Official Paper

RRB Clerk Prelims Memory Based Paper (Held On: 17 August 2024 Shift 1) (Previous Year Paper)

80 questions · 45 minutes · with answers · free

Reasoning (40 questions)

Six people live in a three storey building. The ground floor is numbered 1 and the floor above it numbered 2 and so on. Each floor consists of two flats i.e. Flat X and Flat Y. Flat X of floor 2 is just above Flat X of floor 1 and just below Flat X of floor 3. Flat X is in the west of Flat Y. S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different Flat. T and V live on the same floor. Q lives to the southeast of V. Only one person lives between P and S in the same Flat. R does not live on the floor where S lives.

Who lives adjacent to R in the same flat?

((a))
V
((b))
T
((c))
P
((d))
S
((e))
None of these

Show Answer

Answer: ((b))

From the given instructions:

Floor	Flat X	Flat Y
3
2
1

S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different building. Only one person lives between P and S in the same building. So, here we have two cases,

Case 1:

Floor	Flat X	Flat Y
3	P
2		T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2		T
1	P

T and V live on the same floor.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P

Q lives to the southeast of V.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S	Q

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P	Q

R does not live on the floor where S lives. So, here Case 2 gets eliminated.

So, Final Arrangement,

Floor	Flat X	Flat Y
3	P	R
2	V	T
1	S	Q

T lives adjacent to R in the same building.

How many people live below R in both flats?

((a))
Two
((b))
Three
((c))
Four
((d))
Five
((e))
None

Show Answer

Answer: ((c))

Four

From the given instructions:

Floor	Flat X	Flat Y
3
2
1

S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different building. Only one person lives between P and S in the same building. So, here we have two cases,

Case 1:

Floor	Flat X	Flat Y
3	P
2		T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2		T
1	P

T and V live on the same floor.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P

Q lives to the southeast of V.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S	Q

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P	Q

R does not live on the floor where S lives. So, here Case 2 gets eliminated.

So, Final Arrangement,

Floor	Flat X	Flat Y
3	P	R
2	V	T
1	S	Q

Four people live below R in both flats.

Who lives to the northwest of T?

((a))
P
((b))
S
((c))
V
((d))
Q
((e))
None

Show Answer

Answer: ((a))

From the given instructions:

Floor	Flat X	Flat Y
3
2
1

S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different building. Only one person lives between P and S in the same building. So, here we have two cases,

Case 1:

Floor	Flat X	Flat Y
3	P
2		T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2		T
1	P

T and V live on the same floor.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P

Q lives to the southeast of V.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S	Q

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P	Q

R does not live on the floor where S lives. So, here Case 2 gets eliminated.

So, Final Arrangement,

Floor	Flat X	Flat Y
3	P	R
2	V	T
1	S	Q

P lives to the northwest of T.

Find the odd one out.

((a))
P
((b))
Q
((c))
R
((d))
V
((e))
S

Show Answer

Answer: ((d))

From the given instructions:

Floor	Flat X	Flat Y
3
2
1

S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different building. Only one person lives between P and S in the same building. So, here we have two cases,

Case 1:

Floor	Flat X	Flat Y
3	P
2		T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2		T
1	P

T and V live on the same floor.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P

Q lives to the southeast of V.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S	Q

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P	Q

R does not live on the floor where S lives. So, here Case 2 gets eliminated.

So, Final Arrangement,

Floor	Flat X	Flat Y
3	P	R
2	V	T
1	S	Q

All other options live on odd number floor whereas, V lives on even numbered floor. So, V is the odd one out.

Who lives on floor floor 1 of Flat X?

((a))
P
((b))
S
((c))
T
((d))
Q
((e))
None of these

Show Answer

Answer: ((b))

From the given instructions:

Floor	Flat X	Flat Y
3
2
1

S, who lives in Flat X, lives adjacent to the floor where T lives, but in a different building. Only one person lives between P and S in the same building. So, here we have two cases,

Case 1:

Floor	Flat X	Flat Y
3	P
2		T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2		T
1	P

T and V live on the same floor.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P

Q lives to the southeast of V.

Case 1:

Floor	Flat X	Flat Y
3	P
2	V	T
1	S	Q

Case 2:

Floor	Flat X	Flat Y
3	S
2	V	T
1	P	Q

R does not live on the floor where S lives. So, here Case 2 gets eliminated.

So, Final Arrangement,

Floor	Flat X	Flat Y
3	P	R
2	V	T
1	S	Q

S lives on floor 1 of Flat X.

Directions: Study the following information carefully and answer the questions that follow:

Pavan starts walking from point T. He walks for 5km in the north direction from point T to reach point W. Then he turns towards the west and walks for 7km to reach point K. From point K he turns towards the South and walks for 10km to reach point H. From point H he turns towards the east and walks for 15km to reach point F. Then he turns towards the south and walks 5km to reach point G. Finally he turns towards the west and walks for 10km to reach the final point C.

Point W is in which direction with respect to point C?

((a))
North
((b))
South
((c))
Northeast
((d))
Northwest
((e))
West

Show Answer

Answer: ((c))

Northeast

According to the given information,

Northeast is the correct answer.

Point G is in which direction with respect to point H?

((a))
South
((b))
East
((c))
West
((d))
Southeast
((e))
Southwest

Show Answer

Answer: ((d))

Southeast

According to the given information,

Southeast is the correct answer.

What is the total distance covered by Pavan?

((a))
50 km
((b))
51 km
((c))
53 km
((d))
54 km
((e))
52 km

Show Answer

Answer: ((e))

52 km

According to the given information,

Total distance covered by Pavan = 5 + 7 + 10 + 15 + 5 + 10 = 52

52 km is the correct answer.

Study the following information carefully to answer the questions given below.

In a meeting, eight teachers A, B, C, D, E, F, G and H are sitting in two parallel rows, opposite to each other. Four persons with equal distance between them sit in each row. In row-1, A, B, D, E are sitting, and all are facing south. In row-2 C, F, H, G are sitting, and all are facing north.

G sits second to the right of H who sits opposite to the one who is an immediate neighbour of E. D does not sit to the extreme end of the row. C sits second to the right of F who sits opposite to A. F is not a neighbour of G. B sits second to the left of D.

Who sits opposite to D?

((a))
F
((b))
G
((c))
H
((d))
C
((e))
None of these

Show Answer

Answer: ((c))

People: A, B, C, D, E, F, G & H

D does not sit at the extreme end of the row.
B sits second to the left of D.
C sits second to the right of F who sits opposite to A.

