RRB Clerk Prelims Memory Based Paper (Held on: 17 August 2019) (Previous Year Paper)

7 people: P, Q, R, S, T, U and V

Arrangement: Facing the centre

1) U is sitting 3^rd to the right of R.

2) S is sitting to the immediate right of U.

3) Two persons are sitting between Q and S.

4) T is sitting 2^nd to the left of Q.

5. V is not the immediate neighbour of T.

This is the final arrangement.

Hence, P is sitting to the immediate left of T.

7 people: P, Q, R, S, T, U and V

Arrangement: Facing the centre

1) U is sitting 3^rd to the right of R.

2) S is sitting to the immediate right of U.

3) Two persons are sitting between Q and S.

4) T is sitting 2^nd to the left of Q.

5. V is not the immediate neighbour of T.

This is the final arrangement.

Hence, S is sitting 2^nd to the right of V.

7 people: P, Q, R, S, T, U and V

Arrangement: Facing the centre

1) U is sitting 3^rd to the right of R.

2) S is sitting to the immediate right of U.

3) Two persons are sitting between Q and S.

4) T is sitting 2^nd to the left of Q.

5. V is not the immediate neighbour of T.

This is the final arrangement.

Hence, U is sitting 2^nd to the right of Q.

7 people: P, Q, R, S, T, U and V

Arrangement: Facing the centre

1) U is sitting 3^rd to the right of R.

2) S is sitting to the immediate right of U.

3) Two persons are sitting between Q and S.

4) T is sitting 2^nd to the left of Q.

5. V is not the immediate neighbour of T.

This is the final arrangement.

Hence, 'R is sitting 2^nd to the right of V' is the false statement.

7 people: P, Q, R, S, T, U and V

Arrangement: Facing the centre

1) U is sitting 3^rd to the right of R.

2) S is sitting to the immediate right of U.

3) Two persons are sitting between Q and S.

4) T is sitting 2^nd to the left of Q.

5. V is not the immediate neighbour of T.

This is the final arrangement.

RV - one person (Q) is sitting between R and V when counted from the right of R

ST - one person (P) is sitting between S and T when counted from the right of S

UP - one person (S) is sitting between U and P when counted from the right of U

VP - two persons (U and S) are sitting between V and P.

QU - one person (V) is sitting between Q and U when counted from the right of Q

Hence, 'VP' does not belong to the group.

Consider the following least possible Venn diagram,

Conclusions:

I. Some men are people →False It is possible but not definite)

II. All people are missing → False (It is possible but not definite)

Hence, neither conclusion I or II follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some oval are bread. → True (A part of oval which is circle is also bread)

II. No oval is bread. → False (It is definitely false)

Hence, only I follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some intelligent are not scientists. → False (it is possible but not definite)

II. Some politicians are intelligent. → True (Politicians who are scientists are also intelligent)

Hence, only II follows.

Hence, E is in south-west direction with respect to C.

Hence, the shortest distance between F and D = (28 + 14) m = 42m.

Hence, G is in south-east direction with respect to A.

1.D is sitting 2^nd from the right side in the row.

2.Only three persons are sitting between D and H.

3.H is sitting 5^th to the right of B.

4.Q is the immediate left  neighbor of B

5.Q is sitting 3^rd to the right of M.

6.Only 8 persons are sitting between Y and M, also Y is sitting to the left of P.

Hence there are 24 people in the row.

1.D is sitting 2^nd from the right side in the row.

2.Only three persons are sitting between D and H.

3.H is sitting 5^th to the right of B.

4.Q is the immediate left  neighbor of B

5.Q is sitting 3^rd to the right of M.

6.Only 8 persons are sitting between Y and M, also Y is sitting to the left of P.

 If G is sitting 3^rd to the left of H

Hence G is on 16^th position from left side.

