac{\text { Arc length }}{\text { Perimeter of circle }} × \text { Area of circle }

Explanation:-

Radius of the given circle r = 14 cm

Length of the arc L = 22 cm

Suppose, θ is the angle of arc. Thus,

L=2πr×θ360 22=2×227×14×θ360 θ=90o⇒ L= 2\pi r\times \dfrac{\theta }{360}\ ⇒ 22= 2\times \dfrac{22}{7} \times 14\times \dfrac{\theta }{360}\ ⇒ \theta = 90^o

Now the area of sector OAB,

A=12×OA×OB A=(12×14×14)cm2 A=98 cm2⇒ A=\frac{1}{2} \times O A \times O B\ ⇒ A=\left(\frac{1}{2} \times 14 \times 14\right) \mathrm{cm}^2\ ⇒ A=98 \mathrm{~cm}^2

Here, perimeter of the circle,

⇒ P = 2πr

⇒ P = 2 × (22 / 7) × 14

⇒ P = 88 cm  

Area of circle,

⇒ A1 = πr2

⇒ A1 = (22 / 7) × (14)2

⇒ A1 = 616 cm2  

So, area of segment OADBO,

 Area of segment = Arc length  Perimeter of circle × Area of circle \text { Area of segment }=\frac{\text { Arc length }}{\text { Perimeter of circle }} × \text { Area of circle }

 Area of segment =2288×616  Area of segment =154 cm2\text { Area of segment }=\dfrac{22}{88}\times616\ \text { Area of segment }=154 \rm \ cm^2

Thus, the area of sector ADBA,

⇒ 154 - 98 = 56 cm2 

Thus, the area of segment corresponding to this arc (in cm2) is 56 cm2.

Hence, the correct option is 3.

154

Four circular card board pieces of radii 7 cm are placed on a paper in such a way that each piece touch other two pieces (see figure). The area of the shaded region (in cm2) is :

  1. ((a))

    28

  2. ((b))

    35

  3. ((c))

    42

  4. ((d))

    49

Show Answer
Answer: ((c))

42

Concept Used:

Shaded region area of the given figure is the difference of area of square made among the center of circle and 4 quater circles.

Explanation:-

Radius of circular card board = 7 cm

Draw a square ABCD from the center of the circle as shown in figure below.

The side of this square,

⇒ AB = BC = CD = AB = 7 + 7 = 14 cm

Area of this square,

⇒ As = 142

⇒ As = 196 cm2

In the figure we can see that there are 4 quater circle are there in the square ABCD. The area of all this quater circle,

Ac=4×14π(7)2 Ac=227×(7)2 Ac=154 cm2⇒ A_c = 4\times \dfrac{1}{4}\pi(7)^2\ ⇒ A_c =\dfrac{22}{7}\times (7)^2\ ⇒ A_c =154 \rm \ cm^2

Now, the shaded region is the difference of area of square and area of 4 quater circles. Thus, the area of shaded reagion,

⇒ Ashaded = As - Ac 

⇒ Ashaded = 196 - 154

⇒ Ashaded = 42 cm2

Thus, ​the area of the shaded region is 42 cm2.

Hence, the correct option is 3.

155

A ring is formed between two concentric circles. The radius of inner circle is 17.5 cm and area of outer circle is 1386 cm2. Width of the ring is :

  1. ((a))

    3.5 cm

  2. ((b))

    3.2 cm

  3. ((c))

    3.1 cm

  4. ((d))

    3.6 cm

Show Answer
Answer: ((a))

3.5 cm

Shortcut Trick

Area of outer circle = 1386 cm2

πR2 = 1386 → R2 = 1386 ÷ (22/7) = 441

Outer radius (R) = √441 = 21 cm

Width of the ring = Outer radius (R) − Inner radius (r)

Width = 21 − 17.5 = 3.5 cm

∴ The correct option is A.

