RRB Clerk Prelims Memory Based Paper (Held On: 13 August 2023 Shift 2) (Previous Year Paper)

Floor no: 1 to 7

Person: W, I, N, D, O, B and J

1. J lives immediately above W, who lives on the 4^th floor.
   

2. Two persons live between W and B.

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3. I lives immediately below O, who lives below J and above B.

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The above table will be the final solution.

Hence, Either D or N is live on the topmost floor.

Floor no: 1 to 7

Person: W, I, N, D, O, B and J

1. J lives immediately above W, who lives on the 4^th floor.
   

2. Two persons live between W and B.

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3. I lives immediately below O, who lives below J and above B.

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The above table will be the final solution.

Hence, I lives on the 2^nd floor.

Floor no: 1 to 7

Person: W, I, N, D, O, B and J

1. J lives immediately above W, who lives on the 4^th floor.
   

2. Two persons live between W and B.

<br>

3. I lives immediately below O, who lives below J and above B.

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The above table will be the final solution.

Hence, no one lives between D and N.

Floor no: 1 to 7

Person: W, I, N, D, O, B and J

1. J lives immediately above W, who lives on the 4^th floor.
   

2. Two persons live between W and B.

<br>

3. I lives immediately below O, who lives below J and above B.

4) If D lives immediately above J, then N will live on the 7th floor

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The above table will be the final solution.

Therefore, N will live on the 7^th floor if D lives immediately above J.

Floor no: 1 to 7

Person: W, I, N, D, O, B and J

1. J lives immediately above W, who lives on the 4^th floor.
   

2. Two persons live between W and B.

<br>

3. I lives immediately below O, who lives below J and above B.

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The above table will be the final solution.

Hence, W lives exactly middle of the building.

Given series: 2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ #

Letters, which are immediately followed by a letter but not immediately preceded by a letter

2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ #

Therefore, there are 5 letters. Which are immediately followed by a letter but not preceded by a letter: 5KA, 3EG, $MP, ©QT and 3UB

Hence, “more than four” is the correct answer.

Given series:

Left side: 2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ # Right

side

Eighth element from the left end – 3

Twelfth element to the right of eighth element from the left end (3) – G

Therefore, “G” will be twelfth to the right of the eighth element from the left end of the given arrangement

Hence, “G” is the correct answer.

Given series: 2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ #

Consonants which are immediately followed by a symbol and preceded by a vowel

2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ #

Therefore, there is only one consonant which is immediately followed by a symbol and preceded by a vowel: EG$

Hence, “one” is the correct answer.

Given series: 2 @ 5 K A 7 6 3 2 @ T 8 € V 7 % B 3 E G $M P © Q T$ #

If all the symbols are dropped then the series will be as follows:

Left end: 2 5 K A 7 6 3 2 T 8 V 7 B 3 E G M P Q T 3 U B 6 5: Right end

Fifteenth element from the right end – V

Hence, “V” is the correct answer.

Six persons : A, B, C, D, E and F

1. F is taller than A, who is taller than D and C.

F > A > D/C

2. Only two persons are shorter than E, but neither of them is C.

_ > _ > _ > E > _ > _

3. D is not the shortest person.

The arrangement is F > A > C > E > D > B.

The final arrangement is : F > A > C > E > D > B.

Hence, B is shortest among all.

Six persons : A, B, C, D, E and F

1. F is taller than A, who is taller than D and C.

F > A > D/C

2. Only two persons are shorter than E, but neither of them is C.

E > >

3. D is not the shortest person.

The arrangement is F > A > C > E > D > B.

The final arrangement is : F > A > C > E > D > B.

Hence, four persons are shorter than A.

Six persons : A, B, C, D, E and F

1. F is taller than A, who is taller than D and C.

F > A > D/C

2. Only two persons are shorter than E, but neither of them is C.

E > >

3. D is not the shortest person.

The arrangement is F > A > C > E > D > B.

The final arrangement is : F > A > C > E > D > B.

Hence, D is shorter than E.