1. D is sitting 2^nd from the right side in the row.

2. Only three persons are sitting between D and H.

3. H is sitting 5^th to the right of B.

4. Q is the immediate left  neighbor of B

5. Q is sitting 3^rd to the right of M.

6. Only 8 persons are sitting between Y and M, also Y is sitting to the left of P.

Hence 12 people are sitting between P and H

1.D is sitting 2^nd from the right side in the row.

2.Only three persons are sitting between D and H.

3.H is sitting 5^th to the right of B.

4.Q is the immediate left  neighbor of B

5.Q is sitting 3^rd to the right of M.

6.Only 8 persons are sitting between Y and M, also Y is sitting to the left of P.

P is toward left of Q hence statement  "P is sitting on Q's right" is False.

1.D is sitting 2^nd from the right side in the row.

2.Only three persons are sitting between D and H.

3.H is sitting 5^th to the right of B.

4.Q is the immediate left  neighbor of B

5.Q is sitting 3^rd to the right of M.

6.Only 8 persons are sitting between Y and M, also Y is sitting to the left of P.

Hence D is 13^th to right of P.

Given: M > U > L ≤ N; L ≥ Y > A

On combining: M > U > L ≥ Y > A; N ≥ L ≥ Y > A

I. Y < N ⇒ False (as N ≥ L ≥ Y so it is also possible that N = Y)

II. Y = N ⇒ False (as N ≥ L ≥ Y so it is also possible that N > Y)

Here conclusion I and II form complimentary pair.

Therefore, either conclusion I or II follows.

Given statement: M ≥ O ≥ G = R ≥ N = T

I. M = T → False (as M ≥ O ≥ G = R ≥ N = T → M ≥ T).

II. T ˂ M → False (as M ≥ O ≥ G = R ≥ N = T → M ≥ T)

Here, conclusions I and II form a complementary pair.

So, either conclusion I or II follows.

Given Statements: A < B < C, D ≥ E = F ≥ G > C

On combining: A < B < C < G ≤ F = E ≤ D

Conclusions:

I. B < E → True (as B < C < G ≤ F = E → B < E)

II. G ≤ D → True (as G ≤ F = E ≤ D → G ≤ D)

Hence, both I and II are true.

Given statements: P > Q = R < S; R < Y < Z

On combining: P > Q = R< Y < Z; Q = R < S

Conclusions:

I. Q > Z → False (as Q = R < Y < Z → Q < Z)

II. Y > P → False (as P > R and Y > R → thus no clear relation between Y and P can be determined)

Hence, neither conclusion I nor II is True.

Given Word: MINUTE 

The given word can be represented as follows:

Thus, there are two such pairs EI and TU.

Hence, two pairs of letters EI and TU are there in the word ‘MINUTE’, which have as many letters between them as in the English alphabetical series in both forward and backward directions.

The pattern followed here is:

Hence, "QTSR" is odd among the given letters.

10 persons: A, B, C, D, E, M, N, O, P and Q

Facing South: M, N, O, P and Q

Facing North: A, B, C, D and E

1) A is sitting to the immediate left of D and none of them is sitting at the any of the corners.

2) B is sitting 2^nd to the left of D.

3) Q is sitting to the immediate left of the one who is sitting opposite to B.

4) M is sitting 2^nd to the right of Q.

Therefore, case 1 gets eliminated.

5) N and P are immediate neighbours of each other whereas P is sitting at one of the corners.

6) E is sitting exactly opposite to the one who is sitting 4^th to the right of P. 

This is the final arrangement.

Hence, C is sitting opposite to P.

10 persons: A, B, C, D, E, M, N, O, P and Q

Facing South: M, N, O, P and Q

Facing North: A, B, C, D and E

1) A is sitting to the immediate left of D and none of them is sitting at the any of the corners.

2) B is sitting 2^nd to the left of D.

3) Q is sitting to the immediate left of the one who is sitting opposite to B.

4) M is sitting 2^nd to the right of Q.