Alternate Method

Given:

Inner radius (r) = 17.5 cm

Area of outer circle = 1386 cm2

Formula Used:

Area of circle = πR2 (where π ≈ 22/7)

Width of ring = R − r

r = 17.5 R = 21

Width (3.5 cm) Concentric Circles (Ring)

Calculations:

⇒ Area of outer circle = 1386 cm2

⇒ πR2 = 1386

⇒ (22 / 7) × R2 = 1386

⇒ R2 = (1386 × 7) ÷ 22

⇒ R2 = 63 × 7 = 441

⇒ R = √441 = 21 cm

⇒ Width of the ring = R − r

⇒ Width = 21 − 17.5 = 3.5 cm

∴ The correct option is A.

Additional Information

Area of Ring

The area between two concentric circles is given by A = π(R2 − r2), where R is the outer radius and r is the inner radius.

Concentric Circles

Circles with a common center but different radii are called concentric circles.

Circumference of Circle

The distance around the boundary of a circle is C = 2πr.

156

If each edge of a cube is increased by 50%, the percentage increase in volume of the cube is : 

  1. ((a))

    225.5%

  2. ((b))

    150%

  3. ((c))

    237.5%

  4. ((d))

    125%

Show Answer
Answer: ((c))

237.5%

Concept Used:

The volume of a cube is the three times the side of the cube. The volume of the cube with side x is,

⇒ V =  x × x × x = x3

Explanation:-

Suppose, that the side of the cube = a 

Then, the volume of this cube = a3

New side of cube when increased 50%,

New Side =a×100+50100 New Side=a×150100=32a\text {New Side }=a \times \frac{100+50}{100} \ \text {New Side}=a \times \frac{150}{100}=\frac{3}{2} a

Therefore, the new surface area,

 New Volume =(32a)3  New Volume=278a3\Rightarrow \text { New Volume }=(\dfrac{3}{2}a)^3 \ \Rightarrow \text { New Volume} = \frac{27}{8} a^3

Increase in the volume,

V%=278a3a3a3×100 V%=237.5%\Rightarrow V\%= \dfrac{\frac{27}{8} a^3-a^3}{a^3}\times 100\ \Rightarrow V\%= 237.5\%

Thus, the percentage increase in volume of the cube is 237.5%.

Hence, the correct option is 3.

157

Two cones with same base diameter 14 cm and height 15 cm are joined together along their bases. The volume of shape so formed is : 

  1. ((a))

    860 cm3

  2. ((b))

    1540 cm3

  3. ((c))

    6160 cm3

  4. ((d))

    770 cm3

Show Answer
Answer: ((b))

1540 cm3

Concept Used:

The volume of the cone is the space which is occupied by it. It can be calculated with the following formula,

V=13πr2h⇒ V =\dfrac{1}{3} \pi r^2h

Where V is the volume, r is the radius and h is the height of the cone.

Explanation:-

Given that the diameter of the cone d= 14 cm

So, the radius of the cone, r = 14 / 2 = 7 cm

Also, the height of the cone = 15 cm

Both the cones are joined together along their bases. The below figure represents the given cones.

Now, the volume of this figure will be equal to the volume of both the cones. Volume of both cones,

V=13πr2h+13πr2h V=2×23πr2h V=23×227×(7)2(15) V=1540 cm2\Rightarrow V= \dfrac{1}{3}\pi r^2h+\dfrac{1}{3}\pi r^2h\ \Rightarrow V=2\times \dfrac{2}{3}\pi r^2h\ \Rightarrow V= \dfrac{2}{3}\times\dfrac{22}{7} \times(7)^2(15)\ \Rightarrow V=1540 \rm\ cm^2

Thus, the volume of shape so formed is 1540 cm2

Hence, the correct option is 2.

158

A solid metallic hemisphere of radius 8 cm is melted and recast into small spheres of radius 2 cm each. Number of small spheres is : 

  1. ((a))

    8

  2. ((b))

    16

  3. ((c))

    64

  4. ((d))

    32

Show Answer
Answer: ((d))

32

Concept Used:

The volume of metals remains the same after recasting. When a different small solids are melted to make a big solid, then the volume of the bigger solid will be the sum of each small solid.

