Official Paper

KVS PGT Chemistry Official Paper (Held On: 18 Feb, 2023 Shift 1) (Previous Year Paper)

180 questions · 180 minutes · with answers · free

Language Proficiency (20 questions)

1

Rearrange the parts in correct order to make a meaningful sentence.

(a) entering a house,

(b) saw a burglar

(c) when the policeman

(d) he ran and caught him

  1. ((a))

    (a) (b) (c) (d)

  2. ((b))

    (b) (c) (d) (a)

  3. ((c))

    (c) (b) (a) (d)

  4. ((d))

    (d) (a) (b) (c)

Show Answer
Answer: ((c))

(c) (b) (a) (d)

The correct answer is Option (3) i.e. (c) (b) (a) (d)

Key Points

  • The sentence should begin with the time clause "when the policeman" (c), which sets the context for the action.
  • Next, "saw a burglar" (b) logically follows, stating what the policeman observed.
  • This is followed by "entering a house" (a), specifying what the burglar was doing.
  • The sentence ends with "he ran and caught him" (d), completing the action sequence.

Therefore, the correct answer is (c) (b) (a) (d).

Additional Information

  • Option 1 (a b c d): Starts with the action, making the sentence illogical and grammatically awkward.
  • Option 2 (b c d a): Jumbles the sequence of observation, action, and reaction, disrupting the meaning.
  • Option 4 (d a b c): Begins with the result, which should come at the end, making the sentence unclear and confusing.
2

Change the following sentence from Active Voice to Passive Voice.

Why did your friend write such a nasty letter to you?

  1. ((a))

    Why such a nasty letter was written to you by your friend?

  2. ((b))

    Why is a nasty letter written to you by your friend? 

  3. ((c))

    Why a nasty letter to you was written by your friend?

  4. ((d))

    Why was such a nasty letter written to you by your friend?

Show Answer
Answer: ((d))

Why was such a nasty letter written to you by your friend?

The correct answer is Option 4.

 

Key Points

  • Passive voice structure: The object of the active sentence becomes the subject of the passive sentence. The verb takes the form "was/were + past participle" for simple past questions.
  • In the active voice, the sentence is: "Why did your friend write such a nasty letter to you?"
  • To convert to passive voice: Place the object "such a nasty letter" at the beginning of the sentence.
  • Change the verb from "did...write" (simple past) to "was...written" (simple past passive).
  • In questions, the auxiliary verb "was" comes before the subject: "Why was such a nasty letter written to you by your friend?"
  • Keep the question format intact and ensure the meaning remains unchanged.

Therefore, the correct answer is Option 4.

 

Correct Sentence: "Why was such a nasty letter written to you by your friend?"

 

Additional Information

  • Option 1: "Why such a nasty letter was written to you by your friend?" – Incorrect word order for a question in English.
  • Option 2: "Why is a nasty letter written to you by your friend?" – Incorrect tense (present tense instead of past).
  • Option 3: "Why a nasty letter to you was written by your friend?" – Incorrect word order and awkward construction for a question.
3

Fill in the blank with the correct preposition.

The wheel came ______ the vehicle when it was negotiating a dangerous curve.

  1. ((a))

    out

  2. ((b))

    of

  3. ((c))

    off

  4. ((d))

    from

Show Answer
Answer: ((c))

off

The correct answer is 'off'.

 

Key Points

  • The preposition "off" is used to indicate separation or detachment from a surface or object.
  • The sentence describes the wheel detaching from the vehicle, making "off" the correct preposition to use.
  • Options 1, 2, and 4 are grammatically incorrect in this context.

Therefore, the correct answer is Option 3.

 

Complete Sentence: "The wheel came off the vehicle when it was negotiating a dangerous curve."

 

Additional Information

  • Option 1: "out" is incorrect as it does not convey detachment.
  • Option 2: "of" is incorrect as it does not work with the verb "came" in this context.
  • Option 4: "from" is incorrect as it does not match the intended meaning of detachment.
4

Choose the correct tense form from the given options.

I had finished my exercise when my friend came to see me.

  1. ((a))

    Past Indefinite

  2. ((b))

    Past Continuous

  3. ((c))

    Past Perfect

  4. ((d))

    Past Perfect continuous

Show Answer
Answer: ((c))

Past Perfect

The correct answer is Option 3 i.e 'Past Perfect'.

Key Points

  • The sentence "I had finished my exercise when my friend came to see me" demonstrates an action (finishing the exercise) that was completed before another action (the friend coming).
  • Past Perfect tense is used to indicate that one action was completed before another action in the past.
  • The structure of the Past Perfect tense includes the auxiliary verb "had" followed by the past participle of the main verb. In this sentence, "had finished" follows this structure.
  • Past Indefinite (Simple Past) is used for the second action in the sentence ("my friend came"), showing the sequence of events.

Therefore, the correct answer is- Option 3.

Additional Information

  • Past Indefinite: Indicates an action that happened at a specific point in the past, e.g., "my friend came" in the sentence.
  • Past Continuous: Refers to an ongoing action in the past, e.g., "was finishing", which is not applicable here.
  • Past Perfect Continuous: Refers to an action that started in the past and continued up until another point in the past, e.g., "had been finishing", which is also not applicable here.
5

Change the following sentence from Direct Speech into Indirect Speech.

"I always take a cup of green tea in the morning," my father said to his friends.

  1. ((a))

    He always took a cup of green tea in the morning my father told his friends. 

  2. ((b))

    My father told his friends that he always took a cup of green tea in the morning.

  3. ((c))

    My father told his friends that he had always taken a cup of green tea in the morning.

  4. ((d))

    My father told his friends that he has always been taking a cup of green tea.

Show Answer
Answer: ((b))

My father told his friends that he always took a cup of green tea in the morning.

The correct answer is Option 2.

 

Key Points

  • Indirect Speech: My father told his friends that he always took a cup of green tea in the morning.
  • Key Conversions:
  • Pronoun Change:
  • Direct ("I") becomes Indirect ("he") to reflect the change in speaker from the father to a third person.
  • Tense Change:
  • Present simple ("take") becomes past simple ("took") according to the rules of reported speech when the reporting verb is in the past.
  • Reporting Verb:
  • “said to” changes to “told” in indirect speech, as the sentence is directed to someone.
  • Punctuation and Format:
  • Quotation marks are removed in indirect speech.
  • The reporting clause is followed by “that” to introduce the reported statement.

Therefore, the correct answer is Option 2.

 

Correct Sentence: My father told his friends that he always took a cup of green tea in the morning.

 

Additional Information

  • Option 1: He always took a cup of green tea in the morning my father told his friends.
  • The sentence structure is incorrect. The reporting clause should come first, followed by the reported statement.
  • Option 3: My father told his friends that he had always taken a cup of green tea in the morning.
  • Incorrect tense; "had always taken" (past perfect) is not required here, as the original statement is habitual.
  • Option 4: My father told his friends that he has always been taking a cup of green tea.
  • Incorrect tense and aspect; present perfect continuous ("has always been taking") does not match the simple habitual action in the original sentence.
6

Identify the part which has an error in it.

She discovered (1) / to her horror (2) / that she swallowed a fly (3) / while drinking tea. (4)

  1. ((a))

    1

  2. ((b))

    2

  3. ((c))

    3

  4. ((d))

    4

Show Answer
Answer: ((c))

3

The correct answer is Option 3.

 

Key Points

  • The main issue in the sentence is the incorrect use of tense in part 3.
  • After verbs like "discovered," the past perfect tense ("had swallowed") should be used to indicate an action completed before another past action.
  • The sentence currently uses "she swallowed a fly," which is simple past, making the timeline unclear.
  • Therefore, the error is found in part 3 of the sentence.

Therefore, the correct answer is 3.

 

Correct Sentence: "She discovered to her horror that she had swallowed a fly while drinking tea."

 

Additional Information

  • 1: "She discovered" – This part is correct and does not require any changes.
  • 2: "to her horror" – This phrase is correct and properly placed.
  • 4: "while drinking tea." – This part is also grammatically correct.
7

Identify the word nearest in meaning to the given word.

DERISIVE

  1. ((a))

    quarrelsome

  2. ((b))

    disdainful

  3. ((c))

    abusive

  4. ((d))

    decent

Show Answer
Answer: ((b))

disdainful

The correct answer is: Option 2 i.e. 'disdainful'.

Key Points

  • The word "derisive" means expressing contempt or ridicule. (उपहासजनक)
  • Example: His derisive comments about her dress made her feel embarrassed.
  • "Disdainful" refers to showing contempt or lack of respect. (घृणास्पद)
  • Example: She gave him a disdainful look when he tried to explain his mistake.

Therefore, the correct answer is: disdainful.

Additional Information

Here are the other options explained along with their Hindi meanings and example sentences:

  • Quarrelsome (झगड़ालू): Inclined to argue or fight.
  • Example: His quarrelsome nature often got him into trouble with his peers.
  • Abusive (गाली-गलौज): Extremely offensive and insulting behavior.
  • Example: She left her abusive partner to protect herself and her children.
  • Decent (शालीन): Conforming with generally accepted standards of respectable or moral behavior.
  • Example: He is known for being a decent and honest man in the community.
8

Identify the word opposite in meaning to the given word.

MITIGATE

  1. ((a))

    float

  2. ((b))

    increase

  3. ((c))

    reduce

  4. ((d))

    expand

Show Answer
Answer: ((b))

increase

The correct answer is: Increase.

Key Points

  • The word "mitigate" means to make something less severe, serious, or painful. (कम करना)
  • Example: The government took steps to mitigate the effects of the economic crisis.
  • "Increase" is the opposite of mitigate. It means to make something greater in size, amount, or degree. (बढ़ाना)
  • Example: Regular exercise can increase your stamina and improve your health.
  • Hence, we can infer that the opposite of 'mitigate' is 'increase'.

Therefore, the correct answer is: Increase.

Additional Information

Here are the other options explained along with their Hindi meanings and example sentences:

  • Float (तैरना): To rest or move on the surface of a liquid without sinking.
  • Example: The boat began to float gently down the stream.
  • Reduce (कम करना ): To make something smaller or less in amount, degree, or size.
  • Example: The company is working to reduce its environmental impact.
  • Expand (विस्तार करना): To increase in size, number, or importance.
  • Example: The company plans to expand its operations into new markets next year.
9

Identify the Part of Speech of the underlined expression.

Students should not while away their time in frivolous activities.

  1. ((a))

    Adverb

  2. ((b))

    Verb

  3. ((c))

    Conjunction

  4. ((d))

    Pronoun

Show Answer
Answer: ((b))

Verb

The correct answer is Option 2 i.e 'Verb'.

Key Points

  • The underlined word "while" is used as a verb in this context, meaning to spend or pass time in a leisurely manner.
  • Verbs are words that express actions, occurrences, or states of being. Here, "while" denotes an action of passing time.
  • In this context, "while away" is a phrasal verb, where "while" works as the main verb in the phrase.
  • Verbs often indicate what the subject of the sentence is doing, which is evident here as it describes the action "while away their time."

Therefore, the correct answer is- Option 2.

Additional Information

  • Adverb: An adverb modifies verbs, adjectives, or other adverbs. In this sentence, "while" is not modifying any word, so it cannot be classified as an adverb.
  • Conjunction: A conjunction joins words, phrases, or clauses. "While" can function as a conjunction in some contexts, but here it is not connecting any elements.
  • Pronoun: A pronoun is a word used in place of a noun. In this case, "while" is not replacing a noun, so it is not a pronoun.
10

Hurrah We have won.

What punctuation mark should be used after 'Hurrah' ?

  1. ((a))

    Colon

  2. ((b))

    Mark of interrogation

  3. ((c))

    Mark of exclamation

  4. ((d))

    Semi-colon

Show Answer
Answer: ((c))

Mark of exclamation

The correct answer is Option 3.

 

Key Points

  • "Hurrah" is an interjection that expresses strong emotion, such as joy or excitement.
  • Interjections of this kind require a mark of exclamation (!) immediately following them to convey the intended feeling.
  • The correct punctuation is: Hurrah! We have won.
  • Other marks such as a colon, interrogation mark, or semi-colon are not appropriate after interjections.

Therefore, the correct answer is Option 3.

 

Correct Sentence: Hurrah! We have won.

 

Additional Information

  • Option 1 (Colon): Used to introduce a list or explanation, not for interjections.
  • Option 2 (Mark of interrogation): Used for questions, not after exclamatory interjections.
  • Option 3 (Mark of exclamation): Used after interjections and exclamatory sentences to express strong emotions.
  • Option 4 (Semi-colon): Used to join closely related independent clauses, not for interjections.

निम्नलिखित गद्यांश को ध्यानपूर्वक पढ़कर उसपर आधारित प्रश्न का सही उत्तर दीजिए:

समाचार पत्र में विज्ञापन का विशेष महत्व है। विज्ञापन समाचार पत्र की आय का एक प्रमुख स्रोत तो है ही साथ ही अनेक अन्य आवश्यकताओं को भी पूरा करते हैं। बेरोजगार युवक अपने रोजगार की तलाश के लिए, गृहणियाँ अपने बजट के अनुरूप गृहस्थी चलाने के लिए आवश्यक उपकरणों के विज्ञापनों का लाभ उठाती हैं। विवाह योग्य वर-वधू के उपयुक्त साथी की तलाश का माध्यम विज्ञापन हैं। व्यापारी या व्यवसायी को अपने उत्पाद को उपभोक्ता तक पहुँचाने में विज्ञापन से सहायता मिलती है।

11

बेरोजगार युवक अपने रोजगार की तलाश के लिए क्या करते हैं?

  1. ((a))

    रोजगार कार्यालय जाते हैं।

  2. ((b))

    सरकारी दफ्तरों के चक्कर लगाते हैं।

  3. ((c))

    दूरदर्शन समाचार देखते हैं।

  4. ((d))

    समाचार-पत्र के विज्ञापन पढ़ते हैं

Show Answer
Answer: ((d))

समाचार-पत्र के विज्ञापन पढ़ते हैं

इसका सही उत्तर "समाचार-पत्र के विज्ञापन पढ़ते हैं" होगा।

Key Points

गद्यांश के अनुसार ,

  • बेरोजगार युवक अपने रोजगार की तलाश के लिए समाचार-पत्र के विज्ञापन पढ़ते हैं।

Additional Information अन्य विकल्प:

रोजगार कार्यालय जाते हैं -

  • यह भी एक तरीका हो सकता है, लेकिन गद्यांश के अनुसार सही उत्तर नहीं है।

सरकारी दफ्तरों के चक्कर लगाते हैं -

  • इसका उल्लेख गद्यांश में नहीं है।

दूरदर्शन समाचार देखते हैं -

  • इसका भी उल्लेख गद्यांश में नहीं है।
12

विज्ञापन निम्नलिखित में से किसकी आवश्यकताओं को पूरा नहीं करते हैं?

  1. ((a))

    बेरोजगार युवक 

  2. ((b))

    गृहिणी

  3. ((c))

    विवाह योग्य युवक-युवतियों 

  4. ((d))

    सरकारी अधिकारियों

Show Answer
Answer: ((d))

सरकारी अधिकारियों

इसका सही उत्तर "सरकारी अधिकारियों" है।

Key Points

गद्यांश के अनुसार ,

  • विज्ञापन बेरोजगार युवक, गृहिणी, और विवाह योग्य युवक-युवतियों की आवश्यकताओं को पूरा करते हैं।
  • सरकारी अधिकारियों की आवश्यकताओं को पूरा करने का उल्लेख गद्यांश में नहीं है।

Additional Information अन्य विकल्प:

बेरोजगार युवक -

  • ये लोग विज्ञापनों के माध्यम से रोजगार की तलाश करते हैं।

गृहिणी -

  • गृहणियाँ अपने बजट के अनुरूप गृहस्थी चलाने के लिए आवश्यक उपकरणों के विज्ञापनों का लाभ उठाती हैं।

विवाह योग्य युवक-युवतियाँ -

  • विवाह योग्य वर-वधू के उपयुक्त साथी की तलाश का माध्यम विज्ञापन हैं।
13

निम्नलिखित में कौन सा शब्द-युग्म असंगत है:

  1. ((a))

    रोजगार बेरोजगार

  2. ((b))

    आवश्यक अनावश्यक

  3. ((c))

    उपयुक्त अनुपयुक्त

  4. ((d))

    सहायता मदद

Show Answer
Answer: ((d))

सहायता मदद

इसका सही उत्तर "सहायता मदद" है।

Key Points

गद्यांश के अनुसार ,

  • रोजगार - बेरोजगार, आवश्यक - अनावश्यक, और उपयुक्त - अनुपयुक्त शब्द-युग्म विपरीतार्थक (antonyms) हैं।
  • सहायता और मदद समानार्थक (synonyms) हैं, अत: यह असंगत है।

Additional Information अन्य विकल्प:

रोजगार - बेरोजगार -

  • रोजगार का अर्थ होता है नौकरी, और बेरोजगार का अर्थ होता है बिना नौकरी के।

आवश्यक - अनावश्यक -

  • आवश्यक का अर्थ है जरूरी, और अनावश्यक का अर्थ है गैरजरूरी।

उपयुक्त - अनुपयुक्त -

  • उपयुक्त का अर्थ है सही या ठीक, और अनुपयुक्त का अर्थ है गलत या अनुपयुक्त।
14

गृहणियाँ अपने बजट के अनुरूप आवश्यक उपकरणों के विज्ञापन क्यों देखती हैं?

  1. ((a))

    घर की आवश्यकता के लिए

  2. ((b))

    गृहस्थी चलाने के लिए

  3. ((c))

    किचन का काम करने के लिए

  4. ((d))

    सस्ते दामों पर सामान खरीदने के लिए

Show Answer
Answer: ((b))

गृहस्थी चलाने के लिए

इसका सही उत्तर "**गृहस्थी चलाने के लिए"**है।

Key Points

गद्यांश के अनुसार ,

  • गृहणियाँ अपने बजट के अनुरूप आवश्यक उपकरणों के विज्ञापन गृहस्थी चलाने के लिए देखती हैं।

Additional Information अन्य विकल्प:

घर की आवश्यकता के लिए -

  • यह एक कारण हो सकता है लेकिन गद्यांश में विशेष रूप से गृहस्थी चलाने का उल्लेख किया गया है।

किचन का काम करने के लिए -

  • यह एक विशिष्ट आवश्यकता हो सकती है, लेकिन यह गद्यांश के प्रमुख कारण से संबंधित नहीं है।

सस्ते दामों पर सामान खरीदने के लिए -

  • यह भी एक कारण हो सकता है, लेकिन गद्यांश में इसका उल्लेख नहीं है।

निम्नलिखित गद्यांश को ध्यानपूर्वक पढ़कर उसपर आधारित प्रश्न का सही उत्तर दीजिए:

समाचार पत्र में विज्ञापन का विशेष महत्व है। विज्ञापन समाचार पत्र की आय का एक प्रमुख स्रोत तो है ही साथ ही अनेक अन्य आवश्यकताओं को भी पूरा करते हैं। बेरोजगार युवक अपने रोजगार की तलाश के लिए, गृहणियाँ अपने बजट के अनुरूप गृहस्थी चलाने के लिए आवश्यक उपकरणों के विज्ञापनों का लाभ उठाती हैं। विवाह योग्य वर-वधू के उपयुक्त साथी की तलाश का माध्यम विज्ञापन हैं। व्यापारी या व्यवसायी को अपने उत्पाद को उपभोक्ता तक पहुँचाने में विज्ञापन से सह���यता मिलती है।

15

गृहणियाँ किस तरह के विज्ञापनों का लाभ उठाती हैं ?

  1. ((a))

    रिक्त स्थान संबंधी

  2. ((b))

    आवश्यक उपकरण संबंधी

  3. ((c))

    शादी ब्याह संबंधी

  4. ((d))

    वर-संबंधी

Show Answer
Answer: ((b))

आवश्यक उपकरण संबंधी

इसका सही उत्तर "आवश्यक उपकरण संबंधी" है।

Key Points

गद्यांश के अनुसार ,

  • गृहणियाँ अपने बजट के अनुरूप गृहस्थी चलाने के लिए आवश्यक उपकरणों के विज्ञापनों का लाभ उठाती हैं।

Additional Information अन्य विकल्प:

रिक्त स्थान संबंधी -

  • यह विकल्प सही नहीं है क्योंकि गृहणियाँ रोजगार के विज्ञापनों में रुचि नहीं रखती हैं।

शादी ब्याह संबंधी -

  • यह विकल्प सही नहीं है क्योंकि गृहणियाँ विशेष रूप से गृहस्थी चलाने के लिए आवश्यक उपकरणों की तलाश में रहती हैं।

वर-संबंधी -

  • यह विकल्प सही नहीं है क्योंकि गृहणियों की आवश्यकताओं में वर संबंधी विज्ञापन शामिल नहीं होते हैं।
16

निम्नलिखित में असंगत है:

  1. ((a))

    देखने योग्य- दर्शनीय

  2. ((b))

    जाने वाली जगह-गंतव्य

  3. ((c))

    विचार योग्य-वैचारिक

  4. ((d))

    सब का हित करने वाला- सर्व हितकारी

Show Answer
Answer: ((d))

सब का हित करने वाला- सर्व हितकारी

​इसका सही उत्तर है- हितैषी

Key Points

  • वाक्यांश के लिए उपयुक्त शब्द - अनेक शब्दों के लिए एक शब्द को प्रयुक्त करना ही वाक्यांश के लिए एक शब्द कहलाता है।

Important Pointsकुछ महत्वपूर्ण वाक्यांश के लिए एक शब्द -

वाक्यांशशब्द
जो बिना वेतन के कार्य करेअवैतनिक
जिसे छूना वर्जित होअछूत
किए हुए उपकार को मानने वालाकृतज्ञ
जिसे मोक्ष प्राप्त करने की इच्छा होमुमुक्षु
जीतने की इच्छा वालाजिगीषु
चिर निद्रा को प्राप्त हुआचिरनिद्रित
काला पीला मिला रंगकपिश
17

निम्नलिखित में विसर्ग संधि वाला शब्द नही है

  1. ((a))

    दुरुपयोग

  2. ((b))

    बहिर्मुख

  3. ((c))

    लघूर्मि

  4. ((d))

    मनोयोग

Show Answer
Answer: ((c))

लघूर्मि

सही उत्तर है- लघूर्मि

Important Points

विसर्ग संधि में विसर्ग (:) वाले शब्द के बाद स्वर या व्यंजन आने पर विसर्ग में परिवर्तन (जैसे र्, ओ, ष्, स् आदि में बदलना या लोप) होता है।

  • दुरुपयोग: दुः + उपयोग → विसर्ग संधि (दु: में विसर्ग का 'रु' रूप)।
  • बहिर्मुख: बहिः + मुख → विसर्ग संधि (बहि: में विसर्ग का 'र' रूप)।
  • मनोयोग: मनः + योग → विसर्ग संधि (मन: में विसर्ग + य → 'ओ' बनता है)।
  • लघूर्मि: लघु + ऊर्मि → दीर्घ स्वर संधि (उ + ऊ = ऊ), इसमें विसर्ग का कोई भूमिका नहीं है।
18

निम्नलिखित में तत्सम शब्द नहीं है:

  1. ((a))

    आज्ञा

  2. ((b))

    राजा

  3. ((c))

    वत्स

  4. ((d))

    सांई

Show Answer
Answer: ((a))

आज्ञा

तत्सम शब्द नहीं है- आज्ञा

Key Points

  • तत्सम - जिन शब्दों को संस्कृत से बिना किसी परिवर्तन के ले लिया जाता है, उन्हें तत्सम शब्द कहते हैं। 
  • जैसे- अस्थि, धैर्य, पक्ष आदि।
  • तद्भव - जिन शब्दों में समय और परिस्थितियों के कारण कुछ परिवर्तन होने से जो शब्द बने हैं, उन्हें तद्भव कहते हैं। 
  • जैसे- हड्डी, धीरज, पंख आदि।​

 Additional Information कुछ महत्वपूर्ण ​तत्सम और तद्भव शब्द -

तत्समतद्भव
किसलयकोंपल
अमूल्यअमोल
​वज्रांगबजरंग
उलूकउल्लू
कृषककिसान
श्रंखलासाँकल
चंद्रिकाचाँदनी
तड़ागतालाब
धरित्रीधरती
19

'अमृत' शब्द का पर्यायवाची शब्द हैं

  1. ((a))

    उदक

  2. ((b))

    जलधि

  3. ((c))

    डर्बी

  4. ((d))

    अमिय

Show Answer
Answer: ((d))

अमिय

'अमृत' शब्द का पर्यायवाची शब्द हैं- अमिय

Key Points

  • 'अमृत' शब्द के पर्यायवाची शब्द हैं-
  • सुधा, पीयूष, अमी, अमिय, सोम, जीवनोदक, सुरभोग, मधु, देवान्न, आदि

Important Pointsपर्यायवाची शब्द-

  • जो शब्द समान अर्थ के कारण किसी दूसरे शब्द की जगह ले लेते हैं उन्हें पर्यायवाची शब्द कहते है।

Additional Information

  • कुछ महत्वपूर्ण पर्यायवाची शब्द:-
  • पानी - जल, वारि, नीर, तोय, सलिल, अंबु, सर।
  • आकाश - व्योम, शून्य, गगन, अम्बर, आसमान, अंतरिक्ष, नभ, अनंत।
  • हवा - पवन, वायु, समीर, अनिल, वात, मरुत्, पवमान, बयार, प्रकंपन।
  • साँप - सर्प, नाग, विषधर, व्याल, भुजंग, उरग, अहि पन्नग।
  • जंगल - वन, कानन, बीहड़, विटप, विपिन।
  • घर - गृह, सदन, आवास, आलय, गेह, निवास, निलय, मंदिर।
  • अमृत - सुधा, सोम, पीयूष, अमिय, जीवनोदक
  • असुर - राक्षस, दैत्य, दानव, निशाचर, दनुज, यातुधान, निशिचर, रजनीचर।
  • अश्व - घोड़ा, हय, तुरंग, वाजी, घोटक, सैंधव, तुरंग।
  • आँख - नेत्र, दृग, नयन, लोचन, चक्षु, अक्षि, अंबक, दृष्टि, विलोचन।
20

निम्नलिखित में सर्वनाम की दृष्टि से असंगत है:

  1. ((a))

    अनिश्चय वाचक- कुछ

  2. ((b))

    निश्चय वाचक क्या

  3. ((c))

    पुरुषवाचक मँ

  4. ((d))

    संबंधवाचक जो

Show Answer
Answer: ((b))

निश्चय वाचक क्या

सर्वनाम की दृष्टि से असंगत है- निश्चय वाचक क्या

Important Points

संज्ञा के स्थान पर प्रयुक्त होने वाले शब्दों को सर्वनाम कहते हैं। जैसे - मैं, वह, वे, उन्हें, अपने तुम, हम आदि। हिंदी में सर्वनामों की संख्या 11 है – ‘मैं, तू, आप, यह, वह, जो, सो, कोई, कुछ, कौन, क्या’ सर्वनाम के छः भेद हैं -
निश्चयवाचक सर्वनामजो सर्वनाम शब्द किसी व्यक्ति, वस्तु आदि का निश्चयपूर्वक बोध कराते हैं वे निश्चयवाचक सर्वनाम कहलाते हैं। जैसे - वे, यह, वह आदि।
पुरुषवाचक (व्यक्तिवाचक) सर्वनामजिस सर्वनाम का प्रयोग वक्ता द्वारा स्वयं के लिए या अन्य व्यक्ति के लिए किया जाता है। जैसे - मैं, हम, मुझे, तू, तुम, तुझे, तुम्हारा, वह, वे, उसने आदि।
निजवाचक सर्वनामजहाँ स्वयं के लिए 'आप, अपना, अपने आप' शब्दों का प्रयोग हो। जैसे - वह अपने आप ही घर चली गयी।
प्रश्नवाचक सर्वनामजो सर्वनाम शब्द संज्ञा के स्थान पर आकर वाक्य को प्रश्वाचक बनाते हैं। जैसे - क्या, कौन आदि।
अनिश्चयवाचक सर्वनामजिन सर्वनाम शब्दों से वस्तु, व्यक्ति, स्थान आदि की निश्चितता का बोध नही होता वे अनिश्चयवाचक सर्वनाम कहलाते हैं। जैसे- कुछ, कोई आदि।
सम्बन्धवाचक सर्वनामजिन सर्वनाम शब्दों का प्रयोग किसी वस्तु या व्यक्ति का सम्बन्ध बताने के लिए किया जाए वे शब्द सम्बन्धवाचक सर्वनाम कहलाते हैं। जैसे - जो-सो, जैसा-वैसा आदि।

GK, LR & Computer (20 questions)

21

Which of the following states in India does not have a bicameral legislature ?

  1. ((a))

    Bihar

  2. ((b))

    Maharashtra

  3. ((c))

    Andhra Pradesh

  4. ((d))

    Madhya Pradesh

Show Answer
Answer: ((d))

Madhya Pradesh

The correct answer is Madhya Pradesh.

Key Points

  • India has two types of legislatures in its states: unicameral and bicameral legislatures. Only a few states have bicameral legislatures.
  • Madhya Pradesh has a unicameral legislature, meaning it has only a Legislative Assembly (Vidhan Sabha).
  • The bicameral legislature includes a Legislative Assembly (Vidhan Sabha) and a Legislative Council (Vidhan Parishad).
  • States with bicameral legislatures include Bihar, Maharashtra, Andhra Pradesh, Uttar Pradesh, Karnataka, and Telangana.
  • Legislative Councils are established in states under Article 169 of the Indian Constitution, based on the need and recommendation of the Legislative Assembly.

Additional Information

  • Bihar:
  • Bihar has a bicameral legislature, consisting of the Legislative Assembly (243 members) and the Legislative Council (75 members).
  • The Legislative Council in Bihar is an upper house with members elected, nominated, or appointed through various processes.
  • Maharashtra:
  • Maharashtra has a bicameral legislature, including the Legislative Assembly (288 members) and the Legislative Council (78 members).
  • The Legislative Council serves as the upper house, with members elected from local bodies, graduates, teachers, and the governor's nominations.
  • Andhra Pradesh:
  • Andhra Pradesh has a bicameral legislature, consisting of the Legislative Assembly (175 members) and the Legislative Council (58 members).
  • The Legislative Council in Andhra Pradesh was re-established in 2007 after being abolished in 1985.
  • Madhya Pradesh:
  • Madhya Pradesh has a unicameral legislature, meaning it has only the Legislative Assembly with 230 members.
  • There is no Legislative Council in Madhya Pradesh as the state operates with a single-house system.
22

Assertion (A): The Government of India adopted the 'waterfall' framework for policy making during pandemic induced uncertainities since 2020.

Reason (R) :The 'waterfall' framework is a flexible approach to policy making which uses feedback loops and real-time adjustment.

Choose the correct answer from the codes below:

  1. ((a))

    (A) is correct but (R) is wrong

  2. ((b))

    (A) is wrong but (R) is correct

  3. ((c))

    Both (A) and (R) are correct and (R) explains (A) 

  4. ((d))

    Both (A) and (R) are wrong

Show Answer
Answer: ((d))

Both (A) and (R) are wrong

The correct answer is Both (A) and (R) are wrong.

Key Points

  • The Government of India did not adopt the 'waterfall' framework for policymaking during the pandemic-induced uncertainties since 2020. Instead, it relied on dynamic and adaptive strategies based on real-time data.
  • The 'waterfall' framework is generally used in software development and project management, characterized by a sequential approach that lacks flexibility for real-time adjustments.
  • For pandemic-related policymaking, the Indian government employed agile and data-driven methodologies, incorporating iterative feedback loops to address rapidly changing circumstances.
  • Examples include the phased lockdown approach, real-time monitoring of COVID-19 cases, and flexible vaccination strategies.
  • The assertion (A) and reason (R) are both incorrect as they misattribute the 'waterfall' framework to Indian policymaking during the pandemic.

Additional Information

  • The 'waterfall' methodology is a traditional project management framework that follows linear stages such as requirement gathering, design, implementation, testing, and deployment.
  • Agile methodologies, on the other hand, are iterative and adaptive, making them suitable for uncertain and rapidly changing scenarios like a pandemic.
  • During the COVID-19 pandemic, governments worldwide, including India, adopted adaptive strategies to tackle evolving challenges, such as dynamic lockdowns, vaccination drives, and digital platforms for tracking and managing resources.
23

Which of the following kingdoms was not annexed by the East India company under the 'Doctrine of Lapse' ?