G sits second to the right of H who sits opposite to the one who is an immediate neighbour of E.
Thus, the final arrangement is,

H sits opposite to D.

Who sits second to the right of E?

((a))
D
((b))
B
((c))
F
((d))
A
((e))
None of these

Show Answer

Answer: ((d))

People: A, B, C, D, E, F, G & H

D does not sit to the extreme end of the row.
B sits second to the left of D.
C sits second to the right of F who sits opposite A.

G sits second to the right of H, who sits opposite to the one who is an immediate neighbour of E.
Thus, the final arrangement is,

A sits second to the right of E.

Four of the following are alike in a certain way, then which of the following does not follow the same pattern?

((a))
B
((b))
E
((c))
A
((d))
F
((e))
G

Show Answer

Answer: ((b))

People: A, B, C, D, E, F, G & H

D does not sit at the extreme end of the row.
B sits second to the left of D.
C sits second to the right of F who sits opposite to A.

G sits second to the right of H who sits opposite to the one who is an immediate neighbour of E.
Thus, the final arrangement is,

Except for E, all others are sitting at corners.

E does not follow the same pattern.

Who sits opposite to E?

((a))
B
((b))
C
((c))
F
((d))
D
((e))
None of these

Show Answer

Answer: ((b))

People: A, B, C, D, E, F, G & H

D does not sit at the extreme end of the row.
B sits second to the left of D.
C sits second to the right of F who sits opposite to A.

G sits second to the right of H, who sits opposite to the one who is an immediate neighbour of E.
Thus, the final arrangement is,

C sits opposite to E.

Who is an immediate neighbour of F?

((a))
A
((b))
C
((c))
H
((d))
G
((e))
None of these

Show Answer

Answer: ((c))

People: A, B, C, D, E, F, G & H

D does not sit at the extreme end of the row.
B sits second to the left of D.
C sits second to the right of F who sits opposite to A.

G sits second to the right of H, who sits opposite to the one, who is an immediate neighbour of E.
Thus, the final arrangement is,

H is an immediate neighbour of F.

Directions: In the question below are given three statements followed by two conclusions. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statement:

I. All party are muffin

II. Only a few muffin are home

III. Some home are butterfly

Conclusion:

I. Some butterfly are party

II. All muffin are home is a possibility

((a))
Only conclusion I follows
((b))
Only conclusion II follows
((c))
Either conclusion I or II follows
((d))
Neither conclusion I nor II follows
((e))
Both conclusion I and II follows

Show Answer

Answer: ((d))

Neither conclusion I nor II follows

The least possible venn diagram for the given statements is:

Conclusion:

I. Some butterfly are party → False (It is possible but not definite, because no definite relation is given between the elements, therefore we will consider it as false)

II. All muffin are home is a possibility → False (As the relation of “only a few” is given between the elements which implies that “some” and “some not” are true, no other relationship is true except these two)

Neither conclusion I nor II follows.

Statement:

I. Some lobby is balcony

II. Some balcony are garage

III. Only a few lobby is market

Conclusion:

I. Some lobby are not market

II. Some garage being lobby is a possibility

((a))
Only conclusion I follows
((b))
Only conclusion II follows
((c))
Either conclusion I or II follows
((d))
Neither conclusion I nor II follows
((e))
Both conclusions I and II follows

Show Answer

Answer: ((e))

Both conclusions I and II follows

The least possible venn diagram for the given statements is:

Conclusions:

I. Some lobby are not market→ True (as relation of “only a few” is given between the elements which implies that “some” and “some not” both are true)

II. Some garage being lobby is a possibility → True (as no definite positive or negative relation is given between the elements)

Both conclusions I and II follows.

Direction: In the question below are given three statements followed by two conclusions numbered I, and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statements

A few carrots are radishes

Each radish is tomato

No radish is potato

Conclusions

I. All carrot being potato is a possibility

II. Some potato being tomato is a possibility

((a))
Only I follows
((b))
Only II follows
((c))
Both I and II follows
((d))
Either I or II follows
((e))
Neither I nor II follows

Show Answer

Answer: ((b))

Only II follows

Venn diagram for the given statements are as follows.

Conclusions:

I. All carrot being potato is a possibility - False (Because given A few carrots are radishes and No radish is potato thus the part of carrot which are radish can never be potato so All carrot being potato is a possibility is not followed)

II. Some potato being tomato is a possibility - True (Because given Each radish is tomato and No radish is potato thus the part of tomato which are not radish can be potato so Some potato being tomato is a possibility true)

Only II follows.

Direction: The following questions are based on the sequence of five three letter words.

DOG MAN HIS FOR TOY

If M is added at the end of each word, then how many of the new words formed are meaningful words?

((a))
One
((b))
Two
((c))
Three
((d))
More than three
((e))
None

Show Answer

Answer: ((a))

One

DOG MAN HIS FOR TOY

Adding M at the end of each word,

DOGM MANM HISM FORM TOYM

One meaningful word is formed.

If the first and second letter of each word are interchanged, then how many words will have letters which are in alphabetical orders?

((a))
One
((b))
Two
((c))
Three
((d))
Four
((e))
None

Show Answer

Answer: ((b))

Two

DOG MAN HIS FOR TOY

After interchaning first and second letter,

ODG AMN IHS OFR OTY

Two words have letters in alphabetical order.

Mistake Points

ODG AMN IHS OFR OTY

A =1, M = 13, N = 14 so this is dictionary or alphabetical order. Similarly OTY O = 15, T = 20, Y = 25

So both are in alphabetical order.

If the second letter in each word is changed to its succeeding letter as in the english alphabetical series, then how many of the new words formed will have more than one vowel?

((a))
Four
((b))
Three
((c))
One
((d))
None
((e))
More than three

Show Answer

Answer: ((d))

None

DOG MAN HIS FOR TOY

After changing the second letter of each word to its succeeding alphabet,

DPG MBN HJS FPR TPY

None of the words have any vowel.

If all the consonants are changed to its preceeding alphabet and all the vowels are changed to its succeeding alphabet ,then how many words will have one or more than one vowels in it?

((a))
One
((b))
Two
((c))
Three
((d))
None
((e))
More than three

Show Answer

Answer: ((a))

One

DOG MAN HIS FOR TOY

After changing all the consonants to preceeding alphabet and all vowel to its succeeding alphabet ,

CPF LBM GJR EPQ SPX

One word will have vowel.

How many letters are there between the second letter of second word from left and third letter of the second word from right in the alphabetical series?