Therefore, case 1 gets eliminated.

5) N and P are immediate neighbours of each other whereas P is sitting at one of the corners.

6) E is sitting exactly opposite to the one who is sitting 4^th to the right of P. 

This is the final arrangement.

Q sits in the middle of the row facing South.

A sits in the middle of the row facing North.

Hence, among the given options, Q sits in the middle of the row.

10 persons: A, B, C, D, E, M, N, O, P and Q

Facing South: M, N, O, P and Q

Facing North: A, B, C, D and E

1) A is sitting to the immediate left of D and none of them is sitting at the any of the corners.

2) B is sitting 2^nd to the left of D.

3) Q is sitting to the immediate left of the one who is sitting opposite to B.

4) M is sitting 2^nd to the right of Q.

Therefore, case 1 gets eliminated.

5) N and P are immediate neighbours of each other whereas P is sitting at one of the corners.

6) E is sitting exactly opposite to the one who is sitting 4^th to the right of P. 

This is the final arrangement.

Q is sitting to the immediate right of the one who is sitting opposite to D.

B is sitting to the immediate right of the one who is sitting opposite to M.

Similarly, C is sitting to the immediate right of the one who is sitting opposite to N.

Hence, C is related to N among the given options.

10 persons: A, B, C, D, E, M, N, O, P and Q

Facing South: M, N, O, P and Q

Facing North: A, B, C, D and E

1) A is sitting to the immediate left of D and none of them is sitting at the any of the corners.

2) B is sitting 2^nd to the left of D.

3) Q is sitting to the immediate left of the one who is sitting opposite to B.

4) M is sitting 2^nd to the right of Q.

Therefore, case 1 gets eliminated.

5) N and P are immediate neighbours of each other whereas P is sitting at one of the corners.

6) E is sitting exactly opposite to the one who is sitting 4^th to the right of P. 

This is the final arrangement.

Hence, two people sit between O and P.

10 persons: A, B, C, D, E, M, N, O, P and Q

Facing South: M, N, O, P and Q

Facing North: A, B, C, D and E

1) A is sitting to the immediate left of D and none of them is sitting at the any of the corners.

2) B is sitting 2^nd to the left of D.

3) Q is sitting to the immediate left of the one who is sitting opposite to B.

4) M is sitting 2^nd to the right of Q.

Therefore, case 1 gets eliminated.

5) N and P are immediate neighbours of each other whereas P is sitting at one of the corners.

6) E is sitting exactly opposite to the one who is sitting 4^th to the right of P. 

This is the final arrangement.

P, M, C and E are sitting at the extreme ends of their respective rows whereas B is not.

Hence, B does not belong to the group.

Six persons: P, Q, R, S, T, and U 

T is lighter than only one person

U is heavier than S but lighter than Q. R is heavier than Q.

Order is: R > Q > U > S

since S is not the lightest one, P is lightest among them and R will be Heaviest.

S is the second lightest and his weight is 58kgs.

Hence, the possible weight of P is 55kgs.

Six persons: P, Q, R, S, T, and U 

T is lighter than only one person.

U is heavier than S but lighter than Q. R is heavier than Q.

Order is: R > Q > U > S

since S is not the lightest one, P is lightest among them and R will be Heaviest.

Hence P is the lightest among them.

Six persons: P, Q, R, S, T, and U 

T is lighter than only one person

U is heavier than S but lighter than Q. R is heavier than Q.

Order is: R > Q > U > S

since S is not the lightest one, P is lightest among them and R will be Heaviest.

T + R = 230 

R = 117

Hence, T = 113.

S + U = 120 

S = 58

Hence, U = 62.

T + U = 113 + 62 = 175

Hence, the summation of weights of the T and U is 175.

In this given series:

N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

Required pattern: no symbol → consonant → vowel

Hence, there is only one consonant which is immediately followed by a vowel but not immediately preceded by a symbol: 3 V O.