  1. ((a))

    Jhansi

  2. ((b))

    Mysore

  3. ((c))

    Satara

  4. ((d))

    Nagpur

Show Answer
Answer: ((b))

Mysore

The correct answer is Mysore.

Key Points

  • The Doctrine of Lapse was a policy introduced by Lord Dalhousie during his tenure as Governor-General of India (1848–1856).
  • This doctrine allowed the British East India Company to annex the princely states whose rulers died without a male heir.
  • Mysore was not annexed under the Doctrine of Lapse as it was a princely state restored to its rulers after the fall of Tipu Sultan in 1799 and governed under British supervision.
  • The Doctrine of Lapse was specifically applied to states like Jhansi, Satara, and Nagpur, which did not have a rightful male heir.
  • Mysore remained independent under British control but did not come under annexation due to this policy.

Additional Information

  • British expansion policies:
  • Direct Conquest & War: Using superior military strength to defeat Indian states (e.g., Marathas, Punjab) through decisive battles.
  • Subsidiary Alliance (Lord Wellesley): Indian rulers had to maintain British troops, pay subsidies, accept a British Resident, and cede control of foreign policy in exchange for protection, effectively losing sovereignty.
  • Policy of Paramountcy: The idea that the British East India Company was the supreme power, justifying intervention and annexation to protect its interests.
  • Economic Exploitation: Transforming India into a supplier of raw materials and a market for British manufactured goods, weakening local industries.
24

Which of the following statements about mineral resources is incorrect?

  1. ((a))

    Copper is ductile and a good conductor of electricity

  2. ((b))

    Aluminium is obtained from a clay-like substance called Bauxite

  3. ((c))

    Tin is a Non-Ferrous mineral

  4. ((d))

    Hematite is the finest iron ore containing iron upto 70 percent

Show Answer
Answer: ((d))

Hematite is the finest iron ore containing iron upto 70 percent

The correct answer is Hematite is the finest iron ore containing iron up to 70 percent.

Key Points

  • Hematite is a type of iron ore that is known for its high iron content, but it typically contains iron around 60-65%, not up to 70% as stated in the incorrect option.
  • The statement that Hematite contains iron up to 70% is factually incorrect and misleading.
  • Hematite is widely used for iron extraction due to its high iron content and is reddish-brown in color.
  • The finest quality iron ore with the highest iron content is often considered to be Magnetite, which contains up to 72% iron.
  • Hematite, though not the finest, is still an economically significant ore for iron extraction.

Additional Information

  • Copper
  • Copper is a highly ductile metal and an excellent conductor of electricity and heat.
  • It is widely used in electrical wiring, electronics, and other industries due to its conductivity and malleability.
  • Copper is also resistant to corrosion, which makes it useful for plumbing and roofing applications.
  • Aluminium
  • Aluminium is extracted from Bauxite, a clay-like substance that is the chief ore of aluminium.
  • Bauxite undergoes refining through the Bayer process to obtain alumina (aluminium oxide), which is further reduced to produce aluminium metal.
  • Aluminium is lightweight, corrosion-resistant, and widely used in industries such as aerospace, construction, and packaging.
  • Tin
  • Tin is classified as a non-ferrous mineral because it does not contain iron and is resistant to corrosion.
  • It is primarily used in the production of tinplate for food packaging and as a component in soldering materials.
  • Tin is also used in making alloys like bronze (tin and copper) and pewter.
  • Mineral Resources
  • Minerals are naturally occurring substances with a definite chemical composition and physical properties.
  • They are classified into metallic (e.g., iron, copper, tin) and non-metallic (e.g., limestone, mica) minerals.
  • Mineral resources are vital for industrial development and are extracted through mining activities.
  • Conservation of minerals is important due to their non-renewable nature.
25

The Limited Test Ban Treaty (LTBT) signed in 1963 banned nuclear weapon tests

  1. ((a))

    Only in the atmosphere and outer space

  2. ((b))

    Only in the outer space and underground

  3. ((c))

    Only in the outer space and under water

  4. ((d))

    Only in the atmosphere, outer space and under water

Show Answer
Answer: ((d))

Only in the atmosphere, outer space and under water

The correct answer is Only in the atmosphere, outer space and under water.

Key Points

  • The Limited Test Ban Treaty (LTBT) was signed on August 5, 1963 by the United States, the Soviet Union, and the United Kingdom.
  • It aimed to prohibit nuclear weapon test explosions in the atmosphere, outer space, and under water to reduce radioactive fallout affecting humans and the environment.
  • The LTBT was implemented on October 10, 1963, marking an important milestone in arms control and disarmament efforts.
  • While banning nuclear tests in the above-mentioned environments, the LTBT allowed underground nuclear tests as long as they did not cause radioactive debris to cross national borders.

Additional Information

  • Comprehensive Nuclear-Test-Ban Treaty (CTBT): Extends the LTBT by banning all nuclear explosions (underground too) but hasn't fully entered into force.
  • Nuclear Non-Proliferation Treaty (NPT): A cornerstone treaty preventing the spread of nuclear weapons, promoting peaceful energy, and working towards disarmament.
  • Treaty on the Prohibition of Nuclear Weapons (TPNW): A newer treaty that completely bans the development, testing, possession, and use of nuclear weapons.
  • Treaty of Tlatelolco: A regional treaty creating a nuclear-weapon-free zone in Latin America.
  • Antarctic Treaty: While broader, it prohibits military activity, including nuclear explosions, in Antarctica.
26

Among the following which metal is more reactive?

  1. ((a))

    Copper

  2. ((b))

    Iron

  3. ((c))

    Zinc

  4. ((d))

    Gold

Show Answer
Answer: ((c))

Zinc

The correct answer is Zinc.

Key Points

  • Zinc is more reactive compared to copper, iron, and gold as it is positioned higher in the reactivity series of metals.
  • Zinc reacts readily with dilute acids like hydrochloric acid, releasing hydrogen gas, which is an indicator of its higher reactivity.
  • It displaces less reactive metals like copper from their compounds in solution, which is a characteristic property of more reactive metals.
  • Zinc is commonly used as a sacrificial anode in galvanization to protect iron and steel from rusting, showcasing its higher reactivity.
  • The higher reactivity of zinc is due to its ability to lose electrons more easily, forming positive ions (Zn2+).

Additional Information

  • Copper
  • Copper is less reactive than zinc and iron and is placed below zinc in the reactivity series.
  • It does not react with dilute acids under normal conditions, indicating its lower reactivity.
  • Copper is widely used in electrical wiring and plumbing due to its excellent conductivity and resistance to corrosion.
  • Iron
  • Iron is more reactive than copper but less reactive than zinc.
  • It reacts with dilute acids, releasing hydrogen gas, and is prone to rusting when exposed to moisture and oxygen.
  • Iron is extensively used in construction and manufacturing due to its strength and availability.
  • Gold
  • Gold is one of the least reactive metals and is positioned at the bottom of the reactivity series.
  • It does not react with dilute acids or oxygen, making it highly resistant to corrosion and tarnishing.
  • Gold is primarily used in jewelry, electronics, and as a standard for monetary systems due to its stability and malleability.
27

Which of the following is not present in the cytoplasm?

  1. ((a))

    Mitochondria

  2. ((b))

    Golgi bodies

  3. ((c))

    Ribosomes

  4. ((d))

    Nucleus

Show Answer
Answer: ((d))

Nucleus

The correct answer is Nucleus.

Key Points

  • The nucleus is a membrane-bound organelle that is present in eukaryotic cells and acts as the control center of the cell.
  • Unlike other organelles such as mitochondria, ribosomes, or Golgi bodies, the nucleus is not part of the cytoplasm. It is separated from the cytoplasm by a double membrane called the nuclear envelope.
  • The nuclear envelope contains pores that regulate the exchange of substances between the nucleus and the cytoplasm.
  • The nucleus houses genetic material in the form of DNA, which is organized into chromosomes. This genetic material is responsible for controlling cellular activities and heredity.
  • It also contains a dense structure called the nucleolus, which is involved in ribosome synthesis.

Additional Information

  • Mitochondria:
  • Mitochondria are known as the "powerhouses of the cell" as they generate energy in the form of ATP through cellular respiration.
  • They are double-membraned organelles found in the cytoplasm of both plant and animal cells.
  • Mitochondria have their own DNA and ribosomes, enabling them to produce some of their own proteins.
  • Golgi bodies:
  • The Golgi apparatus, also known as Golgi bodies, is involved in the modification, packaging, and transport of proteins and lipids.
  • It is a stack of membrane-bound sacs located in the cytoplasm of eukaryotic cells.
  • The Golgi apparatus plays a crucial role in the secretion of substances and the formation of lysosomes.
  • Ribosomes:
  • Ribosomes are molecular machines responsible for protein synthesis in cells.
  • They can be found floating freely in the cytoplasm or attached to the endoplasmic reticulum (forming rough ER).
  • Ribosomes consist of RNA and proteins and are present in both prokaryotic and eukaryotic cells.
28

Who among the following players won the FIFA World Cup 2022 'The Golden Ball' Award ?

  1. ((a))

    Kylian Mbappe

  2. ((b))

    Cristiano Ronaldo

  3. ((c))

    Lionel Messi

  4. ((d))

    Neymar

Show Answer
Answer: ((c))

Lionel Messi

The correct answer is Lionel Messi.

Key Points

  • Lionel Messi won the FIFA World Cup 2022 Golden Ball award for his outstanding performance throughout the tournament.
  • Messi scored a total of 7 goals and provided 3 assists in 7 matches, leading Argentina to their third World Cup title.
  • He became the first player in history to win the Golden Ball twice, having previously won it in the 2014 FIFA World Cup.
  • Messi's leadership and crucial contributions in key matches, including the final against France, were instrumental in Argentina's victory.
  • The Golden Ball is awarded to the best player of the FIFA World Cup, as decided by FIFA's Technical Study Group and media representatives.

Additional Information

  • Kylian Mbappe
  • Kylian Mbappe was the runner-up for the Golden Ball in FIFA World Cup 2022.
  • He won the Golden Boot, awarded to the top scorer of the tournament, with an impressive 8 goals, including a hat-trick in the final.
  • Mbappe's hat-trick made him the second player in history to score three goals in a World Cup final.
  • Cristiano Ronaldo
  • Cristiano Ronaldo participated in the FIFA World Cup 2022 as captain of the Portugal team.
  • He became the first male player to score in five different World Cups with his goal against Ghana in the group stage.
  • Portugal was eliminated in the quarterfinals by Morocco, marking the end of Ronaldo's World Cup journey in 2022.
  • Neymar
  • Neymar represented Brazil in the FIFA World Cup 2022.
  • He scored two goals during the tournament, including a stunning strike in the quarterfinals against Croatia.
  • Brazil was eliminated in the quarterfinals after a penalty shootout loss to Croatia.
  • The Golden Ball Award
  • Introduced in the 1982 FIFA World Cup, the Golden Ball is awarded to the best player of the tournament.
  • The winner is selected through votes cast by journalists and FIFA's Technical Study Group.
  • Other notable winners include Diego Maradona (1986), Zinedine Zidane (2006), and Luka Modric (2018).
29

Who among the following authors won the 'Sahitya Akademi Yuva Puraskar' 2022 in Sindhi language?

  1. ((a))

    Geeta Pradeep RupanI

  2. ((b))

    Kirti Pradeep Rupani

  3. ((c))

    Monika Panjwani

  4. ((d))

    Heena Aswani

Show Answer
Answer: ((a))

Geeta Pradeep RupanI

The correct answer is Geeta Pradeep Rupani.

Key Points

  • Geeta Pradeep Rupani won the prestigious Sahitya Akademi Yuva Puraskar 2022 for her exceptional contribution to Sindhi literature.
  • The Sahitya Akademi Yuva Puraskar is awarded annually to young writers under the age of 35 to recognize and encourage literary talent in Indian languages.
  • Geeta Pradeep Rupani was honored for her work in Sindhi, a language with rich cultural and literary heritage.
  • The award is presented by the Sahitya Akademi, India’s National Academy of Letters, which supports and promotes Indian literature.
  • Her work highlights the traditions, values, and evolving narratives of the Sindhi language, contributing to its preservation and growth.

Additional Information

  • Kirti Pradeep Rupani:
  • There is no record of Kirti Pradeep Rupani winning the Sahitya Akademi Yuva Puraskar 2022 or any other notable award.
  • This name might be confused with Geeta Pradeep Rupani, who is the correct recipient of the award.
  • Monika Panjwani:
  • Monika Panjwani is not associated with winning the Sahitya Akademi Yuva Puraskar 2022 in Sindhi language.
  • Her name might belong to a different field or a different literary category not relevant to this award.
  • Heena Aswani:
  • Heena Aswani has not been recognized as the recipient of the Sahitya Akademi Yuva Puraskar for 2022 in Sindhi language.
  • The Sindhi Yuva Puraskar was specifically awarded to Geeta Pradeep Rupani for her literary contributions.
  • Sahitya Akademi Yuva Puraskar:
  • The Sahitya Akademi Yuva Puraskar was established in 2011 to recognize and encourage young literary talents under the age of 35.
  • The award covers 24 Indian languages recognized by the Sahitya Akademi.
  • It aims to promote literature in regional languages and encourage the younger generation to contribute to their linguistic heritage.
  • The award consists of a cash prize of Rs. 50,000 and a copper plaque.
30

Which of the following computer languages uses mnemonics?

  1. ((a))

    High Level Language

  2. ((b))

    Machine Language

  3. ((c))

    Assembly Language

  4. ((d))

    C Programming Language

Show Answer
Answer: ((c))

Assembly Language

The correct answer is Assembly Language.

Key Points

  • Assembly Language is a low-level programming language that uses mnemonics (short codes) to represent machine-level instructions.
  • It acts as a bridge between high-level programming languages and machine language, making it easier for programmers to write instructions.
  • Mnemonics in assembly language are symbolic codes like ADD, SUB, MOV, and JMP, which correspond to specific machine instructions.
  • Assembly language is hardware-specific, meaning programs written in it are tailored to a specific CPU architecture.
  • It requires an assembler to convert the mnemonics into machine code that can be directly executed by the computer's processor.

Additional Information

  • High-Level Language:
  • High-level programming languages, like Python, Java, and C++, are user-friendly and closer to human language.
  • They are abstracted from the hardware and use natural language elements, making programming easier and more intuitive.
  • High-level languages are independent of machine architecture and require a compiler or interpreter to convert the code into machine language.
  • Machine Language:
  • Machine language consists of binary code (0s and 1s) that a computer's CPU can directly execute.
  • It is the lowest-level programming language and is extremely difficult for humans to write and understand.
  • Programs written in machine language are hardware-dependent and do not use mnemonics.
  • C Programming Language:
  • C is a high-level, general-purpose programming language that is widely used for system and application software.
  • It does not use mnemonics; instead, it employs English-like syntax for writing instructions (e.g., printf, scanf, if-else).
  • It is known for its performance and close interaction with hardware, making it useful for system-level programming.
31

Choose the correct alternative that will continue the same pattern and replace the question mark (?) in the given letter cluster series.

HMS, MTB, SBL, ZKW,?

  1. ((a))

    HVX

  2. ((b))

    HUI

  3. ((c))

    KVL

  4. ((d))

    HWM

Show Answer
Answer: ((a))

HVX

The logic followed here is:

So, 'HVX' will replace the question mark in the given series.

Hence, the correct answer is "Option 1".

32

Six friends Anuradha, Abha, Manisha, Monika, Rashmi and Sulekha are sitting around a circular table facing outside the circle (not facing towards the centre). Anuradha is neighbour of Manisha and Abha. Anuradha is sitting third to the right of Monika and is second to the left of Sulekha. Manisha is sitting third to the right of Sulekha.

Who is sitting immediate right of Monika ?

  1. ((a))

    Sulekha

  2. ((b))

    Rashmi

  3. ((c))

    Manisha

  4. ((d))

    Abha

Show Answer
Answer: ((a))

Sulekha

Given: Six friends Anuradha, Abha, Manisha, Monika, Rashmi and Sulekha are sitting around a circular table facing outside the circle (not facing towards the centre).

  1. Anuradha is neighbour of Manisha and Abha.

  2. Anuradha is sitting third to the right of Monika and is second to the left of Sulekha.

  3. Manisha is sitting third to the right of Sulekha.

Here, Sulekha is sitting immediate right of Monika .

Hence, the correct answer is "Option 1".

33

'B' is to the North of 'A' and to the West of 'C'. In what direction is 'C' with respect to 'A' ?

  1. ((a))

    North-East

  2. ((b))

    North-West 

  3. ((c))

    South-East

  4. ((d))

    South-West

Show Answer
Answer: ((a))

North-East

Given: 

'B' is to the North of 'A' and to the West of 'C'.

So, North-East is 'C' with respect to 'A'.

Hence, the correct answer is "Option 4".

34

You are given a question and two statements numbered (I) and (II) each containing some information. Decide which of the statements is/are sufficient to answer the question.

Q: Ayush and Ranjan are standing at a distance of 20 km. They start walking towards each other. After how much time will they meet if they keep walking?

(I): Ayush and Ranjan walk at the speed of 2 km/hr and 3 km/hr respectively.

(II): The speed of walking of Ayush to Ranjan is 2:3.

  1. ((a))

    The statement (1)  alone is sufficient to answer the question while the statement (II) alone is not sufficient to answer the question.

  2. ((b))

    The statement (II) alone is sufficient to answer the question while the statement (I) alone is

    not sufficient to answer the question.

  3. ((c))

    Both statements (I) and (II) together are necessary to answer the question.

  4. ((d))

    Both statements (I) and (II) together are not sufficient to answer the question.

Show Answer
Answer: ((a))

The statement (1)  alone is sufficient to answer the question while the statement (II) alone is not sufficient to answer the question.

Given: Ayush and Ranjan are standing at a distance of 20 km.

They start walking towards each other. 

Explanation:

Statement I: Ayush and Ranjan walk at the speed of 2 km/hr and 3 km/hr respectively.

Statement (I) gives speeds 2 km/hr and 3 km/hr.

Relative speed = 2 + 3 = 5 km/hr, so time = distance / relative speed = 20 / 5 = 4 hours — sufficient.

Statement II: The speed of walking of Ayush to Ranjan is 2:3.

Statement (II) only gives the ratio 2:3 (no actual speeds), so it’s insufficient.

Combining both the statements :Statement I + Statement II

The statement (I) alone is sufficient while (II) alone is not.

Hence, the correct answer is 'Option 1'.

35

In the following figure, the square represents lawyers, the circle represents judges, the triangle represents girls and rectangle represents honest people.

Which number represents girls who are lawyers and honest but not judges?

  1. ((a))

    8

  2. ((b))

    12

  3. ((c))

    14

  4. ((d))

    15

Show Answer
Answer: ((b))

12

Given: 

Girls: Must be inside the Triangle.

Lawyers: Must be inside the Square.

Honest: Must be inside the Rectangle.

Not Judges: Must NOT be inside the Circle.

So, 12 is the only number that satisfies all the conditions.

Hence, the correct answer is 'Option 2'.

36

Gagan Sen is planning to buy a new smartphone, which one of the following aspects should he not be bothered about?

  1. ((a))

    Operating system

  2. ((b))

    Ethernet Port

  3. ((c))

    Internal Memory

  4. ((d))

    Camera Pixels

Show Answer
Answer: ((b))

Ethernet Port

The correct answer is Ethernet Port

Key Points

  • The Ethernet port is not a necessary feature in smartphones as they rely on wireless connectivity like Wi-Fi or mobile data.
  • Smartphones are designed to be portable and lightweight, making Ethernet ports obsolete for regular usage.
  • Other aspects like the operating system, internal memory, and camera pixels play a critical role in user experience.
  • The inclusion of an Ethernet port would be impractical and rarely found in modern smartphones.

Additional Information

  • Operating System: Determines the interface, features, and compatibility of the smartphone.
  • Internal Memory: Affects the storage capacity for apps, photos, and other data.
  • Camera Pixels: Impacts the quality of photos and videos taken with the smartphone.
  • Ethernet Port: Used in some devices for wired internet connectivity but is not applicable for smartphones.
37

Which of the following ports will be most suitable for connecting High Quality Audio-Video output on a PC/ a laptop ?

  1. ((a))

    PS2

  2. ((b))

    USB

  3. ((c))

    VGA

  4. ((d))

    HDMI

Show Answer
Answer: ((d))

HDMI

The correct answer is HDMI

Key Points

  • HDMI (High-Definition Multimedia Interface) is the most suitable port for high-quality audio and video output.
  • It supports both audio and video signals over a single cable, ensuring minimal cable clutter.
  • HDMI is capable of transmitting uncompressed video and multi-channel audio.
  • It is widely used for connecting laptops, PCs, and other devices to monitors, TVs, and projectors.

Additional Information

  • PS2 Port: This is used for connecting keyboards and mice, not suitable for audio-video output.
  • USB Port: While it supports data transfer and external peripherals, it is not optimized for high-quality audio-video output.
  • VGA Port: It is an older standard that only supports video signals, not audio.
  • HDMI: Supports high-definition video and audio over a single cable, making it ideal for modern multimedia needs.
38

_______ is not a basic function of MS Excel.

  1. ((a))

    count()

  2. ((b))

    sum()

  3. ((c))

    min()

  4. ((d))

    multiply()

Show Answer
Answer: ((a))

count()

The correct answer is count()

Key Points

  • MS Excel is a popular spreadsheet application used for data analysis and calculations.
  • Basic functions like sum(), min(), and multiply() are commonly used.
  • count() is not a basic function in MS Excel; instead, COUNT is the correct function to count numeric values.
  • Understanding functions in Excel helps improve efficiency in handling data.

Additional Information

  • COUNT function: Used to count numeric entries in a range.
  • SUM function: Adds values in a range of cells.
  • MIN function: Finds the smallest value in a range.
  • MULTIPLY operation: Can be achieved using the * operator in formulas.
39

______ is the file extension of an Excel file?

  1. ((a))

    excel

  2. ((b))

    xel

  3. ((c))

    xlsx

  4. ((d))

    xelx

Show Answer
Answer: ((c))

xlsx

The correct answer is xlsx

Key Points

  • Excel files typically use the .xlsx extension.
  • This format is used for saving spreadsheets created in Microsoft Excel.
  • The .xlsx extension is based on the Office Open XML (OOXML) format.
  • It is widely compatible with various spreadsheet software.

Additional Information

  • .xls: This is the older file extension used for Excel files before the .xlsx format.
  • .csv: A different format used for simple text-based spreadsheets.
  • Compatibility: Modern Excel versions can open both .xls and .xlsx files.
  • Office Open XML: A standard for representing spreadsheets, charts, presentations, and word processing documents.
40

Which of the following is not an example of RDBMS

  1. ((a))

    MySQL

  2. ((b))

    ORACLE

  3. ((c))

    CALC

  4. ((d))

    IBM DB2

Show Answer
Answer: ((c))

CALC

The correct answer is Option 3

Key Points

  • MySQL, ORACLE, and IBM DB2 are examples of Relational Database Management Systems (RDBMS).
  • RDBMS is a database management system based on the relational model introduced by E.F. Codd.
  • CALC is a spreadsheet software and not an RDBMS.
  • Spreadsheet software like CALC is used for data analysis and mathematical calculations, not for database management.

Additional Information

  • MySQL: An open-source RDBMS that uses Structured Query Language (SQL).
  • ORACLE: A commercial RDBMS widely used for enterprise-level database solutions.
  • IBM DB2: A family of RDBMS products from IBM, designed for large-scale data storage and processing.
  • CALC: Part of the LibreOffice suite, used for creating and managing spreadsheets.

Education and Leadership (40 questions)

41

The 'cephalo-caudal' principle status that development of the body spreads from:

  1. ((a))

    legs to head

  2. ((b))

    heads to legs

  3. ((c))

    the center of the body outward

  4. ((d))

    outward to the center of the body

Show Answer
Answer: ((b))

heads to legs

In child development, growth and motor skill acquisition follow certain predictable patterns. These patterns help educators and parents understand the sequence in which children gain control over their body and motor abilities. One important principle in this context is the cephalo-caudal principle.

Key Points

  • The cephalo-caudal principle states that development proceeds from the head downwards toward the lower parts of the body.
  • Infants first gain control over head and neck muscles, followed by the upper body, arms, and eventually the legs. This pattern explains why babies can lift their heads and sit before they walk.
  • Understanding this principle helps teachers and caregivers plan age-appropriate activities and support the gradual acquisition of motor skills in children.

Hint

  • Development does not start from the legs to the head; that would contradict observed motor progression.
  • The principle involving the center of the body outward describes the proximodistal pattern, not cephalo-caudal.
  • Outward to center development also corresponds to the proximodistal principle rather than head-to-toe growth.

Hence, the correct answer is heads to legs.

42

In the context of puberty, which one of the following is an absolutely correct option?

(A) Estrogen and Progesterone are female sex hormones

(B) Androgens and Testosterone are female sex hormones

(C) Entrogen and Progesterone are male sex hormones

(D) Androgens and Testosterone are male sex hormones

  1. ((a))

    (B) and (C) are correct.

  2. ((b))

    (A) and (C) are correct.

  3. ((c))

    (A) and (D) are correct.

  4. ((d))

    (B) and (D) are correct.

Show Answer
Answer: ((c))

(A) and (D) are correct.

Puberty is the period of physical and hormonal changes that lead to sexual maturity in adolescents. It involves the production of sex hormones, which regulate the development of secondary sexual characteristics, reproductive organs, and other physiological changes. 

Key Points

  • In females, Estrogen and Progesterone are the primary sex hormones responsible for the development of breasts, regulation of the menstrual cycle, and preparation of the uterus for pregnancy.
  • In males, Androgens, particularly Testosterone, regulate the growth of facial and body hair, deepening of the voice, and development of male reproductive organs.
  • These hormones are specific to each sex and play a critical role in sexual development during puberty.
<br>

Hence, the correct answer is (A) and (D) are correct.

43

A teacher observes that his students are taller and heavier than before. On the part of the students, it shows their _____.

  1. ((a))

    growth

  2. ((b))

    maturation

  3. ((c))

    development

  4. ((d))

    morphogenesis

Show Answer
Answer: ((a))

growth

In child development, it is important to distinguish between growth, maturation, and development. Growth generally refers to measurable physical changes, such as increases in height, weight, and body size.

Key Points

  • When students become taller and heavier, it reflects growth, which is a quantitative change in the body.
  • Growth involves observable and measurable changes in physical dimensions, such as height, weight, and muscle mass.
  • These changes are influenced by genetics, nutrition, and overall health. Monitoring growth helps teachers and parents track the physical well-being and general health of children over time.

Hint

  • Maturation refers to the unfolding of biological processes that prepare a child for functioning, such as puberty, rather than measurable size changes.
  • Development is a broader term that includes physical, cognitive, emotional, and social changes over time.
  • Morphogenesis refers to the biological process that causes tissues and organs to develop their shape, usually a more technical term in biology.

Hence**, the correct answer is growth.**

44

Which of the following is the correct options?

  1. ((a))

    Learning and maturation are two processes through which growth occurs

  2. ((b))

    Progress and maturation are two processes through which growth occurs

  3. ((c))

    Maturation and learning are two processes through which development occurs

  4. ((d))

    Development and learning are two processes through which maturaion occurs

Show Answer
Answer: ((c))

Maturation and learning are two processes through which development occurs

In developmental psychology, growth and development are influenced by both biological and experiential processes. Maturation refers to the natural unfolding of biological processes, while learning represents the changes brought about by experience, practice, and education.

Key Points

  • Development occurs through the combined effects of maturation and learning. Maturation provides the biological readiness needed for certain skills and abilities to emerge, while learning shapes behavior, knowledge, and skills through experience.
  • For example, a child may be biologically ready to speak (maturation), but learning through interaction and practice enables them to acquire language fluency.
  • Together, these two processes drive holistic development in physical, cognitive, and socio-emotional domains.

Hint

  • Learning and maturation contribute to development, not directly to growth alone.
  • Progress is a general term and does not specifically describe a biological or experiential process.
  • Growth occurs mainly as a quantitative physical change and is not defined by development or learning.

Hence**, the correct answer is Maturation and learning are two processes through which development occurs.**

45

Which one of the following studied the child's responses to moral dilemmas ?

  1. ((a))

    Piaget

  2. ((b))

    Erikson

  3. ((c))

    Kohlberg

  4. ((d))

    Skinner

Show Answer
Answer: ((c))

Kohlberg

Moral development in children explores how they understand, reason about, and respond to ethical dilemmas. Several psychologists have contributed to understanding this aspect of development, focusing on different dimensions such as cognitive reasoning, social-emotional growth, and behavior reinforcement.

Key Points

  • Kohlberg studied children’s responses to moral dilemmas to understand the stages of moral reasoning. He presented children with hypothetical moral conflicts, such as the famous “Heinz dilemma,” and analyzed their reasoning rather than the choice itself.
  • Through these studies, he identified a progression of moral development across three levels—pre-conventional, conventional, and post-conventional—with each level containing two stages.
  • Kohlberg’s work emphasizes how children reason about right and wrong and how moral judgment evolves with cognitive and social maturity.

Hint

  • Piaget studied cognitive development and also explored moral reasoning but focused more broadly on general cognitive stages.
  • Erikson analyzed psychosocial development and identity formation rather than moral reasoning specifically.
  • Skinner focused on behaviorism and reinforcement, studying how behavior is shaped by consequences, not moral dilemmas.

Hence, the correct answer is Kohlberg.

46

The cognitive aspects of the personality of an individual do not include his/her :

  1. ((a))

    motivation

  2. ((b))

    thinking

  3. ((c))

    attention

  4. ((d))

    perception

Show Answer
Answer: ((a))

motivation

Personality encompasses multiple dimensions, including cognitive, emotional, and behavioral aspects. Cognitive aspects relate to mental processes such as thinking, attention, perception, problem solving, and memory.

Key Points

  • Motivation is primarily an affective or emotional aspect rather than a cognitive one.
  • It drives behavior, energizes action, and influences goal-directed activity but is not directly involved in information processing or mental representation.
  • In contrast, thinking, attention, and perception are core cognitive functions: thinking involves reasoning and problem solving, attention regulates focus on stimuli, and perception interprets sensory information. Together, these shape the cognitive dimension of personality.

Hint

  • Thinking refers to mental processes of reasoning and decision making.
  • Attention involves selectively focusing on relevant stimuli while ignoring distractions.
  • Perception is the process of organizing and interpreting sensory information to understand the environment.

Hence, the correct answer is motivation.

47

Read the following:

(A) Among boys and girls, different parts of the body grow at same rate.

(B) Among boys and girls, same parts of the body grow at different rate.

(C) Among boys and girls, different parts of the body grow at different rate.

(D) Among boys and girls, same parts of the body grow at same rate.

Which one of the following is the correct option?

  1. ((a))

    (A) and (D) are correct.

  2. ((b))

    (B) and (C) are correct.

  3. ((c))

    (C) and (D) are correct.

  4. ((d))

    (A) and (B) are correct.

Show Answer
Answer: ((b))

(B) and (C) are correct.

In child development, growth is uneven and variable across different body parts and between sexes. Patterns of physical growth are influenced by genetics, hormones, nutrition, and environmental factors. 

Key Points

  • Among boys and girls, different parts of the body grow at different rates. For example, the head grows more rapidly in early infancy, while the legs and trunk grow faster during later childhood and adolescence.
  • Additionally, the same body parts may grow at different rates in boys and girls, especially during puberty, due to hormonal differences. These variations explain why boys and girls show differences in height, weight, and body composition at the same age.
  • Recognizing these patterns helps educators and parents support healthy development and realistic expectations for growth.

Hint

  • Assuming all parts of the body grow at the same rate ignores natural growth variability.
  • Assuming the same parts of the body grow at the same rate in boys and girls overlooks sex-specific differences, particularly during adolescence.

Hence**, the correct answer is (B) and (C) are correct.**

48

Pre-school children trust on their parents as a secure base to explore the environment. This shows their

  1. ((a))

    cognitive development

  2. ((b))

    social development

  3. ((c))

    emotional development

  4. ((d))

    moral development

Show Answer
Answer: ((c))

emotional development

In early childhood, children’s interactions with caregivers play a crucial role in shaping their overall development. Trusting parents as a secure base reflects how children relate to others, regulate emotions, and form attachments.