((a))
17
((b))
15
((c))
16
((d))
11
((e))
10

Show Answer

Answer: ((c))

DOG MAN HIS FOR TOY

Second letter of second word from left - A

Third letter of second word from right - R

ABCDEFGHIJKLMNOPQR

16 letters are betwwen A and R.

In a word "PNEUMONIA", if all letters are arranged in the alphabetical order, and then the consonants are changed to the previous letter and the vowels are changed to the next letter as per the English alphabetical series, then how many letters repeat more than once?

((a))
Two
((b))
Three
((c))
Four
((d))
Five
((e))
One

Show Answer

Answer: ((e))

One

Given Word: PNEUMONIA

After arranging all letters of the given word in alphabetical order:

A E I M N N O P U

After changing all consonants to the previous letter and all vowels to the next letter as per the English alphabetical series:

B F J L M M P O V

One letter i.e. M is repeating more than once in the above arrangement.

How many such pairs of digits are there in the number ‘6358427’, each of which has as many digits between them in the number (both forward and backward direction) as they have between them in the Numeric Series?

((a))
None
((b))
One
((c))
Two
((d))
Three
((e))
More than three

Show Answer

Answer: ((b))

One

Only one such pair is there in the number ‘6358427’, each of which has as many digits between them in the number (both forward and backward direction) as they have between them in the Numeric Series.

Direction: Read the following information carefully and answer the given question

Seven persons Shivi, Navi, Pihu, Ravi, Rishi, Mahi and Juhi were born on different month viz March, April, May, June, July, August and September of the same year but not necessarily in the same order.

Only three persons were born before Mahi. Two persons born between Mahi and Ravi.Pihu was born in the month having 30 days. Two persons born between Pihu and Rishi.Juhi was born immediately after Navi.

Navi was born in which of the following month?

((a))
March
((b))
May
((c))
June
((d))
August
((e))
September

Show Answer

Answer: ((d))

August

Only three persons were born before Mahi.
Two persons born between Mahi and Ravi.
Pihu was born in the month having 30 days.

CASE 1	CASE 2	CASE 3
Month	Days	Name	Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi	March	31	Ravi
April	30	Pihu	April	30		April	30	Pihu
May	31		May	31		May	31
June	30	Mahi	June	30	Mahi	June	30	Mahi
July	31		July	31		July	31
August	31		August	31		August	31
September	30	Ravi	September	30	Pihu	September	30

Two persons born between Pihu and Rishi. (This eliminates case 2)

CASE 1	CASE 3
Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi
April	30	Pihu	April	30	Pihu
May	31		May	31
June	30	Mahi	June	30	Mahi
July	31	Rishi	July	31	Rishi
August	31		August	31
September	30	Ravi	September	30

Juhi was born immediately after Navi. (This eliminates case 1)

CASE 3
Month	Days	Name
March	31	Ravi
April	30	Pihu
May	31	Shivi
June	30	Mahi
July	31	Rishi
August	31	Navi
September	30	Juhi

Hence, Navi was born in August.

How many persons are born between Ravi and Rishi?

((a))
One
((b))
Two
((c))
Three
((d))
Four
((e))
None

Show Answer

Answer: ((c))

Three

Only three persons were born before Mahi.
Two persons born between Mahi and Ravi.
Pihu was born in the month having 30 days.

CASE 1	CASE 2	CASE 3
Month	Days	Name	Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi	March	31	Ravi
April	30	Pihu	April	30		April	30	Pihu
May	31		May	31		May	31
June	30	Mahi	June	30	Mahi	June	30	Mahi
July	31		July	31		July	31
August	31		August	31		August	31
September	30	Ravi	September	30	Pihu	September	30

Two persons born between Pihu and Rishi. (This eliminates case 2)

CASE 1	CASE 3
Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi
April	30	Pihu	April	30	Pihu
May	31		May	31
June	30	Mahi	June	30	Mahi
July	31	Rishi	July	31	Rishi
August	31		August	31
September	30	Ravi	September	30

Juhi was born immediately after Navi. (This eliminates case 1)

CASE 3
Month	Days	Name
March	31	Ravi
April	30	Pihu
May	31	Shivi
June	30	Mahi
July	31	Rishi
August	31	Navi
September	30	Juhi

Hence, three persons born between Ravi and Rishi.

The number of people born before Shivi is same as that of after _________?

((a))
Navi
((b))
Rishi
((c))
Mahi
((d))
Pihu
((e))
Ravi

Show Answer

Answer: ((b))

Rishi

Only three persons were born before Mahi.
Two persons born between Mahi and Ravi.
Pihu was born in the month having 30 days.

CASE 1	CASE 2	CASE 3
Month	Days	Name	Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi	March	31	Ravi
April	30	Pihu	April	30		April	30	Pihu
May	31		May	31		May	31
June	30	Mahi	June	30	Mahi	June	30	Mahi
July	31		July	31		July	31
August	31		August	31		August	31
September	30	Ravi	September	30	Pihu	September	30

Two persons born between Pihu and Rishi. (This eliminates case 2)

CASE 1	CASE 3
Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi
April	30	Pihu	April	30	Pihu
May	31		May	31
June	30	Mahi	June	30	Mahi
July	31	Rishi	July	31	Rishi
August	31		August	31
September	30	Ravi	September	30

Juhi was born immediately after Navi. (This eliminates case 1)

CASE 3
Month	Days	Name
March	31	Ravi
April	30	Pihu
May	31	Shivi
June	30	Mahi
July	31	Rishi
August	31	Navi
September	30	Juhi

Hence, the number of people born before Shivi is the same as that of after Rishi.

Four among the five are the same in some way and thus form a group. Who among the following does not belong to the group?

((a))
Pihu
((b))
Ravi
((c))
Shivi
((d))
Rishi
((e))
Navi

Show Answer

Answer: ((a))

Pihu

Only three persons were born before Mahi.
Two persons born between Mahi and Ravi.
Pihu was born in the month having 30 days.

CASE 1	CASE 2	CASE 3
Month	Days	Name	Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi	March	31	Ravi
April	30	Pihu	April	30		April	30	Pihu
May	31		May	31		May	31
June	30	Mahi	June	30	Mahi	June	30	Mahi
July	31		July	31		July	31
August	31		August	31		August	31
September	30	Ravi	September	30	Pihu	September	30

Two persons born between Pihu and Rishi. (This eliminates case 2)

CASE 1	CASE 3
Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi
April	30	Pihu	April	30	Pihu
May	31		May	31
June	30	Mahi	June	30	Mahi
July	31	Rishi	July	31	Rishi
August	31		August	31
September	30	Ravi	September	30

Juhi was born immediately after Navi. (This eliminates case 1)

CASE 3
Month	Days	Name
March	31	Ravi
April	30	Pihu
May	31	Shivi
June	30	Mahi
July	31	Rishi
August	31	Navi
September	30	Juhi

All of them born in the month which has 31 days except Pihu.