Hence, the answer is one.

Given series:

N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

Let's check each option:

KFG: F is to the immediate left of K, G is second to the right of K.

A#Z: # is to the immediate left of A, Z is second to the right of A.

E*P : * is to the immediate left of E, P is second to the right of E.

€B@: B is to the immediate left of €, @ is second right to the of €.

4HZ: H is to the immediate left of 4, Z is second to the left of 4.

Except for 4HZ, the rest of them follow the above-mentioned pattern.

Hence, 4HZ does not belong to the group.

Given series:

N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

As Left – Left = Left

⇒ 6^th from the Left – 27^th to the Left = 21^st from the Left

Now, N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

Clearly, 21^st from the Left is B.

In the given series:

N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

Required pattern: Number → Symbol → Alphabet

Hence, there is one symbol which is immediately preceded by a number and followed by an alphabet: 6 & F.

Hence, the answer is one.

Given series:

N 6 & F K ~ G U 7 S # A 8 Z T * E W P 5 B € X @ J Z H 4 I ^ 3 V O 2 C

If all the symbols and numbers are dropped:

N F K G U S A Z T E W P B X J Z H I V O C

10^th from the left end

Then, letter that is 10^th from left end is ‘E’.

1. C lives on even number floor above floor number 3.

2. Only two people live between F and C. B lives immediately above F.

3. Only two people live between A and E.

Case 1: Case 2:

4. More than two persons live between A and B. (This eliminates case 1)

5. G lives on one of the floors above D.

Case 2:

Hence, no one lives above G.

1. C lives on even number floor above floor number 3.

2. Only two people live between F and C. B lives immediately above F.

3. Only two people live between A and E.

Case 1: Case 2:

4. More than two persons live between A and B. (This eliminates case 1)

5. G lives on one of the floors above D.

Case 2:

Hence, only one person lives between A and C.

1. C lives on even number floor above floor number 3.

2. Only two people live between F and C. B lives immediately above F.

3. Only two people live between A and E.

Case 1: Case 2:

4. More than two persons live between A and B. (This eliminates case 1)

5. G lives on one of the floors above D.

Case 2:

Hence, E lives just below C.

1. C lives on even number floor above floor number 3.

2. Only two people live between F and C. B lives immediately above F.

3. Only two people live between A and E.

Case 1: Case 2:

4. More than two persons live between A and B. (This eliminates case 1)

5. G lives on one of the floors above D.

Case 2:

Hence, B lives between E and F

1. C lives on even number floor above floor number 3.

2. Only two people live between F and C. B lives immediately above F.

3. Only two people live between A and E.

Case 1: Case 2:

4. More than two persons live between A and B. (This eliminates case 1)

5. G lives on one of the floors above D.

Case 2:

Person – Floor just below that person, is given.

Clearly, ‘D - 3’ does not belong to the group.

Let the ages of B and C be 9x and 5x

So that 5x = 30

⇒ x = 6

Now B’s age will be 9x = 9 × 6 = 54

Now A is 6 years older than B So A’s age will be 54 + 6 = 60 years

21 + 11 = 32

32 + 22 = 54

54 + 33 = 87

87 + 44 = 131

131 + 55 = 186

9 + 1² = 10

10 - 2² = 6

6 + 3² = 15

15 - 4² = -1

-1 + 5² = 24

⇒ 3 + 1² = 4

⇒ 4 + 2² = 8

⇒ 8 + 3² = 17

⇒ 17 + 4² = 33

⇒ 33 + 5² = 58

⇒ 58 + 6² =94 

Hence option 5 is correct.

⇒ 84 + 12 = 96

⇒ 96 – 13 = 83

⇒ 83 + 12 = 95

⇒ 95 – 13 = 82

⇒ 82 + 12 = 94

⇒ 94 - 13 = 81

Hence option 1 is correct.