Six persons : A, B, C, D, E and F

1. F is taller than A, who is taller than D and C.

F > A > D/C

2. Only two persons are shorter than E, but neither of them is C.

E > >

3. D is not the shortest person.

The arrangement is F > A > C > E > D > B.

The final arrangement is : F > A > C > E > D > B.

Hence, C is shorter than A but taller than E.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some lemons are mangoes → False (It is given that all mangoes are apples)

II. All lemons are apples → False (It is given that only a few lemons are apples)

Hence, neither I nor II follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some baskets are bottles → True (It is possible)

II. No bottle is basket → False (It is false as only a few baskets are bottles)

Hence, Only I follows.

The least possible Venn Diagram for the given statements will be as follows,

I. All Chairs are Table → False (It is possible, but not definite.)

II. Some Tables are Bench → False (It is possible, but not definite, as no direct relationship between the two is given).

Hence, Neither I nor II follows.

The least possible Venn Diagram for the given statements will be as follows,

I. No Paint are Tall → True (As all paint are wall and no wall is tall. Thus, No paint are tall.)

II. Some Paint are Tall → False (This is definitely not true)

Hence, ‘Only I follows’ is the correct answer.

Given words are: EDC     TGF     VBJ     QAL     KJU

Odd positions: 1^st and 3^rd positions

On interchanging both alphabets of each word present at odd positions

CDE     FGT     JBV     LAQ     UJK

Clearly, only one word, CDE ending with vowel will be formed.

Hence, only one word will be formed.

Note: In English alphabetical series there are 5 vowels i.e. A, E, I, O, U else all are consonants.

Given words are: EDC     TGF     VBJ     QAL     KJU

On changing the first and last alphabet of each word to the previous alphabet and the middle alphabet to its next alphabet in the English alphabetical series:

DEB     SHE     UCI     PBK     JKT

Clearly, two words PBK and JKT having only consonants will be formed.

Hence, two words will be formed.

Note: In English alphabetical series there are 5 vowels i.e. A, E, I, O, U else all are consonants.

Given words are: EDC     TGF     VBJ     QAL     KJU

On arranging alphabets within the word in English alphabetical order:

CDE     FGT     BJV     ALQ     JKU

Clearly, three words, FGT, BJV and ALQ will end with a consonant.

Note: In English alphabetical series there are 5 vowels i.e. A, E, I, O, U else all are

Hence, three words will end with a consonant.

Given words are: EDC     TGF     VBJ     QAL     KJU

The second word from the left is TGF and its first letter is T

First word from the right is KJU and its second letter is J

There are nine letters between J and T in the English alphabetical series, namely, K, L, M, N, O, P, Q, R, S.

Hence, nine is the correct answer.

Given Statements: A ≥ B ≥ C = D; D ≥ E < F < G

On combining: A ≥ B ≥ C = D ≥ E < F < G

Conclusion:

I. B > E → False (As A ≥ B ≥ C = D ≥ E < F < G → B ≥ E. So, it is false)

II. E = B → False (As A ≥ B ≥ C = D ≥ E < F < G → B ≥ E. So, it is false)

As B ≥ E → B > E or E = B

Hence, Either I or II follows.

Given Statement: E ≥ W = A < B ≤ S ≤ T < X

Conclusions: 

I. E > T → False (As E ≥ W = A < B ≤ S ≤ T there is no relation between E and T because of the opposite sign between E and T).

II. A = X → False (As A < B ≤ S ≤ T < X → A < X. So, it is false).

Hence, Neither I nor II follows.

Given Statement: M > N > O > P > Q < A = B < F

Conclusions:

I. M < A → False (As M > N > O > P > Q < A = B < F, there is no relation between M and A because the signs between M and A are opposite. So, it is false).

II. N < Q → False (As M > N > O > P > Q < A = B < F → N > Q. So, it is false).

Hence, Neither I nor II follows.

Given number is 724536986

Now we add 1 in all even digits and subtract 1 from all odd digits.