Hence, Pihu does not belong to the group.

What is true regarding Ravi?

((a))
No one born before Ravi
((b))
There is only one person born between Ravi and Shivi
((c))
Ravi was born after Pihu
((d))
Both 2) and 3)
((e))
Both 1) and 2)

Show Answer

Answer: ((e))

Both 1) and 2)

Only three persons were born before Mahi.
Two persons born between Mahi and Ravi.
Pihu was born in the month having 30 days.

CASE 1	CASE 2	CASE 3
Month	Days	Name	Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi	March	31	Ravi
April	30	Pihu	April	30		April	30	Pihu
May	31		May	31		May	31
June	30	Mahi	June	30	Mahi	June	30	Mahi
July	31		July	31		July	31
August	31		August	31		August	31
September	30	Ravi	September	30	Pihu	September	30

Two persons born between Pihu and Rishi. (This eliminates case 2)

CASE 1	CASE 3
Month	Days	Name	Month	Days	Name
March	31		March	31	Ravi
April	30	Pihu	April	30	Pihu
May	31		May	31
June	30	Mahi	June	30	Mahi
July	31	Rishi	July	31	Rishi
August	31		August	31
September	30	Ravi	September	30

Juhi was born immediately after Navi. (This eliminates case 1)

CASE 3
Month	Days	Name
March	31	Ravi
April	30	Pihu
May	31	Shivi
June	30	Mahi
July	31	Rishi
August	31	Navi
September	30	Juhi

Hence, Both 1) and 2) are true.

Direction: In the following question assuming the given statements to be true, find which of the conclusion among given some conclusion is/are definitely true and then give your answers accordingly:

Statements:

A ≤ B < C < D ≥ E ≥ F < G

Conclusions:

I. A < D

II. F ≤ D

((a))
Only I follow
((b))
Only II follow
((c))
Both I and II follow
((d))
Either I or II follow
((e))
Neither I nor II follow

Show Answer

Answer: ((c))

Both I and II follow

Given statements:

A ≤ B < C < D ≥ E ≥ F < G

Conclusions:

I. A < D → True (A ≤ B < C < D)

II. F ≤ D → True (F ≤ E ≤ D)

Both I and II follow is the correct answer.

Directions: In the following question assuming the given statements to be True, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements: - Y = K ≥ V ≤G = C

Conclusions:-

a. K ≤ G

b. K > G

((a))
Only Conclusion (a) follows
((b))
Only Conclusion (b) follows
((c))
Either Conclusion (a) or (b) follows
((d))
Both Conclusions (a) & (b) follows
((e))
Neither Conclusion (a) Nor (b) follows

Show Answer

Answer: ((c))

Either Conclusion (a) or (b) follows

Given statement: - Y = K ≥ V ≤G = C

Conclusions:-

a. K ≤ G – False (when we find path from K to G we get K ≥ V ≤G , so we can’t find definite relation between K and G, so this conclusion holds false).

b. K > G – False (when we find path from K to G we get K ≥ V ≤G, so we can’t find definite relation between K and G, so this conclusion holds false).

Here, our both Conclusion holds false and all the conditions of “either-or” Or Satisfies, so our answer is Either K ≤ G or K > G.

The correct answer is Either Conclusion (a) or (b) follows.

Directions: In the following question assuming the given statements to be true, find which of the conclusion among given conclusion is/are definitely true and then give your answers accordingly.

Statement: L = M ≥ Q ≥ R ≤ N ≥ O

Conclusions:

I. L ≥ R

II. M ≥ R

((a))
Only I follow
((b))
Only II follow
((c))
Both I and II follow
((d))
Either I or II follows
((e))
Neither I nor II follows

Show Answer

Answer: ((c))

Both I and II follow

Given Statement: L = M ≥ Q ≥ R ≤ N ≥ O

Conclusions:

I. L ≥ R → True (Here L = M ≥ Q ≥ R → L ≥ R, so it is true).

II. M ≥ R → True (Here M ≥ Q ≥ R → M ≥ R, so it is true).

Hence, Both I and II follow.

Directions: Read the following information carefully and answer the questions given below.

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

If the numbers are arranged from the right end in ascending order and the position of rest elements remain the same then which of the following element will be placed 20th from the right end?

((a))
J
((b))
S
((c))
%
((d))
F
((e))
D

Show Answer

Answer: ((c))

Given Series:

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

After numbers are arranged from the right end in ascending order and the position of the rest elements remain the same then the series is,

M ! T E @ Q W R $ O ^ P U * J S % D F ? A V + B > Z N L 9 8 7 6 4 3 2 1

The element that will be placed 20th from the right end is %.

If all symbols and numbers are dropped. Then which of the following element is tenth from the right end?

((a))
F
((b))
U
((c))
S
((d))
J
((e))
D

Show Answer

Answer: ((d))

Given Series:

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

After numbers and symbols are dropped then the series is,

M T E Q W R O P U J S D F A V B Z N L

The element which is tenth from the right end is J.

J is the correct answer.

Four out of five pairs are similar in a certain way. Find the odd one from the rest?

((a))
E$
((b))
O*
((c))
D9
((d))
V3
((e))
M4

Show Answer

Answer: ((a))

Given Series:

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

Three elements are between first and second element except E$.

E$ is the correct answer.

How many consonants are immediately followed by the number in the series?

((a))
Four
((b))
Three
((c))
Two
((d))
Five
((e))
More than five

Show Answer

Answer: ((a))

Four

Given Series:

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

The consonants are immediately followed by the number in the series is,

T4, Q1, J7, and D8

Four is the correct answer.

Which element is seventh to the right of 20th from the right end?

((a))
8
((b))
B
((c))
F
((d))
D
((e))
W

Show Answer

Answer: ((a))

Given Series

M ! 2 T 4 E @ Q 1 W R $ 6 O ^ P U * J 7 S % D 8 F ? 9 A V + B > 3 Z N L

The element which is seventh to the right of 20th from the right end is

20th from the right is U.

seventh from the right of the 20th element is 8.

8 is the correct answer.

If it is possible to make only one four-letter meaningful word with the second, fourth, seventh, and eighth letter of the word ‘SIGNATURE’, which could be the second letter of the word from the right end? If more than one such word can be formed, give ‘X’ as the answer. If no such word can be formed, give ‘Z’ as your answer.