Explanation:-

Given, radius of hemisphere R = 8 cm

Radius of spheres r = 2 cm

Suppose, the number of small spheres is n. Thus,

⇒ Volume of hemisphere = n × volume of sphere

23πR3=n×43πr3 23π×83=n×43π×23 n=32\Rightarrow \dfrac{2}{3}\pi R^3=n\times \dfrac{4}{3}\pi r^3\ \Rightarrow \dfrac{2}{3}\pi \times 8^3= n\times \dfrac{4}{3}\pi\times 2^3\ \Rightarrow n =32

Thus, the number of small spheres is 32.

Hence, the correct option is 4.

159

The radii of bases of cone and cylinder are in the ratio 4 ∶ 3 and their heights are in the ratio 3 ∶ 2, then ratio between the volume of cone to volume of cylinder is : 

  1. ((a))

    9 ∶ 8

  2. ((b))

    8 ∶ 9

  3. ((c))

    7 ∶ 5

  4. ((d))

    5 ∶ 7

Show Answer
Answer: ((b))

8 ∶ 9

Concept Used:

The formula to calculate the volume of cone is,

v=13πr2h⇒ v=\dfrac{1}{3}\pi r^2 h

Where, v is the volume, r is the radius and h is the height of the cone.

The formula to calculate the volume of the cylinder is,

V=πR2H⇒ V= \pi R^2 H

Where, V is the volume, R is the radius and H is the height of the cylinder.

Explanation:-

Given that the radii of bases of cone and cylinder are in the ratio 4 ∶ 3. Thus,

rR=43\Rightarrow \dfrac{r}{R}=\dfrac{4}{3}

Also, their heights are in the ratio 3 ∶ 2. Thus,

hH=32\Rightarrow \frac{\mathrm{h}}{\mathrm{H}}=\frac{3}{2}

So, the ratio between the volume of cone to volume of cylinder is,

vV=13πr2hπR2H vV=13×(rR)2×(hH) vV=13×(43)2×(32) vV=13×(43)2×(32) vV=89\Rightarrow \dfrac{v}{V}=\frac{\frac{1}{3}\pi r^2 h}{ \pi R^2 H}\ \Rightarrow \dfrac{v}{V}=\dfrac{1}{3} \times\left(\frac{\mathrm{r}}{\mathrm{R}}\right)^2 \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right) \ \Rightarrow \dfrac{v}{V}=\dfrac{1}{3}\times\left(\frac{4}{3}\right)^2 \times\left(\frac{3}{2}\right)\ \Rightarrow \dfrac{v}{V}=\dfrac{1}{3}\times\left(\frac{4}{3}\right)^2 \times\left(\frac{3}{2}\right)\ \Rightarrow \dfrac{v}{V}=\dfrac{8}{9}

Thus, the ratio between the volume of cone to the volume of cylinder is 8 : 9.

Hence, the correct option is 2.

160

The largest sphere is carved out of a solid cube of side 21 cm. The surface area of sphere (in cm2) is:

  1. ((a))

    1386

  2. ((b))

    693

  3. ((c))

    1848

  4. ((d))

    924

Show Answer
Answer: ((a))

1386

Concept Used:

Surface area of a sphere can be calculated with the following formula,

SA=4πr2⇒S_A =4\pi r^2

Where V is the volume and r is the radius of the sphere. 

Explanation:-

Since, the largest sphere is carved out of a solid cube. Thus, the diameter of sphere and side of cube will be equal in length.

So the diameter of the sphere will be 21 cm. Now, the radius of sphere,

⇒ r = 21 / 2 = 10.5 cm

Surface area of this sphere,

SA=4πr2 SA=4×227×(212)2 SA=1386 cm3⇒S_A =4\pi r^2\ ⇒S_A = 4\times \dfrac{22}{7} \times (\dfrac{21}{2})^2\ ⇒ S_A=1386 \rm \ cm^3

Thus, the surface area of the sphere is 1386 cm2.

Hence, the correct option is 1.