The pattern in the given series is:

 4 + 7 = 11

⇒ 11 + 14 = 25

⇒ 25 + 21 = 46

⇒ 46 + 28 = 74

⇒ 74 + 35 = 109

⇒ 109 + 42 = 151

Hence the wrong number in the series is 129

GIVEN :

The ratio of the salary of a male and a female is 6 ∶ 5.

After 20% increment the salary of a male becomes Rs. 216 and the salary of a female increased by 4%.

ASSUMPTION :

Let salary of male and female be 6x and 5x

20% increment in male salary became 216

CALCULATION :

⇒ 6x × 1.2 = 216

⇒ x = 30

Female salary after increment 0f 4% become 5x × 1.04 = 5.2x

                                                                          5.2 × 30 = 156

Hence option 2 is correct

⇒ 4 × (x – 2) + 20x = 328

⇒ x = 14

Now price of 14 pencil and 11 pen will be

⇒ 14 × 4 + 11 × 20

⇒ 276

Hence option B is correct.

I. x² - 5x - 24 = 0

⇒ (x - 8) (x + 3) = 0

⇒ x = 8, - 3

II. y² - 7y - 18 = 0

⇒ (y - 9) (y + 2) = 0

⇒ y = 9, - 2

Hence, relationship between x and y cannot be established

I. x² - 6x + 9 = 0

⇒ (x - 3) (x - 3) = 0

⇒ x = 3

II. y² - 11y + 24 = 0

⇒ (y - 8) (y - 3) = 0

⇒ y = 3, 8

Hence, x ≤ y

I. x² = 441 ⇒ x = ±21

II. y² = 371 – 47 ⇒ y = ±18

For one value x is greater and for one x is smaller than y. 

Hence, relationship cannot be established between x and y.

I. x² – x – 42 = 0

⇒ x² – 7x + 6x – 42 = 0

⇒ x(x – 7) + 6(x – 7) = 0

⇒ x = 7, x = –6

II. y² + y – 30 = 0

⇒ y² + 6y – 5y – 30 = 0

⇒ y(y + 6) – 5(y – 6) = 0

⇒ y = –6, y = 5

∴ Relationship cannot be determined

⇒ x² – 9x – 8x + 72 = 0

⇒ x(x – 9) – 8(x – 9) = 0

⇒ x = 9 ,  8

⇒ y² – 17y + 70 = 0

⇒ y² – 10y – 7y + 70 = 0

⇒ y(y – 10) – 7(y – 10) =0

⇒ y = 10 , 7

When x = 9, y = 10, then x < y

When x = 9, y = 7, then x > y

When x = 8, y = 10, then x < y

When x = 8, y = 7, then x > y

∴ Relationship cannot be determine

Let the radius be r1 and r2,

So for the first circle

⇒ 2π (r1) = 132

⇒ r1 = 21,

And for second circle

⇒ 2π (r2) = 88

⇒ r2 = 14

∴ r1 – r2 = 7 cm

Hence option 1 is correct.

Given:

Distance travelled in Downstream & upstream = 66 km & 36 kms respectively.

Time taken in Downstream & Upstream = 3 & 2 hours.

Assumption:

Let x be the speed of boat and y be the speed of current

Formula used:

Downstream speed = Speed of boat in still water + Speed of river

Upstream speed = Speed of boat in still water - Speed of river

Calculation:

When boat goes upstream x – y = \(\frac {36} 2\) = 18 km/hr    –-– (i)

When boat goes downstream x + y = \(\frac{66}3\) = 22 km/hr     ––– (ii)

By adding eq (i) and (ii)

⇒ 2x = 40

⇒ x = 20 km/hr

Hence the speed of the boat in still water is 20 km/hr.

Concept used:

Follow BODMAS rule to solve this question, as per the order given below, 

Calculation:

2³ × 3² ÷ (90 ÷ ?) = √64

Let the unknown number be x.