Key Points

  • When pre-school children rely on their parents as a secure base to explore, it reflects emotional development. They feel safe, supported, and confident to engage with their environment because of a secure attachment.
  • Emotional development involves understanding, expressing, and managing emotions, as well as developing empathy and forming healthy relationships.
  • Secure attachment enables children to explore, learn, and develop resilience while maintaining a sense of security and trust.

Hint

  • Cognitive development relates to thinking, problem solving, and understanding, which is not the focus here.
  • Social development involves interactions with peers and social norms, though attachment contributes indirectly.
  • Moral development concerns understanding right and wrong, which is not indicated in this scenario.

Hence**, the correct answer is emotional development.**

49

A teacher gives a problem to adolescent students that 'X is taller than Y, Y is taller than Z then who is the tallest' ?

This teacher expects that this problem ______

  1. ((a))

    is too easy for the students as it requires symbolic thinking

  2. ((b))

    can not to be solved by the students as it requires critical thinking

  3. ((c))

    can be solved by the students as it requires abstract thinking

  4. ((d))

    should not be given to the students as it requires concrete thinking

Show Answer
Answer: ((c))

can be solved by the students as it requires abstract thinking

Adolescent students, typically in Piaget’s formal operational stage, develop the ability to think abstractly, reason logically, and solve problems mentally without needing concrete objects.

Key Points

  • The problem "X is taller than Y, Y is taller than Z; who is the tallest?" requires students to analyze relationships and use abstract thinking to arrive at the solution.
  • They can mentally manipulate the information and determine that X is the tallest without any physical representation.
  • This demonstrates the development of formal operational thinking, where adolescents are capable of reasoning symbolically and systematically about hypothetical situations.

Hint

  • The problem is not too easy merely because it involves symbolic thinking; abstract reasoning is the focus.
  • It is solvable by students and does not require critical thinking in a complex sense, but rather logical abstraction.
  • Concrete thinking involves physical objects, which is not necessary here, so the problem is not inappropriate.

Hence, the correct answer is can be solved by the students as it requires abstract thinking.

50

in case of adolescents, the peers, parents and teachers have no influence on their :

  1. ((a))

    social development

  2. ((b))

    cognitive development

  3. ((c))

    physical development

  4. ((d))

    emotional development

Show Answer
Answer: ((c))

physical development

Adolescence is a critical stage of development characterized by rapid physical, cognitive, emotional, and social changes. During this period, peers, parents, and teachers play significant roles in shaping attitudes, behaviors, and skills. However, not all aspects of development are equally influenced by social interactions.

Key Points

  • Physical development during adolescence is largely determined by genetics, hormones, and biological maturation.
  • While peers, parents, and teachers can provide guidance on nutrition, exercise, and health, they do not directly control the biological growth processes such as height increase, sexual maturation, or secondary sexual characteristics.
  • These physical changes occur naturally and follow genetically programmed timelines.

Hint

  • Social development is heavily influenced by interactions with peers, parents, and teachers.
  • Cognitive development is shaped by guidance, teaching, and social experiences.
  • Emotional development is influenced by relationships, modeling, and support from significant adults and peers.

Hence, the correct answer is physical development.

51

The word adolescence has been derived from the word 'adolescene' which is a :

  1. ((a))

    Latin word

  2. ((b))

    Greek word

  3. ((c))

    Japaneese word

  4. ((d))

    African word

Show Answer
Answer: ((a))

Latin word

The term adolescence refers to the transitional stage of development between childhood and adulthood, characterized by physical, cognitive, emotional, and social changes. 

Key Points

  • The word adolescence is derived from the Latin word “adolescere,” which means “to grow up” or “to mature.” This etymology reflects the process of physical, emotional, and social growth that occurs during this stage.
  • The term was adopted in psychology and education to describe the critical phase when individuals develop independence, identity, and adult capacities. Recognizing its Latin origin emphasizes the concept of growth and maturation inherent in adolescence.

Hence, the correct answer is Latin word.

52

The socialization agents support an individual in:

  1. ((a))

    learning

  2. ((b))

    confirmity

  3. ((c))

    communication

  4. ((d))

    growth

Show Answer
Answer: ((a))

learning

Socialization agents, such as family, peers, teachers, and media, play a crucial role in shaping an individual’s behavior, values, and skills. They guide the person in interacting with society, understanding norms, and acquiring the necessary tools to function effectively within a social context.

Key Points

  • Socialization agents primarily support an individual in learning. They help the person acquire knowledge, skills, language, social norms, and cultural values.
  • Through observation, guidance, and interaction, individuals learn how to behave appropriately, communicate effectively, and develop cognitive, emotional, and social competencies.
  • This learning process forms the foundation for personal development and societal participation.

Hint

  • Conformity may result from socialization but is not the primary purpose; it is an outcome rather than the process itself.
  • Communication is a skill learned through socialization, but it is only one aspect of the broader learning process.
  • Growth generally refers to physical or overall development, which occurs alongside but is not the main focus of socialization agents.

Hence, the correct answer is learning.

53

Socialization helps an individual in establishing his/her :

  1. ((a))

    self-identity

  2. ((b))

    social identity

  3. ((c))

    group image

  4. ((d))

    community identity

Show Answer
Answer: ((b))

social identity

Socialization is the lifelong process through which individuals learn norms, values, behaviors, and roles necessary to function in society. It involves interaction with family, peers, teachers, and other social institutions, shaping both personal and social aspects of identity.

Key Points

  • Socialization helps an individual in establishing social identity. Through social interactions, a person learns how to behave in different roles, understands societal expectations, and develops a sense of belonging to various social groups.
  • Social identity encompasses one’s position in society, group memberships, and recognition by others, which are all shaped by the process of socialization.

Hint

  • Self-identity refers to personal awareness and self-concept, which is influenced by but distinct from socialization.
  • Group image and community identity relate more to the perception of the group or community as a whole rather than the individual’s integration into society.

Hence, the correct answer is Social identity.

54

'Shiksha Karmi Project' of Rajasthan is :

  1. ((a))

    the name of professional development programme of school teachers

  2. ((b))

    concerned with identifying outstanding contribution of school teacher in education

  3. ((c))

    scholarship programme for meritorious pre-service teachers

  4. ((d))

    a way to ensure community participation in formal education

Show Answer
Answer: ((d))

a way to ensure community participation in formal education

The Shiksha Karmi Project in Rajasthan is a notable educational initiative aimed at improving access to education in remote and underserved areas. It reflects an effort to involve local communities in enhancing educational opportunities, particularly in villages where conventional schooling faces logistical challenges.

Key Points

  • The Shiksha Karmi Project primarily functions as a way to ensure community participation in formal education.
  • Local residents, often educated youth from the community, are appointed as Shiksha Karmis (teachers) to provide basic education to children in their villages.
  • This approach helps in increasing enrollment, reducing dropout rates, and making education more accessible and culturally relevant. By involving community members directly, the project fosters ownership and accountability for education, creating a supportive environment for learning.

Hint

  • It is not a professional development program for existing school teachers.
  • It does not focus on identifying outstanding contributions of teachers.
  • It is not a scholarship program for pre-service teachers.

Hence**, the correct answer is a way to ensure community participation in formal education.**

55

In India, home schooling is recognized by :

  1. ((a))

    NIOS

  2. ((b))

    CBSE

  3. ((c))

    IB

  4. ((d))

    ICSE

Show Answer
Answer: ((a))

NIOS

Home schooling refers to the practice of educating children at home rather than sending them to formal schools. In India, although conventional schooling is the norm, certain boards and institutions provide frameworks that allow recognition of learning for students educated at home, enabling them to appear for public examinations.

Key Points

  • In India, NIOS (National Institute of Open Schooling) recognizes home schooling. NIOS provides flexibility for learners to complete school education outside formal classrooms.
  • It allows students to register under its Open Basic Education or Secondary and Senior Secondary courses, appear for examinations, and obtain valid certificates.
  • This recognition ensures that home-schooled students can continue their academic and career progression without barriers, aligning with inclusive and flexible education principles.

Hint

  • CBSE and ICSE primarily cater to students enrolled in formal schools and do not formally recognize home schooling.
  • IB (International Baccalaureate) is an international program and not a regulatory body in India for home schooling certification.

Hence, the correct answer is NIOS.

56

Which of the following statements is not true about curriculum?

  1. ((a))

    Curriculum is a complete set and very broad in nature.

  2. ((b))

    Curriculum includes the planned and guided learning experiences.

  3. ((c))

    Curriculum is descriptive in nature.

  4. ((d))

    Curriculum is framed by high level educational experts.

Show Answer
Answer: ((c))

Curriculum is descriptive in nature.

Curriculum refers to the structured plan of educational experiences designed to achieve specific learning outcomes. It encompasses objectives, content, learning experiences, teaching methods, and assessment strategies.

Key Points

  • Saying that curriculum is descriptive in nature is not entirely accurate.
  • Curriculum is primarily prescriptive and planned, specifying what is to be taught, how it should be taught, and the expected outcomes.
  • While it may describe certain content, its main function is to guide teaching and learning, rather than merely describe educational experiences. This distinguishes curriculum from a simple description of learning or a textbook.

Hint

  • Curriculum being a complete set and broad in nature reflects its comprehensive scope across subjects and skills.
  • Including planned and guided learning experiences is a core characteristic of curriculum.
  • Framing by high-level educational experts ensures that curriculum is coherent, structured, and aligned with educational goals.

Hence, the correct answer is Curriculum is descriptive in nature.

57

Which of the following is not commonly used approach for curriculum development?

  1. ((a))

    Subject centred approach

  2. ((b))

    Community centred approach

  3. ((c))

    Child centred approach

  4. ((d))

    Life centered approach

Show Answer
Answer: ((b))

Community centred approach

Curriculum development involves designing educational experiences that are meaningful, relevant, and effective for learners. Various approaches guide this process, focusing on different priorities such as the subject matter, the learner, or societal needs.

Key Points

  • The community centered approach is not commonly recognized as a standard approach in mainstream curriculum development.
  • While community needs may inform curriculum design indirectly, the commonly accepted approaches include subject-centered, child-centered, and life-centered approaches.

These focus respectively on organized subject matter, the interests and developmental needs of the child, and preparing learners for practical life skills and problem solving.

Hint

  • Subject-centered approach emphasizes mastery of disciplines or subjects.
  • Child-centered approach prioritizes the interests, abilities, and developmental needs of learners.
  • Life-centered approach integrates real-life experiences and skills to make learning meaningful and applicable.

Hence, the correct answer is Community centered approach.

58

Which one of the following is the key to Competency Based Education?

  1. ((a))

    Acquisition of skill (s)

  2. ((b))

    Learning at one's own pace

  3. ((c))

    Immediate feedback

  4. ((d))

    Mastering learning

Show Answer
Answer: ((d))

Mastering learning

Competency Based Education (CBE) focuses on ensuring that learners acquire specific abilities, knowledge, and skills, rather than just completing a set amount of time in class. It emphasizes measurable outcomes, mastery of content, and the application of knowledge in real-life contexts, making learning personalized and results-oriented.

Key Points

  • The core of Competency Based Education is mastering learning. In CBE, students progress only after demonstrating mastery of a concept or skill. This ensures that learning is meaningful and complete, rather than superficial.
  • Mastery allows learners to apply knowledge effectively, build confidence, and move on to more complex skills without gaps.
  • Immediate feedback, personalized pacing, and skill acquisition support mastery, but achieving it remains the primary goal of the approach.

Hint

  • Acquisition of skills is important but is a component rather than the defining feature.
  • Learning at one’s own pace and immediate feedback are supportive mechanisms that facilitate mastery, not the key itself.

Hence**, the correct answer is Mastering learning.**

59

'Assessment as learning' is:

  1. ((a))

    Partially teacher controlled

  2. ((b))

    Entirely teacher controlled 

  3. ((c))

    Partially student controlled 

  4. ((d))

    Entirely student controlled

Show Answer
Answer: ((c))

Partially student controlled 

Assessment in education can be categorized into assessment of learning, assessment for learning, and assessment as learning. Each type has a distinct purpose: measuring achievement, guiding instruction, or fostering self-regulation.

Key Points

  • Assessment as learning emphasizes students’ active role in monitoring and regulating their own learning.
  • It is partially student controlled, as learners reflect on their progress, set goals, and make decisions about strategies to improve.
  • The teacher facilitates this process by providing guidance, feedback, and tools for self-assessment. This approach encourages metacognition, self-awareness, and responsibility for learning while still involving the teacher as a supportive facilitator.

Hint

  • Entirely teacher controlled assessment aligns more with assessment of learning.
  • Entirely student controlled assessment would remove teacher guidance, which is not the intent of assessment as learning.
  • Partially teacher controlled does not fully capture the students’ active role in self-regulation.

Hence, the correct answer is Partially student controlled.

60

Which one the following can be most useful in developing a habit among children to search from new knowledge from the familiar environment?

  1. ((a))

    Text book

  2. ((b))

    Integrated text books

  3. ((c))

    Exposure to ICT

  4. ((d))

    Exposure to real life situations

Show Answer
Answer: ((d))

Exposure to real life situations

Developing a habit of exploring and discovering new knowledge is essential for fostering curiosity and critical thinking in children. Learning becomes meaningful when students connect new concepts to their existing experiences and environment, promoting active engagement and lifelong learning.

Key Points

  • Exposure to real-life situations is most effective for encouraging children to search for new knowledge from familiar environments.
  • When students interact with their surroundings—such as observing plants, visiting markets, or exploring local communities—they relate classroom concepts to real-world experiences.
  • This hands-on engagement stimulates curiosity, encourages questioning, and develops problem-solving skills. It helps children learn actively rather than passively, making knowledge acquisition more meaningful and memorable.

Hint

  • Textbooks provide structured content but are often abstract and less connected to the child’s immediate environment.
  • Integrated textbooks combine subjects but still primarily offer guided information rather than experiential learning.
  • Exposure to ICT can enhance access to information but does not directly connect learning to familiar, tangible experiences.

Hence, the correct answer is Exposure to real life situations.

61

Main limitation of Computer Assisted Instruction (CAI) is that:

  1. ((a))

    It is a self learning technique.

  2. ((b))

    It uses mix of text, graphics, sound and videos.

  3. ((c))

    Its learning is too mechanical.

  4. ((d))

    it provides immediate feedback.

Show Answer
Answer: ((c))

Its learning is too mechanical.

Computer Assisted Instruction (CAI) refers to the use of computers to deliver instructional material and facilitate learning. CAI offers advantages such as interactive content, multimedia integration, individualized pacing, and immediate feedback.

Key Points

  • The primary limitation of CAI is that its learning can be too mechanical. While CAI provides structured exercises, drills, and practice, it may emphasize rote memorization and repetitive tasks rather than deep understanding, critical thinking, or creative problem solving.
  • Students may follow programmed instructions without actively engaging in higher-order cognitive processes, limiting the development of reasoning and conceptual skills.

Hint

  • Being a self-learning technique is an advantage, allowing learners to progress at their own pace.
  • Using a mix of text, graphics, sound, and videos enhances engagement and understanding.
  • Providing immediate feedback helps correct errors and reinforce learning, making it a positive feature rather than a limitation.

Hence**, the correct answer is Its learning is too mechanical.**

62

Which one of the following is not a characteristic of a teacher made test?

  1. ((a))

    Norms are available for comparison.

  2. ((b))

    Helps identifying learning difficulties of pupils.

  3. ((c))

    Can contain variety of items.

  4. ((d))

    Covers limited number of competencies.

Show Answer
Answer: ((a))

Norms are available for comparison.

Teacher-made tests are assessments designed by classroom teachers to evaluate student learning. They are typically tailored to the specific content taught and the learning objectives of the class. These tests are useful for monitoring progress, identifying difficulties, and guiding instruction.

Key Points

  • Norms are available for comparison is not a characteristic of teacher-made tests. Teacher-made tests are generally criterion-referenced, meaning they assess whether students have achieved specific learning objectives rather than comparing them to a broader population.
  • Norm-referenced tests, in contrast, provide standardized comparisons across a larger group of students, which is not the purpose of typical teacher-designed assessments.

Hint

  • Helping identify learning difficulties is a key function of teacher-made tests.
  • They can contain a variety of items, such as multiple-choice, short answer, and practical exercises.
  • They often cover a limited number of competencies, focusing on material taught in a particular class or unit.

Hence, the correct answer is Norms are available for comparison.

63

Which of the following may not be a part of strategy for preventing indiscipline?

  1. ((a))

    Adoption of task oriented approach

  2. ((b))

    Provision of a long list of restrictions which you expect to maintain

  3. ((c))

    Evolving rules through discussion with students

  4. ((d))

    Praising/ Appreciating students for their good achievements

Show Answer
Answer: ((b))

Provision of a long list of restrictions which you expect to maintain

Maintaining discipline in the classroom is crucial for creating a conducive learning environment. Effective strategies for preventing indiscipline focus on guidance, positive reinforcement, and involving students in the process rather than relying solely on punishment or rigid rules.

Key Points

  • Provision of a long list of restrictions which you expect to maintain may not be effective in preventing indiscipline.
  • Overloading students with numerous strict rules can lead to confusion, resentment, and resistance.
  • Such an approach emphasizes control rather than learning self-discipline, and often fails to address the underlying causes of misbehavior.
  • Preventing indiscipline is more effective when students understand, participate in, and internalize the rules.

Hint

  • Adoption of a task-oriented approach keeps students engaged and focused, reducing opportunities for misbehavior.
  • Evolving rules through discussion with students promotes ownership and understanding of expectations.
  • Praising and appreciating students for good achievements reinforces positive behavior and motivates adherence to norms.

Hence, the correct answer is Provision of a long list of restrictions which you expect to maintain.

64

Which of the following classroom practice is not an outcome of Behavior modification approach?

  1. ((a))

    Repetition without reinforcement does not enhance learning.

  2. ((b))

    Punishment is very effective for eliminating undesirable behavior.

  3. ((c))

    Interest in work and improvement is conducive to learning.

  4. ((d))

    Variations in presenting the reinforces help modification of behavior.

Show Answer
Answer: ((b))

Punishment is very effective for eliminating undesirable behavior.

Behavior modification is a psychological approach that focuses on shaping behavior through reinforcement, punishment, and systematic practice. In the classroom, it is used to encourage desirable behaviors, reduce undesirable ones, and enhance learning through structured reinforcement strategies.

Key Points

  • The idea that punishment is very effective for eliminating undesirable behavior is not fully aligned with the principles of behavior modification.
  • While punishment can temporarily suppress unwanted behavior, it does not teach alternative desirable behaviors and may have negative side effects such as fear, anxiety, or resentment.
  • Behavior modification emphasizes positive reinforcement, structured practice, and reinforcement variations to sustainably shape behavior.

Hint

  • Repetition without reinforcement does not enhance learning, highlighting the importance of reinforcement in behavior modification.
  • Interest in work and improvement being conducive to learning aligns with motivating behavior through positive engagement.
  • Variations in presenting reinforcers help in maintaining motivation and effectively modifying behavior over time.

Hence, the correct answer is Punishment is very effective for eliminating undesirable behavior.

65

Which is not a characteristic feature of course delivery in 'teacher centred approach' ?

  1. ((a))

    Use of lecture method

  2. ((b))

    Summative tests

  3. ((c))

    Active learning

  4. ((d))

    No unit planning and unit test

Show Answer
Answer: ((c))

Active learning

In a teacher-centred approach, the focus is primarily on the teacher as the source of knowledge. Instruction is structured, with the teacher controlling the pace, content, and assessment, while students are mostly passive recipients of information.

Key Points

  • Active learning is not a characteristic of the teacher-centered approach. In active learning, students engage directly with content through discussions, problem solving, group activities, and hands-on experiences.
  • Teacher-centered instruction, in contrast, emphasizes lectures, note-taking, and passive reception of information, leaving little room for student participation or interactive learning.

Hint

  • Use of lecture method is typical of teacher-centered instruction.
  • Summative tests are commonly used to evaluate learning outcomes in this approach.
  • No unit planning and unit tests may occur in poorly structured teacher-centered delivery but planning is generally guided by the teacher rather than students.

Hence, the correct answer is Active learning.

66

Read the following carefully :

(a) Students are working individually or in small groups.

(b) They are busy analyzing the identified theme within a pre-set time limit

(c) They are dealing with 'real life' problem.

Which method of teaching-learning is being followed?

  1. ((a))

    Problem solving method

  2. ((b))

    Project method

  3. ((c))

    Discovery method

  4. ((d))

    Play way method

Show Answer
Answer: ((b))

Project method

Different teaching-learning methods emphasize various ways of engaging students with knowledge. These methods are designed to develop critical thinking, problem-solving abilities, creativity, and practical understanding.

Key Points

  • The described scenario corresponds to the Project method. In this method, students work individually or in small groups to investigate and analyze a chosen theme or topic over a period of time.
  • They engage with real-life problems or themes, plan their activities, gather information, and present findings.
  • This method promotes active learning, collaboration, practical application, and integration of knowledge across disciplines, making learning meaningful and contextually relevant.

Hint

  • Problem-solving method focuses on identifying and resolving specific problems but may not involve extensive projects or themes.
  • Discovery method emphasizes exploring and uncovering concepts independently, often guided by curiosity rather than structured projects.
  • Play-way method uses games and playful activities to facilitate learning, primarily in early childhood education.

Hence, the correct answer is Project method.

67

Which of the following restrictions will not be effective in making an essay type item as restricted response item ?

Restriction to be imposed on:

  1. ((a))

    Length of response 

  2. ((b))

    Content of response

  3. ((c))

    Duration of response 

  4. ((d))

    Convergent thinking

Show Answer
Answer: ((c))

Duration of response 

In assessment design, essay-type items can be modified to focus responses and make scoring more objective. Restricted-response items limit the scope of answers, guiding students to provide concise and relevant responses, thereby improving reliability and ease of evaluation.

Key Points

  • Duration of response is not an effective restriction for converting an essay-type item into a restricted-response item.
  • Limiting the time a student has to write does not inherently restrict the content, length, or focus of the response.
  • Students may still write broad or unfocused answers within the time limit, so it does not serve the purpose of narrowing the scope or making the item easier to score objectively.

Hint

  • Restricting the length of response ensures concise answers.
  • Restricting the content of response directs students to address specific aspects of the topic.
  • Encouraging convergent thinking focuses responses toward a particular solution or viewpoint, limiting variability and subjectivity.

Hence, the correct answer is Duration of response.

68

Which one of the following is not a characteristic of integrated teaching' ?

  1. ((a))

    Flexible student groupings

  2. ((b))

    Inflexible schedules

  3. ((c))

    Sources that go beyond textbooks

  4. ((d))

    Relationship among concepts

Show Answer
Answer: ((b))

Inflexible schedules

Integrated teaching is an approach that connects knowledge, skills, and experiences across different subjects or learning areas. It emphasizes holistic understanding, relevance to real-life situations, and the application of learning in meaningful contexts.

Key Points

  • Inflexible schedules is not a characteristic of integrated teaching.
  • Integrated teaching requires flexibility in planning and execution, allowing teachers to adjust time, groupings, and activities based on learning objectives and student needs.
  • Rigid schedules hinder the interdisciplinary and student-centered nature of this approach.

Hint

  • Flexible student groupings facilitate collaboration and peer learning.
  • Using sources beyond textbooks enriches learning and promotes inquiry.
  • Establishing relationships among concepts helps students see connections and develop a deeper understanding of content.

Hence**, the correct answer is Inflexible schedules.**

69

In the final analysis, the key to motivation in classroom is : 

  1. ((a))

    The interest inherent in the subject matter

  2. ((b))

    The teacher's personality and his / her teaching method

  3. ((c))

    The emotional climate of the classroom

  4. ((d))

    The suitability of curricular experiences in the class

Show Answer
Answer: ((a))

The interest inherent in the subject matter

Motivation in the classroom is essential for effective learning. It determines the level of engagement, persistence, and enthusiasm students show toward learning activities.

Key Points

  • The interest inherent in the subject matter is the central element in motivating students.
  • When students find the content meaningful, relevant, and engaging, they are naturally driven to learn, explore, and persist in overcoming challenges.
  • While the teacher’s personality, teaching methods, emotional climate, and suitable curricular experiences support motivation, the intrinsic appeal and relevance of the subject matter directly stimulate curiosity and sustained learning.

Hint

  • The teacher’s personality and teaching method can enhance motivation but are secondary to the content itself.
  • The emotional climate of the classroom creates a supportive environment but does not inherently make the content interesting.
  • Suitability of curricular experiences facilitates learning but is effective only if the content itself engages the student.

Hence, the correct answer is The interest inherent in the subject matter.

70

Aptitude Tests measure:

  1. ((a))

    Potentiality

  2. ((b))

    Proficiency

  3. ((c))

    Likely success in a profession

  4. ((d))

    Achievement

Show Answer
Answer: ((a))

Potentiality

Aptitude tests are designed to assess an individual’s natural abilities, talents, and potential to perform certain tasks or succeed in specific areas. These tests are widely used in educational and career guidance to help predict future performance rather than evaluate what has already been learned.

Key Points

  • Aptitude tests primarily measure potentiality. They identify an individual’s inherent strengths, reasoning ability, problem-solving skills, and capacity to acquire specific knowledge or skills.
  • For example, a mechanical aptitude test evaluates the potential to excel in engineering-related tasks, even if the person has not received formal training.
  • This focus on innate ability distinguishes aptitude tests from achievement tests, which assess learned knowledge.

Hint

  • Proficiency refers to current skill or competence, which is measured by achievement or performance tests.
  • Likely success in a profession is an outcome that aptitude may help predict but is not directly measured.
  • Achievement measures what a person has already learned or accomplished, unlike aptitude tests.

Hence, the correct answer is Potentiality.

71

By following, which one of the actions, a school can act as a 'learning resource' for community? 

  1. ((a))

    By organizing educative movie shows in community

  2. ((b))

    By nominating teachers as members of all local civic bodies

  3. ((c))

    By organizing 'discussion camps' on social issues in community

  4. ((d))

    By inviting community people in science exhibitions in schools

Show Answer
Answer: ((a))

By organizing educative movie shows in community

Schools are not just centers for student learning; they can also serve as learning resources for the broader community. By extending educational activities beyond the classroom, schools can foster community engagement, awareness, and lifelong learning.

Key Points

  • A school can act as a learning resource for the community by organizing educative movie shows.
  • Such activities provide accessible, engaging, and informative experiences for community members, spreading knowledge on social, scientific, or cultural topics. 'These programs create a bridge between formal education and community learning, allowing the school to serve as a hub for public education and awareness.

Hint

  • Nominating teachers to local civic bodies increases influence but does not directly provide learning opportunities to the community.
  • Organizing discussion camps on social issues may be useful but often involves only a limited group of participants.
  • Inviting community members to science exhibitions is beneficial but tends to be occasional rather than a systematic resource for community learning.

Hence, the correct answer is By organizing educative movie shows in community.

72

How a community can contribute best to school as a 'learning resource' ?

  1. ((a))

    By selecting its best persons from all vocations to interact with students and teachers

  2. ((b))

    By effectively participating in P.T.A. meetings

  3. ((c))

    By donating generously for school development

  4. ((d))

    By providing free of cost, best technicians to build school labs 

Show Answer
Answer: ((a))

By selecting its best persons from all vocations to interact with students and teachers

Schools can enhance learning when they actively involve the community. Viewing the school as a hub of knowledge, the community can contribute expertise, experiences, and resources, making learning more relevant, practical, and connected to real-life contexts.

Key Points

  • A community can contribute best as a learning resource by selecting its best persons from all vocations to interact with students and teachers.
  • Such interactions expose students to practical knowledge, career insights, and real-world problem-solving experiences.
  • Experts from diverse fields can serve as mentors, provide guidance, and enrich classroom learning beyond textbooks, fostering curiosity, skill development, and contextual understanding.

Hint

  • Participating in P.T.A. meetings supports administrative and planning processes but is indirect in enhancing learning.
  • Donating funds helps infrastructure but does not directly contribute to knowledge or skill development.
  • Providing technicians for labs is useful for setup but does not involve knowledge sharing or interactive learning with students.

Hence**, the correct answer is by selecting its best persons from all vocations to interact with students and teachers.**

73

As per WHO which one of the following is not an indicator of sound mental health? 

  1. ((a))

    Sense of Coherence

  2. ((b))

    Optimism 

  3. ((c))

    Sense of Control

  4. ((d))

    Confidence

Show Answer
Answer: ((a))

Sense of Coherence

Mental health, according to the World Health Organization (WHO), is a state of well-being in which an individual realizes their abilities, can cope with normal stresses, work productively, and contribute to the community.

Key Points

  • Sense of Coherence is a concept introduced by Aaron Antonovsky and is not specifically listed by WHO as an indicator of sound mental health.
  • It refers to a person’s ability to perceive life as comprehensible, manageable, and meaningful, which is related to coping and resilience but is a distinct theoretical framework rather than a WHO-defined mental health indicator.
  • In contrast, optimism, sense of control, and confidence are recognized as traits that contribute directly to psychological well-being and sound mental health.

Hint

  • Optimism reflects a positive outlook on life, aiding stress management and resilience.
  • Sense of control indicates perceived ability to influence life events, enhancing well-being.
  • Confidence relates to self-assurance in one’s abilities, supporting mental stability and social functioning.

Hence, the correct answer is Sense of Coherence.

74

How many types of disabilities have been identified through RPWD Act, 2016?

  1. ((a))

    18

  2. ((b))

    19

  3. ((c))

    21

  4. ((d))

    23

Show Answer
Answer: ((c))

21

The Rights of Persons with Disabilities (RPWD) Act, 2016 in India provides a comprehensive framework for recognizing, protecting, and promoting the rights of persons with disabilities. 

Key Points

  • The RPWD Act, 2016 recognizes 21 types of disabilities. These include physical, sensory, intellectual, mental, and multiple disabilities, ranging from blindness, low vision, hearing impairment, and locomotor disability to specific learning disabilities, autism spectrum disorder, chronic neurological conditions, and more.
  • Identifying these categories ensures that all individuals receive appropriate support, accessibility accommodations, and legal protection to participate fully in society.

Hence**, the correct answer is 21.**

75

Which one of the following member of school development planning committee is likely to contribute minimum?

  1. ((a))

    District inspector of schools

  2. ((b))

    Manager of an adjoining industry

  3. ((c))

    Parents of school children

  4. ((d))

    Professors of a nearby college

Show Answer
Answer: ((b))

Manager of an adjoining industry

A School Development Planning Committee is designed to bring together diverse stakeholders to enhance the quality of education and overall school development. Members contribute based on their expertise, experience, and connection with the school and community, ensuring holistic planning and effective implementation of programs.

Key Points

  • The Manager of an adjoining industry is likely to contribute minimum to the school development planning committee.
  • While industrial managers have valuable experience in administration or technical fields, they generally lack direct involvement with school education, teaching-learning processes, student needs, and academic planning.
  • Their inputs may be peripheral compared to members who are directly engaged in educational activities.

Hint

  • District inspectors of schools provide regulatory guidance, curriculum understanding, and administrative oversight.
  • Parents contribute insight into students’ needs, community expectations, and support for school initiatives.
  • Professors of nearby colleges bring academic expertise, pedagogical knowledge, and guidance for curriculum enhancement or teacher development.

Hence**, the correct answer is Manager of an adjoining industry.**

76

Which one of the following can provide a good school leadership?

  1. ((a))

    A teacher who has a mastery in communication

  2. ((b))

    A teacher who involves learners and seeks their partnership even in teaching

  3. ((c))

    A teacher who recently passed a course on school leadership with distinction 

  4. ((d))

    A teacher who was elected as president of teacher association

Show Answer
Answer: ((b))

A teacher who involves learners and seeks their partnership even in teaching

Effective school leadership plays a critical role in shaping the learning environment, motivating staff, and ensuring student success. Good leadership goes beyond formal qualifications or positions; it involves vision, collaboration, and the ability to engage all stakeholders in the educational process.

Key Points

  • A teacher who involves learners and seeks their partnership even in teaching exemplifies good school leadership. Such a teacher promotes participatory learning, encourages shared responsibility, and fosters a positive school culture.
  • By valuing student input and collaboration, the teacher enhances motivation, builds trust, and models democratic and inclusive practices that strengthen both teaching and overall school functioning.

Hint

  • Mastery in communication is important but insufficient alone for comprehensive leadership.
  • Recently passing a leadership course provides knowledge but does not guarantee effective practice.
  • Being elected president of a teacher association reflects recognition but may not translate into active, student-focused leadership in the school setting.