After the arrangement we get:

635427897

The 5th digit from the right end is 2 and the 4th digit from the left end is 4. so, the sum is 4 + 2 = 6

Hence, the correct answer is 6.

The first, third, and eighth letters of the word PREDOMINANT are P, E, and N respectively. 

1st letter → P,   3rd letter → E, and 8th letter → N

So, PEN is a meaningful word.

Hence, E is the second letter from the right end.

People: A, B, C, D, E, F and G.

1. A sits second to the left of D.

2. E is third to the right of D.

3. C sits third to the right of G, who is not an immediate neighbour of E.

Case1:

Case 2:

4. B sits second to the right of G.

In Case 2, the above conditions are not satisfied in this case and thus eliminated.

The remaining F is between E and A.

The final arrangement will be:

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Hence, A sits second right of E.

People: A, B, C, D, E, F and G.

1. A sits second to the left of D.

2. E is third to the right of D.

3. C sits third to the right of G, who is not an immediate neighbour of E.

Case1:

Case 2:

4. B sits second to the right of G.

In Case 2, the above conditions are not satisfied in this case and thus eliminated.

The remaining F is between E and A.

The final arrangement will be:

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Hence, A is third to the right of C.

People: A, B, C, D, E, F and G.

1. A sits second to the left of D.

2. E is third to the right of D.

3. C sits third to the right of G, who is not an immediate neighbour of E.

Case1:

Case 2:

4. B sits second to the right of G.

In Case 2, the above conditions are not satisfied in this case and thus eliminated.

The remaining F is between E and A.

The final arrangement will be:

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Hence, E is third to the left of G.

People: A, B, C, D, E, F and G.

1. A sits second to the left of D.

2. E is third to the right of D.

3. C sits third to the right of G, who is not an immediate neighbour of E.

Case1:

Case 2:

4. B sits second to the right of G.

In Case 2, the above conditions are not satisfied in this case and thus eliminated.

The remaining F is between E and A.

The final arrangement will be:

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If E and G interchanges their position:

Hence, G is third right of D.

People: A, B, C, D, E, F and G.

1. A sits second to the left of D.

2. E is third to the right of D.

3. C sits third to the right of G, who is not an immediate neighbour of E.

Case1:

Case 2:

4. B sits second to the right of G.

In Case 2, the above conditions are not satisfied in this case and thus eliminated.

The remaining F is between E and A.

The final arrangement will be:

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In all except CB, the second person is sitting to the immediate right of first one. In CB, B is sitting to the immediate left of C.

Hence, B is sitting immediate left of C.

The alphabets are positioned in the following order:

Given word:  REMEMBER

The given word can be represented as follows:

Thus, there is one pair → Forward: MR.

Hence, one is the correct answer.

From the given information

1. A is the father of D, who is the wife of C.

2. B is the mother-in-law of C.

3. F is the paternal uncle of E, who is the daughter of B.

4. G is the husband of E.

Hence, A is the husband of B.

From the given information

1. A is the father of D, who is the wife of C.

2. B is the mother-in-law of C.

3. F is the paternal uncle of E, who is the daughter of B.

4. G is the husband of E.

Hence, C is the brother-in-law of E.

From the given information

1. A is the father of D, who is the wife of C.

2. B is the mother-in-law of C.

3. F is the paternal uncle of E, who is the daughter of B.

4. G is the husband of E.

Hence, there are four males in the family.

1)A and R purchased Middle march and Wonderland but not necessarily in the same order

 

2. Either H or R purchase Pride.

3. Neither P nor N purchased The lion.

4. D purchase either The Grapes or Brave world.

 

5. P does not purchase Catch22.

 

6)A and P purchase Brave world and Wonderland but not necessarily in the same order.

(With respect to statement 1, it is clear that A purchased Wonderland and accordingly, P purchase Brave world. Also, as P purchase Brave world, implies, D must be purchasing The Grapes. R purchase Middle march.)

M purchased The lion.

1)A and R purchased Middle march and Wonderland but not necessarily in the same order

 

2) Either H or R purchase Pride.