((a))
I
((b))
U
((c))
X
((d))
Z
((e))
N

Show Answer

Answer: ((a))

Word: SIGNATURE

The second, fourth, seventh, and eighth letters are I, N, U, and R respectively.

There is only one word that can be formed using these letters i.e. RUIN.

Thus, ‘I’ is the second letter from the right end.

Directions: Read the following comprehension carefully and answer the questions given below.

A certain number of people are sitting in a linear row facing North. Two people are sitting between X and T. Only one person is sitting between T and M, who is not sitting to the left of T. M is sitting third to the right of S. Two people are sitting between M and Q, who is sitting third to the left of Y. P is sitting second to the left of S. P is sitting at the end of the row.

How many people are sitting in the row?

((a))
Eleven
((b))
Fourteen
((c))
Eighteen
((d))
Twelve
((e))
Fifteen

Show Answer

Answer: ((d))

Twelve

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

Twelve people are sitting in the row.

What is the position of X with respect to Q?

((a))
Second to the right
((b))
Second to the left
((c))
Immediate left
((d))
Immediate right
((e))
Third to the left

Show Answer

Answer: ((b))

Second to the left

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

X is second to the left of Q.

Directions: Read the following comprehension carefully and answer the questions given below.

If A is sitting in between T and M then who is sitting Fourth to the right of A?

((a))
P
((b))
Y
((c))
Q
((d))
X
((e))
S

Show Answer

Answer: ((c))

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

If A is sitting in between T and M then Q is sitting Fourth to the right of A.

Numerical Ability (40 questions)

Directions: Study the table and answer the given questions.

In the following table, the number of participants (in units) for three fitness activities (Yoga, Zumba, Cycling) over a four-day period is provided for a local gym.

Day	Yoga (participants)	Zumba (participants)	Cycling (participants)
Monday	123	157	146
Tuesday	139	143	155
Wednesday	114	168	132
Thursday	127	159	149

What is the percentage increase or decrease in the total number of participants in Yoga from Monday to Thursday?

((a))
3.25% increase
((b))
3.25% decrease
((c))
6.25% increase
((d))
4.25% increase
((e))
4.25% decrease

Show Answer

Answer: ((a))

3.25% increase

Calculation:

Monday participants = 123, Thursday participants = 127

Percentage change = $\frac{127 - 123}{123} \times 100 = \frac{4}{123} \times 100 = 3.25%$

Answer: 3.25% increase

If the total number of participants across all activities on Tuesday was increased by 20% on Friday, how many more participants were there on Friday than on Tuesday?

((a))
56
((b))
75
((c))
87
((d))
96
((e))
64

Show Answer

Answer: ((c))

Calculation:

Total participants on Tuesday = 139 + 143 + 155 = 437

Increased by 20% = 437 × 1.20 = 524.4 (rounded to 524)

Difference = 524 - 437 = 87

Answer: 87 more participants

Find the ratio of the total participants in Zumba on Wednesday and Thursday combined to the total participants in Cycling on Monday and Tuesday combined.

((a))
227 : 301
((b))
327 : 101
((c))
357 : 201
((d))
327 : 301
((e))
427 : 101

Show Answer

Answer: ((d))

327 : 301

Calculation:

Zumba (Wednesday + Thursday) = 168 + 159 = 327

Cycling (Monday + Tuesday) = 146 + 155 = 301

Ratio = 327 : 301

Answer: 327:301

On which day was the difference between the number of Yoga participants and Cycling participants the maximum? What was the difference?

((a))
Monday, 23
((b))
Tuesday, 46
((c))
Wednesday, 43
((d))
Tuesday, 23
((e))
Thursday, 37

Show Answer

Answer: ((a))

Monday, 23

Calculation:

Monday: |123 - 146| = 23

Tuesday: |139 - 155| = 16

Wednesday: |114 - 132| = 18

Thursday: |127 - 149| = 22

Answer: Monday, Difference = 23

If 10% of the Zumba participants on each day were also part of Yoga on the same day, what was the total number of unique participants in Zumba across all four days?

((a))
654
((b))
754
((c))
774
((d))
554
((e))
564

Show Answer

Answer: ((e))

564

Calculation:

Zumba participants = 157 + 143 + 168 + 159 = 627

10% of Zumba participants on each day = 10% of 627 = 62.7

Unique Zumba participants = 627 - 62.7 = 564.3 (rounded to 564)

Answer: 564 unique participants

Paresh does 40% work in 10 days. Then he consulted Bhave and together they finished the remaining work in 6 days. How many days Bhave would take to do it alone?

((a))
$16\frac{2}{3}days$
((b))
$14\frac{2}{3}days$
((c))
10 days
((d))
20 days
((e))
None of these

Show Answer

Answer: ((a))

$16\frac{2}{3}days$

Paresh does 40% work in 10 days

Paresh can do the 100% work in

$= \frac{{10}}{{1 \times \left( {\frac{{40}}{{100}}} \right)}}$

=10 × 100/40 = 25 days

Rest work =1 – (4/10) = 6 / 10 = 3 / 5

Paresh & Bhave finished the remaining work in 6 days

The whole work will be done by Paresh & Bhave in 5/3 × 6 = 10 days

Paresh’s 1 day’s work = 1/25

And (Paresh + Bhave)’s 1 day’s work = 1/10

∴ Bhave’s 1 day’s work = (1/10) – (1/25)

= 15 / 250

∴ Bhave will do the whole work in 16 2/3 days

Rahul spend 15% of total income in shopping and 20% of remaining income in school fees and 20% of total income in other items if his saving is Rs. 9600 then what is the total income of Rahul?

((a))
Rs. 20,000
((b))
Rs. 30,000
((c))
Rs. 40,000
((d))
Rs. 50,000
((e))
None of the above

Show Answer

Answer: ((a))

Rs. 20,000

Given:

Saving of Rahul = Rs. 9600

Expenditure on Shopping = 15%

Expenditure on School fees = 20% of the remaining = 20% of 85% = 17%

Expenditure on other items = 20%

Concept:

Income = Expenditure + Saving

Calculation:

Let total income be 100%

Savings = 100% – (15% + 17% + 20%)

⇒ 100% – 52%

⇒ 48%

Now, 48% = Rs. 9600

⇒ 100% = 20000

∴ The required result will be Rs. 20,000

A train running at speed of 54 km/hr crosses a platform of length same as that of the train in 36 seconds. If train which is 230 meters long crosses the same platform in 25 Seconds, then find the speed of train B (in km/hr).