Hence, the correct answer is A teacher who involves learners and seeks their partnership even in teaching.

77

In the present school scenario which role is generally not expected from a school teacher? 

  1. ((a))

    Curriculum designing

  2. ((b))

    Reflective practitioner

  3. ((c))

    Team builder and initiator

  4. ((d))

    Coach and mentor

Show Answer
Answer: ((a))

Curriculum designing

The role of a school teacher has evolved beyond just delivering lessons. Modern teachers are expected to guide learning, foster collaboration, mentor students, and contribute to the overall development of the school environment.

Key Points

  • Curriculum designing is generally not expected from a school teacher in the present scenario.
  • Curriculum design is typically undertaken by educational boards, curriculum authorities, or specialized experts.
  • While teachers may adapt or supplement teaching materials, creating the formal curriculum is not their primary responsibility in most schools.

Hint

  • Being a reflective practitioner allows teachers to evaluate and improve their own teaching practices.
  • Acting as a team builder and initiator helps in collaborative projects and school initiatives.
  • Serving as a coach and mentor supports student development, motivation, and guidance beyond academics.

Hence, the correct answer is Curriculum designing.

78

The best role of a school teacher as a coach is reflected in the act of ______

  1. ((a))

    Curriculum planning

  2. ((b))

    Preparing students for examination

  3. ((c))

    Story telling

  4. ((d))

    Evaluating student's performance

Show Answer
Answer: ((d))

Evaluating student's performance

A school teacher’s role as a coach focuses on guiding, supporting, and nurturing students’ overall growth, rather than merely delivering content.

Key Points

  • Evaluating students’ performance best reflects the teacher’s role as a coach.
  • Through careful assessment, feedback, and guidance, the teacher identifies students’ strengths and areas for improvement, helps them set goals, and provides strategies to enhance learning and performance.
  • This approach encourages continuous growth, self-reflection, and skill mastery, which are hallmarks of effective coaching.

Hint

  • Curriculum planning is primarily a design and organizational task, not direct coaching.
  • Preparing students for examinations focuses narrowly on academic outcomes rather than overall development.
  • Storytelling may engage and inspire students but does not systematically guide individual growth or performance.

Hence, the correct answer is Evaluating student's performance.

79

Ms. Nair, the language teacher was told by her Principal, 'Our education minister has come through this new technique of evaluation and he wants us to implement it immediately. This is an example of:

  1. ((a))

    Demonstration Model

  2. ((b))

    Grassroot Model

  3. ((c))

    Administrative Line Staff Model

  4. ((d))

    Activity Model

Show Answer
Answer: ((c))

Administrative Line Staff Model

Different models of implementing educational innovations or reforms describe how new methods, techniques, or policies are introduced and adopted in schools. These models vary based on who initiates the change and how it is communicated to teachers and institutions.

Key Points

  • This scenario exemplifies the Administrative Line Staff Model. In this model, directives come from higher authorities, such as government officials or educational administrators, and are communicated down the administrative hierarchy to schools and teachers.
  • The implementation is often top-down, with little initial teacher input or grassroots involvement.
  • Here, Ms. Nair is instructed to adopt a new evaluation technique because the education minister has mandated it, reflecting centralized administrative control.

Hint

  • Demonstration Model involves showing the innovation in action for teachers to learn and adopt it.
  • Grassroot Model emphasizes changes initiated by teachers or local stakeholders at the school level.
  • Activity Model focuses on engaging teachers in hands-on activities to understand and implement innovations.

Hence, the correct answer is Administrative Line Staff Model.

80

The most suitable stage to develop analytical and critical thinking among students is:

  1. ((a))

    Primary level

  2. ((b))

    Middle school level

  3. ((c))

    Secondary school level

  4. ((d))

    Senior secondary school level

Show Answer
Answer: ((c))

Secondary school level

Analytical and critical thinking are higher-order cognitive skills that involve evaluating information, making reasoned judgments, and solving complex problems.

Key Points

  • The secondary school level is the most suitable stage to develop analytical and critical thinking.
  • At this stage, students possess the necessary cognitive maturity, abstract reasoning abilities, and prior knowledge to analyze, evaluate, and synthesize information.
  • Teachers can engage students in problem-solving tasks, debates, project work, and critical discussions, fostering independent thinking and informed decision-making.

Hint

  • Primary level focuses on foundational skills like literacy, numeracy, and basic observation.
  • Middle school level introduces reasoning and basic analytical skills but not yet at the level required for advanced critical thinking.
  • Senior secondary level can further refine and deepen critical thinking but the foundational development occurs during secondary school.

Hence, the correct answer is Secondary school level.

Subject Specific (100 questions)

81

Arsenic (III) sulphide reacts with oxygen to form arsenic (III) oxide and sulphur (IV) oxide :

_As2 S3 + _O2 → _As2 O3 + SO2

What is the coefficient for O2 when the equation is balanced using whole number coefficents?

  1. ((a))

    5

  2. ((b))

    7

  3. ((c))

    9

  4. ((d))

    11

Show Answer
Answer: ((c))

9

CONCEPT:

Balancing Chemical Equations

  • A balanced chemical equation ensures that the number of atoms for each element is equal on both sides of the reaction.
  • To balance an equation, we assign coefficients to the reactants and products so that the law of conservation of mass is maintained.
  • The coefficients must be whole numbers and should represent the smallest ratio possible.

EXPLANATION:

  • The given reaction is:
  • As2S3 + O2 → As2O3 + SO2
  • Step-by-step balancing:
  • Start with arsenic (As): There are 2 As atoms in As2S3 and 2 As atoms in As2O3, so arsenic is already balanced.
  • Next, balance sulfur (S): There are 3 S atoms in As2S3 and 3 SO2 molecules, so sulfur is balanced.
  • Finally, balance oxygen (O):
  • 2 As2S3 + 9 O2 → 2 As2O3 + 6 SO2
  • On the right side, there are 3 O atoms in As2O3 and 6 O atoms in 3 SO2 molecules, totaling 9 O atoms.
  • On the left side, O2 contributes 2 O atoms per molecule. To balance, 9 O atoms are required, so the coefficient for O2 is 9/2.
  • To use whole number coefficients, multiply all coefficients in the equation by 2:
  • The coefficient for O2 is 9.

Therefore, the coefficient for O2 when the equation is balanced using whole number coefficients is 9.

82

When FeCl3 is ignited in an atmosphere of pure oxygen, the reaction that takes place is :

4FeCl3(s) + 3O2(g) → 2Fe2O3(s) + 6Cl2(g)

If 3.0 Mol of FeCl3 are ignited in the presence of 2.0 Mol of O2 gas, how much of which reagent is present of 2.0 Mol of O2 gas, how much of which reagent is present in excess and therefore remains unreacted?

  1. ((a))

    0.33 Mol FeCl3

  2. ((b))

    0.67 Mol FeCl​3

  3. ((c))

    0.25 Mol O2

  4. ((d))

    0.50 Mol O​2

Show Answer
Answer: ((a))

0.33 Mol FeCl3

CONCEPT:

Limiting Reagent and Excess Reagent

  • In a chemical reaction, the limiting reagent is the reactant that is completely consumed first, limiting the amount of product formed.
  • The excess reagent is the reactant that remains after the reaction is complete.
  • To determine the limiting reagent:
  • Use the mole ratio from the balanced chemical equation to compare the moles of reactants available.

EXPLANATION:

  • The given reaction is:
  • 4FeCl3(s) + 3O2(g) → 2Fe2O3(s) + 6Cl2(g)
  • From the balanced equation:
  • 4 moles of FeCl3 react with 3 moles of O2.
  • Mole ratio of FeCl3:O2 = 4:3.
  • Given:
  • 3.0 moles of FeCl3
  • 2.0 moles of O2
  • Calculate the moles required:
  • For FeCl3:
  • Moles of O2 required for 3.0 moles of FeCl3 = (3.0 × 3) / 4 = 2.25 moles
  • Available O2: 2.0 moles
  • Since 2.0 < 2.25, O2 is the limiting reagent.
  • Determine excess reagent:
  • Moles of FeCl3 that react with 2.0 moles of O2:
  • Moles of FeCl3 = (2.0 × 4) / 3 = 2.67 moles
  • Excess FeCl3 = Total FeCl3 - Reacted FeCl3
  • Excess FeCl3 = 3.0 - 2.67 = 0.33 moles

Therefore, FeCl3 is the excess reagent, and 0.33 moles of FeCl3 remain unreacted.

83

Magnetite Fe3O4, is a mixture of iron (II) oxide and iron (III) oxide. What is the most likely ratio of iron (II) oxide to iron (III) oxide in magnetite?

  1. ((a))

    1 : 1

  2. ((b))

    1 : 2

  3. ((c))

    2 : 3

  4. ((d))

    3 : 2

Show Answer
Answer: ((a))

1 : 1

CONCEPT:

Composition of Magnetite (Fe3O4)

  • Magnetite (Fe3O4) is a mixed oxide of iron.
  • It is composed of both iron(II) oxide (FeO) and iron(III) oxide (Fe2O3).
  • The chemical formula of magnetite, Fe3O4, can be rewritten as FeO·Fe2O3, indicating it is a combination of 1 mole of FeO and 1 mole of Fe2O3.

EXPLANATION:

  • To determine the ratio of FeO (iron(II) oxide) to Fe2O3 (iron(III) oxide) in magnetite:
  • Fe3O4 consists of 1 FeO and 1 Fe2O3.
  • FeO contains one Fe atom, while Fe2O3 contains two Fe atoms.
  • Thus, the total number of Fe atoms in Fe3O4 is 3 (1 from FeO and 2 from Fe2O3).
  • The oxygen atoms in Fe3O4 are balanced as well, with 4 oxygen atoms in total (1 from FeO and 3 from Fe2O3).
  • This shows that Fe3O4 is a combination of FeO and Fe2O3 in a 1:1 molar ratio.

Therefore, the most likely ratio of iron(II) oxide to iron(III) oxide in magnetite is 1:1.

84

Calculate the volume of 0.110 M Copper (II) nitrate solution that can be prepared by dissolving 33.29 g of Copper (II) nitrate trihydrate in sufficient distilled water.

The Molar mass of Cu(NO3)2. 3H2O is 241.6 g mol-1.

  1. ((a))

    0.50 L

  2. ((b))

    1.25 L

  3. ((c))

    2.50 L

  4. ((d))

    3.75 L

Show Answer
Answer: ((b))

1.25 L

CONCEPT:

Molarity (M)

  • Molarity is defined as the number of moles of solute dissolved per liter of solution.
  • The formula for molarity is:
  • M = (moles of solute) / (volume of solution in liters)
  • Moles of solute can be calculated using the formula:
  • Moles = (mass of solute) / (molar mass of solute)

EXPLANATION:

  • We are given:
  • Mass of Copper (II) nitrate trihydrate (Cu(NO3)2.3H2O) = 33.29 g
  • Molar mass of Cu(NO3)2.3H2O = 241.6 g mol-1
  • Molarity of solution (M) = 0.110 M
  • Step 1: Calculate the moles of Copper (II) nitrate trihydrate.
  • Moles = (mass) / (molar mass)
  • Moles = 33.29 g / 241.6 g mol-1
  • Moles = 0.1379 mol
  • Step 2: Calculate the volume of solution required to achieve the given molarity.
  • M = (moles of solute) / (volume of solution in liters)
  • Rearranging for volume:
  • Volume = (moles of solute) / (Molarity)
  • Volume = 0.1379 mol / 0.110 M
  • Volume = 1.25 L

Therefore, the volume of 0.110 M Copper (II) nitrate solution that can be prepared is 1.25 L.

85

The formula of sodium tungstate is Na2WO4 and that of lead phosphate is Pb3(PO4)2. What is the formula for lead tungstate?

  1. ((a))

    PbWO4

  2. ((b))

    Pb(WO4)3

  3. ((c))

    Pb3(WO4)2

  4. ((d))

    Pb3(WO4)4

Show Answer
Answer: ((a))

PbWO4

CONCEPT:

Formation of Chemical Compounds

  • The formula of a chemical compound is determined by the charges of the ions involved.
  • An ionic compound is formed when the positive charge of the cation equals the negative charge of the anion, resulting in a neutral compound.
  • Sodium tungstate (Na2WO4) contains a tungstate ion (WO42-), and lead phosphate (Pb3(PO4)2) uses the lead ion (Pb2+).

EXPLANATION:

  • In lead tungstate, the lead ion is Pb2+ and the tungstate ion is WO42-.
  • The charges of the ions must balance to form a neutral compound:
  • The Pb2+ ion has a +2 charge.
  • The WO42- ion has a -2 charge.
  • Since the charges are equal and opposite (+2 and -2), the formula of the compound is PbWO4.

The formula of lead tungstate is PbWO4.

86

An electron can move from one orbital of a hydrogen atom to another. In which transition will the photon of highest energy be emitted ?

  1. ((a))

    2p → 1s

  2. ((b))

    1s → 2p

  3. ((c))

    3s → 2s

  4. ((d))

    2s → 3s

Show Answer
Answer: ((a))

2p → 1s

CONCEPT:

Energy of Photons during Electron Transitions

  • When an electron transitions between energy levels in an atom, it emits or absorbs a photon.
  • The energy of the photon corresponds to the energy difference between the two orbitals involved in the transition.
  • In the hydrogen atom, the energy levels are quantized, and the energy difference is given by the formula:
  • ΔE = Efinal - Einitial
  • The energy of an orbital in a hydrogen atom is given by:
  • En = -13.6 eV / n2, Where n is the principal quantum number of the orbital.
  • The photon emitted during a transition will have the highest energy when the energy difference (ΔE) between the two orbitals is the largest.

EXPLANATION:

  • Option 1: 2p → 1s
  • ΔE = E1 - E2
  • E1 = -13.6 eV / (1)2 = -13.6 eV
  • E2 = -13.6 eV / (2)2 = -3.4 eV
  • ΔE = -13.6 eV - (-3.4 eV) = 10.2 eV
  • Option 2: 1s → 2p
  • This is an absorption process, not an emission.
  • Option 3: 3s → 2s
  • ΔE = E2 - E3
  • E2 = -13.6 eV / (2)2 = -3.4 eV
  • E3 = -13.6 eV / (3)2 ≈ -1.51 eV
  • ΔE = -3.4 eV - (-1.51 eV) ≈ 1.89 eV
  • Option 4: 2s → 3s
  • This is an absorption process, not an emission.
  • The photon with the highest energy is emitted during the 2p → 1s transition.

Therefore, the correct answer is 2p → 1s.

87

Which electron configuration represents a violation of Hund's rules?

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((d))

CONCEPT:

Hund's Rule of Maximum Multiplicity

  • Hund's rule states that when filling degenerate orbitals (orbitals of the same energy, such as the three p orbitals or five d orbitals), the electrons will first occupy the orbitals singly with parallel spins (same spin direction) before any orbital is doubly occupied (paired).
  • This rule is based on the principle that the electron configuration with the maximum multiplicity (maximum number of unpaired electrons with parallel spins) is the most stable (lowest energy).
  • For example, if you have three electrons to place in three p orbitals, you must place one electron in each of the three orbitals, and all three must have the same spin direction, before placing a fourth electron in any of the orbitals.

EXPLANATION: 

  • All three electrons are placed singly with parallel spins. This obeys Hund's Rule.

  • There are four electrons. Two electrons are paired in the first orbital, and the remaining two are distributed singly. The process of filling would be: first ↑ in all three, then ↑↓ in the first. This obeys Hund's Rule.
  • The three degenerate orbitals have ↑↓, ↑↓, ↑. There are five electrons. Two electrons are paired in the first orbital, two are paired in the second, and one is in the third. The proper filling for 5 electrons would be ↑ in all three, then ↑↓. It does not violate the Hund's rule which concerns the maximum number of unpaired electrons before pairing starts.
  • The three degenerate orbitals have ↑↓, ↑, empty. There are three electrons to be placed in these three boxes. According to Hund's rule, these three electrons must be placed singly in the three available orbitals, with parallel spins, before any orbital is paired.                
  • Correct filling (Hund's Rule): ↑, ↑, ↑. (Maximum three unpaired electrons)
  • Option 4 filling: ↑↓, ↑, empty. (Only one unpaired electron)

Therefore, the electron configuration in Option 4 represents a violation of Hund's rule.

88

Consider the species \(\rm ^{72}{30}Zn, ^{75}{33}As\) and 3274Ge\rm ^{74}_{32}Ge. These species have the same number of:

  1. ((a))

    Electrons

  2. ((b))

    Protons

  3. ((c))

    Neutrons

  4. ((d))

    Protons and neutrons

Show Answer
Answer: ((c))

Neutrons

CONCEPT:

Atomic Number, Mass Number, and Isotopes

  • The atomic number (Z) of an element is the number of protons in its nucleus and defines the element.
  • The mass number (A) is the total number of protons and neutrons in the nucleus of an atom.
  • Neutrons can be found by subtracting the atomic number from the mass number (N = A - Z).

EXPLANATION:

  • For 7230Zn:
  • Number of protons (atomic number) = 30
  • Number of neutrons = Mass number - Atomic number = 72 - 30
  • = 42
  • For 7533As:
  • Number of protons (atomic number) = 33
  • Number of neutrons = Mass number - Atomic number = 75 - 33
  • = 42
  • For 7432Ge:
  • Number of protons (atomic number) = 32
  • Number of neutrons = Mass number - Atomic number = 74 - 32
  • = 42
  • Clearly, all three species have the same number of neutrons, which is 42.

Therefore, the correct answer is Neutrons

89

What is the atomic weight of a hypothetical element consisting of two isotopes, one with mass 64.2 u (25%) and the other with mass 65.3u ?

  1. ((a))

    65.3 u

  2. ((b))

    64.4 u

  3. ((c))

    64.9 u

  4. ((d))

    65.0 u

Show Answer
Answer: ((d))

65.0 u

CONCEPT:

Atomic Weight of an Element

  • The atomic weight of an element with multiple isotopes is the weighted average of the isotope masses based on their relative abundance.
  • The formula to calculate the atomic weight is:
  • Atomic Weight = (Mass1 × Fraction1) + (Mass2 × Fraction2) + ...

EXPLANATION:

  • Given:
  • Isotope 1: Mass = 64.2 u, Abundance = 25% = 0.25
  • Isotope 2: Mass = 65.3 u, Abundance = 75% = 0.75
  • Using the formula for atomic weight:
  • Atomic Weight = (64.2 × 0.25) + (65.3 × 0.75)
  • = 16.05 + 48.975
  • = 65.025 u
  • Atomic Weight ≈ 65.0 u

Therefore, the atomic weight of the hypothetical element is 65.0 u.

90

What is the frequency of light having a wavelength of 4.50 × 10-8 m?

(Given: c = 3 x 108 ms-1):

  1. ((a))

    2.84 × 10-12 s-1

  2. ((b))

    2.10 × 104 s-1

  3. ((c))

    4.29 × 10-14 s-1

  4. ((d))

    6.67 × 1015 s-1

Show Answer
Answer: ((d))

6.67 × 1015 s-1

CONCEPT:

Relationship Between Wavelength, Frequency, and Speed of Light

c = ν × λ

  • The speed of light (c) is related to its frequency (ν) and wavelength (λ) by the equation:
  • Here:
  • c = speed of light = 3 × 108 m/s
  • ν = frequency of the light (in s-1)
  • λ = wavelength of the light (in meters)
  • To find the frequency (ν), rearrange the formula:
  • ν = c / λ

EXPLANATION:

  • Given:
  • c = 3 × 108 m/s
  • λ = 4.50 × 10-8 m
  • Using the formula:
  • ν = c / λ
  • ν = (3 × 108) / (4.50 × 10-8)
  • ν = 6.67 × 1015 s-1

Therefore, the frequency of light having a wavelength of 4.50 × 10-8 m is 6.67 × 1015 s-1.

91

When the acids H2Se, HBr and HI are arranged in order of increasing acid strength, which is the correct order?

  1. ((a))

    H2Se < HBr < HI

  2. ((b))

    HBr < HI < H2Se

  3. ((c))

    HBr < H2Se < HI

  4. ((d))

    HI < H2Se < HBr

Show Answer
Answer: ((a))

H2Se < HBr < HI

CONCEPT:

Acid Strength

  • The strength of an acid depends on its ability to donate protons (H+) in a solution.
  • For binary acids (HX, where X is a nonmetal), the acid strength generally increases down a group in the periodic table due to:
  • Increasing bond length: The larger the atom X, the weaker the H–X bond, making it easier to release H+.
  • Decreasing bond dissociation energy: As the bond becomes weaker, it requires less energy to break, increasing acidity.

EXPLANATION:

  • For the given acids H2Se, HBr, and HI:
  • H2Se is a hydride of selenium (Se), while HBr and HI are binary acids involving halogens (Br and I).
  • Among HBr and HI:
  • Iodine (I) is larger than bromine (Br), making the H–I bond weaker than the H–Br bond.
  • Thus, HI is a stronger acid than HBr.
  • H2Se has a stronger bond compared to HBr and HI because selenium (Se) is smaller than bromine (Br) and iodine (I).
  • Arranging the acids in order of increasing strength is H2Se < HBr < HI

Therefore, the correct order of increasing acid strength is H2Se < HBr < HI.

92

Which metal requires the least energy to exhibit the photoelectric effect?

  1. ((a))

    Cs

  2. ((b))

    Ca

  3. ((c))

    Cu

  4. ((d))

    Hg

Show Answer
Answer: ((a))

Cs

CONCEPT:

Photoelectric Effect and Work Function

  • The photoelectric effect refers to the emission of electrons from a material when it is exposed to light of sufficient energy.
  • The energy required for this process is determined by the work function (Φ) of the material.
  • The work function is the minimum energy needed to eject an electron from the surface of the material.
  • Materials with lower work functions require less energy to exhibit the photoelectric effect.

EXPLANATION:

  • Cesium (Cs) has the lowest work function, approximately 2.1 eV.
  • Calcium (Ca) has a work function of around 2.9 eV.
  • Copper (Cu) has a work function of about 4.7 eV.
  • Mercury (Hg) has a work function of around 4.5 eV.
  • Since Cs has the lowest work function, it requires the least energy to exhibit the photoelectric effect.

Therefore, the correct answer is Cs.

93

Which group of elements is listed in the order of increasing boiling point?

  1. ((a))

    Lithium, sodium, potassium

  2. ((b))

    Chlorine, bromine, iodine

  3. ((c))

    Sulphur, chlorine, argon

  4. ((d))

    Zinc, cadmium, mercury

Show Answer
Answer: ((b))

Chlorine, bromine, iodine

CONCEPT:

Boiling Point and Trends in Elements

  • The boiling point of an element is the temperature at which it changes from the liquid phase to the gas phase.
  • Boiling points are influenced by the strength of intermolecular forces or metallic bonding in the substance.
  • In the periodic table:
  • For Group 1 (alkali metals): Boiling points generally decrease down the group due to weaker metallic bonding as atomic size increases.
  • For Group 17 (halogens): Boiling points increase down the group due to stronger van der Waals forces as molecular mass increases.
  • For elements in mixed groups, trends depend on the type of bonding (e.g., covalent, metallic, or van der Waals forces).

EXPLANATION:

  • Lithium, sodium, potassium (Group 1 elements):
  • Boiling points decrease down the group (Li > Na > K).
  • This order does not show increasing boiling points.
  • Chlorine, bromine, iodine (Group 17 elements):
  • Boiling points increase down the group (Cl < Br < I).
  • This is due to increasing molecular mass and stronger van der Waals forces.
  • This order represents increasing boiling points.
  • Sulphur, chlorine, argon (Mixed elements):
  • Boiling points depend on molecular structure and bonding.
  • Order is not consistent with increasing boiling points.
  • Zinc, cadmium, mercury (Transition metals):
  • Boiling points generally decrease in this group (Zn > Cd > Hg).
  • This order does not show increasing boiling points.

Therefore, group of elements with the order of increasing boiling point is Chlorine, bromine, iodine.

94

Which pair of atoms should form the most polar bond?

  1. ((a))

    B and F

  2. ((b))

    C and O

  3. ((c))

    O and F

  4. ((d))

    F and N

Show Answer
Answer: ((a))

B and F

CONCEPT:

Polarity of Bonds

  • Polarity of a bond is determined by the difference in electronegativity between the two atoms involved.
  • The greater the difference in electronegativity, the more polar the bond.
  • Electronegativity is a measure of an atom's ability to attract shared electrons in a chemical bond.
  • Fluorine (F) is the most electronegative element with an electronegativity of 3.98.
  • Other atoms mentioned in the options:
  • Boron (B): Electronegativity = 2.04
  • Carbon (C): Electronegativity = 2.55
  • Oxygen (O): Electronegativity = 3.44
  • Nitrogen (N): Electronegativity = 3.04

EXPLANATION:

  • B and F → |3.98 - 2.04| = 1.94
  • C and O → |3.44 - 2.55| = 0.89
  • O and F → |3.98 - 3.44| = 0.54
  • F and N → |3.98 - 3.04| = 0.94
  • Based on the calculations, the pair of atoms with the greatest electronegativity difference is B and F, with a difference of 1.94.

Therefore, the pair of atoms that should form the most polar bond is B and F.

95

The first five ionization energies, in kJ mol-1, for a particular element, are shown in the table below:

FirstSecondThirdFourthFifth
580181527401160018500
<br>

The element is likely to form ionic compounds in which its charge is :

  1. ((a))

    1+

  2. ((b))

    2+

  3. ((c))

    3+

  4. ((d))

    4+

Show Answer
Answer: ((c))

3+

CONCEPT:

Ionization Energy and Ionic Charge

  • Ionization energy is the energy required to remove an electron from an atom in the gaseous state.
  • The successive ionization energies indicate the amount of energy needed to remove electrons one by one.
  • A large jump in ionization energy suggests that the electron being removed is from a more stable, inner electron shell (closer to the nucleus).
  • Elements typically form ions by losing electrons until they reach a stable electron configuration, such as a noble gas configuration.

EXPLANATION:

  • First ionization energy: 580 kJ/mol
  • Second ionization energy: 1815 kJ/mol
  • Third ionization energy: 2740 kJ/mol
  • Fourth ionization energy: 11600 kJ/mol
  • Fifth ionization energy: 18500 kJ/mol
  • From the data, we observe a relatively small increase in ionization energy from the first to the third ionization (580 → 1815 → 2740 kJ/mol).
  • However, there is a very large jump between the third and fourth ionization energies (2740 → 11600 kJ/mol).
  • This significant jump indicates that the fourth electron is much closer to the nucleus and is part of a more stable inner electron shell.
  • As a result, the element is likely to lose only 3 electrons to achieve a stable electron configuration.
  • Therefore, the element is most likely to form ionic compounds with a charge of 3+.

The element is likely to form ionic compounds in which its charge is 3+.

96

The arrangement of the atoms in the ammonia molecule at its lowest energy is described as :

  1. ((a))

    Trigonal pyramidal

  2. ((b))

    Trigonal planar

  3. ((c))

    Trigonal bipyramidal

  4. ((d))

    Square planar

Show Answer
Answer: ((a))

Trigonal pyramidal

CONCEPT:

Valence Shell Electron Pair Repulsion (VSEPR) Theory

  • VSEPR theory is used to predict the geometry (arrangement of electron groups) and molecular shape (arrangement of atoms only) of molecules.
  • Postulates:                      
  • Electron groups (single bonds, double bonds, triple bonds, and lone pairs) around the central atom repel each other.
  • These electron groups arrange themselves in three-dimensional space to minimize repulsion and maximize the distance between them.
  • The repulsion strength follows the order: Lone Pair-Lone Pair > Lone Pair-Bond Pair > Bond Pair-Bond Pair.
  • Molecular shape only considers the positions of the atoms, while electron geometry considers both bonding pairs and lone pairs.

EXPLANATION:

  • Ammonia (NH3) has four regions of electron density: three bonding pairs and one lone pair.
  • The electron pair geometry of NH3 is tetrahedral.
  • However, due to the lone pair of electrons, the molecular geometry is described as trigonal pyramidal with bond angles slightly less than 109.5° (approximately 107°).

Therefore, the arrangement of the atoms in the ammonia molecule at its lowest energy is described as: Trigonal pyramidal.

97

In which of the following compounds would the molecules be expected to be linear?

  1. ((a))

    O3

  2. ((b))

    SO2

  3. ((c))

    H2O

  4. ((d))

    CO2

Show Answer
Answer: ((d))

CO2

CONCEPT:

Molecular Geometry and VSEPR Theory

  • Molecular geometry is determined by the arrangement of electron pairs around the central atom in a molecule.
  • Valence Shell Electron Pair Repulsion (VSEPR) theory states that electron pairs around a central atom will arrange themselves as far apart as possible to minimize repulsion.
  • The geometry can be linear, bent, trigonal planar, tetrahedral, etc., depending on the number of bonding pairs and lone pairs of electrons.

EXPLANATION:

  • To determine whether the molecules are linear:
  • O3: Ozone has a bent molecular shape due to the presence of lone pairs on the central oxygen atom. It is not linear.
  • SO2: Sulfur dioxide also has a bent molecular shape due to the lone pairs on the sulfur atom. It is not linear.
  • H2O: Water has a bent molecular shape due to the two lone pairs on the oxygen atom. It is not linear.
  • CO2: Carbon dioxide is linear because the central carbon atom is bonded to two oxygen atoms with no lone pairs on the carbon. The bond angle is 180°.

Therefore, among the given compounds, only CO2 is expected to have a linear molecular geometry.

98

What is the hybridization of the S atom is SF4?

  1. ((a))

    sp2

  2. ((b))

    sp3

  3. ((c))

    sp3d

  4. ((d))

    sp3d2

Show Answer
Answer: ((c))

sp3d

CONCEPT:

Hybridization

  • Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals that are suitable for chemical bonding.
  • The type of hybridization is determined by the number of electron pairs (bonding and lone pairs) around the central atom.
  • The steric number (number of regions of electron density) determines the hybridization:
  • Steric number 2 → sp
  • Steric number 3 → sp2
  • Steric number 4 → sp3
  • Steric number 5 → sp3d
  • Steric number 6 → sp3d2

EXPLANATION:

  • The central atom in SF4 is sulfur (S).
  • To determine the hybridization of S, count the number of regions of electron density around it:
  • Sulfur forms 4 bonds with fluorine atoms.
  • Sulfur also has 1 lone pair of electrons.
  • Total regions of electron density = 4 (bonds) + 1 (lone pair) = 5.
  • Since the steric number is 5, the hybridization of sulfur in SF4 is sp3d.

Therefore, the hybridization of the S atom in SF4 is sp3d.

99

One way of writing the Lewis structure of the cyanate ion OCN- is [O=C=N]-. What are the formal charges on the O, C and N atoms, respectively, for the structure?

  1. ((a))

    0, 0, -1

  2. ((b))

    1, 0, 0

  3. ((c))

    -1, +1, -1

  4. ((d))

    -2, 1, 0

Show Answer
Answer: ((a))

0, 0, -1

CONCEPT:

Formal Charge Calculation

  • The formal charge on an atom in a molecule or ion is calculated using the formula:
  • Formal Charge = Valence Electrons - (Nonbonding Electrons + Bonding Electrons/2)
  • Valence electrons are the number of electrons in the outermost shell of an atom.
  • Nonbonding electrons are lone pairs of electrons, while bonding electrons are shared in bonds.

EXPLANATION:

  • In the cyanate ion (OCN-), the Lewis structure is [O=C=N]-.
  • Formal charge calculations for each atom:
  • Oxygen (O):
  • Valence electrons = 6
  • Nonbonding electrons = 4 (two lone pairs)
  • Bonding electrons = 4 (one double bond with carbon)
  • Formal charge = 6 - (4 + 4/2) = 6 - 6 = 0
  • Carbon (C):
  • Valence electrons = 4
  • Nonbonding electrons = 0
  • Bonding electrons = 8 (two double bonds: one with oxygen and one with nitrogen)
  • Formal charge = 4 - (0 + 8/2) = 4 - 4 = 0
  • Nitrogen (N):
  • Valence electrons = 5
  • Nonbonding electrons = 4 (two lone pairs)
  • Bonding electrons = 4 (one double bond with carbon)
  • Formal charge = 5 - (4 + 4/2) = 5 - 6 = -1

Therefore, the formal charges on O, C, and N are 0, 0, and -1, respectively.

100

Which one of the following violates the octet rule?