3) Neither P nor N purchased The lion.

4) D purchase either The Grapes or Brave world.

 

5) P does not purchase Catch22.

 

6)A and P purchase Brave world and Wonderland but not necessarily in the same order.

(With respect to statement 1, it is clear that A purchased Wonderland and accordingly, P purchase Brave world. Also, as P purchase Brave world, implies, D must be purchasing The Grapes. R purchase Middle march.)

H purchase the Pride book

1)A and R purchased Middle march and Wonderland but not necessarily in the same order

 

2) Either H or R purchase Pride.

3) Neither P nor N purchased The lion.

4) D purchase either The Grapes or Brave world.

 

5) P does not purchase Catch22.

 

6)A and P purchase Brave world and Wonderland but not necessarily in the same order.

(With respect to statement 1, it is clear that A purchased Wonderland and accordingly, P purchase Brave world. Also, as P purchase Brave world, implies, D must be purchasing The Grapes. R purchase Middle march.)

P purchased Brave world book

1)A and R purchased Middle march and Wonderland but not necessarily in the same order

 

2) Either H or R purchase Pride.

3) Neither P nor N purchased The lion.

4) D purchase either The Grapes or Brave world.

 

5) P does not purchase Catch22.

 

6)A and P purchase Brave world and Wonderland but not necessarily in the same order.

(With respect to statement 1, it is clear that A purchased Wonderland and accordingly, P purchase Brave world. Also, as P purchase Brave world, implies, D must be purchasing The Grapes. R purchase Middle march.)

A purchased wonderland.

1)A and R purchased Middle march and Wonderland but not necessarily in the same order

 

2) Either H or R purchase Pride.

3) Neither P nor N purchased The lion.

4) D purchase either The Grapes or Brave world.

 

5) P does not purchase Catch22.

 

6)A and P purchase Brave world and Wonderland but not necessarily in the same order.

(With respect to statement 1, it is clear that A purchased Wonderland and accordingly, P purchase Brave world. Also, as P purchase Brave world, implies, D must be purchasing The Grapes. R purchase Middle march.)

 

Statement I and III is true.

 

Total number of employees (Manufacturing + Service) in all four given companies together = (1740 + 1560)/4 = 825

Total number of employees (Manufacturing + Service) in company 'X' = 120% × 825 = 990

Number of employees working in the 'Service' sector of company 'B' = 54.55% × 990 = 540

Required average = (540 + 360)/2 = 450

Hence, the correct answer is 450.

 

Let the average salary of all the employees working in the 'Service' sector of company 'B' = x Rs.

ATQ, 840 × 54000 + x × 360 = (840 + 360) × 60000

⇒ 7 × 54000 + x × 3 = 10 × 60000

⇒ 3x = 222000

⇒ x = 74000 Rs.

Hence, the correct answer is 74000 Rs.

 

The number of female employees working in the 'Manufacturing' sector of company 'A' = 45% × 100 = 45

The number of female employees working in the 'Manufacturing' sector of company 'C' = 45 + 35 = 80

The number of male employees working in the 'Manufacturing' sector of company 'C' = 440 - 80 = 360

Hence, the correct answer is 360.

 

Number of employees who are working in the 'Service' sector of company 'E' = (8/9) × 540 = 480

Total number of employees who are working in the 'Service' sector of company 'A' and company 'E' together = 300 + 480 = 780

Hence, the correct answer is 780.

 

Total number of employees working in the 'Service' sectors of company 'C' and company 'D' together = 360 + 540 = 900

Required ratio = 900 : 840 = 15 : 14

Hence, the correct answer is 15 : 14.