((a))
54 km/hr
((b))
88 km/hr
((c))
59 km/hr
((d))
72 km/hr
((e))
108 km/hr

Show Answer

Answer: ((d))

72 km/hr

Let the length of train be x

Then, the length of platform is also x

Speed of train = 54 km/hr = 54 × (5/18) m/s = 15 m/s

∴ According to question

(x + x)/15 = 36

⇒ 2x = 540

⇒ x = 270 m

The length of the platform is 270 m

Now, a train of length 230 m crosses the platform in 25 sec

Let the speed of train be v m/s

⇒ (270 + 230)/v = 25

⇒ v = 20m/s

Speed of train = 20 m/s = 20 × (18/5) = 72 km/hr

∴ The speed of the train is 72 km/hr

In the following number series, a wrong number is given. Find out the wrong number.

8, 27, 64, 343, 1331

((a))
8
((b))
27
((c))
64
((d))
343
((e))
1331

Show Answer

Answer: ((c))

Given:

8, 27, 64, 343, 1331.

Calculation:

The logic follows here is:

(2)³ = 8

(3)³ = 27

(5)³ = 125

(7)³ = 343

(11)³ = 1331

By observing the above pattern, we can see that

Except 64, all numbers are cube of prime numbers

∴ 64 is the wrong term.

In the following number series, a wrong number is given. Find out the wrong number.

8, 4, 4, 8, 33, 256

((a))
4
((b))
33
((c))
256
((d))
8
((e))
None of these

Show Answer

Answer: ((b))

Given:

8, 4, 4, 8, 33, 256

Calculation:

The series follows the following pattern,

8 × (1/2) = 4

4 × 1 = 4

4 × 2 = 8

8 × 4 = 32 ≠ 33

32 × 8 = 256

Since 32 will come in place of 33

∴ The required wrong number will be 33.

In the following number series, a wrong number is given. Find out the wrong number.

25, 27, 33, 40, 51, 65

((a))
27
((b))
25
((c))
40
((d))
51
((e))
33

Show Answer

Answer: ((e))

Given:

25, 27, 33, 40, 51, 65

Calculation:

The pattern of the given series can be expressed as,

Since 32 will come in place of 33

∴ The required wrong number will be 33.

In the following number series, a wrong number is given. Find out the wrong number.

50, 51, 59, 86, 140

((a))
86
((b))
51
((c))
140
((d))
59
((e))
50

Show Answer

Answer: ((c))

140

Given:

50, 51, 59, 86, 140

Calculation:

The series follows the following pattern,

50 + 1³ = 51

51 + 2³ = 59

59 + 3³ = 86

86 + 4³ = 150 ≠ 140

Since 150 will come in place of 140

∴ The required wrong number will be 140.

In the following number series, a wrong number is given. Find out the wrong number.

154, 145, 161, 136, 174, 123, 187

((a))
145
((b))
136
((c))
174
((d))
123
((e))
187

Show Answer

Answer: ((c))

174

Given:

154, 145, 161, 136, 174, 123, 187

Calculation:

The series follows the following pattern

⇒ 154 - 3² = 145

⇒ 145 + 4² = 161

⇒ 161 - 5² = 136

⇒ 136 + 6² = 172 ≠ 174

⇒ 172 - 7² = 123

⇒ 123 + 8² = 187

∴ 174 is wrong and should be replaced by 172.

Alternate Method

∴ 174 is wrong and should be replaced by 172.

Direction: Study the following information carefully and answer based on it.

The following bar graph shows the total number of laptops sold by a company over five consecutive years from 2010 to 2014.

What is the percentage increase in the number of laptops sold from 2010 to 2014?

((a))
128.33%
((b))
109.33%
((c))
133.33%
((d))
157.33%
((e))
113.33%

Show Answer

Answer: ((c))

133.33%

Calculation:

Number of laptops sold in 2010 = 150

Number of laptops sold in 2014 = 350

Percentage increase = $\frac{350 - 150}{150} \times 100 = \frac{200}{150} \times 100 = 133.33%$

Answer: 133.33%

What is the average number of laptops sold per year over the given period?

((a))
150
((b))
250
((c))
350
((d))
75
((e))
50

Show Answer

Answer: ((b))

250

Calculation:

Total laptops sold over 5 years = 150 + 250 + 200 + 300 + 350 = 1250

Average = $\frac{1250}{5} = 250$

Answer: 250 laptops

The company decides to offer a 10% discount on each laptop in 2013 to boost sales. If the revenue without the discount would have been ₹15,000 per laptop, calculate the revenue lost due to the discount in 2013.

((a))
550,000
((b))
450,000
((c))
350,000
((d))
650,000
((e))
750,000

Show Answer

Answer: ((b))

450,000

Calculation:

Number of laptops sold in 2013 = 300

Revenue per laptop without discount = ₹15,000

Revenue lost per laptop due to 10% discount = 15,000 × 10% = ₹1,500

Total revenue lost = 300 × ₹1,500 = ₹450,000

Answer: ₹450,000

Calculate the difference in the number of laptops sold between the year with the highest sales and the year with the lowest sales.

((a))
50
((b))
100
((c))
150
((d))
200
((e))
250

Show Answer

Answer: ((d))

200

Calculation:

Highest sales = 350 (in 2014)

Lowest sales = 150 (in 2010)

Difference = 350 - 150 = 200

Answer: 200 laptops

If the company aims to achieve an average sale of 320 laptops per year over the six years from 2010 to 2015, what should be the minimum number of laptops sold in 2015?

((a))
670
((b))
770
((c))
870
((d))
470
((e))
570

Show Answer

Answer: ((a))

670

Calculation:

Total laptops needed for an average of 320 over 6 years = 320 × 6 = 1920

Total laptops sold from 2010 to 2014 = 150 + 250 + 200 + 300 + 350 = 1250

Laptops needed in 2015 = 1920 - 1250 = 670

Answer: 670 laptops

Mixture of milk and water is 2 : 3 in 20 L of mixture, in order to make the ratio of milk and water 1 : 3, what quantity of water should be added to the mixture?

((a))
15 L
((b))
16 L
((c))
14 L
((d))
12 L
((e))
None of these

Show Answer

Answer: ((d))

12 L

Given :

Quantity of mixture = 20 L

Ratio of milk and water = 2 : 3

Calculations :

Quantity of milk = (2/5) × 20 = 8 L

Quantity of water in mixture = 20 - 8 = 12 L

Let x L of water be mixed

⇒ 8/(12 + x) = 1/3

⇒ x = 12

∴ 12 L of water should be mixed.