  1. ((a))

    PCl3

  2. ((b))

    CBr4

  3. ((c))

    OF2

  4. ((d))

    AsF5

Show Answer
Answer: ((d))

AsF5

CONCEPT:

Octet Rule

  • The octet rule states that atoms tend to form bonds such that they have eight electrons in their valence shell, achieving a stable electron configuration similar to noble gases.
  • However, there are exceptions to the octet rule:
  • Atoms like hydrogen, helium, lithium, and beryllium can have fewer than eight electrons.
  • Atoms in periods 3 and higher (e.g., phosphorus, sulfur, arsenic) can have expanded octets due to the availability of d-orbitals.
  • Molecules with an odd number of valence electrons may not follow the octet rule.

EXPLANATION:

  • PCl3: Phosphorus has 5 valence electrons and forms three covalent bonds with chlorine, following the octet rule.
  • CBr4: Carbon has 4 valence electrons and forms four covalent bonds with bromine, following the octet rule.
  • OF2: Oxygen has 6 valence electrons and forms two covalent bonds with fluorine, following the octet rule.
  • AsF5: Arsenic has 5 valence electrons and forms five covalent bonds with fluorine. This violates the octet rule because arsenic has 10 electrons in its valence shell, which is possible due to its ability to expand the octet using d-orbitals.
  • AsF5 is the molecule that violates the octet rule.

Therefore, the answer is AsF5.

101

All are state functions except:

  1. ((a))

    Pressure

  2. ((b))

    Heat

  3. ((c))

    Free energy

  4. ((d))

    Enthalpy

Show Answer
Answer: ((b))

Heat

CONCEPT:

State Functions and Path Functions

  • A state function is a property that depends only on the current state of the system and not on how the system reached that state. Examples include pressure, temperature, enthalpy, and free energy.
  • A path function, on the other hand, depends on the specific pathway taken to achieve a state. Examples include heat (q) and work (w).

EXPLANATION:

  • Pressure is a state function as it depends only on the state of the system.
  • Heat (q) is a path function because it depends on the process or pathway taken to transfer energy.
  • Free energy (e.g., Gibbs free energy, G) is a state function as it depends only on the state variables like temperature, pressure, and composition.
  • Enthalpy (H) is a state function because it depends only on the state of the system (temperature, pressure, etc.).
  • Hence, among the options, heat (q) is not a state function.

Therefore, the correct answer is Heat.

102

Calculate the bond energy of the B-F bond in BF3 (boron trifluoride) gas:

ΔH0f of atomic B=134.5 kcal/mol

ΔH0f of atomic F = 18.86 kcal/mol

ΔH0f of BF= -271.75 kcal/mol

  1. ((a))

    97.7 kcal/mol 

  2. ((b))

    116.6 kcal/mol 

  3. ((c))

    135.4 kcal/mol

  4. ((d))

    154.3 kcal/mol

Show Answer
Answer: ((d))

154.3 kcal/mol

CONCEPT:

Bond Energy Calculation

  • The bond energy is the energy required to break one mole of a bond in a molecule in the gas phase.
  • To calculate the bond energy, use the enthalpy change of formation (ΔHf) values of the molecule and its constituent atoms.
  • The formula for bond energy per bond in a molecule is:
  • Bond Energy = [Σ(ΔHf of atoms)] - [ΔHf of molecule]
  • Divide the result by the number of bonds in the molecule to get the bond energy per bond.

EXPLANATION:

  • Given data:
  • ΔHf of atomic B = 134.5 kcal/mol
  • ΔHf of atomic F = 18.86 kcal/mol
  • ΔHf of BF3 = -271.75 kcal/mol
  • In BF3, there are three B-F bonds.
  • Total enthalpy of formation of atoms:
  • Σ(ΔHf of atoms) = ΔHf of atomic B + 3 × ΔHf of atomic F
  • = 134.5 + 3 × 18.86
  • = 134.5 + 56.58
  • = 191.08 kcal/mol
  • Using the bond energy formula:
  • Bond Energy = [Σ(ΔHf of atoms)] - [ΔHf of molecule]
  • = 191.08 - (-271.75)
  • = 191.08 + 271.75
  • = 462.83 kcal/mol (total bond energy for 3 bonds)
  • Bond energy per B-F bond:
  • Bond Energy per bond = 462.83 / 3
  • = 154.3 kcal/mol

Therefore, the bond energy of the B-F bond in BF3 gas is 154.3 kcal/mol.

103

Given the following standard enlhatpies of formation: CO2(g), -394 kJ/mol; H2O(l), -286 kJ/mol; C4H3(g), 16.0 kJ/mol, calculate the heat of combustion of one mole of C4H3 if the equation describing the process is:

C4H3(g) + 6O2(g) → 4CO2(g) + 4H2O(l)

  1. ((a))

    -2736 kJ/mol

  2. ((b))

    -696 kJ/mol

  3. ((c))

    696 kJ/mol

  4. ((d))

    2736 kJ/mol

Show Answer
Answer: ((a))

-2736 kJ/mol

CONCEPT:

Heat of Combustion

  • The heat of combustion is the amount of heat released when one mole of a substance undergoes complete combustion with oxygen under standard conditions.
  • It can be calculated using the standard enthalpy of formation values of the reactants and products in the combustion reaction.
  • The formula used is:
  • ΔHcombustion = [Σ ΔHf (products)] - [Σ ΔHf (reactants)]

EXPLANATION:

  • In the given combustion reaction: C4H3(g) + 6O2(g) → 4CO2(g) + 4H2O(l)
  • Given standard enthalpies of formation:
  • ΔHf(CO2(g)) = -394 kJ/mol
  • ΔHf(H2O(l)) = -286 kJ/mol
  • ΔHf(C4H3(g)) = +16.0 kJ/mol
  • ΔHf(O2(g)) = 0 kJ/mol (element in its standard state)
  • Heat of combustion calculation:
  • ΔHcombustion = [Σ ΔHf (products)] - [Σ ΔHf (reactants)]
  • = [4(ΔHf(CO2(g))) + 4(ΔHf(H2O(l)))] - [ΔHf(C4H3(g)) + 6(ΔHf(O2(g)))]
  • = [4(-394) + 4(-286)] - [16.0 + 6(0)]
  • = [-1576 - 1144] - [16.0]
  • = -2736 kJ/mol

Therefore, the heat of combustion of one mole of C4H3(g) is -2736 kJ/mol.

104

Determine the value of ΔG° (in kJ) for the following reaction using data from the table below:

2H2O(g) + O2(g) → 2H2O2(g)

SubstanceΔGo (kJ/mol)
H2O(g)-228
H2O2(g)-105
  1. ((a))

    -246

  2. ((b))

    666

  3. ((c))

    246

  4. ((d))

    -666

Show Answer
Answer: ((c))

246

CONCEPT:

Standard Gibbs Free Energy Change (ΔG°)

  • For a chemical reaction, the change in standard Gibbs free energy (ΔG°) is calculated using the standard Gibbs free energy of formation (ΔG°f) for each compound involved in the reaction.
  • The formula used is:
  • ΔG° = Σ(ΔG°f of products) - Σ(ΔG°f of reactants)

EXPLANATION:

  • Given reaction: 2H2O(g) + O2(g) → 2H2O2(g)
  • Standard Gibbs free energy of formation (ΔG°f) values:
  • ΔG°f for H2O(g) = -228 kJ/mol
  • ΔG°f for H2O2(g) = -105 kJ/mol
  • ΔG°f for O2(g) = 0 kJ/mol (elements in their standard state have ΔG°f = 0)
  • Using the formula:
  • ΔG° = Σ(ΔG°f of products) - Σ(ΔG°f of reactants)
  • ΔG° = [2(ΔG°f of H2O2)] - [2(ΔG°f of H2O) + (ΔG°f of O2)]
  • ΔG° = [2(-105)] - [2(-228) + 0]
  • ΔG° = -210 - (-456)
  • ΔG° = -210 + 456
  • ΔG° = 246 kJ

Therefore, the value of ΔG° for the reaction is 246 kJ.

105

How many kJ of heat are liberated when 50.0 g of Mn(s) is burnt to form Mn3O4(s) under standard states ?

3Mn(s) + 2O2(g) → Mn3O4(s)

(Atomic mass (Mn) = 55; ΔHf0 (Mn3O4(s)) = -1388 kJ mol-1)

  1. ((a))

    421

  2. ((b))

    946

  3. ((c))

    1388

  4. ((d))

    2838

Show Answer
Answer: ((a))

421

CONCEPT:

Heat Released in Combustion Reactions

  • When a substance undergoes combustion, heat is released based on its enthalpy of formation (ΔHf0). This is calculated using the stoichiometry of the reaction and the molar enthalpy values.
  • The enthalpy change for the reaction can be calculated using the equation:
  • ΔH = n × ΔHf0

EXPLANATION:

  • In the given reaction: 3Mn(s) + 2O2(g) → Mn3O4(s)
  • Given data:
  • Mass of Mn = 50.0 g
  • Atomic mass of Mn = 55 g/mol
  • ΔHf0(Mn3O4(s)) = -1388 kJ/mol
  • Moles of Mn:
  • Moles of Mn = (Mass of Mn) / (Atomic mass of Mn)
  • Moles of Mn = 50.0 g / 55 g/mol = 0.909 mol
  • From the stoichiometry of the reaction, 3 moles of Mn produce 1 mole of Mn3O4. Therefore, moles of Mn3O4 formed:
  • Moles of Mn3O4 = 0.909 mol / 3 = 0.303 mol
  • Heat released:
  • Heat released = Moles of Mn3O4 × ΔHf0(Mn3O4)
  • Heat released = 0.303 mol × (-1388 kJ/mol)
  • Heat released = -421 kJ

Therefore, the heat liberated when 50.0 g of Mn(s) is burnt is 421 kJ.

106

A saturated solution of MgF2 contains 1.16 x 10-3 mol of MgF2 per litre. What is the Ksp of MgF2?

  1. ((a))

    2.7 × 10-6

  2. ((b))

    1.6 × 10-9

  3. ((c))

    3.1 × 10-9

  4. ((d))

    6.2 × 10-9

Show Answer
Answer: ((d))

6.2 × 10-9

CONCEPT:

Solubility Product Constant (Ksp)

  • The solubility product constant (Ksp) is the equilibrium constant for a solid substance dissolving in water.
  • It represents the level at which a solute dissolves in solution. For a compound such as MgF2, the dissociation can be written as:
  • MgF2(s) ⇌ Mg2+(aq) + 2F-(aq)
  • The Ksp expression is:
  • Ksp = [Mg2+][F-]2
  • The concentration of ions in a saturated solution is derived from the molar solubility of the salt.

EXPLANATION:

  • In the given solution, the molar solubility of MgF2 is 1.16 × 10-3 mol/L.
  • From the dissociation equation: MgF2(s) ⇌ Mg2+(aq) + 2F-(aq)
  • For every 1 mole of MgF2 that dissolves, 1 mole of Mg2+ and 2 moles of F- are produced.
  • Thus:
  • [Mg2+] = 1.16 × 10-3 mol/L
  • [F-] = 2 × (1.16 × 10-3) = 2.32 × 10-3 mol/L
  • Substituting these values into the Ksp expression:
  • Ksp = [Mg2+][F-]2
  • Ksp = (1.16 × 10-3) × (2.32 × 10-3)2
  • Ksp = (1.16 × 10-3) × (5.38 × 10-6)
  • Ksp = 6.23 × 10-9

Therefore, the Ksp of MgF2 is approximately 6.2 × 10-9.

107

Which will be the same for solutions of 0.50 M NH3 and 0.50 M NaOH ?

(A) Concentration of OH- ions.

(B) Volume of 0.20 M HCl required for neutralization.

  1. ((a))

    (A) only

  2. ((b))

    Both (A) and (B)

  3. ((c))

    (B) only

  4. ((d))

    Neither (A) nor (B)

Show Answer
Answer: ((c))

(B) only

CONCEPT:

Behavior of 0.50 M NH3 (weak base) and 0.50 M NaOH (strong base)

  • Ammonia (NH3) is a weak base, meaning it only partially ionizes in water to produce OH- ions.
  • Sodium hydroxide (NaOH) is a strong base, meaning it fully dissociates in water to produce OH- ions.
  • For the same molarity, the concentration of OH- ions will be much higher for NaOH compared to NH3.
  • However, the amount of acid (like HCl) required to completely neutralize 0.50 M NH3 and 0.50 M NaOH will be the same because both solutions contain the same molar concentration of base (0.50 mol/L).

EXPLANATION:

  • For (A): the concentration of OH- ions will not be the same because:
  • NaOH being a strong base will fully dissociate, providing a higher concentration of OH- ions.
  • NH3 being a weak base will only partially ionize, producing fewer OH- ions.
  • For (B), the volume of 0.20 M HCl required for neutralization will be the same because:
  • Neutralization depends on the number of moles of base, not the extent of ionization.
  • Both NH3 and NaOH have the same concentration (0.50 M), so they contain the same amount of base in moles per liter.

Final Answer: Option 3) (B) only

108

For the reaction

2NO(g) + O2(g) = 2NO2(g)

the equilibrium concentrations at a certain temperature are found to be [NO] = 0.10 M, [O2] = 0.20 M, [NO2] = 0.30 M. The value of the equlibrium constant for the reaction at this temperature is:

  1. ((a))

    1.5

  2. ((b))

    15

  3. ((c))

    45

  4. ((d))

    150

Show Answer
Answer: ((c))

45

CONCEPT:

Equilibrium Constant (Keq)

  • The equilibrium constant (Keq) is a measure of the ratio of the concentrations of products to the concentrations of reactants at equilibrium, raised to the power of their stoichiometric coefficients.
  • For a general reaction: aA + bB ⇌ cC + dD
  • Keq = ([C]c[D]d) / ([A]a[B]b)

EXPLANATION:

  • In the given reaction: 2NO(g) + O2(g) ⇌ 2NO2(g)
  • The equilibrium constant expression is:
  • Keq = ([NO2]2) / ([NO]2[O2])
  • Substitute the equilibrium concentrations:
  • [NO] = 0.10 M
  • [O2] = 0.20 M
  • [NO2] = 0.30 M
  • Calculate Keq:
  • Keq = (0.30)2 / ((0.10)2 × 0.20)
  • = 0.09 / (0.01 × 0.20)
  • = 0.09 / 0.002
  • = 45

Therefore, the equilibrium constant (Keq) for the reaction is 45.

109

An aqueous solution of which salt would be expected to have the most basic pH?

  1. ((a))

    Na2CO3

  2. ((b))

    NaC2H3O2

  3. ((c))

    NaCl

  4. ((d))

    NH4Cl

Show Answer
Answer: ((a))

Na2CO3

CONCEPT:

Basicity of aqueous solutions of salts

  • The pH of a salt solution depends on the nature of the ions produced when the salt dissolves in water.
  • Salts can be classified into three categories based on the acid and base from which they are derived:
  • Neutral salts: Derived from a strong acid and a strong base (e.g., NaCl). These do not hydrolyze and have a pH of 7.
  • Acidic salts: Derived from a strong acid and a weak base (e.g., NH4Cl). These hydrolyze to produce H+, lowering the pH.
  • Basic salts: Derived from a weak acid and a strong base (e.g., Na2CO3 or NaC2H3O2). These hydrolyze to produce OH-, raising the pH.

EXPLANATION:

  • Na2CO3: Sodium carbonate is a basic salt derived from a weak acid (H2CO3) and a strong base (NaOH). It hydrolyzes to produce OH-, making the solution basic.
  • NaC2H3O2: Sodium acetate is a basic salt derived from a weak acid (acetic acid) and a strong base (NaOH). It also hydrolyzes to produce OH-, making the solution basic, but less so than Na2CO3.
  • NaCl: Sodium chloride is a neutral salt derived from a strong acid (HCl) and a strong base (NaOH). It does not hydrolyze and has a pH of 7.
  • NH4Cl: Ammonium chloride is an acidic salt derived from a weak base (NH3) and a strong acid (HCl). It hydrolyzes to produce H+, making the solution acidic.
  • Among the options, Na2CO3 hydrolyzes the most, producing the highest concentration of OH- and thus having the most basic pH.

Therefore, the aqueous solution of Na2CO3 would have the most basic pH.

110

If 40.0 mL of 0.20 M CH3COOH are titrated with 0.20 M NaOH, how many mL of base must be added to form a buffer solution with the greatest buffering capacity?

  1. ((a))

    5.0

  2. ((b))

    10.0

  3. ((c))

    20.0

  4. ((d))

    40.0

Show Answer
Answer: ((c))

20.0

CONCEPT:

Buffering Capacity

  • A buffer solution resists changes in pH when small amounts of acid or base are added.
  • The greatest buffering capacity of a buffer solution is achieved when the concentrations of the weak acid (CH3COOH) and its conjugate base (CH3COO-) are equal. This occurs at the half-equivalence point during the titration.
  • The half-equivalence point is the point where exactly half of the weak acid has been neutralized by the base, forming an equal amount of the conjugate base.

EXPLANATION:

  • The initial volume of CH3COOH is 40.0 mL with a concentration of 0.20 M.
  • The reaction between CH3COOH and NaOH is:
  • CH3COOH + NaOH → CH3COO- + H2O
  • The moles of CH3COOH initially present are:
  • Moles = Molarity × Volume = 0.20 M × 0.040 L = 0.008 mol
  • At the half-equivalence point, half of the CH3COOH is neutralized. Hence, the moles of NaOH added will also be 0.004 mol (half of 0.008 mol).
  • Since the concentration of NaOH is 0.20 M, the volume of NaOH required is:
  • Volume = Moles / Molarity = 0.004 mol / 0.20 M = 0.020 L = 20.0 mL

Therefore, 20.0 mL of NaOH must be added to achieve the greatest buffering capacity.

111

In which pair does the named substance have the same oxidation number?

  1. ((a))

    Sulphur in H2S2O7, and H2SO4

  2. ((b))

    Mercury in Hg2+ and Hg22+\rm Hg_2^{2+}

  3. ((c))

    Cobalt in Co(NH3)63+\rm Co(NH_3)_6^{3+} and Co(NO3)2

  4. ((d))

    Oxygen in Na2O2 and H2O.

Show Answer
Answer: ((a))

Sulphur in H2S2O7, and H2SO4

CONCEPT:

Oxidation Number

  • The oxidation number (or oxidation state) of an element in a compound is a measure of the degree of oxidation of that element.
  • It is assigned based on a set of rules which take into account the structure and bonding of the compound.

EXPLANATION:

  • Sulfur in H2S2O7 and H2SO4
  • In H2S2O7, the oxidation number of sulfur (x) is calculated as:
  • 2(+1) + 2x + 7(-2) = 0
  • 2 + 2x - 14 = 0
  • 2x = 12
  • x = +6
  • In H2SO4, the oxidation number of sulfur (y) is calculated as:
  • 2(+1) + y + 4(-2) = 0
  • 2 + y - 8 = 0
  • y = +6
  • Therefore, the oxidation number of sulfur is +6 in both compounds.
  • Mercury in Hg2+ and Hg22+
  • In Hg2+, the oxidation number of mercury is +2.
  • In Hg22+, each mercury atom has an oxidation number of +1.
  • Cobalt in [Co(NH3)6]3+ and Co(NO3)2
  • In [Co(NH3)6]3+, the oxidation number of cobalt is +3.
  • In Co(NO3)2, the oxidation number of cobalt is +2.
  • Oxygen in Na2O2 and H2O
  • In Na2O2 (sodium peroxide), the oxidation number of oxygen is -1.
  • In H2O (water), the oxidation number of oxygen is -2.

Therefore, the correct pair is Sulphur in H2S2O7 and H2SO4

112

What is the oxidation number for carbon in CaC2O4?

  1. ((a))

    0

  2. ((b))

    +2

  3. ((c))

    +3

  4. ((d))

    +4

Show Answer
Answer: ((c))

+3

CONCEPT:

Oxidation Number Concept

  • The oxidation number (or oxidation state) of an atom in a molecule or ion is the charge that atom would have if all bonds were ionic.
  • The sum of oxidation numbers for all atoms in a neutral compound equals zero, while in a polyatomic ion, the sum equals the charge of the ion.
  • Group 1 and Group 2 elements (like calcium in this example) typically have oxidation numbers of +1 and +2, respectively.
  • Oxygen in most compounds has an oxidation number of -2.

EXPLANATION:

  • In calcium oxalate (CaC2O4):
  • Calcium (Ca) is in Group 2 and has an oxidation number of +2.
  • Oxygen (O) typically has an oxidation number of -2.
  • The oxalate ion (C2O42-) is a polyatomic ion with an overall charge of -2.
  • Let the oxidation number of carbon (C) be x.
  • In the oxalate ion, there are 2 carbon atoms and 4 oxygen atoms. The sum of oxidation numbers in the oxalate ion must equal -2:
  • 2x + (4 × -2) = -2
  • 2x - 8 = -2
  • 2x = 6
  • x = +3

Therefore, the oxidation number of carbon in CaC2O4 is +3.

113

Which of the following is a correct statement ?

  1. ((a))

    Oxidation is caused by a reducing agent. 

  2. ((b))

    The oxidation reaction is a redox reaction. 

  3. ((c))

    Addition of an electropositive element is a type of oxidation.

  4. ((d))

    Reduction is the addition of hydrogen.

Show Answer
Answer: ((d))

Reduction is the addition of hydrogen.

CONCEPT:

Redox Definitions

Oxidation and reduction are complementary processes that always occur together in a Redox (Reduction-Oxidation) reaction.

  • Oxidation (O): Loss of electrons, increase in oxidation state, addition of oxygen or electronegative element, removal of hydrogen or electropositive element.
  • Reduction (R): Gain of electrons, decrease in oxidation state, addition of hydrogen or electropositive element, removal of oxygen or electronegative element.

Agents

  • Oxidizing Agent (Oxidant): A substance that causes another substance to be oxidized (by accepting electrons from it) and is itself reduced.
  • Reducing Agent (Reductant): A substance that causes another substance to be reduced (by donating electrons to it) and is itself oxidized.

EXPLANATION:

1) Oxidation is caused by a reducing agent.

  • A reducing agent causes reduction in another species, while it is itself oxidized.
  • Oxidation is caused by an oxidizing agent.
  • This statement is INCORRECT.

2) The oxidation reaction is a redox reaction.

  • Oxidation is only one-half of a complete reaction (loss of electrons). The complete reaction, which includes both oxidation and reduction, is called a redox reaction.
  • A substance cannot be oxidized unless another substance is simultaneously reduced. Thus, oxidation is not the full redox reaction, but a half-reaction.
  • This statement is INCORRECT.

3) Addition of an electropositive element is a type of oxidation.

  • Addition of an electropositive element (like Na or Mg) means the oxidation state of the receiving species decreases.
  • A decrease in oxidation state is the definition of reduction.
  • This statement is INCORRECT.

4) Reduction is the addition of hydrogen.

  • Historically and chemically, the addition of hydrogen (Hydrogenation) is a definition of reduction (e.g., Ethylene + H2 → Ethane). Removal of hydrogen is oxidation.
  • This statement is CORRECT.

Therefore, the correct option is 4.

114

What is the coefficient for Fe2+ when the redox equation

Fe2+ + MnO-4 + H+ → Fe3+ + Mn2+ + H2O is balanced using the smallest whole number coefficients?

  1. ((a))

    2

  2. ((b))

    3

  3. ((c))

    4

  4. ((d))

    5

Show Answer
Answer: ((d))

5

CONCEPT:

Balancing Redox Reactions

  • In a redox reaction, one species is oxidized (loses electrons) and another is reduced (gains electrons).
  • To balance a redox reaction, both the number of atoms and the charges must be balanced.
  • Steps to balance a redox reaction:
  1. Separate the reaction into two half-reactions (oxidation and reduction).
  2. Balance all elements except hydrogen and oxygen.
  3. Balance oxygen using H2O, and hydrogen using H+.
  4. Balance charges by adding electrons (e-).
  5. Combine the two half-reactions, ensuring the number of electrons lost equals the number of electrons gained.

EXPLANATION:

  • In the given reaction:
  • Fe2+ + MnO4- + H+ → Fe3+ + Mn2+ + H2O
  • We divide the reaction into two half-reactions:
  • Oxidation half-reaction: Fe2+ → Fe3+ + e-
  • Reduction half-reaction: MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
  • To balance the number of electrons, we multiply the oxidation half-reaction by 5 and the reduction half-reaction by 1:
  • 5Fe2+ → 5Fe3+ + 5e-
  • MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
  • Adding these two half-reactions, we get:
  • 5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O
  • The coefficient for Fe2+ in the balanced equation is 5.

Therefore, the answer is 5.

115

Which one of the following statements is NOT correct for the given reaction?

Fe(s)+ CuSO4(aq) → FeSO4(aq) + Cu(s)

  1. ((a))

    Iron is the reducing agent.

  2. ((b))

    The solution turns green in colour after the reaction.

  3. ((c))

    Copper is a more reactive metal than iron.

  4. ((d))

    The reaction is an example of a redox reaction.

Show Answer
Answer: ((c))

Copper is a more reactive metal than iron.

CONCEPT:

Redox Reaction and Reactivity Series

  • A redox reaction involves the transfer of electrons, where one species is oxidized (loses electrons) and the other is reduced (gains electrons).
  • The reactivity series ranks metals based on their ability to lose electrons and form positive ions.
  • In displacement reactions, a more reactive metal displaces a less reactive metal from its compound.

EXPLANATION:

  • The given reaction is:
  • Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
  • Key observations in the reaction:
  • Iron (Fe) is oxidized to Fe2+, making it the reducing agent.
  • Copper (Cu2+) is reduced to Cu, making it the oxidizing agent.
  • Iron displaces copper from copper sulfate solution, causing the solution to turn green due to the formation of iron sulfate (FeSO4).
  • Correct statements:
  • Iron is the reducing agent.
  • The solution turns green in color after the reaction.
  • The reaction is an example of a redox reaction.
  • Incorrect statement:
  • "Copper is a more reactive metal than iron" is NOT correct because iron is more reactive than copper as per the reactivity series, which is why iron displaces copper from its sulfate compound.

Therefore, the incorrect statement is: Copper is a more reactive metal than iron(Option 3).

116

An aquous solution is 1.00 Molal in KI. Which change will cause the vapour pressure of the solution to increase?

  1. ((a))

    Addition of water.

  2. ((b))

    Addition of NaCl.

  3. ((c))

    Addition of Na2SO4

  4. ((d))

    Addition of 1.0 Molal KI.

Show Answer
Answer: ((a))

Addition of water.

CONCEPT:

Vapour Pressure and Solution Composition

  • Vapour pressure is the pressure exerted by the vapour of a liquid when it is in equilibrium with its liquid phase at a given temperature.
  • The addition of solutes to a solvent generally decreases the vapour pressure of the solution due to a phenomenon called "Raoult's Law."
  • Raoult's Law states that the vapour pressure of a solution is directly proportional to the mole fraction of the solvent. Adding solutes decreases the mole fraction of the solvent, thereby lowering the vapour pressure.
  • However, if water (the solvent) is added to the solution, the mole fraction of the solvent increases, and the vapour pressure of the solution increases.

EXPLANATION:

  • The solution in question is 1.00 molal KI (potassium iodide), meaning KI is the solute and water is the solvent.
  • To increase the vapour pressure of the solution, the mole fraction of the solvent (water) must be increased.
  • Option 1 (Addition of water): Adding water increases the mole fraction of the solvent and thus increases the vapour pressure.
  • Option 2 (Addition of NaCl): Adding NaCl introduces more solute particles, decreasing the mole fraction of water and lowering the vapour pressure.
  • Option 3 (Addition of Na2SO4): Similar to NaCl, adding Na2SO4 introduces more solute particles, further decreasing the mole fraction of water and lowering the vapour pressure.
  • Option 4 (Addition of 1.0 molal KI): Adding more KI increases the concentration of solute particles, decreasing the mole fraction of water and lowering the vapour pressure.

Therefore, Addition of water(Option 1), increases the mole fraction of the solvent (water) and raises the vapour pressure.

117

What is the molality of the Li+ ion in a solution prepared by dissolving 2.20 g of Li2SO4 (MM = 110.0 g/mol) in enough H2O to make 50.0 mL of solution?

  1. ((a))

    2.00 × 10-2 M

  2. ((b))

    4.00 × 10-2​ M

  3. ((c))

    0.400 M

  4. ((d))

    0.800 M

Show Answer
Answer: ((d))

0.800 M

CONCEPT:

Molality

  • Molality (m) is defined as the number of moles of solute per kilogram of solvent.
  • The formula for molality is:
  • m = (moles of solute) / (mass of solvent in kg)

EXPLANATION:

  • Given:
  • Mass of Li2SO4 = 2.20 g
  • Molar mass of Li2SO4 = 110.0 g/mol
  • Volume of solution = 50.0 mL (Note: This does not affect molality directly since molality depends on the mass of the solvent.)
  • Moles of Li2SO4:
  • Moles = Mass / Molar Mass
  • Moles of Li2SO4 = 2.20 g / 110.0 g/mol
  • Moles of Li2SO4 = 0.0200 mol
  • Each molecule of Li2SO4 dissociates into 2 Li+ ions and 1 SO42- ion:
  • Li2SO4 → 2 Li+ + SO42-
  • Moles of Li+ = 2 × Moles of Li2SO4 = 2 × 0.0200 mol = 0.0400 mol
  • Assume the mass of water used is approximately equal to the volume of the solution (50.0 mL of water ≈ 50.0 g of water):
  • Mass of water = 50.0 g = 0.0500 kg
  • Molality of Li+:
  • m = (moles of solute) / (mass of solvent in kg)
  • m = 0.0400 mol / 0.0500 kg
  • m = 0.800 mol/kg

Therefore, the molality of the Li+ ion in the solution is 0.800 m.

118

Calculate the Molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density of CCI4 is 1.60 g/mL:

  1. ((a))

    0.250 m

  2. ((b))

    0.500 m

  3. ((c))

    0.750 m

  4. ((d))

    0.840 m

Show Answer
Answer: ((b))

0.500 m

CONCEPT:

Molality (m)

  • Molality is defined as the number of moles of solute per kilogram of solvent.
  • The formula for molality is:
  • m = (moles of solute) / (mass of solvent in kg)
  • Molality is independent of temperature as it does not involve the volume of the solution.

EXPLANATION:

  • In the given problem:
  • Mass of solute (naphthalene, C10H8) = 51.2 g
  • Molar mass of C10H8 = (10 × 12.01 g/mol) + (8 × 1.008 g/mol) = 128.16 g/mol
  • Volume of solvent (carbon tetrachloride, CCl4) = 500 mL
  • Density of CCl4 = 1.60 g/mL
  • Mass of the solvent (CCl4):
  • Mass of solvent = density × volume
  • Mass of solvent = 1.60 g/mL × 500 mL
  • Mass of solvent = 800 g = 0.800 kg
  • Moles of solute (naphthalene):
  • Moles of solute = mass of solute / molar mass
  • Moles of naphthalene = 51.2 g / 128.16 g/mol
  • Moles of naphthalene ≈ 0.4 mol
  • Molality (m):
  • Molality, m = (moles of solute) / (mass of solvent in kg)
  • m = 0.4 mol / 0.800 kg
  • m ≈ 0.500 m

Therefore, the molality of the solution is 0.500 m.

119

The vapour pressure of pure water at 85°C is 57.9 kPa. What is the vapour pressure at 85°C of a solution prepared from 100 mL of water (density 1.00 g/mL) and 150 g of diglycine, C4H8N2O3, a non-volatile substance?

  1. ((a))

    48.1 kPa

  2. ((b))

    52.0 kPa

  3. ((c))

    56.7 kPa

  4. ((d))

    51.7 kPa

Show Answer
Answer: ((a))

48.1 kPa

CONCEPT:

Raoult's Law

  • Raoult's Law states that the vapour pressure of a solution is directly proportional to the mole fraction of the solvent in the solution.
  • Mathematically, it is expressed as:

Psolution = Xsolvent × Posolvent

  • Psolution: Vapour pressure of the solution
  • Xsolvent: Mole fraction of the solvent
  • Posolvent: Vapour pressure of the pure solvent

EXPLANATION:

  • Number of moles of water and diglycine:
  • Moles of water:
  • Mass of water = 100 g (since density = 1.00 g/mL)
  • Molar mass of water = 18.015 g/mol
  • Moles of water = 100 / 18.015 = 5.55 mol
  • Moles of diglycine:
  • Mass of diglycine = 150 g
  • Molar mass of diglycine = 132.12 g/mol
  • Moles of diglycine = 150 / 132.12 = 1.135 mol
  • Mole fraction of the solvent (water):
  • Total moles = Moles of water + Moles of diglycine
  • Total moles = 5.55 + 1.135 = 6.685 mol
  • Mole fraction of water (Xwater) = Moles of water / Total moles
  • Xwater = 5.55 / 6.685 = 0.830
  • Apply Raoult's Law:
  • Psolution = Xwater × Powater
  • Powater = 57.9 kPa (vapour pressure of pure water at 85°C)
  • Psolution = 0.830 × 57.9 = 48.1 kPa

Therefore, the vapour pressure of the solution is 48.1 kPa.