Let these numbers are A, B and C 

⇒ A+ B = 7×2

⇒ A+ B = 14  ----- eq 1

Average of last numbers is 9

⇒ B + C = 9×2

⇒ B + C = 18   ------- eq 2

Average of first and last number is 8

⇒ A + C = 8× 2

⇒ A + C = 16 --------- eq 3

subtract eq 1 and eq 2 

We get, A - C = -4 ------ eq 4

Then add eq 3 and eq 4

We get value of A = 6 

Then get the value of B = 8 and C = 10

Average of these numbers = ( 6+8+10) / 3

⇒ 24 / 3

⇒ 8

Hence 8 is the correct answer.

let, speed of current and speed of boat in still water be y km/h and 3y km/h respectively.

According to the question,

45/4y = X ........ (1)

27/2y = (X + 1/2) .......(2)

From equation (1) and (2) comparing the value of X we get

(45/4y) = (27/2y) - 1/2

⇒ (45/4y) - (27/2y) = - 1/2

⇒ - (9/4y) =  - 1/2

⇒ 2y = 9

Speed of boat in upstream = 3y - y = 2y = 9 km/hr

Hence, the correct answer is option 2.

Given:

A can complete the work in = 20 days

B can complete the work in  =  30 days

The whole work was completed in  = 16 days

Concept used :

1 day work = (Total work /No. of days)

Solution:

Total work = 60 (L.C.M of 20 days & 30 days)

 Work completed by A in 1 day = (60/20) = 3       

 Work completed by B in 1 day = (60/30) = 2

The whole work was completed in  = 16 days

A completed  work  = 3 × 16 = 48 

left work = (60 - 48) = 12 

Now, the left work done by B = (12 / 2) = 6 days

Hence B left work after 6 days.

Shortcut Trick

Initial Ratio (Oil:Water) = 5 : 11 (Total 16 units)

Final Ratio (Oil:Water) = 9 : 16 (Note: water to oil was 16:9)

Using Cross-Multiplication Method: (5 × 16) − (11 × 9) units = (11 × 15) − (5 × 14) units is wrong here. Correct setup: (5 × 16 − 11 × 9) units = (14 × 9 − 15 × 16)

|80 − 99| units = |126 − 240| ⇒ 19 units = 114 ⇒ 1 unit = 6 liters

Initial Mixture = 16 × 6 = 96 liters. 83.33% (5/6) of 96 = 80 liters.

∴ The correct answer is 80 liters.

Alternate Method

Given: Initial Ratio Oil:Water = 5:11. Final Ratio Water:Oil = 16:9.

Formula Used: Ratio × constant = Actual Quantity.

⇒ Let Initial Oil = 5x and Initial Water = 11x.

⇒ (5x + 15) / (11x + 14) = 9 / 16

⇒ 16 × (5x + 15) = 9 × (11x + 14)

⇒ 80x + 240 = 99x + 126

⇒ 99x − 80x = 240 − 126

⇒ 19x = 114 ⇒ x = 6

⇒ Total Initial Mixture = 5x + 11x = 16x = 16 × 6 = 96 liters.

⇒ Required Value = 83.33% of 96 = (5/6) × 96

⇒ 5 × 16 = 80 liters.

∴ The correct answer is 80 liters.

Additional Information

Fractional Percentage Values

83.33% is equivalent to the fraction 5/6. Memorizing common fractions like 16.66% = 1/6 and 66.66% = 2/3 helps in faster calculation.

Cross-Multiplication Trick in Ratios

When both parts of a ratio are increased by different amounts, (Initial Ratio 1 × Final Ratio 2 − Initial Ratio 2 × Final Ratio 1) units = (Added Value 2 × Final Ratio 1 − Added Value 1 × Final Ratio 2).

Mixture Replacement

If a part of the mixture is removed, the ratio of ingredients in the remaining mixture and the removed part remains the same as the initial ratio.

Given:

Difference between their profits = 200

Profit gain by Mahesh and Dinesh both = 20%

Formula used:

Gain or loss percent = (Loss or gain/Cost price) × 100

Concept used:

Profit = Selling Price – Cost Price

Loss = Cost Price – Selling Price

Calculation:

Let the selling price for both of them be Rs. x.