A is 4 years older than B. The sum of present age of A and C is 48 years. The ratio of present age of B and C is 7 : 4. What is the age of A two years ago?

((a))
28 years
((b))
30 years
((c))
32 years
((d))
34 years
((e))
36 years

Show Answer

Answer: ((b))

30 years

Given:

A is 4 years older than B.

The sum of present age of A and C is 48 years.

The ratio of present age of B and C is 7 : 4.

Calculation:

Let the age of A be x.

The age of C = 48 - x

A is 4 years older than B.

The age of B = x - 4

The ratio of present age of B and C is 7 : 4.

⇒(x - 4)/(48 - x) = 7/4

⇒ 4x - 16 = 336 - 7x

⇒ 11x = 352

⇒ x = 32

The age of A two years ago = 32 - 2 = 30 years

∴ The age of A two years ago is 30 years.

Ram is a boatman and he can row a boat downstream at 30 km/h and upstream at 20 km/h. What will be the speed of the boat in still water?

((a))
20
((b))
30
((c))
22
((d))
25
((e))
None

Show Answer

Answer: ((d))

Given:

Speed in downstream = 30 km/h

Speed in upstream = 20 km/h

Formula:

Speed of downstream = Speed of a boat in still water + Speed of water current

Speed of upstream = Speed of a boat in still water - Speed of water current

Speed = Distance/Time

Calculation:

Let the speed of the boat in still water be x km/h and speed of water current be y km/h

Now, according to question

x + y = 30 ----(1)

x – y = 20 ----(2)

Now,

From equation (1) and (2), we get

⇒ 2x = 50

⇒ x = 50/2

⇒ x = 25

∴ The Speed of the boat in still water is 25 km/h

A shopkeeper marks a product at ₹3750. He sells it at a 20% discount and still makes a profit of ₹250. Calculate the difference between the marked price (MP) and the cost price (CP) of the product.

((a))
750
((b))
1000
((c))
500
((d))
900
((e))
1050

Show Answer

Answer: ((b))

1000

Calculation:

The product is sold at a 20% discount.

Discounted price = MP - 20% of MP = 3750 - (20/100 × 3750)

= 3750 - 750 = ₹3000

So, Selling Price (SP) = ₹3000

Profit = SP - CP

CP = SP - Profit

CP = ₹3000 - ₹250 = ₹2750

Difference = MP - CP

Difference = ₹3750 - ₹2750 = ₹1000

Answer: The difference between the marked price and the cost price is ₹1000.

What will come in place of question mark (?) in the following equation?

494 - 15 × 8 + 43 - 77 = ?2

((a))
21
((b))
29
((c))
31
((d))
19
((e))
11

Show Answer

Answer: ((d))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

494 - 15 × 8 + 43 - 77 = ?2

⇒ 494 - 120 + 64 - 77 = ?2

⇒ 494 -120 - 13 = ?2

⇒ 494 - 133 = ?2

⇒ 361 = ?2

∴ The value of ? is 19.

What will come in place of question mark (?) in the following equation?

336 ÷ 24 × ∛343 + (7)2 = ?

((a))
151
((b))
157
((c))
161
((d))
167
((e))
147

Show Answer

Answer: ((e))

147

Given:

336 ÷ 24 × ∛343 + (7)2 = ?

Concept:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

336 ÷ 24 × ∛343 + (7)2 = ?

⇒ 14 × 7 + 49 = ?

⇒ 98 + 49 = ?

∴ ? = 147

What will come in place of question mark (?) in the following equation?

$1{2 \over 13}$ × 338 + ? = 9² × 3 + 237

((a))
70
((b))
75
((c))
82
((d))
90
((e))
98

Show Answer

Answer: ((d))

GIVEN :

$1{2 \over 13}$ × 338 + ? = 92 × 3 + 237

CONCEPT :

CALCULATION :

$1{2 \over 13}$ × 338 + ? = 92 × 3 + 237

⇒ 15/13 × 338 + ? = 243 + 237

⇒ 390 + ? = 480

⇒ ? = 90

What will come in place of question mark (?) in the following equation?

60% of 800 + 192 ÷ 32 = 6 × ?

((a))
27
((b))
54
((c))
108
((d))
81
((e))
72

Show Answer

Answer: ((d))

Given:

60% of 800 + 192 ÷ 32 = 6 × ?

Concept:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

60% of 800 + 192 ÷ 32 = 6 × ?

⇒ 480 + 192 ÷ 32 = 6 × ?

⇒ 480 + 6 = 6 × ?

⇒ 486 = 6 × ?

⇒ 81 = ?

What will come in place of question mark (?) in the following equation?

25% of (15 × 24 ÷ 18 + 12) = ?

((a))
12
((b))
16
((c))
4
((d))
24
((e))
8

Show Answer

Answer: ((e))

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

25% of (15 × 24 ÷ 18 + 12) = ?

⇒ 25% of (15 × 4/3 + 12) = ?

⇒ 25% of (5 × 4 + 12) = ?

⇒ 25% of (20 + 12) = ?

⇒ 25% of 32 = ?

⇒ ? = 8

What will come in place of question mark (?) in the following equation?

383.99 ÷ 11.92 × 4.14 – 119.99 = ∛?

((a))
2
((b))
64
((c))
128
((d))
512
((e))
729

Show Answer

Answer: ((d))

512

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

383.99 ÷ 11.92 × 4.14 – 119.99 = ∛?

⇒ 384 ÷ 12 × 4 – 120 = ∛?

⇒ 32 × 4 – 120 = ∛?

⇒ 128 – 120 = ∛?

⇒ 8 = ∛?

∴ ? = 512

What will come in place of question mark (?) in the following equation?

165 + 156 ÷ 13 – 32 × 19 = ?

((a))
12
((b))
6
((c))
16
((d))
22
((e))
2

Show Answer

Answer: ((b))

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

165 + 156 ÷ 13 – 3² × 19 = ?

⇒ 165 + 156 ÷ 13 – 9 × 19 = ?

⇒ 165 + 12 – 9 × 19 = ?

⇒ 177 – 171 = ?

∴ ? = 6

What will come in place of question mark (?) in the following equation?