⇒ 8 × 9 ÷ (90 ÷ x) = 8

⇒ 72 ÷ (90/x) = 8

⇒ 72 × x/90 = 8

⇒ 8x/10 = 8

⇒ x = 8 × 10/8 = 10

∴ The value of ? is 10.

Follow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,

Step-2-  Then any mathematical 'Of' or 'Exponent' must be solved,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

64 + 60 ÷ (30 ÷ 3) = (?) ÷ 20

⇒ 64 + 60 ÷ 10 = x/ 20

⇒ 64 + 6 = x/ 20

⇒ x = 1400

Hence option 2 is correct

Concept:

Follow BODMAS rule to solve this question, as per the order given below, 

Calculations:

(9/2 + 4) × 8 = ? × 10

⇒ (9 + 8)/2 × 8 = x × 10

⇒ 17 × 4 = x × 10

⇒ x = 68/ 10

⇒ x = 6.8

Hence option 3 is correct.

16/18 of 75/2 of 11/85 of ? = 220

⇒ (16/ 18) × (75/ 2) × (11/ 85) × x = 220

⇒ x = (220 × 18 × 2 × 85)/ (16 × 75 × 11)

⇒ x = 51

Hence option 4 is correct.

122 – ? = √784

⇒ 144 – x = 28

⇒ x = 116

Hence option 4 is correct.

(? – 0.5) ÷ 0.2 = 120 ÷ 3

⇒ x – 0.5 = 40 × 0.2

⇒ x = 8.5

Hence option 5 is correct.

80% of (2.5 × 4 + ?) = 24

⇒ 0.8 × (10 + x) = 24

⇒ 8 + 0.8x = 24

⇒ x = 20

Hence option 1 is correct.

Follow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,

Step-2-  Then any mathematical 'Of' or 'Exponent' must be solved,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

1251/3 × 271/3 × 1254/3 = 15 × 5?

⇒ 5 × 3 × 5⁴ = 15× 5^x

⇒ 15 × 5 ⁴ = 15× 5^x

⇒ x = 4

Hence option 4 is correct.

15% of 120 × 25% of 180 = (?) – 5²

⇒ 0.15 × 120 × 0.25 × 180 = x – 25

⇒ 18 × 45 = x– 25

⇒ x = 835

Hence option 3 is correct.

43 × 84 ÷ 82 = 2? × 4

⇒ 4³ × 8^{4 – 2} = 2^x × 4

⇒ 4³ × 8² = 2^x × 4

⇒ 4³ × 4² × 2² = 2^x × 4

⇒ 4⁵ × 2² = 2^x × 4

⇒ 4 × 4⁴ 2² = 2^x × 4

⇒ 4 × 2¹⁰ = 2^x × 4

⇒ x = 10

Option 2 is correct.

Concept Used:

Calculation:

√144 × √81 - (6)2 = ? + (8)2

⇒ 12 × 9 - 36 = ? + 64

⇒ 108 - 100 = ?

⇒ ? = 8

∴ The required value of "?" is 8

Given:

Marked Price (MP) is greater than the Cost Price (CP) by Rs.340

Discount offered = 15%

Profit = 27.5%

Formulae Used:

SP = [(100 – %discount)/100] × MP

SP = [(100 + %profit)/100] × CP

%Profit = [(SP – CP)/CP] × 100

Calculation:

Let the CP of the article be x

So, the MP = x + 340

For a discount of 15%, the Selling Price is:

SP = [(100 – 15)/100] × (x + 340) = 0.85x + 289

SO, the profit% is calculated as:

27.5% = {[(0.85x + 289) – x]/x} × 100

⇒ 11560 – 6x = 11x

⇒ x = 11560/17 = 680

∴ The Cost Price of the article is Rs.680

Shortcut Trick We know that,

C.P/M.P = (100 - D%)/(100 + P%)

C.P/M.P = (100 - 15%)/(100 + 27.5%)