120

If 45 g of glucose, C6H12O6, are dissolved in 300 mL of water, what will be the boiling point of the resulting solution? (Kb for water = 0.512 °C/m).

  1. ((a))

    101.64°C

  2. ((b))

    100.78°C

  3. ((c))

    100.43°C 

  4. ((d))

    99.626°C

Show Answer
Answer: ((c))

100.43°C 

CONCEPT:

Boiling Point Elevation

  • Boiling point elevation is a colligative property, which means it depends on the number of solute particles present in the solution, not on their identity.
  • The change in boiling point (ΔTb) can be calculated using the formula:
  • ΔTb = i × Kb × m
  • Here:
  • i = Van't Hoff factor (number of particles into which a compound dissociates in solution)
  • Kb = boiling point elevation constant for the solvent
  • m = molality of the solution

EXPLANATION:

  • For glucose (C6H12O6), it does not dissociate in water, so i = 1.
  • Given data:
  • Mass of glucose = 45 g
  • Molar mass of glucose = 180 g/mol
  • Volume of water = 300 mL (0.3 L)
  • Kb for water = 0.512 °C/m
  • First, calculate the molality (m):
  • Number of moles of glucose = mass / molar mass = 45 g / 180 g/mol = 0.25 mol
  • Molality (m) = moles of solute / kilograms of solvent
  • Mass of water = 300 mL × 1 g/mL = 300 g = 0.3 kg
  • m = 0.25 mol / 0.3 kg = 0.833 mol/kg
  • Calculate ΔTb:
  • ΔTb = i × Kb × m
  • = 1 × 0.512 °C/m × 0.833 m
  • = 0.426 °C
  • Boiling point of pure water = 100 °C
  • Boiling point of solution = boiling point of pure water + ΔTb
  • = 100 °C + 0.426 °C
  • = 100.43 °C

Therefore, the boiling point of the solution is 100.43 °C.

121

The standard reduction potentials for AI3+ and Zn2+ are -1.66 V and -0.76 V, respectively. Calculate the Gibbs free energy change for the balanced reaction.

2AI(s) + 3Zn2+ (aq) → 2AI3+ (aq) + 3Zn(s) (IF = 96,500 C)

  1. ((a))

    -5.2 × 105 J

  2. ((b))

    -6.0 × 105 J

  3. ((c))

    +9.0 × 105 J

  4. ((d))

    +1.4 × 105 J

Show Answer
Answer: ((a))

-5.2 × 105 J

CONCEPT:

Standard Cell Potential (Eocell) and Gibbs Free Energy Change (ΔG)

  • The standard cell potential (Eocell) is the difference in the standard reduction potentials of the cathode and the anode in an electrochemical cell.
  • The Gibbs free energy change (ΔG) for the reaction is related to the standard cell potential by the equation:

ΔG = -nFEocell

  • Where:
  • n: Number of moles of electrons transferred in the reaction
  • F: Faraday constant (96,500 C mol-1)
  • Eocell: Standard cell potential in volts (V)

EXPLANATION:

  • In the given reaction:

2Al(s) + 3Zn2+(aq) → 2Al3+(aq) + 3Zn(s)

  • Aluminum (Al) is oxidized to Al3+, so Al is the anode.
  • Zinc (Zn2+) is reduced to Zn, so Zn is the cathode.
  • Given standard reduction potentials:
  • EoZn = -0.76 V (for Zn2+ + 2e- → Zn)
  • EoAl = -1.66 V (for Al3+ + 3e- → Al)
  • Using the standard cell potential equation:
  • Eocell = Eocathode - Eoanode
  • = -0.76 V - (-1.66 V)
  • = -0.76 V + 1.66 V
  • = +0.90 V
  • Now, calculate ΔG using the equation:
  • ΔG = -nFEocell
  • For the balanced reaction, n = 6 (since 6 electrons are transferred).
  • F = 96,500 C mol-1
  • Eocell = 0.90 V
  • ΔG = - (6) (96,500) (0.90)
  • ΔG = -520,650 J

Therefore, the Gibbs free energy change (ΔG) for the balanced reaction is -5.2 × 105 J.

122

Which of the following statements about electrochemical cells is true?

  1. ((a))

    Reduction occurs at the anode.

  2. ((b))

    An element with a high affinity for electrons is likely to be easily oxidized. 

  3. ((c))

    Oxidation occurs at the anode.

  4. ((d))

    Only oxidation half reactions are important.

Show Answer
Answer: ((c))

Oxidation occurs at the anode.

CONCEPT:

Electrochemical Cells

  • Electrochemical cells consist of two electrodes: the anode and the cathode, where oxidation and reduction occur, respectively.
  • Oxidation is the loss of electrons, and reduction is the gain of electrons.
  • In any electrochemical cell:
  • Oxidation occurs at the anode.
  • Reduction occurs at the cathode.
  • The flow of electrons is from the anode to the cathode through an external circuit.

EXPLANATION:

  • "Reduction occurs at the anode." -
  • This is incorrect because reduction always occurs at the cathode.
  • "An element with a high affinity for electrons is likely to be easily oxidized." -
  • This is incorrect because an element with a high electron affinity is more likely to gain electrons (reduction) rather than lose them (oxidation).
  • "Oxidation occurs at the anode." -
  • This is correct because oxidation always occurs at the anode in electrochemical cells.
  • "Only oxidation half reactions are important." -
  • This is incorrect because both oxidation and reduction half reactions are necessary to complete the cell reaction.

Therefore, the correct statement about electrochemical cells is: Oxidation occurs at the anode(Option 3).

123

What is Eo for the following balanced reaction?

Zn(s) + Pb2+ (aq) → Zn2+ (aq) + Pb(s)

<br>

Half-reaction

Zn2+ (aq) + 2e → Zn(s)

Pb2+ (aq) + 2e → Pb(s)

Standard Reduction Potential

-0.763 V

-0.126 V

  1. ((a))

    +0.637 V

  2. ((b))

    -0.637 V

  3. ((c))

    -0.889 V

  4. ((d))

    +0.889 V

Show Answer
Answer: ((a))

+0.637 V

CONCEPT:

Standard Cell Potential (Eocell)

  • The standard cell potential (Eocell) is the difference in the standard reduction potentials of the cathode and the anode in an electrochemical cell.
  • The standard cell potential can be calculated using the equation:

Eocell = Eocathode - Eoanode

EXPLANATION:

  • In the given reaction:

Zn(s) + Pb2+(aq) → Zn2+(aq) + Pb(s)

  • Zinc (Zn) is oxidized to Zn2+, so Zn is the anode.
  • Lead (Pb2+) is reduced to Pb, so Pb is the cathode.
  • Given standard reduction potentials:
  • EoPb = -0.126 V (for Pb2+ + 2e- → Pb)
  • EoZn = -0.763 V (for Zn2+ + 2e- → Zn)
  • Using the standard cell potential equation:
  • Eocell = Eocathode - Eoanode
  • = (-0.126 V) - (-0.763 V)
  • = -0.126 V + 0.763 V
  • = +0.637 V

Therefore, the standard cell potential (Eocell) is +0.637 V.

124

Identify the strongest reducing agent based on the following half-reactions:

Half reactionStandard reduction potential
MnO2(s) + 4H+ (aq) + 2e- → Mn2+(aq) + 2H2O(I)+1.22 V
Hg2SO4(s) + 2e- → 2Hg(I) + SO42-(aq)+0.61 V
SnO2(s) + 2H2O(I) + 4e- → Sn(s) + 4OH- (aq)+0.95 V
Cr(OH)3(s) + 3e- → Cr(s) + 3OH- (aq)-1.48 V
  1. ((a))

    Cr

  2. ((b))

    MnO2

  3. ((c))

    Sn

  4. ((d))

    Hg

Show Answer
Answer: ((a))

Cr

CONCEPT:

Standard Reduction Potential (Eo) and Redox Agents

The standard reduction potential (Eo) is a measure of the tendency of a chemical species to be reduced (gain electrons). This value is measured in volts (V) under standard conditions.

  • Relationship between Eo and Reducing Agent Strength:
  • A lower (more negative) Eo value indicates a lower tendency for reduction (gaining electrons) and a higher tendency for oxidation (losing electrons).
  • The species that is most easily oxidized is the strongest reducing agent.
  • Therefore, the strongest reducing agent corresponds to the half-reaction with the lowest (most negative) Eo value.
  • Reducing Agent: In a half-reaction written as a reduction (e.g., A+ + e- → A), the reducing agent is the product (A). It is the species that exists in its reduced form and is ready to be oxidized.

EXPLANATION:

Half ReactionStandard Reduction Potential (Eo)Reducing Agent (Product)
MnO2(s)+4H+(aq)+2eMn2+(aq)+2H2O(l)\text{MnO}_2(\text{s}) + 4\text{H}^+(\text{aq}) + 2\text{e}^- → \text{Mn}^{2+}(\text{aq}) + 2\text{H}_2\text{O}(\text{l})+1.22 VMn2+
Hg2SO4(s)+2e2Hg(l)+SO42(aq)\text{Hg}_2\text{SO}_4(\text{s}) + 2\text{e}^- → 2\text{Hg}(\text{l}) + \text{SO}_4^{2-}(\text{aq})+0.61 VHg
SnO2(s)+2H2O(l)+4eSn(s)+4OH(aq)\text{SnO}_2(\text{s}) + 2\text{H}_2\text{O}(\text{l}) + 4\text{e}^- → \text{Sn}(\text{s}) + 4\text{OH}^-(\text{aq})+0.95 VSn
Cr(OH)3(s)+3eCr(s)+3OH(aq)\text{Cr}(\text{OH})_3(\text{s}) + 3\text{e}^- → \text{Cr}(\text{s}) + 3\text{OH}^-(\text{aq})-1.48 VCr
  • The half-reaction with the lowest (most negative) Eo value is the reduction of Cr(OH)3 to Cr, with Eo = -1.48 V.
  • This indicates that the reverse reaction (oxidation of Cr) has the highest tendency to occur.
  • Cr(s) + 3OH- (aq) → Cr(OH)3 (s) + 3e- (Eoox = +1.48 V)
  • Since Cr is the species most easily oxidized, it is the strongest reducing agent.

Therefore, the strongest reducing agent is Cr,.

125

What mass of nickel (atomic mass 58.7u) could be electroplated from a solution of nickel (II) chloride by a current of 0.25 amperes flowing for 10 hours? (1F=96,500 C)

  1. ((a))

    12 g

  2. ((b))

    5.5 g

  3. ((c))

    0.046 g

  4. ((d))

    2.7 g

Show Answer
Answer: ((d))

2.7 g

CONCEPT:

Electroplating and Faraday's Laws of Electrolysis

  • Electroplating involves the deposition of a metal on the surface of an electrode using an electric current.
  • Faraday's First Law of Electrolysis states that the mass of a substance deposited or liberated at an electrode is directly proportional to the amount of electric charge passed through the electrolyte.
  • Faraday's Second Law of Electrolysis states that the mass of a substance deposited is directly proportional to the equivalent weight of the substance.
  • The amount of charge (Q) is related to the current (I) and time (t) by the equation:
  • Q = I × t
  • The number of moles of electrons (n) can be calculated as:
  • n = Q / F, where F is the Faraday constant (96,500 C/mol).
  • The mass of the deposited substance is calculated using the formula:
  • m = (M × Q) / (z × F), where:
  • M is the molar mass of the substance (g/mol).
  • z is the number of electrons transferred per ion.

EXPLANATION:

  • Given:
  • Current (I) = 0.25 A
  • Time (t) = 10 hours = 10 × 3600 s = 36,000 s
  • Faraday constant (F) = 96,500 C/mol
  • Molar mass of nickel (M) = 58.7 g/mol
  • Nickel (II) ion (Ni2+) undergoes reduction, so z = 2
  • Calculate the charge (Q):
  • Q = I × t
  • Q = 0.25 × 36,000
  • Q = 9,000 C
  • Mass (m) of nickel deposited:
  • m = (M × Q) / (z × F)
  • m = (58.7 × 9,000) / (2 × 96,500)
  • m = 528,300 / 193,000
  • m ≈ 2.74 g

Therefore, the mass of nickel that could be electroplated is approximately 2.7 g.

126

The first order reaction 

2N2O(g) → 2N2(g) + O2(g)

has a rate constant of 1.3 x 10-11 s-1 at 227°C and 6.5 x 10-10 s-1 at 327°C. What is the activation energy for the reaction? (R = 8.3 JK-1 mol-1, log102 = 0.30)

  1. ((a))

    15 kJ/mol

  2. ((b))

    30 kJ/mol

  3. ((c))

    68 kJ/mol

  4. ((d))

    97 kJ/mol

Show Answer
Answer: ((d))

97 kJ/mol

CONCEPT:

Activation Energy (Ea) and Arrhenius Equation

  • Activation energy is the minimum energy required for a chemical reaction to occur.
  • The Arrhenius equation relates the rate constant (k) of a reaction to its activation energy (Ea), the temperature (T), and the gas constant (R).
  • The equation is:
  • ln(k2/k1) = (Ea/R) [(1/T1) - (1/T2)]

EXPLANATION:

  • Given data:
  • Rate constant at 227°C (T1) = 1.3 × 10-11 s-1
  • Rate constant at 327°C (T2) = 6.5 × 10-10 s-1
  • Gas constant (R) = 8.3 J K-1 mol-1
  • Temperature must be converted to Kelvin:
  • T1 = 227 + 273 = 500 K
  • T2 = 327 + 273 = 600 K
  • Using the Arrhenius equation:
  • ln(k2/k1) = (Ea/R) [(1/T1) - (1/T2)]
  • Substitute the values:
  • k2 = 6.5 × 10-10, k1 = 1.3 × 10-11
  • ln(k2/k1) = ln((6.5 × 10-10) / (1.3 × 10-11))
  • ln(k2/k1) = ln(50) = log10(50) × 2.303
  • log10(50) = log10(5 × 10) = log10(5) + log10(10)
  • log10(5) ≈ 0.7, log10(10) = 1
  • log10(50) ≈ 0.7 + 1 = 1.7
  • ln(k2/k1) = 1.7 × 2.303 ≈ 3.92
  • Now, solve for Ea:
  • ln(k2/k1) = (Ea / 8.3) [(1/500) - (1/600)]
  • 3.92 = (Ea / 8.3) [(600 - 500) / (500 × 600)]
  • 3.92 = (Ea / 8.3) [100 / 300000]
  • 3.92 = (Ea / 8.3) × (1 / 3000)
  • Ea = 3.92 × 8.3 × 3000
  • Ea ≈ 97500 J/mol
  • Ea ≈ 97 kJ/mol

Therefore, the activation energy (Ea) for the reaction is approximately 97 kJ/mol.

127

The rate of the reaction 2NO + Cl2 → 2NOCI is given by the rate equation rate = k[NO]2[CI]. The value of the rate constant can be increased by :

  1. ((a))

    Increasing the concentration of NO

  2. ((b))

    Increasing the concentration of Cl2.

  3. ((c))

    Increasing the temperature.

  4. ((d))

    Doing all of these.

Show Answer
Answer: ((c))

Increasing the temperature.

CONCEPT:

The rate of a chemical reaction often depends on the concentration of reactants, temperature, and other factors. The rate constant (k) in the rate equation is influenced by temperature, as it is related to the activation energy and the kinetic energy of molecules.

  • The rate equation is given as:
  • rate = k[NO]2[Cl2]
  • The rate constant (k) is temperature-dependent and follows the Arrhenius equation:
  • k = A * e-Ea/RT
  • Where:
  • A is the frequency factor (related to the frequency of collisions).
  • Ea is the activation energy.
  • R is the gas constant.
  • T is the absolute temperature.

EXPLANATION:

  • Increasing the concentration of NO or Cl2 increases the rate of the reaction, but it does not affect the value of the rate constant (k).
  • The rate constant is independent of reactant concentrations.
  • Temperature is the key factor that influences the rate constant (k).
  • An increase in temperature results in higher kinetic energy of reactant molecules, increasing the likelihood of successful collisions and lowering the effect of activation energy (Ea).

Therefore, the value of the rate constant (k) can be increased by increasing the temperature.

128

The ionic reaction 3I+S2O822SO42+I3\rm 3I^-+S_2O_8^{2-}\rightarrow 2SO_4^{2-}+I_3^-

is found to be described by the experimental rate equation.

Rate = k[I][S2O82]\rm k[I^-][S_2O_8^{2-}]

This suggests that:

  1. ((a))

    The reaction occurs when three iodide ions collide simultaneously with one S2O82\rm S_2O_8^{2-} ion

  2. ((b))

    There must be only one step in the overall reaction since the rate is first order in both reactants.

  3. ((c))

    The rate of reaction is inhibited by the presence of I3\rm I_3^-.

  4. ((d))

    A slow step in the overall reaction sequence may involve the collision of a single I- ion with a single S2O82\rm S_2O_8^{2-} ion.

Show Answer
Answer: ((d))

A slow step in the overall reaction sequence may involve the collision of a single I- ion with a single S2O82\rm S_2O_8^{2-} ion.

CONCEPT:

Reaction Mechanisms and Rate Equations

  • The rate equation for a reaction provides information about the order of the reaction with respect to each reactant.
  • The order of reaction indicates how the concentration of each reactant affects the rate of reaction.
  • In a given reaction mechanism, the slowest step (rate-determining step) usually dictates the form of the rate equation.

EXPLANATION:

  • Given the ionic reaction:
  • 3I+S2O822SO42+I3\rm 3I^- + S_2O_8^{2-} \rightarrow 2SO_4^{2-} + I_3^-
  • And the experimental rate equation:
  • Rate=k[I][S2O82]Rate = \rm k[I^-][S_2O_8^{2-}]
  • The rate equation suggests that the reaction is first order in I\rm I^- and first order in S2O82S_2O_8^{2-}  , indicating:
    1. The reaction depends on the concentration of each reactant individually.
    1. A slow step in the reaction likely involves the collision of a single \rm I^- ion with a single S2O82\rm S_2O_8^{2-} ion.
  • Thus, the mechanism of the reaction is likely to be multistep with the rate-determining (slow) step involving a single I-  and a single S2O82\rm S_2O_8^{2-} ion.

Therefore, the correct answer is A slow step in the overall reaction sequence may involve the collision of a single I- ion with a single S2O82- ion.

129

The rate equation of a reaction is given by

Rate = k[A]2

The units of k are

  1. ((a))

    mol dm-3 s-1

  2. ((b))

    dm3 mol-1

  3. ((c))

    s-1

  4. ((d))

    mol-1 dm3s-1

Show Answer
Answer: ((d))

mol-1 dm3s-1

CONCEPT:

Units of the Rate Constant (k)

  • The rate constant (k) in a rate equation depends on the order of the reaction.
  • For a reaction of order n, the units of k can be determined from the rate equation:
  • Rate = k[A]n
  • Here, Rate has units of mol dm-3 s-1, and [A] (concentration) has units of mol dm-3. Using dimensional analysis:
  • k = Rate / [A]n
  • Units of k = (mol dm-3 s-1) / (mol dm-3)n

EXPLANATION:

  • Given the rate equation:
  • Rate = k[A]2
  • This is a second-order reaction, so n = 2.
  • Using the units of Rate and [A]:
  • Rate has units of mol dm-3 s-1.
  • [A]2 has units of (mol dm-3)2, which is mol2 dm-6.
  • Units of k = (mol dm-3 s-1) / (mol2 dm-6)
  • = dm3 mol-1 s-1

Therefore, the units of k are dm3 mol-1 s-1.

130

Which of the following equations is not correct? 

  1. ((a))

    k = A exp (-Ea/RT)

  2. ((b))

    ΔG = ΔH - TΔS

  3. ((c))

    ΔGf0 = RTIn Kp

  4. ((d))

    T = pV / nR

Show Answer
Answer: ((c))

ΔGf0 = RTIn Kp

CONCEPT:

Thermodynamics and Kinetics Equations

  • In thermodynamics and kinetics, several key equations are used to describe different phenomena such as reaction rates, free energy changes, and gas laws.
  • Equation 1: k = A exp (Ea/RT)
  • This is the Arrhenius equation, which describes how the rate constant (k) depends on temperature (T), activation energy (Ea), and the pre-exponential factor (A). This equation is correct.
  • Equation 2: ΔG = ΔH - TΔS
  • This is the Gibbs free energy equation, which relates free energy change (ΔG) to enthalpy change (ΔH), entropy change (ΔS), and temperature (T). This equation is correct.
  • Equation 3: ΔGf0 = RTln Kp
  • This equation is incorrect. The correct form is ΔG0 = -RTln Kp (note the negative sign).
  • Equation 4: T = pV / nR
  • This is a rearrangement of the ideal gas law (pV = nRT), which describes the relationship between pressure (p), volume (V), temperature (T), and the number of moles (n). This equation is correct.

EXPLANATION:

  • Among the given options, the incorrect equation is:
  • ΔGf0 = RTln Kp
  • The correct form of this equation includes a negative sign: ΔG0 = -RTln Kp.
  • The negative sign indicates that the Gibbs free energy is inversely related to the equilibrium constant.

Therefore, the answer is Option 3: ΔGf0 = RTln Kp.

131

Which of the following electron configurations is correct for Nickel ?

  1. ((a))

    [Xe] 4s1 3d8

  2. ((b))

    [Kr] 4s1 3d8

  3. ((c))

    [Kr] 4s2 3d8

  4. ((d))

    [Ar] 4s2 3d8

Show Answer
Answer: ((d))

[Ar] 4s2 3d8

CONCEPT:

Electron Configuration

  • Electron configuration is the arrangement of electrons in the orbitals of an atom or molecule.
  • It follows the Aufbau principle, which states that electrons occupy the lowest energy orbitals first.
  • The Pauli Exclusion Principle and Hund's Rule are also critical for determining electron configurations:
  • Pauli Exclusion Principle: No two electrons in the same atom can have the same set of quantum numbers.
  • Hund's Rule: Electrons will fill degenerate orbitals singly before pairing up.
  • The electron configuration of an element is written using the notation that specifies the energy level (n), type of orbital (s, p, d, f), and the number of electrons in that orbital as a superscript.

EXPLANATION:

  • Nickel (Ni) has an atomic number of 28, meaning it has 28 electrons.
  • The electron configuration is determined by filling the orbitals in the order of increasing energy levels.
  • Following the Aufbau principle, the configuration is:
  • 1s2 2s2 2p6 3s2 3p6 4s2 3d8
  • For shorthand notation, the core configuration of Argon ([Ar]) is used for the first 18 electrons, resulting in:
  • [Ar] 4s2 3d8

The correct option is therefore: Option 4: [Ar] 4s2 3d8

132

The atomic radii of Zr (145 pm) and Hf (144 pm) are almost equal because of:

  1. ((a))

    Their being isoelectronic.

  2. ((b))

    Their being isotonic.

  3. ((c))

    Lanthanoid contraction.

  4. ((d))

    Higher atomic number of Zr as compared to Hf.

Show Answer
Answer: ((c))

Lanthanoid contraction.

CONCEPT:

Lanthanoid Contraction

  • Lanthanoid contraction refers to the steady decrease in the atomic and ionic radii of the lanthanoid elements as the atomic number increases.
  • This occurs due to poor shielding by the 4f electrons, which results in a higher effective nuclear charge and pulls the outer electrons closer to the nucleus.
  • The lanthanoid contraction affects elements that come after the lanthanoids in the periodic table, such as Hf and Zr.

EXPLANATION:

  • Zirconium (Zr) and Hafnium (Hf) belong to Group 4 of the periodic table.
  • Despite Hf having a much higher atomic number than Zr, the atomic radii of Hf (144 pm) and Zr (145 pm) are nearly identical.
  • This similarity is due to the lanthanoid contraction:
  • Hf follows the lanthanoids in the periodic table.
  • The poor shielding by 4f electrons in the lanthanoids causes a significant reduction in the atomic size of Hf.
  • As a result, the atomic radius of Hf becomes almost equal to that of Zr.

Therefore, the correct answer is Option 3) Lanthanoid contraction.

133

Choose the correct option for Mn2O7, CrO3 and V2O5 from the following:

  1. ((a))

    Mn2O, CrO3 and V2O5 are acidic.

  2. ((b))

    CrO3 is acidic while Mn2O7 and V2O5 are basic.

  3. ((c))

    V2O5 is acidic while CrO3 and Mn2O7 are basic

  4. ((d))

    Mn2O7, CrO3 and V2O5 are all basic.

Show Answer
Answer: ((a))

Mn2O, CrO3 and V2O5 are acidic.

CONCEPT:

Acidic and Basic Nature of Oxides

  • The nature of oxides (acidic, basic, or amphoteric) depends on the oxidation state of the element and its position in the periodic table.
  • Oxides of non-metals and elements in high oxidation states tend to be acidic.
  • Oxides of metals and elements in low oxidation states are typically basic.

EXPLANATION:

  • Mn2O7:
  • Manganese is in the +7 oxidation state in Mn2O7.
  • Oxides of elements in high oxidation states like +7 are acidic in nature.
  • CrO3:
  • Chromium is in the +6 oxidation state in CrO3.
  • Oxides of elements in high oxidation states like +6 are acidic in nature.
  • V2O5:
  • Vanadium is in the +5 oxidation state in V2O5.
  • Oxides of elements in high oxidation states like +5 are acidic in nature.

Therefore, Mn2O7, CrO3, and V2O5 are all acidic in nature.

134

The formula of the deep red liquid formed on heating potassium dichromatie with KCI in concentrated sulphuric acid is :

  1. ((a))

    CrCl3

  2. ((b))

    CrO2Cl2

  3. ((c))

    CrO3

  4. ((d))

    CrSO4

Show Answer
Answer: ((b))

CrO2Cl2

CONCEPT:

Formation of Chromyl Chloride (CrO2Cl2)

  • When potassium dichromate (K2Cr2O7) is heated with potassium chloride (KCl) in the presence of concentrated sulphuric acid (H2SO4), a deep red liquid known as chromyl chloride (CrO2Cl2) is formed.
  • This reaction is a qualitative test for the presence of chloride ions (Cl-).
  • The reaction involves the oxidation of chloride ions by potassium dichromate in an acidic medium, resulting in the formation of chromyl chloride.

EXPLANATION:

  • The chemical reaction is as follows:
  • K2Cr2O7 + 4KCl + 6H2SO4 → 2CrO2Cl2 + 3K2SO4 + 3H2O
  • In this reaction:
  • Potassium dichromate reacts with potassium chloride and concentrated sulphuric acid.
  • Chromyl chloride (CrO2Cl2) is formed as a deep red liquid, along with potassium sulphate (K2SO4) and water (H2O).

The formation of chromyl chloride confirms the presence of chloride ions in the reaction mixture.

135

The magnetic moment of Cr2+ is:

  1. ((a))

    2.85 BM

  2. ((b))

    4.40 BM

  3. ((c))

    5.92 BM

  4. ((d))

    3.87 BM

Show Answer
Answer: ((b))

4.40 BM

CONCEPT:

Magnetic Moment

  • The magnetic moment of an atom or ion is determined by the number of unpaired electrons in its electronic configuration.
  • The formula to calculate the magnetic moment is:
  • μ = √(n(n + 2)) BM
  • Where μ is the magnetic moment in Bohr Magneton (BM).
  • n is the number of unpaired electrons.

EXPLANATION:

  • For Cr2+, the electronic configuration of Cr is [Ar] 3d5 4s1.
  • When Cr loses two electrons to become Cr2+, the configuration becomes [Ar] 3d4 (since the 4s electrons are lost first).
  • In the 3d4 configuration, there are 4 unpaired electrons.
  • Using the formula for magnetic moment:
  • μ = √(n(n + 2)) BM
  • n = 4 (number of unpaired electrons)
  • μ = √(4(4 + 2)) BM
  • μ = √(4 × 6) BM
  • μ = √24 BM
  • μ ≈ 4.90 BM

Therefore, the magnetic moment of Cr2+ is approximately 4.40 BM.

136

Which of the following is a coordination compound? 

  1. ((a))

    KCl MgCl2.6H2O

  2. ((b))

    FeSO4(NH4)2SO4.6H2O

  3. ((c))

    KAI(SO4)2.12H2O

  4. ((d))

    K3[AI(C2O4)3]

Show Answer
Answer: ((d))

K3[AI(C2O4)3]

CONCEPT:

Coordination Compound

  • A coordination compound is a chemical substance in which a central metal atom or ion is bonded to a group of surrounding ligands (atoms, ions, or molecules) through coordinate covalent bonds.
  • These compounds are characterized by the presence of complex ions, where the metal is surrounded by ligands in a specific arrangement.
  • Coordination compounds typically have square planar, tetrahedral, or octahedral geometries depending on the number of ligands and their spatial arrangement.

EXPLANATION:

  • Option 1: KCl MgCl2.6H2O -
  • This is not a coordination compound because it is simply a hydrated ionic compound (magnesium chloride hexahydrate).
  • Option 2: FeSO4(NH4)2SO4.6H2O -
  • This is not a coordination compound because it is a double salt and dissociates completely in water.
  • Option 3: KAl(SO4)2.12H2O -
  • This is not a coordination compound; it is a double salt (potassium alum) that dissociates completely in water.
  • Option 4: K3[Al(C2O4)3] -
  • This is a coordination compound because it contains a complex ion, [Al(C2O4)3]3-, where Al3+ is bonded to oxalate ligands.
  • Based on the above analysis, the correct answer is Option 4: K3[Al(C2O4)3].

Therefore, K3[Al(C2O4)3] is the coordination compound among the given options.

137

The coordination number of cobalt in the complex [Co(en)2Br2]Cl2 is : (en = NH2CH2CH2NH2)

  1. ((a))

    4

  2. ((b))

    6

  3. ((c))

    5

  4. ((d))

    2

Show Answer
Answer: ((b))

6

CONCEPT:

Coordination Number in Complexes

  • The coordination number of a central metal ion in a complex is defined as the number of ligand atoms directly bonded to the metal ion.
  • Each ligand contributes one or more atoms that coordinate to the metal ion.
  • In cases involving chelating ligands, such as ethylenediamine (en), multiple atoms from the same ligand can bond to the metal ion.

EXPLANATION:

  • In the given complex, [Co(en)2Br2]Cl2, the central metal ion is cobalt (Co).
  • The ligands surrounding the cobalt ion are:
  • Two ethylenediamine (en) molecules. Each ethylenediamine molecule is a bidentate ligand, meaning it uses two donor atoms (two nitrogen atoms) to bond to the metal. Hence, 2 en molecules contribute 2 × 2 = 4 coordination bonds.
  • Two bromide (Br-) ions. Each bromide ion is a monodentate ligand, contributing one coordination bond each. Hence, 2 Br- ions contribute 2 coordination bonds.
  • Thus, the total coordination number of cobalt in the complex is 4 (from en) + 2 (from Br-) = 6.

Therefore, the coordination number of cobalt in the complex [Co(en)2Br2]Cl2 is 6.

138

Which of the following is a hexadentate ligand?

  1. ((a))

    Ox(oxalate ion, C2O42-)

  2. ((b))

    CN-

  3. ((c))

    en(enthylenediamine), NH2CH2CH2NH2)

  4. ((d))

    EDTA

Show Answer
Answer: ((d))

EDTA

CONCEPT:

Hexadentate Ligands

  • Ligands are molecules or ions that can donate a pair of electrons to a central metal atom or ion to form a coordination complex.
  • The term "hexadentate" refers to a ligand that has six donor atoms, meaning it can form six bonds with a central metal atom or ion.
  • Hexadentate ligands are known for their strong chelating ability, as they can bind to the central metal ion through six different sites, forming a very stable complex.