161

The sum of the radius of base and height of a solid right circular cylinder is 37 cm. If the total surface area of the solid cylinder is 1628 cm2, the volume of cylinder (in cm3) is:

  1. ((a))

    3680

  2. ((b))

    4620

  3. ((c))

    6420

  4. ((d))

    5640

Show Answer
Answer: ((b))

4620

Concept Used:

Total surface area of cylinder = 2πr(r + h)

 and Volume of the cylinder = πr2h

Where r and h are the radius and heigh of cylinder.

Calculation:

Let the radius of the cylinder be 'r' and the height be 'h'. Then, we have:

r + h = 37 . . .(1) 

Total surface area of cylinder = 2πr(r + h) = 1628 cm2 . . . (2) (given)

Substituting equation (1) in (2), we get:

⇒ 2πr × 37 = 1628

⇒ 74 ×22 × r ÷ 7= 1628

⇒ 74 × 22 × r = 11396

⇒ r = 11396 / (74 × 22)

⇒ r = 7

Using equation (1), we get:

h = 37 - 7

⇒ h = 30 cm

Therefore, the volume of the cylinder = πr2h

 ⇒ Volume= π × 7× 30 

⇒ Volume= 22 × 7 × 30 = 4620 cm3

Hence, the volume of the cylinder is 4620 cm3.

162

A histogram is to be drawn for the following frequency distribution 

Class Interval5-1010-1515-2525-4545-75
Frequency61210815
<br>

The adjusted frequency for class interval 15 - 25 will be :

  1. ((a))

    2

  2. ((b))

    5

  3. ((c))

    3

  4. ((d))

    4

Show Answer
Answer: ((b))

5

Formula Used:

Adjusted frequency = (Frequency of the class interval × Minimum Class Width)/ Class width of the required interval

Calculation:

For class interval 15 - 25, 

Class width = upper limit of the class - lower limit of the class

⇒ Class width = 25 - 15 = 10

Frequency of that interval = 10

Minimum class width here is for the interval 5 - 10 = 5

Adjusted frequency = (10 × 5)/10 = 5

Therefore, the adjusted frequency for the class interval 15 - 25 is 5.

163

The mean of 100 observations is 60. If one of observation 60 is replaced by 210, the new mean will be:

  1. ((a))

    605

  2. ((b))

    61

  3. ((c))

    61.5

  4. ((d))

    62

Show Answer
Answer: ((c))

61.5

Solution:

The mean of 100 observations is 60, which means the sum of all 100 observations is:

100 x 60 = 6000

If we replace one observation of 60 by 210, the new sum of observations is = 6000 - 60 + 210 = 6150

Now, the total number of observations is still 100. Therefore, the new mean can be calculated as:

New mean = (sum of all observations) / (total number of observations)

New mean = 6150 / 100

New mean = 61.5

Hence, the new mean will be 61.5.

164

The width of each of five continuous class intervals in a frequency distribution is 5 and lower class limit of lowest class interval is 25. The upper class limit of the highest class interval will be : 

  1. ((a))

    40

  2. ((b))

    55

  3. ((c))

    45

  4. ((d))

    50

Show Answer
Answer: ((d))

50

Solution:

Given that the width of each of the five continuous class intervals in a frequency distribution is 5 and the lower class limit of the lowest class interval is 25.

Let's represent the class intervals in terms of their lower limits:

First-class interval: 25 - a

Second class interval: a - b

Third class interval: b - c

Fourth class interval: c - d

Fifth class interval: d - f

Since the class interval width is 5, we know that the difference between the lower and upper-class limits of each interval is 5.

Therefore, the upper-class limit of the first class interval will be:

25 + 5 = 30

Similarly, the lower and upper-class limits of the remaining class intervals are:

Second class interval: 30 - 35

Third class interval: 35 - 40

Fourth class interval: 40 - 45

Fifth class interval: 45 - 50

Thus, the upper-class limit of the highest class interval is 50.

165

The mode of the following frequency distribution is : 

Class IntervalFrequency
0-108
10-2010
20-3010
30-4016
40-5012
50-606
60-707
  1. ((a))

    34

  2. ((b))

    36

  3. ((c))

    38

  4. ((d))

    35

Show Answer
Answer: ((b))

36

Formula Used:

Mode = L + [(f1 - f0)/(2f1 - f0 - f2)] × h

where:

L = lower limit of the modal class

h = width of the class interval

f1 = frequency of the modal class

f0 = frequency of the class preceding the modal class

f2 = frequency of the class succeeding the modal class

and modal class is the class interval of the highest frequency.