(20 × 45) – (70 × 3) + 360 = ? × 6

((a))
125
((b))
145
((c))
175
((d))
105
((e))
215

Show Answer

Answer: ((c))

175

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

(20 × 45) – (70 × 3) + 360 = ? × 6

⇒ 900 – 210 + 360 = ? × 6

⇒ 1260 – 210 = ? × 6

⇒ 1050 = ? × 6

∴ ? = 175

What will come in place of question mark (?) in the following equation?

40% of 450 + 85% of 800 = ?

((a))
960
((b))
860
((c))
920
((d))
820
((e))
900

Show Answer

Answer: ((b))

860

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

40% of 450 + 85% of 800 = ?

⇒ 180 + 680 = ?

∴ ? = 860

What will come in the place of the question mark ‘?’ in the following question?

(16/23 × 47/288 × 92/141) + ? = 1/9

((a))
1/21
((b))
1/9
((c))
1/3
((d))
1/27
((e))
1/18

Show Answer

Answer: ((d))

1/27

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

(16/23 × 47/288 × 92/141) + ? = 1/9

⇒ (16/23 × 47/288 × 92/141) + ? = 1/9

⇒ (4 × 1/72 × 4/3) + ? = 1/9

⇒ (4 × 1/18 × 1/3) + ? = 1/9

⇒ (2/27) + ? = 1/9 × 3/3

⇒ ? = 3/27 – 2/27

∴ ? = 1/27

What will come in the place of the question mark ‘?’ in the following question?

(963 – 221) × (? + 2)² = 36358

((a))
10
((b))
2
((c))
5
((d))
12
((e))
15

Show Answer

Answer: ((c))

(963 – 221) × (? + 2)²= 36358

⇒ (742) × (? + 2)²= 36358

⇒ (? + 2)² = 36358/742

⇒ (? + 2)² = 49

⇒ (? + 2) = 7

⇒ ? = 5

∴ ? = 5

What will come in the place of the question mark ‘?’ in the following question?

92 × 2² + 164 + 968 – 27 × 16 = ?

((a))
2⁸
((b))
2¹³
((c))
2¹¹
((d))
2¹⁰
((e))
2⁹

Show Answer

Answer: ((d))

2¹⁰

92 × 22 + 164 + 968 – 27 × 16 = ?

⇒ 81 × 4 + 164 + 968 – 27 × 16 = ?

⇒ 324 + 164 + 968 – 432 = ?

⇒ 1024 = ?

∴ ? = 2¹⁰

What will come in the place of the question mark ‘?’ in the following question?

600 + 38% of ? = 60² – 32 – 2²

((a))
7200
((b))
7800
((c))
7600
((d))
7400
((e))
8200

Show Answer

Answer: ((b))

7800

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

600 + 38% of ? = 60² – 32 – 2²

⇒ 600 + 38% of ? = 3600 – 32 – 4

⇒ 38% of ? = 3000 – 32 – 4

⇒ 38% of ? = 2964

⇒ ? = 2964/38 × 100

⇒ ? = 7800

∴ ? = 7800

What will come in the place of the question mark ‘?’ in the following question?

24²/16 + (3³ + 1) × (2³ – 1) – 199 = ?

((a))
31
((b))
33
((c))
35
((d))
37
((e))
39

Show Answer

Answer: ((b))

242/16 + (33 + 1) × (23 – 1) – 199 = ?

⇒ 576/16 + (28) × (7) – 199 = ?

⇒ 36 + 196 – 199 = ?

⇒ 33 = ?

∴ ? = 33

What will come in the place of the question mark ‘?’ in the following question?

12% of 900 + 13% of 1200 – 102 = ?

((a))
138
((b))
160
((c))
187
((d))
162
((e))
164

Show Answer

Answer: ((d))

162

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

12% of 900 + 13% of 1200 – 102 = ?

⇒ 108 + 156 – 102 = ?

⇒ 162 = ?

∴ ? = 162

The average weight of a group of members increased from 28 kg to 32 kg, when three new members of weight 32 kg, 34 kg and 46 kg join the group. Find the initial number of members in the group.

((a))
4
((b))
5
((c))
6
((d))
7
((e))
8

Show Answer

Answer: ((a))

Given:

Initial average of the group = 28 kg

Final average after three members were included = 32 kg

Weights of members included in the group = 32 kg, 34 kg and 46 kg

Formula used:

Average = Sum of observations/ Number of observations

Calculation:

Let the number of members initially in the group be x

Initial sum of observations = (28 × x)

Total number of observations when three new members joined the group

⇒ [(28 × x) + (32 + 34 + 46)]

Total number of members in the group after three members were added

⇒ (x + 3)

According to Question,

[(28 × x) + (32 + 34 + 46)]/(x + 3) = 32

⇒ [28x + 112]/(x + 3) = 32

⇒ [28x + 112] = 32 × (x + 3)

⇒ 28x + 112 = 32x + 96

⇒ 112 – 96 = 32x – 28x

⇒ 16 = 4x

⇒ x = 4

∴ The initial number of members in a group is 4.

A and B invest ₹4,500 and ₹1,800, respectively, in a business. A withdraws his investment after 6 months, while B continues for the entire year. What will be the profit ratio between A and B after 1 year?

((a))
5 : 4
((b))
3 : 7
((c))
4 : 5
((d))
1 : 2
((e))
5 : 7

Show Answer

Answer: ((a))

5 : 4

Given:

Investment of A = ₹4,500

Investment of B = ₹1,800

A's investment duration = 6 months

B's investment duration = 12 months

Formula used:

Profit ratio = (Investment of A × Time of A) : (Investment of B × Time of B)

Calculation:

Profit ratio = (4500 × 6) : (1800 × 12)

⇒ Profit ratio = 27,000 : 21,600

⇒ Profit ratio = 5 : 4

∴ The profit ratio after 1 year is 5:4.

The side of a square is 16 cm. The perimeter of a rectangle is double the perimeter of the square. If the breadth of the rectangle is 20 cm, what is the length of the rectangle?

((a))
32
((b))
44
((c))
56
((d))
25
((e))
64

Show Answer

Answer: ((b))

Given:

Side of square = 16 cm

Perimeter of rectangle = 2 × Perimeter of square

Breadth of rectangle = 20 cm

Formula used:

Perimeter of square = 4 × side

Perimeter of rectangle = 2 × (Length + Breadth)

Calculation:

Perimeter of square = 4 × 16 = 64 cm

Perimeter of rectangle = 2 × 64 = 128 cm

128 = 2 × (Length + 20)

⇒ 128 = 2 × Length + 40

⇒ 2 × Length = 128 - 40

⇒ 2 × Length = 88

⇒ Length = 44 cm

∴ The length of the rectangle is 44 cm.

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