EXPLANATION:

  • Option 1: Ox (oxalate ion, C2O42-): Oxalate is a bidentate ligand, meaning it has two donor atoms that can bind to a central metal atom.
  • Option 2: CN-: Cyanide is a monodentate ligand, meaning it has only one donor atom (the carbon atom) that can bind to a central metal atom.
  • Option 3: en (ethylenediamine, NH2CH2CH2NH2): Ethylenediamine is a bidentate ligand, as it has two nitrogen atoms that can bind to a central metal atom.
  • Option 4: EDTA: EDTA (Ethylenediaminetetraacetic acid) is a hexadentate ligand. It has six donor atoms: four oxygen atoms from carboxylate groups and two nitrogen atoms from amine groups. EDTA can bind to a central metal atom through all six donor sites, forming a very stable chelate complex.
  • Therefore, the correct answer is EDTA, as it is the only ligand in the list that is hexadentate.

Answer: Option 4 - EDTA

139

The oxidation state of the central metal atom in the coordination compound [Pt (NH3)3Cl] Cl is:

  1. ((a))

    +2

  2. ((b))

    +1

  3. ((c))

    0

  4. ((d))

    -1

Show Answer
Answer: ((a))

+2

CONCEPT:

Oxidation State in Coordination Compounds

  • The oxidation state of the central metal atom in a coordination compound is calculated by considering the charges of the ligands and counterions present.
  • In coordination compounds:
  • Neutral ligands (e.g., NH3) contribute zero charge.
  • Anionic ligands (e.g., Cl-) contribute negative charges.
  • The overall charge of the compound is distributed between the central metal atom and ligands.

EXPLANATION:

  • In the given coordination compound [Pt(NH3)3Cl]Cl:
  • The complex ion [Pt(NH3)3Cl]+ has a charge of +1, as indicated by the counterion Cl-.
  • Platinum (Pt) is the central metal atom.
  • The three NH3 ligands are neutral and contribute zero charge.
  • The chloride ligand (Cl-) contributes a charge of -1.
  • Let the oxidation state of Pt be x. Based on the overall charge of the complex ion, we can write:
  • x + (0) + (-1) = +1
  • x - 1 = +1
  • x = +2

Therefore, the oxidation state of the central metal atom (Pt) in the coordination compound [Pt(NH3)3Cl]Cl is +2.

140

Given the list of ligands and their corresponding names, choose the pair that does not match.

LigandName
1.OH-Hydroxo
2.CN-Cyanide
3.Cl-Chloro
4.H2OAqua
  1. ((a))

    1

  2. ((b))

    2

  3. ((c))

    3

  4. ((d))

    4

Show Answer
Answer: ((b))

2

CONCEPT:

Ligands and Their Nomenclature

  • Ligands are ions or molecules that donate a pair of electrons to a central atom/ion in a coordination complex.
  • The names of ligands are based on specific rules in coordination chemistry:
  • Anionic ligands typically end with "-o" (e.g., "Cl-" is "chloro," "OH-" is "hydroxo").
  • Neutral ligands often have specific names (e.g., "H2O" is "aqua," "NH3" is "ammine").

EXPLANATION:

  • Analyzing the given ligand names:
  • OH- is correctly named "hydroxo."
  • Cyanide (CN-) must change its suffix to "-o" to become Cyano (or Cyanido). The given name Cyanide is the name of the ion itself, not its name as a ligand. This is NOT a match.
  • Cl- is correctly named "chloro."
  • H2O is correctly named "aqua."

Therefore, the pair that does not match is CN- and Cyanide(Option 2).

141

The IUPAC name of

  1. ((a))

    1, 2, 3, 4-tetramethyl-1, 3-propandiol.

  2. ((b))

    1, 1, 2-trimethyl butan -1, 3-diol. 

  3. ((c))

    1,2-dimethyl pentan-2, 4-diol.

  4. ((d))

    2,3-dimethyl pentan -2, 4-diol.

Show Answer
Answer: ((d))

2,3-dimethyl pentan -2, 4-diol.

CONCEPT:

IUPAC Nomenclature Rules for Alcohols (Alkanols)

The International Union of Pure and Applied Chemistry (IUPAC) rules are used to systematically name organic compounds. For poly-functional compounds like diols (alcohols with two hydroxyl (-OH) groups), the following priority rules apply:

  • 1. Identify the Parent Chain: Select the longest continuous carbon chain that includes both of the hydroxyl (-OH) groups.
  • 2. Identify the Principal Functional Group: The -OH group is the principal functional group, so the suffix will be "-diol".
  • 3. Number the Parent Chain: Number the chain from the end that gives the lowest possible locants (numbers) to the principal functional groups (the -OH groups).
  • 4. Identify and Name Substituents: Name all groups attached to the parent chain (e.g., methyl, ethyl) and assign them a locant number.
  • 5. Assemble the Name: Construct the full name in the order: (Substituent Locant)-(Substituent Name) (Parent Alkane Name)-(OH Locants)-(Suffix -diol)

EXPLANATION:

1. Select the Parent Chain

  • We must find the longest continuous chain that includes both -OH groups.
  • The parent chain is a pentane derivative.

2. Number the Parent Chain

  • The -OH groups are at C2 and C4.

3. Identify Functional Groups and Substituents (Numbering from Right to Left)

  • Parent Chain: Pentane.
  • Principal Functional Group (-OH): at C2 and C4. Suffix: -2,4-diol.
  • Substituents (CH3): at C2 and C3. Name: 2,3-dimethyl.

So, the correct answer is  2,3-dimethylpentane-2,4-diol.

142

Consider the following sequence of reaction

The Product 'D' is

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((d))

CONCEPT:

This is a multi-step organic synthesis sequence starting from Aniline. It involves three key reactions of aromatic chemistry:

  • 1. Electrophilic Aromatic Substitution (EAS): Aniline (C6H5NH2) contains a highly activating amino (-NH2) group. It is a powerful ortho/para director. Since Br2/H2O is a strong brominating agent and no deactivating groups are present, bromination occurs at all available ortho and para positions.
  • 2. Diazotization: Conversion of a primary aromatic amine (-NH2) to an Arenediazonium Salt (-N2+X-) using NaNO2/HCl at 0-5oC. This is essential because the -N2+ group is a good leaving group that can be replaced by various nucleophiles.
  • 3. Balz-Schiemann Reaction: A specific reaction used to replace the diazonium group (-N2+) with a Fluorine atom (-F). The diazonium salt is treated with tetrafluoroboric acid (HBF4) to form an intermediate diazonium tetrafluoroborate salt (Ar-N2+BF4-), which is then heated to decompose, releasing nitrogen gas and yielding the aryl fluoride.

EXPLANATION:

Step 1: Formation of Product A (Bromination)

Step 2: Formation of Product B (Diazotization)

Step 3 & 4: Formation of Product C and D (Balz-Schiemann Reaction)

The structure in option 4 correctly represents 1-Fluoro-2,4,6-tribromobenzene.

Therefore, the correct option is 4.

143

Which of these species is aromatic?

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Aromaticity

  • Aromatic compounds are cyclic, planar molecules with a conjugated π-electron system.
  • They follow the Hückel’s Rule, which states that a molecule is aromatic if it has (4n + 2) π-electrons, where n is a non-negative integer (0, 1, 2, etc.).
  • Aromatic compounds exhibit extra stability due to resonance and delocalization of π-electrons.
  • A molecule is Antiaromatic if it has (4n) π-electrons, where n is a non-negative integer (0, 1, 2, etc.).
  • a molecule is Nonaromatic if it is not planar.

EXPLANATION:​:

  • Cyclic, planar, and has 2 π-electrons (satisfies Hückel’s Rule). Therefore, it is aromatic.

  • Cyclic, planar, and has 4 π-electrons. Therefore, it is antiaromatic.

  • Cyclic, non-planar. Therefore, it is Non aromatic.
  • Cyclic, non-planar. Therefore, it is Non aromatic.

Answer: Option 1 is aromatic species.

144

In the given molecule : 

  1. ((a))

    All three carbons are sp hybridized.

  2. ((b))

    C-I and C-III are sp2 hybridized and C-II is sp hybridized.

  3. ((c))

    Both C-I and C-III are sp hybridized and C-II sp2 hybridized.

  4. ((d))

    All three carbons are sp2 hybridized.

Show Answer
Answer: ((b))

C-I and C-III are sp2 hybridized and C-II is sp hybridized.

CONCEPT:

Hybridization of Carbon Atoms

  • The hybridization of a carbon atom depends on the number and types of bonds it forms.
  • Key points for hybridization:
  • sp hybridization: Carbon forms two sigma bonds and has two unhybridized p orbitals (linear geometry).
  • sp2 hybridization: Carbon forms three sigma bonds and one unhybridized p orbital (trigonal planar geometry).
  • sp3 hybridization: Carbon forms four sigma bonds (tetrahedral geometry).

EXPLANATION:

  • In the given molecule:
  • C-I and C-III: They are sp2 hybridized.
  • 2σ bond to C-H and 1σ bond + 1 π bond to C=C.
  • 2σ bond + 1σ bond = 3σ bond and 0 lone pair. Therefore, sp2 hybridisation.
  • C-II: It is sp hybridized.
  • 1σ bond + 1 π bond to C(I) and 1σ bond + 1 π bond to C(III).
  • Total 2σ bond and 0 lone pair. Therfore, sp hybridisation.
  • The correct answer is Option 2: Both C-I and C-III are sp2 hybridized and C-II is sp hybridized.
145

In pyridine

, the maximum electron density is found at position :

  1. ((a))

    IIl only 

  2. ((b))

    II and IV only

  3. ((c))

    I and V only

  4. ((d))

    I, II, IV and V only

Show Answer
Answer: ((b))

II and IV only

CONCEPT:

Electron Density in Aromatic Compounds

  • Aromatic compounds like pyridine exhibit delocalized π-electrons over the ring structure.
  • Pyridine has a nitrogen atom in the ring, which has a lone pair of electrons in an sp2 orbital. This lone pair does not participate in the π-electron delocalization.
  • The electron density in pyridine is distributed among the carbon atoms and the nitrogen atom. However, the nitrogen atom is more electronegative, which influences the electron density distribution.

EXPLANATION:

  • Resonance Structure of Pyridine:
  • Resonance structures of pyridine show that the electron density is relatively higher at II and IV positions, making them more nucleophilic and reactive in electrophilic substitution reactions.

Correct Answer: 2) II and IV only

146

The C-Cl bond distance is shortest in : 

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

C-Cl Bond Length

  • The bond length between a carbon (C) atom and a chlorine (Cl) atom depends on the hybridization of the carbon atom and the nature of the bonding.
  • Hybridization affects the bond length as follows:
  • sp hybridized carbon forms the shortest bond due to higher s-character, resulting in greater electron density between the bonded atoms.
  • sp2 hybridized carbon forms a bond of intermediate length.
  • sp3 hybridized carbon forms the longest bond due to lower s-character.

EXPLANATION:

  • In the given options:
  • Option 1: The carbon atom is sp2 hybridized.
  • Option 2: The carbon atom is sp3 hybridized.
  • Option 3: The carbon atom is sp3 hybridized.
  • Option 4: The carbon atom is sp3 hybridized.
  • Since sp hybridized carbon has the highest s-character, it forms the shortest C-Cl bond.
  • Thus, the correct option is Option 1, as it involves an sp2 hybridized carbon atom bonded to chlorine.

Therefore, the C-Cl bond distance is shortest in Option 1.

147

Which of these species will produce a precipitate of AgBr most readily when treated with AgNO3 solution ?

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((d))

CONCEPT:

Silver halides precipitation

  • When a halide ion reacts with silver nitrate (AgNO3) solution, a precipitate of silver halide (AgX) forms.
  • The ease of formation of the precipitate depends on the nucleophilicity of the halide ion and the strength of its bond with silver (Ag+).
  • Among the halides, bromide ions (Br-) form a precipitate of AgBr most readily due to their moderate bond strength with Ag+ and their high reactivity compared to chloride (Cl-) and iodide (I-).

EXPLANATION:

  • It will not release bromide ions (Br-) readily as the carbocation species is antiaromatic which is highly unstable.
  • Resulting carbocation species will form at sp2 carbon which is not stable..
  • Stable carbocation is formed at primary benzylic position.
  • Upon loss of Br-, it forms a carbocation. This carbocation is stabilized by:
  • Resonance with the benzene ring (Benzylic stabilization).
  • Resonance/Delocalization of the lone pair of electrons from the adjacent Oxygen atom (from the OCH3 group).  .
  • Carbocations stabilized by the lone pair of an adjacent oxygen or nitrogen atom (like oxonium or ammonium ions) are among the most stable carbocations known.
  • The species in Option 4 is the most reactive in forming AgBr due to its ability to provide Br- ions efficiently.

Therefore, the correct answer is Option 4, as it produces a precipitate of AgBr most readily when treated with AgNO3 solution.

148

Which of the following are structural isomers? 

  1. ((a))

    II and IV only

  2. ((b))

    I, II and IV only

  3. ((c))

    III and IV only

  4. ((d))

    I and II only.

Show Answer
Answer: ((d))

I and II only.

Here is the answer in HTML format based on the provided structure:

CONCEPT:

Structural Isomers

  • Structural isomers are compounds with the same molecular formula but different structural arrangements of atoms.
  • They differ in the connectivity of atoms, leading to variations in physical and chemical properties.
  • Types of structural isomers include chain isomers, position isomers, and functional group isomers.

EXPLANATION:

  • In the given options, the comparison of structures leads to the following conclusions:
  • I and II are structural isomers as they have the same molecular formula but different arrangements of atoms.
  • III and IV are not structural isomers as they are different compound altogether.
  • II and IV are not structural isomers as they are different compound altogether.
  • From the given options, the correct answer is:
  • Option 4: I and II only.

Therefore, the correct answer is Option 4: I and II only.

149

Which of these reactions will give cis-diols as the product? 

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Cis-Diols Formation

  • Cis-diols are formed when alkenes undergo hydroxylation, adding two hydroxyl (-OH) groups to the same side of the double bond (syn-addition).
  • This reaction is typically achieved using reagents such as osmium tetroxide (OsO4) or potassium permanganate (KMnO4) in mild conditions.
  • The key characteristic of this reaction is the syn-addition mechanism, leading to both hydroxyl groups being added to the same face of the alkene, resulting in a syn-diol.

EXPLANATION:

1) Alkene + Cold, alk.KMnO4

  • Product Stereochemistry: cis-diol (Syn-hydroxylation).

2) Alkene + H2O2/ OH-

  • Product: Epoxide is formed.

3) Alkene + (i) BH3 (ii) H2O2/ OH-

  • Product Stereochemistry: The overall reaction is the anti-Markovnikov addition of H2O (H and OH). The two OH groups are not added to adjacent carbons; only one OH group is added to the alkene. The product is an alcohol, not a diol.

4) Alkene + (i) Br2 (ii) KOH (aq)

  • Product Stereochemistry: Leads to a diol, but the overall result is complex and not a reliable, stereospecific cis-addition method.

The only reaction which is stereospecific syn-hydroxylation to form a diol is the treatment of the alkene with cold, alkaline KMnO4.

Therefore, the correct option is 1.

150

The spots of separated components in paper chromatography can be made visible by :

  1. ((a))

    Putting the chromatogram under UV light.

  2. ((b))

    Spraying a visualizing agent.

  3. ((c))

    Placing the chromatogram in a jar containing a few crystals of iodine.

  4. ((d))

    By complexing with heavy metal ions.

Show Answer
Answer: ((b))

Spraying a visualizing agent.

CONCEPT:

Paper Chromatography Visualization Techniques

  • Paper chromatography is a technique used to separate components of a mixture based on their relative affinities to the stationary phase (paper) and mobile phase (solvent).
  • After separation, the spots of the components may not be immediately visible, requiring visualization techniques.
  • Common methods to make the spots visible include exposure to UV light, spraying a visualizing agent, or using chemical reactions to enhance visibility.

EXPLANATION:

  • The separated components can be visualized using the following methods:
  • Putting the chromatogram under UV light: Many compounds fluoresce under UV light, making them visible.
  • Spraying a visualizing agent: Certain chemicals react with the separated components to produce a visible color change or fluorescence.
  • Placing the chromatogram in a jar containing iodine crystals: Iodine vapor reacts with some compounds, forming visible brown or yellow spots.
  • Complexing with heavy metal ions: Some compounds can form colored complexes when exposed to specific metal ions.
  • Among the options, spraying a visualizing agent is the most commonly used method as it provides clear and reliable visualization for a wide range of compounds.

Therefore, the spots of separated components in paper chromatography can be made visible by spraying a visualizing agent.

151

The quantitative estimation of nitrogen by Kjeldahl's method will provide accurate results for: .

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((d))

CONCEPT:

Kjeldahl's Method for Nitrogen Estimation

  • Kjeldahl's method is a standard analytical technique used for the quantitative estimation of nitrogen in organic compounds. The basic principle is the conversion of nitrogen in the compound into ammonium sulfate by boiling the substance with concentrated sulfuric acid (H2SO4) in the presence of a catalyst .
  • The ammonia evolved is absorbed in a known excess of standard acid (H2SO4 or HCl), and the unused acid is estimated by titration.

Limitations of Kjeldahl's Method:

The method works by converting nitrogen to the ammonium ion (NH4+), which requires the nitrogen atom to be bonded in such a way that it can be completely converted to ammonia under the digestion conditions. It fails for compounds where the nitrogen is:

  • Present in a Nitro (-NO2) or Azo (-N=N-) group. These structures resist conversion to ammonium sulfate under the standard reaction conditions.
  • Present in a ring (heterocyclic compounds) where the nitrogen is not part of a primary/secondary/tertiary amino group (e.g., Pyridine, Quinoline). The nitrogen in these heterocyclic rings is tightly bound and does not quantitatively convert to ammonia.

EXPLANATION:

We must evaluate each option to see which compound's nitrogen structure allows for quantitative conversion to ammonium sulfate.

1) N,N'-Diphenylhydrazine:

  • Contains a Hydrazine (-NH-NH-) functional group.
  • These nitrogen atoms are directly bonded to the ring and another nitrogen atom, but they are generally quantitatively converted to NH4HSO4 upon digestion.

2) Azobenzene:

  • Contains an Azo group (-N=N-) linkage.
  • Nitrogen in the azo group is not quantitatively converted to ammonium sulfate.
  • Kjeldahl's method Fails.

3) 4-Aminoquinoline:

  • Contains a primary aromatic amine (-NH2) and a heterocyclic nitrogen atom (in the Quinoline ring).
  • The nitrogen in the primary amine group (-NH2) is easily estimated.
  • However, the nitrogen atom that is part of the Quinoline ring (heterocyclic nitrogen) is not quantitatively converted to ammonium sulfate.
  • Kjeldahl's method Fails.

4) N-Methyl-1,2,3,4-tetrahydro-2-naphthylamine:

  • Contains a Secondary Amine (-NHR) group. The nitrogen is bonded to one hydrogen atom, a methyl group, and a secondary carbon atom of a saturated ring system (Tetralin derivative).
  • Nitrogen atoms present in aliphatic primary, secondary, and tertiary amines are readily and quantitatively converted to ammonium sulfate.
  • Kjeldahl's method Provides accurate results.

Therefore, the quantitative estimation of nitrogen by Kjeldahl's method will provide accurate results for the compound in option 4.

152

The most stable conformational isomer of 2-chloroethanol is : 

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Conformational Isomerism

  • Conformational isomerism arises due to the rotation around single bonds in molecules.
  • In molecules like 2-chloroethanol, the interaction between substituents and the stability of the molecule depends on steric hindrance and electronic effects.
  • The most stable conformation minimizes steric clashes and maximizes favorable interactions, such as hydrogen bonding between functional groups.

EXPLANATION:

  • 2-Chloroethanol has a hydroxyl (-OH) group and a chlorine atom (-Cl) attached to the ethane backbone.
  • The most stable conformer of 2-chloroethanol occurs when the -OH group forms an intramolecular hydrogen bond with the chlorine atom.
  • This hydrogen bonding reduces the repulsion between the groups and stabilizes the molecule.
  • Such a conformation typically occurs when the -OH and -Cl groups are in a gauche position relative to each other.
  • Other conformations, such as anti or eclipsed forms, may have greater steric hindrance or lack favorable interactions, making them less stable.

Therefore, the most stable conformational isomer of 2-chloroethanol is the one where the -OH and -Cl groups are in a gauche position, allowing intramolecular hydrogen bonding.

153

Which of these statements is NOT true about the SN2 reaction?

  1. ((a))

    Order of reactivity of alkyl halides is 1° > 2° > 3°

  2. ((b))

    Reaction rate is dependent on the concentration of the nucleophile.

  3. ((c))

    Protic solvents facilitate the SN2 reaction

  4. ((d))

    Order of reactivity with different halides is RI > RBr > RCl

Show Answer
Answer: ((c))

Protic solvents facilitate the SN2 reaction

CONCEPT:

SN2 Reaction (Substitution Nucleophilic Bimolecular)

  • The SN2 reaction is a type of nucleophilic substitution reaction where the rate-determining step involves both the substrate and the nucleophile.
  • In SN2 reactions, the nucleophile attacks the substrate from the opposite side of the leaving group, resulting in an inversion of configuration (stereochemistry).
  • The reaction is bimolecular, meaning the rate depends on both the concentration of the substrate and the nucleophile.
  • Key factors affecting SN2 reaction rates:
  • Substrate structure: Reactivity order is 1° > 2° > 3° (due to steric hindrance).
  • Solvent: Polar aprotic solvents (e.g., acetone, DMSO) favor SN2 reactions.
  • Leaving group: Better leaving groups (e.g., I⁻, Br⁻, Cl⁻) increase reaction rates.

EXPLANATION:

  • "Order of reactivity of alkyl halides is 1° > 2° > 3°."
  • ​This is true because steric hindrance significantly impacts the SN2 mechanism. Primary alkyl halides react faster than secondary ones, and tertiary alkyl halides are highly unreactive in SN2 reactions.
  • "Reaction rate is dependent on the concentration of the nucleophile."
  • This is true because the SN2 reaction is bimolecular, and the rate equation is:
  • Rate = k [substrate][nucleophile].
  • "Protic solvents facilitate the SN2 reaction."
  • This is NOT true. Polar protic solvents (e.g., water, alcohols) hinder the SN2 reaction because they stabilize the nucleophile through hydrogen bonding, reducing its reactivity. Polar aprotic solvents (e.g., acetone, DMSO) are preferred as they do not stabilize the nucleophile.
  • "Order of reactivity with different halides is RI > RBr > RCl."
  • This is true because iodide (I⁻) is a better leaving group than bromide (Br⁻), which is better than chloride (Cl⁻).

Therefore, the correct answer is "Protic solvents facilitate the SN2 reaction."

154

Consider the following sequence of reactions:

'B' is

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((c))

CONCEPT:

  • Electrophilic Addition (Markovnikov's Rule): The reaction of an alkene (like styrene) with a hydrohalic acid (HBr) is an electrophilic addition. The hydrogen atom (H) adds to the carbon atom of the double bond that already has a greater number of hydrogen atoms, and the halogen (Br) adds to the carbon atom that results in the formation of the most stable carbocation intermediate. This is known as Markovnikov's Rule . In the case of styrenes, the Br adds to the benzylic carbon (C1) because it forms a resonance-stabilized benzylic carbocation, which is the most stable intermediate.
  • Halide Exchange (Swarts Reaction): The reaction of an alkyl halide with a metallic fluoride (SbF3, Hg2F2, or CoF2) to replace a chlorine or bromine atom with a fluorine atom. This is a special type of nucleophilic substitution reaction, specifically used to synthesize fluoroalkanes.

EXPLANATION:

The reaction sequence starts with Styrene (Phenylethene) and proceeds in two steps:

1. Step 1: Formation of Product A (HBr Addition)

2. Step 2: Formation of Product B (Swarts Reaction)

Therefore, the correct option is 3.

155

In the sequence of reactions given below :  

'B' is

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

The reaction sequence involves two standard organic reactions used for the synthetic transformation of Aniline into Benzene.

  • Step 1: Diazotization: The conversion of a primary aromatic amine (-NH2) into an Arenediazonium Salt (-N2+X-) using NaNO2 and HCl at a low temperature (0-5oC).
  • Step 2: Reduction of Diazonium Salt: The replacement of the highly reactive diazonium group (-N2+) with a hydrogen atom (-H), effectively removing the original functional group from the ring. This is achieved using a reducing agent like Hypophosphorous acid (H3PO2).

EXPLANATION:

The reaction proceeds from Aniline in two steps:

1. Step 1: Formation of Product A (Diazotization)

2. Step 2: Formation of Product B (Reduction)

The final product B is Benzene, which has the molecular formula C6H6.

Therefore, the correct option is 1.

156

The preparation of phenol from chlorobenzene is a/an :

  1. ((a))

    Electrophilic addition reaction.

  2. ((b))

    Electrophilic substitution reaction. 

  3. ((c))

    Nucleophilic addition reaction.

  4. ((d))

    Nucleophilic substitution reaction.

Show Answer
Answer: ((d))

Nucleophilic substitution reaction.

CONCEPT:

Types of Organic Reaction Mechanisms

  • In organic chemistry, reactions are broadly classified based on the functional group change and the nature of the attacking species.                       
  • Substitution Reaction: One atom or group is replaced by another atom or group. 
  • Electrophilic Substitution: The attacking species is an electrophile (E+). This is typical for aromatic rings (Electrophilic Aromatic Substitution, SEAr) where a hydrogen atom is usually replaced (e.g., nitration of benzene).
  • Nucleophilic Substitution: The attacking species is a nucleophile (Nu-). This is typical for alkyl halides (SN1, SN2) or activated aryl halides (Nucleophilic Aromatic Substitution, SNAr).
  • Addition Reaction: Atoms or groups are added across a multiple bond (π bond) to form two new single bonds (σ bonds).                            
  • Electrophilic Addition: The initial attacking species is an electrophile (E+). This is typical for alkenes and alkynes (e.g., addition of HBr).
  • Nucleophilic Addition: The initial attacking species is a nucleophile (Nu-). This is typical for carbonyl compounds (C=O) like aldehydes and ketones.

EXPLANATION:

  • The reaction is the conversion of Chlorobenzene (C6H5Cl) to Phenol (C6H5OH).       
  • C6H5Cl + OH- \longrightarrow C6H5OH + Cl-
  • The overall chemical change involves the replacement of the chlorine atom (Cl) by the hydroxyl group (OH). This is a substitution reaction.
  • The attacking species is the hydroxide ion (OH-) which is a nucleophile. Therefore, the reaction is a Nucleophilic Substitution.
  • This specific commercial process is called the Dow process and requires drastic conditions (e.g., 623 K and 300 atm with concentrated NaOH). This is because chloro-benzene is a haloarene and the C-Cl bond is much stronger than in alkyl halides due to π-electron resonance.
  • The mechanism for this reaction is unusual; it proceeds via an elimination-addition mechanism involving a highly reactive and unstable intermediate called benzyne.                                    
  • Step 1: Elimination: The strong base (OH-) abstracts a proton (H+) adjacent to the chlorine, and the Cl- leaves, forming the benzyne intermediate (a triple bond in the ring).
  • Step 2: Addition: The nucleophile (OH-) then adds to the benzyne intermediate, ultimately leading to sodium phenoxide, which is acidified to give phenol.
  • Despite the unusual benzyne intermediate and the harsh conditions, the net result is the substitution of a Cl by an OH group, driven by the nucleophile OH-. Thus, it is classified as a Nucleophilic substitution reaction.

Therefore, the correct classification is Nucleophilic substitution reaction.

157

Freons are manufactured using:

  1. ((a))

    Sandmeyer's reaction.

  2. ((b))

    Swartz reaction.

  3. ((c))

    Finkelstein reaction.

  4. ((d))

    Gatterman reaction.

Show Answer
Answer: ((b))

Swartz reaction.

CONCEPT:

Freons and their Manufacturing

  • Freons are a class of compounds primarily composed of fluorine, carbon, and other halogens, commonly used as refrigerants and aerosol propellants.
  • The manufacturing process involves reactions that substitute halogens into hydrocarbon molecules to form fluorinated compounds.

EXPLANATION:

  • Sandmeyer's reaction: This reaction involves the replacement of an aromatic amine group (-NH2) with a halogen, but it is not used for manufacturing Freons.
  • Swartz reaction: This is a halogen exchange reaction where a hydrocarbon is fluorinated by treating it with metallic fluorides such as AgF or HgF2. This reaction is specifically used for the synthesis of Freons and other fluorinated hydrocarbons.
  • Finkelstein reaction: This reaction involves halogen exchange using salts like NaI, but it is not used for Freon manufacturing.
  • Gatterman reaction: This reaction involves the introduction of a formyl group (-CHO) into aromatic compounds and is unrelated to Freon production.
  • Based on the above explanation, the correct answer is Swartz reaction.

Therefore, Freons are manufactured using the Swartz reaction.

158

The enol form of acetylacetone has :

  1. ((a))

    9σ bonds, 4π bonds, 2 lone pairs 

  2. ((b))

    12σ bonds, 2π bonds, 4 lone pairs

  3. ((c))

    14σ bonds, 2π bonds, 4 lone pairs

  4. ((d))

    14σ bonds, 4π bonds, 2 lone pairs

Show Answer
Answer: ((c))

14σ bonds, 2π bonds, 4 lone pairs

CONCEPT:

Enol Form of Acetylacetone

  • Acetylacetone is a β-diketone and exhibits keto-enol tautomerism. The enol form is stabilized by intramolecular hydrogen bonding.
  • The enol form involves the presence of a hydroxyl (-OH) group attached to one of the carbon atoms and a double bond between two adjacent carbon atoms.
  • The enol form of acetylacetone contains both sigma (σ) and pi (π) bonds along with lone pairs of electrons on the oxygen atoms.

EXPLANATION:

  • The enol structure of acetylacetone can be represented as:
  • In this structure:
  • Sigma (σ) bonds are formed by single bonds between atoms.
  • Pi (π) bonds are formed due to the C=C and C=O bonds..
  • Lone pairs are present on the oxygen atoms.
  • Counting the bonds and lone pairs:
  • There are 14 sigma (σ) bonds (including C-H, C-C, O-H, and C=O single bonds).
  • There are 4 pi (π) bonds (2 in the double bonds between C=C and 2 in the double bonds between C=O).
  • There are 2 lone pairs of electrons, one on each oxygen atom.

Answer: The enol form of acetylacetone has 14 σ bonds, 4 π bonds, and 2 lone pairs of electrons.

159

Which of these alkyl halides will undergo SNI reactions most readily?

  1. ((a))

    C6H5-CH2-I

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

C6H5-CH2-I

CONCEPT:

SN1 Reaction Rate and Stability of Intermediates     

  • The SN1 reaction (Substitution Nucleophilic Unimolecular) is a two-step process whose rate-determining step is the formation of a carbocation intermediate by the loss of the leaving group (L).
  • The rate of an SN1 reaction depends primarily on the stability of the carbocation formed and the nature of the leaving group.                                         
  • Carbocation Stability: A more stable carbocation intermediate lowers the activation energy of the rate-determining step, leading to a faster reaction. The stability order is benzyl ≈ allyl > 3 > 2 > 1.
  • Leaving Group Ability: A better leaving group (L), which is a weaker base (stronger conjugate acid), facilitates bond breaking in the first step, increasing the reaction rate. Good leaving groups include I-, Br-, Cl-, and sulfonate anions.

EXPLANATION:

  • The intermediate formed in the first step will be a primary benzyl carbocation (C6H5CH2+).  
  • This carbocation is highly stable due to resonance stabilization with the phenyl ring. The stability is the same for all four options.
  • Since the carbocation stability is constant, the rate of the SN1 reaction will be determined by the quality of the leaving group (L) in the first step. We must compare the leaving group ability of I- (Option 1) and the leaving groups in Options 2, 3, and 4.                      
  • Option 1: Leaving group is I- (Iodide ion). HI is a very strong acid (pKa ≈ -10). I- is an excellent leaving group.
  • Option 2: Leaving group is the acetate anion (CH3CO2-). Acetic acid (CH3COOH) has a pKa ≈ 4.75. Acetate is a poor leaving group compared to I-.
  • Option 3: Leaving group is the benzenesulfonate anion (C6H5SO3-). Benzenesulfonic acid is a very strong acid (stronger than H2SO4).
  • Option 4: Leaving group is the benzoate anion (C6H5CO2-). Benzoic acid (C6H5COOH) has a pKa ≈ 4.2. Benzoate is a poor leaving group.
  • Conclusion on Leaving Group: The order of leaving group ability (best to worst) is:                      
  • I- > C6H5SO3- > CH3CO2- ≈ C6H5CO2-

Therefore, the compound that will undergo SN1 reactions most readily is C6H5CH2-I (Option 1), due to the superior leaving group ability of the benzenesulfonate anion.