Calculation:

In this case, the modal class is 30-40 with a frequency of 16. The frequency of the class preceding the modal class is 10 and the frequency of the class succeeding the modal class is 12. and 30 is the lower limit of the modal class.

Mode = 30 + ((16 - 10)/(2 × 16 - 10 - 12)) × 10

⇒ Mode = 30 + (6/10) × 10

⇒ Mode = 36

Therefore, the mode of the given frequency distribution is 36.

166

For the frequency distribution : 

Age (in years)Frequency
0-105
10-2025
20-3025
30-4018
40-507
<br>

median is :

  1. ((a))

    25

  2. ((b))

    26

  3. ((c))

    22

  4. ((d))

    24

Show Answer
Answer: ((d))

24

Formula Used:

Median = L + ((n/2 - cf)/f) × w

where L is the lower limit of the median class,

n is the total frequency,

cf is the cumulative frequency of the class interval preceding the median class,

f is the frequency of the median class, and

w is the width of each class interval.

Calculation:

Class IntervalFrequencyCumulative Frequency
0-1055
10-202530
20-302555
30-401873
40-50780
<br>

The total frequency is 80(=n), which is an even number and n/2 = 40.

as n/2 lies between 30 and 55, 20-30 is the median class of the data.

L = 20, cf = 30, f = 25, w = 30 - 20 = 10

Median = 20 + ((40 - 30)/25) × 10

⇒ Median = 20 + (10/25) × 10

⇒ Median = 20 + 4 = 24

Thus, a median of the given data is 24.

167

The point of intersection of 'the less than type’ and of the ‘more than type' ogives is : (29.6, 45.2). This indicates : 

  1. ((a))

    Median = 29.6 

  2. ((b))

    Mode = 39.9 

  3. ((c))

    Median = 45.2 

  4. ((d))

    Mean = 29.6  

Show Answer
Answer: ((a))

Median = 29.6 

Fact:

An ogive is a graph that represents the cumulative frequency distribution of a set of data. It is a type of line graph in which the horizontal axis represents the class intervals of the data, and the vertical axis represents the cumulative frequencies.

The given point of intersection (29.6, 45.2) represents the point where the cumulative frequency curve of the less than type intersects with the cumulative frequency curve of the more than type. This point indicates the median of the given data.

Thus, 29.6 is the median of the data.

168

A bag contains 12 balls out of which x are red. One ball is drawn at random from the bag and p is the probability that it is a red ball. Now 6 more red balls are added to the bag and the probability of drawing a red ball is 2 p. Number of red balls is : 

  1. ((a))

    6

  2. ((b))

    2

  3. ((c))

    4

  4. ((d))

    3

Show Answer
Answer: ((d))

3

Solution:

Let the number of red balls in the bag be x.

Probability of drawing a red ball from the bag initially = x/12

After 6 more red balls are added, the total number of red balls in the bag becomes x + 6.

New probability of drawing a red ball from the bag = (x + 6)/18

According to the problem, the new probability of drawing a red ball is twice the initial probability, i.e.,

2p = (x + 6)/18

⇒ 36p = x + 6

Also, we know that the initial probability of drawing a red ball is:

p = x/12

⇒ 12p = x

Substituting the value of x in terms of p in the equation 36p = x + 6, we get:

36p = 12p + 6

⇒ 24p = 6

⇒ p = 1/4

Substituting the value of p in the equation 12p = x, we get:

x = 3

Therefore, the bag initially had 3 red balls.

169

From the month of July, whose first day is Monday, a day is selected at random. The probability that it is not a Monday is :  

  1. ((a))

    631\frac{6}{31}

  2. ((b))

    56\frac{5}{6}

  3. ((c))

    2631\frac{26}{31}

  4. ((d))

    2531\frac{25}{31}

Show Answer
Answer: ((c))

2631\frac{26}{31}

Solution:

There are 31 days in July, out of which generally at least 4 days are Mondays.