C.P/M.P = 85/127.5

C.P/M.P = 2/3

Difference of M.P and C.P = 3 - 2 = 1 Unit

1 Unit = 340

Then, 2 unit = 680 

So, C.P = Rs. 680

Total sales made by C = 40 + 50 = 90

Total sales made by A = 70 + 55 = 125

∴ Required Percentage = (90/125) × 100 = 18/25 = 72%

Sales made by A on Tuesday = 55

Sales made by B on Tuesday = 60

Sales made by C on Tuesday = 50

∴ Required average = (55 + 60 + 50)/3 = 55

Total sales made by B in both the days = 45 +h 60 = 105

Total sales made by C in both the days = 40 + 50 = 90

∴ Required ratio = 105 : 90 = 7 : 6

Total sales made by A on Tuesday = 55

Total sales made by C on Monday = 40

∴ Required Percentage = [(55 – 40)/40] × 100 = 37.5%

Total number of books sold by A and C on Monday = 70 + 40 = 110

Total number of books sold by B and C on Tuesday = 60 + 50 = 110

∴ Required Ratio = 110 : 110 = 1 : 1

A’s one day work is 1/ 36 and B’s one day work is 1/ 60

Together they can complete the work in one day is,

⇒ 1/ 36 + 1/ 60 = 8/ 180

Whole work will complete in 180/ 8

And 1/ 6^th of the work will completed in 180/ 8 × 1/ 6 = 15/ 4

Hence option 3 is correct.

Concept Used:

When trains running in opposite direction crosses each other then, Relative Speed = S1 + S2

Distance = Speed × Time

Formula Used:

Time taken by both the trains to cross each other completely =

(Sum of length of the trains)/(sum of speed of the trains)

{∵ Trains are crossing each other, they travel in opposite directions}

Calculations:

Let T be the time taken to complete the distance

⇒ (18 + 12) × 18/ 5 = 367.2/ T

⇒ T = 367.2/ 108

⇒ T = 3.4 hour

Option 1 is correct.

Additional Information

When two objects travelling in the same direction,

their relative speed = |Speed of A - Speed of B|

When two objects travelling in the opposite direction,

their relative speed = |Speed of A + Speed of B|

Total sales made by A in all the months together = 80 + 110 + 105 + 60 + 55 = 410

∴ Required Average = 410/5 = 82

Total sales made by A and B in the month of September = 60 + 65 = 125

Total sales made by B and C in the month of October = 80 + 100 = 180

∴ Required Percentage = (125/180) × 100 = 69.4%

Total mobiles sold by A in the month of August, September and October = 105 + 60 + 55 = 220

Total mobiles sold by C in the month of June, July and August = 70 + 85 + 95 = 250

∴ Required Ratio = 220 : 250 = 22 : 25

Total mobiles sold by A in the months together = 80 + 110 + 105 + 60 + 55 = 410

Total mobiles sold by B and C in the month of August and September = 50 + 65 + 95 + 60 = 270

∴ Required Percentage = [(410 – 270) / 270] × 100 = 51.85% ≈ 52%

Total mobiles sold in the month of September and October together = 185 + 235 = 420

Total mobiles sold in the month of July and August together = 295 + 250 = 545

∴ Required Difference = 545 – 420 = 125

Given:

Quantity of water in the mixture = 20 liter

Quantity of milk in the mixture = (64 - 20) = 44 liter

Calculation:

1/ 4^th of the mixture is taken out

Means quantity of milk has taken out 

⇒ 1/ 4^th of 44 = 11 liter

And the quantity of water has taken out

⇒ 1/ 4^th of 20 = 5 liter

Remaining Quantities of milk and water is 33 liter of milk and 15 liters of water

Ratio of milk and water required in the new mixture after addition of milk,

3 : 1

⇒ (33 + x) / 15 = 3 / 1

⇒ 33 + x = 45

⇒ x = 12

∴ 12 liter of milk should be added in the mixture.