160

In the following reaction :  

'P' could be

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Allylic Substitution and Solvolysis (SN1)   

  • The given reactant is an allylic halide because the Br atom is attached to a carbon atom which is directly bonded to an sp2 carbon of a double bond.
  • Allylic halides readily undergo solvolysis (substitution where the solvent acts as the nucleophile) to form a resonance-stabilized allylic carbocation intermediate. The reaction proceeds via an SN1 mechanism.
  • The Me OH (Methanol) acts as a polar protic solvent and a weak nucleophile.
  • The initial step is the loss of the leaving group (Br-) to form the resonance-stabilized allylic carbocation.
  • The allylic carbocation has two resonance structures, meaning the positive charge is delocalized over two different carbon atoms.
  • Nucleophilic attack (Me OH) can occur at either of the two electropositive centers, leading to different substitution products.

EXPLANATION:   

  • Step 1: Ionization and Allylic Carbocation Formation                                 
  • The Br leaving group departs from the starting material.
  • This generates a resonance-stabilized allylic carbocation.
  • Step 2: Nucleophilic Attack by Me OH                        
  • The Me OH nucleophile can attack at the original position (C-4) forms a product where the OMe group is at the same carbon as the original Br

Therefore, P could be the product shown in option 1.

161

Which of these compounds is least acidic ?

  1. ((a))

    Carbolic acid

  2. ((b))

    Oxalic acid

  3. ((c))

    Phthalic acid

  4. ((d))

    Picric acid

Show Answer
Answer: ((a))

Carbolic acid

CONCEPT:

Acidity of Compounds

  • The acidity of a compound depends on its ability to donate a proton (H+) and the stability of the conjugate base formed after the proton is donated.
  • Factors that influence acidity include:
  • Resonance stabilization of the conjugate base.
  • Inductive effects due to electronegative groups or atoms attached to the compound.
  • Presence of electron-withdrawing groups that increase the acidity by stabilizing the conjugate base.

EXPLANATION:

  • The compounds provided are:

  • Carbolic acid (phenol) is a weakly acidic compound as the phenoxide ion (conjugate base) is only moderately stabilized by resonance.

:

  • Oxalic acid is a dicarboxylic acid that is strongly acidic due to the presence of two carboxylic groups, which are electron-withdrawing and stabilize the conjugate base effectively.

  • Phthalic acid is also a dicarboxylic acid, similar to oxalic acid, that exhibits strong acidity due to resonance and inductive effects.

  • Picric acid is a highly acidic compound due to the presence of nitro groups, which are strong electron-withdrawing groups, stabilizing the conjugate base through resonance and inductive effects.
  • Among the given compounds, carbolic acid (phenol) is the least acidic because:
  • It lacks strong electron-withdrawing groups compared to the other compounds.
  • The conjugate base (phenoxide ion) is less stabilized compared to the conjugate bases of oxalic acid, phthalic acid, or picric acid.

Therefore, the compound that is least acidic is Carbolic acid (Phenol).

162

Which of these has the shortest C-CI bond length ?

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((b))

CONCEPT:

Carbon-Halogen (C-Cl) Bond Length

  • The length of a covalent bond is primarily determined by the hybridization state of the carbon atom and the bond order between the atoms.
  • Hybridization Effect: The bond length decreases as the s-character of the hybrid orbital increases: sp < sp2 < sp3.                    
  • sp3 (≈ 25%, s-character) → Longest bond.
  • sp2 (≈ 33%, s-character) → Shorter bond.
  • Resonance Effect (Partial Double Bond Character): If the halogen atom's lone pair of electrons can participate in resonance with an adjacent system (like a benzene ring), the C-Cl bond acquires a partial double bond character.                    
  • A single bond is longer than a double bond. Therefore, partial double bond character significantly shortens the bond length.

EXPLANATION:                       

  • The C-Cl carbon is sp3 hybridized. The Cl is not directly attached to the ring, preventing resonance. It has a single bond character. (Long bond)

  • The C-Cl carbon is sp2 hybridized. More importantly, the Cl atom's lone pair is directly conjugated with the benzene ring, leading to a significant partial double bond character in the C-Cl bond. This effect is very strong and results in the shortest bond length among the choices.

  • The C-Cl carbon (CH2Cl) is sp3 hybridized. The chlorine is attached to an alkyl carbon (C), not the aromatic ring. While the resulting carbocation is stabilized if the Cl leaves, the original C-Cl bond does not have resonance stabilization. It has a single bond character. (Long bond)
  • The C-Cl carbon (CH2Cl) is sp3 hybridized. The Cl atom is too far from the benzene ring (CH2CH2) for its lone pair to participate in resonance. It has a single bond character. (Long bond)
  • The C-Cl bond in Chlorobenzene is the only one with partial double bond character due to resonance, which makes it the shortest bond length.

Therefore, Chlorobenzene (Option 2) has the shortest C-Cl bond length.

163

The dehydration product 'X' of the given compound 

is:

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Dehydration of Alcohols

  • Dehydration of alcohols involves the elimination of a water molecule from the alcohol molecule, resulting in the formation of an alkene.
  • This reaction is typically carried out in the presence of an acid catalyst, such as concentrated sulfuric acid (H2SO4) or phosphoric acid (H3PO4), and heat.
  • In the dehydration process, the -OH group is removed from one carbon atom, and a hydrogen atom is removed from an adjacent carbon atom (β-carbon), leading to the formation of a double bond (C=C).
  • When more than one alkene can be formed, the product follows Zaitsev's rule, which states that the more substituted alkene (having more alkyl groups attached to the double bond) is the major product.

EXPLANATION:

  • In the given compound, dehydration occurs in the presence of an acid catalyst and heat.
  • The mechanism involves three main steps:
  1. Protonation of the -OH group: The acid donates a proton (H+) to the hydroxyl (-OH) group, converting it into a better leaving group (H2O).
  2. Loss of water: The protonated alcohol loses a water molecule, forming a carbocation intermediate.
  3. Formation of the double bond: A hydrogen atom is removed from a β-carbon (adjacent carbon), leading to the formation of a double bond and the alkene product.
  • In this reaction, if multiple β-carbons are available, Zaitsev's rule is applied, and the more substituted alkene is the major product.

The dehydration product of the given compound is Option 1, as it follows Zaitsev's rule and forms the more substituted alkene.

164

The product of the acid catalysed hydration of 2-phenyl propene is:

  1. ((a))

    3 phenyl propan-2-ol

  2. ((b))

    2-phenyl propan-2-ol

  3. ((c))

    1-phenyl propan-2-ol 

  4. ((d))

    2-phenyl propan-1-ol

Show Answer
Answer: ((b))

2-phenyl propan-2-ol

CONCEPT:

Acid Catalysed Hydration of Alkenes

  • Acid-catalysed hydration is a reaction where water adds to an alkene in the presence of an acid catalyst (e.g., H2SO4).
  • The reaction follows Markovnikov's rule, which states that the hydrogen from water adds to the carbon in the double bond with the greater number of hydrogen atoms, while the hydroxyl group (-OH) adds to the carbon with fewer hydrogen atoms.
  • The intermediate formed is a carbocation, and the stability of the carbocation determines the final product.

EXPLANATION:

  • Acid-catalysed hydration:
  • The double bond undergoes electrophilic addition in the presence of an acid catalyst.
  • According to Markovnikov's rule, the hydroxyl group (-OH) adds to the carbon atom with fewer hydrogen atoms, while the hydrogen adds to the carbon atom with more hydrogen atoms.
  • The intermediate formed is a carbocation. In this case, the secondary carbocation (CH3-C+(OH)-CH3) is formed, which is more stable due to hyperconjugation and inductive effects.
  • The final product is 2-phenyl propan-2-ol (C6H5-CH(OH)-CH3).

Answer: 2) 2-phenyl propan-2-ol

165

Which of the following compounds will not undergo nucleophilic attack by a hydroxyl group?

  1. ((a))

    Ethyl benzoate

  2. ((b))

    Diethyl ether

  3. ((c))

    Acetonitrile

  4. ((d))

    Benzamide

Show Answer
Answer: ((b))

Diethyl ether

CONCEPT:

Nucleophilic Attack

  • A nucleophilic attack involves the donation of a pair of electrons from a nucleophile (such as a hydroxyl group, OH-) to an electrophile.
  • The ability of a compound to undergo a nucleophilic attack depends on the presence of an electrophilic center, typically a carbon atom with a partial positive charge.
  • Electrophilic centers are often present in compounds with polar bonds, such as carbonyl groups (C=O), or in compounds with electron-deficient atoms.

EXPLANATION:

  • Examining the given compounds:
  • Ethyl benzoate: Contains a carbonyl group (C=O) in its ester functional group, which is an electrophilic center. It can undergo nucleophilic attack.
  • Diethyl ether: Contains an ether (C-O-C) group, but the oxygen atom is not directly bonded to a carbonyl group or an electrophilic center. Therefore, it does not undergo nucleophilic attack.
  • Acetonitrile: Contains a nitrile group (-C≡N), which has an electrophilic carbon atom. It can undergo nucleophilic attack.
  • Benzamide: Contains a carbonyl group (C=O) in its amide functional group, which is an electrophilic center. It can undergo nucleophilic attack.
  • Based on the analysis, Diethyl ether does not undergo nucleophilic attack by a hydroxyl group as it lacks an electrophilic center.

Answer: Option 2) Diethyl ether

166

Which of the following is the strongest base ?  

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((b))

CONCEPT:

Relative Basicity and Acidity 

  • Basicity is the tendency of a species to donate an electron pair. For anions (A-), the basicity is directly related to the stability of its conjugate acid (HA).
  • Relationship: The stronger the base (A-), the weaker is its conjugate acid (HA), and vice versa.
  • Stability of Conjugate Base (Anion): Factors that stabilize an anion (like electron-withdrawing groups) make the parent compound a stronger acid and the anion a weaker base. Factors that destabilize the anion (like electron-donating groups) make the parent compound a weaker acid and the anion a stronger base.
  • Substituent Effects on Phenoxides: The given options are substituted phenoxide ions (Ar-O-). The stability of the phenoxide ion is affected by groups substituted on the benzene ring, primarily at the ortho and para positions:                   
  • Electron-Withdrawing Groups (EWG): Stabilize the negative charge (by resonance or induction), making the phenoxide ion less basic. Example: NO2.
  • Electron-Donating Groups (EDG): Destabilize the negative charge (by increasing electron density), making the phenoxide ion more basic. Example: OCH3 or CH3.

EXPLANATION:  

  • Strongest base means the least stable phenoxide ion. The least stable ion is the one with the strongest Electron-Donating Group (EDG).
  • The NO2 group is a strong EWG (-R effect), stabilizing the anion significantly. This is the weakest base.
  • The OCH3 (methoxy) group is a strong EDG by resonance (+R effect), which strongly destabilizes the negative charge on the oxygen by pushing electrons into the ring and towards the -O site.                    
  • The +R effect of OCH3 is much stronger than the weak +I effect of CH3.
  • Destabilization → Highest basicity.
  • The CH3 group is a weak EDG (+I and hyperconjugation), which slightly destabilizes the anion, making it a stronger base than phenoxide.
  • This is the unsubstituted parent compound, serving as the baseline.
  • Basicity Order: p-methoxy > p-methyl > unsubstituted > p-nitro.

Therefore, the p-methoxyphenoxide ion (Option 2) is the least stable conjugate base due to the strong +R effect of the methoxy group, making it the strongest base.

167

Which of the these reactions is used to step up the number of carbons in the chain?

  1. ((a))

    Hofmann-Bromamide reaction.

  2. ((b))

    Hydroboration-oxidation.

  3. ((c))

    Stephen reaction.

  4. ((d))

    Gatterman- Koch reaction.

Show Answer
Answer: ((d))

Gatterman- Koch reaction.

CONCEPT:

Step-up Reaction for Carbon Chain Length

  • To increase the number of carbon atoms in a carbon chain, specific reactions are employed in organic chemistry.
  • These reactions typically involve the addition of carbon-based groups or the extension of the existing carbon chain.
  • Among the options provided, the Gatterman-Koch reaction is specifically used to increase the carbon chain length by introducing a formyl group (-CHO).

EXPLANATION:

  • The Gatterman-Koch reaction is a chemical reaction where benzene or its derivatives react with carbon monoxide (CO) and hydrogen chloride (HCl) in the presence of a Lewis acid catalyst, typically aluminum chloride (AlCl3).
  • The reaction introduces a formyl group (-CHO) to the aromatic ring, effectively increasing the number of carbon atoms in the chain.
  • The general reaction can be represented as:
  • This reaction is widely used in organic synthesis to step up the carbon chain length by one carbon atom.

Other options explained:

  • 1) Hofmann-Bromamide reaction: This reaction is used for the conversion of amides to amines with one less carbon atom.
  • 2) Hydroboration-oxidation: This reaction is used for the anti-Markovnikov hydration of alkenes, but it does not increase the carbon chain length.
  • 3) Stephen reaction: This is used to convert nitriles to aldehydes but does not step up the carbon chain length.

Correct Answer: 4) Gatterman-Koch reaction.

168

Consider the following reaction:

'P' is:

  1. ((a))

    CH3CH3

  2. ((b))

    CH3CH2OH

  3. ((c))

    CH3CHO

  4. ((d))

    CH3CH2Cl

Show Answer
Answer: ((c))

CH3CHO

CONCEPT:

Rosenmund Reduction  

  • The Rosenmund reduction is a specific catalytic hydrogenation reaction used for the conversion of acyl chlorides (acid chlorides, RCOCl) into aldehydes (RCHO).
  • Reagents: The reaction uses hydrogen gas (H2) over a palladium (Pd) catalyst supported on barium sulphate (BaSO4).           
  • RCOCl + H2 Pd/BaSO4\xrightarrow{Pd/BaSO_4} RCHO + HCl
  • Poisoning: The palladium catalyst is deliberately poisoned by the addition of substances like barium sulphate, or sometimes sulphur or quinoline.
  • Purpose of Poisoning: This poisoning reduces the activity of the palladium catalyst, preventing the aldehyde product (RCHO) from being further reduced to the corresponding primary alcohol (RCH2OH), which would happen if an unpoisoned catalyst were used. This ensures the aldehyde is the final product.
  • Limitation: This reaction is not suitable for preparing ketones, as it is an aldehyde synthesis, nor for reducing the carbonyl group in ketones or esters.

EXPLANATION:​        

Therefore, the product 'P' is CH3CHO (Acetaldehyde), making Option 3 the correct answer.

169

The reaction of benzaldehyde with semicarbazide hydrochloride is an example of :

  1. ((a))

    Nucleophilic substitution reaction.

  2. ((b))

    Nucleophilic addition reaction.

  3. ((c))

    Elimination reaction.

  4. ((d))

    Electrophilic addition followed by elimination.

Show Answer
Answer: ((b))

Nucleophilic addition reaction.

CONCEPT:

Reaction of benzaldehyde with semicarbazide hydrochloride

  • The reaction involves the addition of semicarbazide to benzaldehyde, forming a semicarbazone derivative.
  • Benzaldehyde contains a carbonyl group (-CHO), which is an electrophilic center.
  • Semicarbazide acts as a nucleophile due to the presence of the -NH2 group.
  • The reaction occurs via nucleophilic addition where the nucleophile attacks the electrophilic carbon of the carbonyl group.

EXPLANATION:

  • In the reaction: Benzaldehyde reacts with semicarbazide hydrochloride to form benzaldehyde semicarbazone.
  • Mechanism:
  • The nucleophilic -NH2 group in semicarbazide attacks the carbonyl carbon of benzaldehyde.
  • This leads to the formation of an intermediate where the oxygen in the carbonyl group is protonated.
  • Subsequent elimination of water occurs, resulting in the formation of a double bond between the carbon and nitrogen, yielding semicarbazone.
  • Since the reaction involves the addition of a nucleophile to the electrophilic carbonyl group, it is classified as a nucleophilic addition reaction(Option 2).
170

In the given sequence of reactions:

'B' is

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Grignard Reagent (RMgX)   

  • Grignard reagents (RMgX, where R is an alkyl or aryl group and X is a halogen) are highly versatile organometallic reagents. They are formed by reacting an alkyl or aryl halide (R-X) with magnesium (Mg) metal in dry ether.           
  • R-X + Mg Dry Ether\xrightarrow{Dry\ Ether} RMgX
  • The key feature is the highly nucleophilic carbon atom in the R group, which attacks electrophilic centers like the carbonyl carbon (C=O).
  • Reaction with Esters: Esters (R'COOR'') react with Grignard reagents in a two-step process to form tertiary alcohols after hydrolysis:                    
  1. First equivalent: The Grignard reagent attacks the carbonyl carbon (C=O), and the leaving group (OR'') is expelled, forming a ketone (R'COR).
  2. Second equivalent (if excess is used): The highly reactive ketone intermediate immediately reacts with a second molecule of the Grignard reagent.
  3. Final step (Hydrolysis): The resulting intermediate is protonated with acid (H3O+) to yield the final tertiary alcohol.

EXPLANATION:

Therefore, the chemically expected product B from the reaction of the ester with C2H5MgBr is the tertiary alcohol, 3-methylpentan-3-ol (Option 1).

171

Assertion (A) : Aromatic aldehydes do not respond to Fehling's reagent test.

Reason (R) : Aromatic aldehydes are not easily oxidized.

  1. ((a))

    (A) and (R) both are correct and (R) is the correct explaination of (A). 

  2. ((b))

    (A) and (R) both are correct but (R) is not the correct explaination of (A). 

  3. ((c))

    (A) is correct but (R) is wrong.

  4. ((d))

    (A) is wrong but (R) is correct.

Show Answer
Answer: ((a))

(A) and (R) both are correct and (R) is the correct explaination of (A). 

CONCEPT:

Fehling’s Test and Aromatic Aldehydes

  • Fehling’s test is a chemical test used to differentiate between aldehydes and ketones. It is specifically useful for identifying aliphatic aldehydes.
  • Fehling’s solution contains copper(II) ions complexed with tartrate ions in an alkaline medium. Aliphatic aldehydes reduce copper(II) ions to copper(I) oxide, forming a reddish precipitate.
  • Aromatic aldehydes, on the other hand, do not give a positive Fehling’s test because they are less reactive toward oxidation compared to aliphatic aldehydes.

EXPLANATION

  • Assertion (A): Aromatic aldehydes do not respond to Fehling's reagent test.                         
  • This statement is Correct according to standard chemical principles. Aromatic aldehydes like benzaldehyde do not react with the weak Cu2+ reagent.
  • Reason (R): Aromatic aldehydes are not easily oxidized.                    
  • This statement is Correct. Due to resonance with the aromatic ring, the aldehyde functional group in aromatic compounds is stabilized and is less readily oxidized than in aliphatic aldehydes.
  • Evaluation: Both Assertion (A) and Reason (R) are chemically correct. Furthermore, the Reason (R) correctly explains why the Assertion (A) is true: the negative test result is because the aromatic aldehydes are not easily oxidized by the weak Fehling's reagent.

Therefore, the correct answer is (A) and (R) both are correct and (R) is the correct explaination of (A).

172

The number of ether isomers possible for a compound with molecular formula C4H10O would be:

  1. ((a))

    2

  2. ((b))

    3

  3. ((c))

    4

  4. ((d))

    5

Show Answer
Answer: ((b))

3

CONCEPT:

Ether Isomers

  • Isomers are compounds with the same molecular formula but different structural arrangements.
  • Ethers are a type of organic compound where an oxygen atom is bonded to two alkyl or aryl groups (R-O-R').
  • In the case of the molecular formula C4H10O, the isomers are ethers with different structural arrangements of the carbon chains.

EXPLANATION:

  • The molecular formula C4H10O corresponds to ethers with four carbon atoms and one oxygen atom.
  • Possible arrangements of the carbon chains lead to different ether isomers:
    1. Methoxypropane (CH3-O-CH2CH2CH3)
    1. Ethoxyethane (CH3CH2-O-CH2CH3)
    1. 2-Methoxypropane (CH3-O-CH(CH3)2)

Therefore, a total of 3 ether isomers are possible for C4H10O.

173

An organic compound has the molecular formula C4H11N. The number of isomers which will give a positive carbylamine test would be:

  1. ((a))

    2

  2. ((b))

    3

  3. ((c))

    4

  4. ((d))

    5

Show Answer
Answer: ((c))

4

CONCEPT:

Carbylamine Reaction Test

  • The carbylamine test is a chemical test used to identify primary amines.
  • Primary amines react with chloroform (CHCl3) and alcoholic potassium hydroxide (KOH) to form isocyanides (carbylamines), which have a foul odor.
  • Secondary and tertiary amines do not give a positive carbylamine test.
  • The general reaction for the carbylamine test is:
  • R-NH2 + CHCl3 + 3KOH → R-NC + 3KCl + 3H2O

EXPLANATION:     

  • The molecular formula is C4H11N. The general formula for saturated aliphatic amines is CnH2n+3N. For n=4, 2n+3 = 11, confirming the structure is saturated.
  • Possible primary amines are:                    
  1. Butan-1-amine: (CH3CH2CH2CH2NH2). The amine group is on the end of a straight chain.
  2. Butan-2-amine: (CH3CH2CH(NH2)CH3). The amine group is on the second carbon of a straight chain. This isomer is chiral (has an asymmetric carbon) and exists as a pair of enantiomers, but we typically count the structural isomer itself.
  3. 2-methylpropan-1-amine: ((CH3)2CHCH2NH2). The amine group is on the end of a branched chain (isobutane skeleton).
  4. 2-methylpropan-2-amine: (CH3C(CH3)(NH2)CH3). The amine group is on the central, tertiary carbon of the branched chain.
  • All four of these isomers are 1o amines (R-NH2).
  • The other possible isomers are 2o amines (R2NH) and 3o amines (R3N), which do not give a positive Carbylamine test:                    
  • 2o amines (3 isomers): N-methylpropan-1-amine, N-methylpropan-2-amine, N-ethylethanamine (diethylamine).
  • 3o amine (1 isomer): N,N-dimethylethanamine.
  • Since only the primary amines give a positive Carbylamine test, and there are 4 primary amine isomers of C4H11N, the number of isomers which will give a positive test is 4.

Therefore, the number of isomers of C4H11N which will give a positive carbylamine test is 4.

174

Consider the following reaction:

'A' could be :

  1. ((a))

    Aniline

  2. ((b))

    N.N-diethyl amine

  3. ((c))

    N-Methyl methanamine 

  4. ((d))

    Methanamine

Show Answer
Answer: ((d))

Methanamine

CONCEPT:

Hinsberg's Test for Amines

  • Hinsberg's Test is a chemical reaction used to distinguish between primary (1o), secondary (2o), and tertiary (3o) amines.
  • Reagent: The reagent used is Benzene sulphonyl chloride (often called Hinsberg's reagent), which is the compound shown: C6H5SO2Cl.
  • Reaction Principle: Amines react with the sulphonyl chloride reagent via nucleophilic substitution, where the amine nitrogen attacks the sulphur atom, forming a sulphonamide.
  • Outcome for different amines: 
  • Primary (R-NH2): Forms an N-alkyl benzene sulphonamide, which has an N-H bond. The N-H proton is acidic, so the sulphonamide product is soluble in aqueous KOH (NaOH).
  • Secondary (R2NH): Forms an N,N-dialkyl benzene sulphonamide. This product has no N-H bond (the nitrogen is fully substituted), so it is insoluble in aqueous KOH (NaOH).
  • Tertiary (R3N): Does not react with the sulphonyl chloride as it has no proton on the nitrogen to be removed as HCl during the substitution.

EXPLANATION:

  • The reaction product is given as N-alkyl benzene sulphonamide. The structure of this product is C6H5SO2NHR.
  • For the product to be an N-alkyl benzene sulphonamide (with one N-H bond), the reacting amine (A) must have contributed one alkyl/aryl group (R) and two hydrogen atoms (H) to the nitrogen atom (N).
  • Therefore, amine A must be a primary amine (R-NH2).                   
  • Aniline (C6H5NH2): This is a primary amine. It would form N-phenyl benzene sulphonamide. (An N-aryl sulphonamide).
  • Option 2: N,N-diethyl amine (C2H5)2NH): This is a secondary amine. It would form N,N-diethyl benzene sulphonamide (a product without an N-H bond).
  • N-Methyl methanamine (CH3NHCH3): CH3NHCH3 (dimethylamine) is a secondary amine.
  • Methanamine (CH3NH2): This is a primary amine. It would form N-methyl benzene sulphonamide.

Therefore, Methanamine(Option 4) will form N- alkyl benzene sulphonamide.

175

Which of these amines can be prepared by Gabriel phthalimide synthesis ? 

  1. ((a))

  2. ((b))

  3. ((c))

  4. ((d))

Show Answer
Answer: ((a))

CONCEPT:

Gabriel Phthalimide Synthesis

  • Gabriel phthalimide synthesis is a chemical reaction used to prepare primary amines.
  • In this method, phthalimide reacts with alkyl halides to form N-alkylphthalimide, which is then hydrolyzed to yield the primary amine.
  • It is important to note that this synthesis is specific for preparing primary amines and cannot be used to synthesize secondary or tertiary amines.

EXPLANATION:

  • Gabriel synthesis involves the reaction of phthalimide with alkyl halides. The alkyl halide must contain a primary alkyl group for the synthesis to proceed successfully.
  • Gabriel Phthalimide Synthesis Mechanism - Testbook
  • Secondary or tertiary alkyl halides are not suitable as they lead to side reactions or steric hindrance, making the reaction inefficient.
  • Among the given options:

  • This represents a primary amine which can be prepared using Gabriel synthesis.

  • This represents a secondary amine, which cannot be synthesized using Gabriel synthesis.

  • This represents a tertiary amine, which also cannot be synthesized using Gabriel synthesis.

  • This represents a tertiary amine, which also cannot be synthesized using Gabriel synthesis.

Therefore, options 1 can be prepared by Gabriel phthalimide synthesis.

176

Maltose has linkage between :

  1. ((a))

    C1 of α-Glucose and C4 of β-Glucose

  2. ((b))

    C1 of β-Glucose and C4 of β-Glucose.

  3. ((c))

    C1 of α- Glucose and C4 of α- Glucose

  4. ((d))

    C1 of α-Glucose and C2 of β-Glucose.

Show Answer
Answer: ((c))

C1 of α- Glucose and C4 of α- Glucose

CONCEPT:

Maltose and its Glycosidic Linkage

  • Maltose is a disaccharide composed of two glucose molecules connected by a glycosidic bond.
  • The glycosidic bond is formed between the C1 carbon of one glucose molecule and the C4 carbon of the second glucose molecule.
  • In maltose, the first glucose molecule is in the alpha (α) configuration, while the second glucose molecule is also in the alpha (α) configuration.
  • Thus, maltose contains an α(1→4) glycosidic bond.

EXPLANATION:

  • Maltose is formed by the condensation of two alpha-glucose molecules.
  • In this process:
  • The hydroxyl group (-OH) on the C1 carbon of one alpha-glucose molecule reacts with the hydroxyl group on the C4 carbon of another alpha-glucose molecule.
  • This reaction results in the release of a water molecule (dehydration reaction) and the formation of an α(1→4) glycosidic bond.
  • Maltose Formula: Know Structure, Properties, Preparation & Uses
  • Maltose is formed by a glycosidic bond between the C1 of α-Glucose and the C4 of another α-Glucose molecule.

Therefore, the correct answer is Option 3: C1 of α-Glucose and C4 of α-Glucose.

177

Which of these is a constituent of the cell wall of plant cells?

  1. ((a))

    Nucleotides

  2. ((b))

    Proteins

  3. ((c))

    Cellulose

  4. ((d))

    Starch

Show Answer
Answer: ((c))

Cellulose

CONCEPT:

Cell Wall Composition in Plant Cells

  • The cell wall is a structural layer surrounding the cell membrane in plant cells, providing mechanical support and protection.
  • It is primarily composed of cellulose, a polysaccharide made up of glucose units.
  • Cellulose is arranged in microfibrils, which provide strength and rigidity to the plant cell walls.
  • Other components such as hemicellulose, pectin, and lignin may also be present, but cellulose is the main constituent.

EXPLANATION:

  • Among the given options:
  • Nucleotides are building blocks of nucleic acids (DNA and RNA) and are not part of the cell wall.
  • Proteins may be present in small amounts in the cell wall but are not the primary constituent.
  • Cellulose is the main component of plant cell walls.
  • Starch is a storage carbohydrate found in plant cells but does not form part of the cell wall structure.

Therefore, the correct answer is Option 3: Cellulose.

178

Which of these amino acids does not have any chiral centres?

  1. ((a))

    Lysine

  2. ((b))

    Cysteine

  3. ((c))

    Glycine

  4. ((d))

    Tyrosine

Show Answer
Answer: ((c))

Glycine

CONCEPT:

Chirality in Amino Acids

  • An amino acid is considered chiral if it has at least one carbon atom bonded to four different groups.
  • Chirality arises due to asymmetry in the molecule, making it non-superimposable on its mirror image.
  • Most amino acids are chiral because the alpha carbon (central carbon) is attached to four different groups: an amino group (-NH2), a carboxyl group (-COOH), a hydrogen atom (-H), and a unique side chain (R-group).
  • However, glycine is an exception because its side chain (R-group) is a hydrogen atom, making the alpha carbon bonded to only three unique groups and hence achiral.

EXPLANATION:

  • Among the given amino acids:
  • Lysine: Has a chiral alpha carbon due to its unique side chain (-CH2-CH2-CH2-NH2).
  • Cysteine: Has a chiral alpha carbon due to its unique side chain (-CH2-SH).
  • Glycine: Does not have a chiral center because its side chain is a hydrogen atom (-H), making the alpha carbon bonded to two identical groups (hydrogen atoms).
  • Tyrosine: Has a chiral alpha carbon due to its unique side chain (-CH2-C6H4-OH).
  • Since chirality depends on having four different groups attached to the central carbon, glycine is the only amino acid in the given options that lacks a chiral center.

Therefore, the correct answer is: Option 3 - Glycine.

179

Which is NOT an essential amino acid?

  1. ((a))

    Aspartic acid

  2. ((b))

    Lysine

  3. ((c))

    Arginine

  4. ((d))

    Methionine

Show Answer
Answer: ((a))

Aspartic acid

CONCEPT:

Essential Amino Acids

  • Essential amino acids are those that cannot be synthesized by the human body and must be obtained through the diet.
  • There are nine essential amino acids: Histidine, Isoleucine, Leucine, Lysine, Methionine, Phenylalanine, Threonine, Tryptophan, and Valine.
  • Non-essential amino acids, on the other hand, can be synthesized by the body from other compounds.

EXPLANATION:

  1. Aspartic acid is a non-essential amino acid because it can be synthesized by the human body.
  2. Lysine is an essential amino acid, as it cannot be synthesized and must be obtained from the diet.
  3. Arginine is considered a conditionally essential amino acid, meaning it is essential under certain conditions, such as in infants or during illness.
  4. Methionine is one of the nine essential amino acids required in the human diet.

Therefore, Aspartic acid is not an essential amino acid.

180

RNA does not contain:

  1. ((a))

    Adenine

  2. ((b))

    Guanine

  3. ((c))

    Uracil

  4. ((d))

    Thymine

Show Answer
Answer: ((d))

Thymine

CONCEPT:

RNA Composition

  • RNA (Ribonucleic Acid) is a molecule essential for various biological processes, including protein synthesis and gene regulation.
  • RNA is composed of four nitrogenous bases: Adenine (A), Guanine (G), Cytosine (C), and Uracil (U).
  • Unlike DNA, RNA contains Uracil instead of Thymine.
  • Thymine is exclusive to DNA and is replaced by Uracil in RNA molecules.

EXPLANATION:

  • RNA contains the bases Adenine, Guanine, Cytosine, and Uracil.
  • Thymine is absent in RNA because Uracil takes its place.
  • Uracil forms complementary base pairs with Adenine in RNA, similar to how Thymine pairs with Adenine in DNA.

Therefore, the correct answer is: Option 4) Thymine.

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