But as months starts with Monday, it must have 5 Mondays.

Therefore, there are 26 days that are not Mondays. The probability of selecting a day that is not a Monday is 26/31.

Hence, the probability that a day selected at random from July is not a Monday is 26/31.

170

A biased dice was rolled 600 times. The frequencies of the various outcomes are given in the following table : 

Outcome123456
Frequency160130120506080
<br>

Now the dice is rolled once, the probability of getting a number which is a perfect square is :

  1. ((a))

    112\frac{1}{12}

  2. ((b))

    1330\frac{13}{30}

  3. ((c))

    415\frac{4}{15}

  4. ((d))

    720\frac{7}{20}

Show Answer
Answer: ((d))

720\frac{7}{20}

Solution:

The perfect squares among the numbers from 1 to 6 are 1 and 4.

The total number of outcomes when the dice is rolled once is 6.

The probability of getting a 1 or 4 is the sum of the frequencies of these outcomes divided by the total number of outcomes, i.e.,

P(getting a perfect square) = (160 + 50)/600

⇒ P = 210/600

⇒ P = 21/60

⇒ P = 7/20

Therefore, the probability of getting a number which is a perfect square is 7/20.

171

A school has 4 clubs A, B, C and D. IX class has 30 students. Its 6 students are in club A, 7 in club B, 2 in club C and rest in D. A single student is selected at random from the class to act as class monitor. The probability that the selected student is from club A or D is:  

  1. ((a))

    710\frac{7}{10}

  2. ((b))

    12\frac{1}{2}

  3. ((c))

    15\frac{1}{5}

  4. ((d))

    1730\frac{17}{30}

Show Answer
Answer: ((a))

710\frac{7}{10}

Solution:

Total number of students in class IX = 30

Number of students in club A = 6

Number of students in club B = 7

Number of students in club C = 2

Number of students in club D = 30 - 6 - 7 - 2 = 15

The probability of selecting a student from club A or D is given by:

P(A or D) = P(A) + P(D)

We know that P(A) = Number of students in club A / Total number of students in class IX

So, P(A)= 6/30 = 1/5

Similarly, P(D) = 15/30 = 1/2

Therefore, P(A or D) = P(A) + P(D) = 1/5 + 1/2 = 7/10

Hence, the probability that the selected student is from club A or D is 7/10.

172

A box contains discs numbered from 10 to 90. If one disc is drawn at random from the box, the probability that number on disc is prime number and both digits of the number are also prime numbers, is : 

  1. ((a))

    19\frac{1}{9}

  2. ((b))

    481\frac{4}{81}

  3. ((c))

    681\frac{6}{81}

  4. ((d))

    18\frac{1}{8}

Show Answer
Answer: ((b))

481\frac{4}{81}

Solution:

There are 20 prime numbers between 10 and 90:11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89.

Out of these, the two-digit primes are:  23, 37, 53, 73.

Therefore, there are 4 two-digit primes among the discs numbered from 10 to 90.

The total number of discs in the box is 81 (90 - 10 + 1).

Hence, the probability of drawing a disc with a two-digit prime number is: 4/81.

173

All the red face cards are removed from a pack of 52 playing cards. A card is drawn at random from the remaining cards, after reshuffling them. The probability that the card drawn is a face card is : 

  1. ((a))

    322\frac{3}{22}

  2. ((b))

    211\frac{2}{11}

  3. ((c))

    323\frac{3}{23}

  4. ((d))

    223\frac{2}{23}

Show Answer
Answer: ((c))

323\frac{3}{23}

Solution:

There are 12 face cards in a deck of 52 playing cards, which includes 3 face cards (jack, queen, and king) each for the 4 suits (hearts, diamonds, clubs, and spades). There are 6 red-face cards and 6 black-face cards.

After removing 6 red face cards, the remaining cards are 46.

Remaining face cards 6

The probability of drawing a face card now is 6/46 = 3/23

Therefore, the probability of drawing a face card from the remaining deck is 3/23.

174

If cosec θ + cot θ = p, then p21p2+1\rm\frac{p^2-1}{p^2+1} equal:

  1. ((a))

    cos θ

  2. ((b))

    sin θ

  3. ((c))

    tan θ

  4. ((d))

    cot θ

Show Answer
Answer: ((a))

cos θ

Formula Used:

(a + b)² = a² + 2ab + b²,

sin2 θ+cos² θ = 1 and 1 - sin2 θ = cos² θ

cot θ = cos θ/sin θ and cosec θ = 1/sin θ

and for equations a/b = c/d

Using the Componendo and Dividendo rule, we get 

(a + b)/(a - b) = (c + d)/(c - d)

or (a-b)/(a+b) = (c-d)/(c+d)

Calculation:

1/sin θ + cos θ/sin θ = p

⇒ (1+cos θ)/sin θ = p/1

Squaring both sides of the given equation:

(1 + cos θ)²/sin2 θ = p²/1

⇒ (1 + cos² θ + 2cos θ)/sin2 θ = p²/1

Applying Componendo and Dividendo, we get

(1 + cos² θ + 2cos θ - sin2 θ)/(1 + cos² θ + 2cos θ + sin2 θ) = (p²-1)/(p2+1)

⇒ (1 - sin2 θ + cos² θ + 2cos θ )/(1 + cos² θ+ sin2 θ + 2cos θ ) = (p²-1)/(p2+1)

⇒ (cos² θ + cos² θ + 2cos θ )/(1 + 1 + 2cos θ ) = (p²-1)/(p2+1)

⇒ (2cos² θ + 2cos θ )/(2 + 2cos θ ) = (p²-1)/(p2+1)

⇒ 2cos θ(cos θ + 1 )/2(1 + cos θ ) = (p²-1)/(p2+1)

⇒ cos θ = (p²-1)/(p2+1)

Thus, value of  (p²-1)/(p2+1) is cos θ.

175

If tan θ - cot θ =5, then value of tan3 θ - cot3 θ is :

  1. ((a))

    135

  2. ((b))

    110

  3. ((c))

    115

  4. ((d))

    140

Show Answer
Answer: ((d))

140

Formula Used:

tan³ θ - cot³ θ = (tan θ - cot θ)(tan² θ + cot² θ + tan θcot θ) 

tan²θ + cot²θ = 1 

 tan θcot θ = 1

(a - b)2 = a2+b2-2ab

Calculation:

tan θ - cot θ = 5

Squaring both sides, we get:

(tan θ - cot θ)² = 25

tan²θ - 2tan θ cot θ + cot²θ = 25

tan²θ + cot²θ - 2 = 25

tan²θ + cot²θ = 27

Now, 

tan³ θ - cot³ θ = (tan θ - cot θ)(tan² θ + cot² θ + tan θcot θ)

tan³ θ - cot³ θ =5(27 + 1)

tan³ θ - cot³ θ =5 × 28

tan³ θ - cot³ θ =140

Therefore, the value of tan³ θ - cot³ θ is 140.

176

In a right angled triangle ABC, ∠B = 90° and ∠C is acute angle. Value of sin C + cos C is :  

  1. ((a))

    more than 1 

  2. ((b))

    1

  3. ((c))

    less than 1 but more than 12\frac{1}{2}

  4. ((d))

    12\frac{1}{2}

Show Answer
Answer: ((a))

more than 1 

Concept Used:

The sum of two sides of a triangle is always greater than its third side.

Explanation:-

Given that in the right-angled triangle ABC, ∠B = 90°.

We know that sum of two sides of a triangle is greater than the third side. Thus, in ΔABC,

⇒ AB + BC > AC 

Now, the trigonometry ratios we have,

⇒ sin C = Perpendicular / Hypotenuse = AB / AC

⇒ cos C = Base / Hypotenuse = BC / AC

Required value,

sinC+cosC=ABAC+BCAC sinC+cosC=AB+BCAC sinC+cosC>ACAC sinC+cosC>1\Rightarrow \sin C+\cos C =\frac{AB}{AC}+\frac{BC}{A C} \ \Rightarrow \sin C+\cos C =\frac{{AB}+{BC}}{{AC}}\ \Rightarrow \sin {C}+\cos {C}>\frac{\mathrm{AC}}{\mathrm{AC}}\ \Rightarrow \sin C+\cos {C}>1

Thus, the value of sin C + cos C is more than 1.  

Hence, the correct option is 1.

177

Value of cos2 θ (1 + tanθ) is:

  1. ((a))

    cos4 θ

  2. ((b))

    cos2 θ.sin2 θ

  3. ((c))

    1

  4. ((d))

    cos θ

Show Answer
Answer: ((c))

1

Formula Used:

We know that tan²θ + 1 = sec²θ 

and sec²θ = 1/cos²θ

Calculation:

Using the identity, 1 + tan²θ = sec²θ

⇒ cos²θ (1 + tan²θ) = cos²θ (sec²θ) = cos²θ / cos²θ = 1

Hence, the value of cos²θ (1 + tan²θ) is equal to 1.

178

If sin θ + cos θ =1, then value of 4 sin θ.cos θ is : 

  1. ((a))

    1

  2. ((b))

    23\frac{2}{3}

  3. ((c))

    32\frac{3}{2}

  4. ((d))

    0

Show Answer
Answer: ((d))

0

Concept Used:

2 sin θ.cos θ = sin 2θ and sin²θ + cos²θ = 1

2 sin θ.cos θ = sin 2θ

Multiplying both sides with 2, we get

4 sin θ.cos θ = 2 sin 2θ

Calculation:

Given, sin θ + cos θ = 1

Squaring both sides, we get

(sin θ + cos θ)² = 1²

⇒ sin²θ + cos²θ + 2sinθcosθ = 1

⇒ 1 + 2sinθcosθ = 1

⇒ 2sinθcosθ = 1 - 1

⇒ 2sinθcosθ = 0

Multiplying both sides by 4, we get

4 sin θ.cos θ = 0

Therefore, the value of 4 sin θ.cos θ is 0.

179

A kite is flying at a height of 30 m from the ground. The length of string from kite to the ground is 60 m. Assuming that there is no slackness in the string, the angle of elevation of kite at the ground is:  

  1. ((a))

    90°

  2. ((b))

    30°

  3. ((c))

    45°

  4. ((d))

    60°

Show Answer
Answer: ((b))

30°

Concept Used:

sin θ = Opposite side/Hypotenuse

Calculation:

Let us consider the right-angled triangle formed by the kite, the string and the ground. The height of the kite from the ground is the length of the perpendicular drawn from the kite to the ground. The length of the string is the hypotenuse of the triangle. Let the angle of elevation of the kite at the ground be θ.

In the right-angled triangle ABC, we have:

AC = height of the kite = 30 m

AB = length of the string = 60 m

⇒ sin θ = height of the kite / length of the string

⇒ sin θ = 30 / 60

⇒ sin θ = 1/2

⇒ θ = 30°

Therefore, the angle of elevation of the kite at the ground is 30°.

180

A man standing on the top of 50 m high tower, observes two cars on the opposite sides of the tower with angles of depression 30°and 45° respectively. The distance between the two cars is : 

  1. ((a))

    150 m

  2. ((b))

    50(3+13)50\left(\sqrt3+\frac{1}{\sqrt3}\right)  m

  3. ((c))

    50(1 + √3) m

  4. ((d))

    50(1+13)50\left(1+\frac{1}{\sqrt3}\right) m

Show Answer
Answer: ((c))

50(1 + √3) m

Solution:

in diagram, it is 50 instead of 100.**

In \triangleBCD, 

tan 45° = 50/BD (as tan 45° = 1)

⇒ BD = 50 m

In \triangleACD,

tan 30° = 50/AD (as tan 30° = 1/√3)

⇒ 1/√3 = 50/AD

⇒ AD = 50√3 m

Distance between both cars = AD + BD = 50 + 50√3 = 50(1 + √3) m

Thus, distance between both cards is 50(1+√3) m.

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