Cost price of Dinesh = x × {(100 - 20)/100}

⇒ x × {80/100}

⇒ 4x/5

Cost price of Mahesh = x × {100/(100 +20)}

⇒ x × {100/120}

⇒ 5x/6

Dinesh’s profit = x – (4x/5)

⇒ x/5

Mahesh’s profit = x – (5x/6)

⇒ x/6

Difference of their profits = (x/5) – (x/6) = 200

⇒ x/30 = 200

⇒ x = 6000

∴ The selling price for both of them is Rs. 6000.

Solution :

The series follows the following pattern :

⇒82 + 19 = 101

⇒101 - 38 = 63

⇒63 + 57 = 120

⇒120 - 76 = 44

⇒44 + 95 =139

⇒139 - 114 = 25

⇒ The missing term in the series will be 120.

Hence, 120 is the correct answer.

Solution :

The series follows the following pattern:

⇒640 × 0.5 = 320

⇒320 × 1.5 = 480

⇒480 × 2.5 = 1200

⇒1200 × 3.5 = 4200

⇒4200 × 4.5 = 18900

⇒ The missing term in the series will be 4200.

Hence, 4200 is the correct answer.

Solution :

The series follows the following pattern :

⇒22 + 6 = 28

⇒28 - 12 = 16

⇒16 + 18 = 34

⇒34 - 24 = 10

⇒10 + 30 = 40

⇒40 - 36 = 4

⇒ The next term in the series will be 4.

Hence, 4 is the correct answer.

The logic followed here is as follows:

⇒ 25 * 2 + 2 = 52

⇒ 52 * 2 + 3 = 107

⇒ 107 * 2 + 5 = 219

⇒ 219 * 2 + 7 = 445

⇒ 445 * 2 + 11 = 901

Hence, 901 will come in the place of '?'.

The given series is consecutive prime number.

19, 23, 29, 31, 37, 41

Hence, 41 will come in the place of '?'.

Given:

328 ÷ 8 + 25 × 2.4 + ? = (11)2

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

328 ÷ 8 + 25 × 2.4 + ? = (11)²

⇒ 41 + 60 + ? = 121

⇒ 101 + ? = 121

⇒ ? = 20

∴ 20 should come in place of the question mark (?).

Given:

18 × 60 - 20 × 48 - 80 = ?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

18 × 60 - 20 × 48 - 80 = ?

⇒ 1080 - 960 - 80 = ?

⇒ 120 - 80 = ?

⇒ ? = 40

∴ 40 will come in place of the question mark ('?').

Given:

40% of √225 + 25% of ∛64 = 49 ÷ ?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

40% of √225 + 25% of ∛64 = 49 ÷ ?

⇒ (40/100) × 15 + (25/100) × 4 = 49/?

⇒ (600/100) + (4/4) = 49/?

⇒ 6 + 1 = 49/?

⇒ 7 = 49/?

⇒ ? = 49/7

⇒ ? = 7

∴ 7 will come in place of the question mark ('?').

Given:

225 ÷ 15 + 598 ÷ 13 + ? = 25% of 2500

Concept Used:

​

Calculation:

225 ÷ 15 + 598 ÷ 13 + ? = 25% of 2500

⇒ 15 + 46 + ? = 625

⇒ ? = 625 - 15 - 46

⇒ ? = 564

∴ The value of (?) is 564.

Given:

​√169 + √225 - √196 ÷ √49 × √289 =?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

​√169 + √225 - √196 ÷ √49 × √289 =?

⇒ 13 + 15 - 14 ÷ 7 × 17 = ?

⇒ 28 - (2 × 17) = ?

⇒ ? = 28 - 34

⇒ ? = -6

∴ The value of ‘?’ Is -6.

Given:

1560 + 1280 + 1820 + 240 = (?)2

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

1560 + 1280 + 1820 + 240 = (?)2

⇒ (?)2 = 4900

⇒ ? = √4900

⇒ ? = 70

∴ The value of ‘?’ Is 70.

Given:

​14.28% × 420 + 28.56% × 420 + 120 = ?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

​14.28% × 420 + 28.56% × 420 + 120 = ?

⇒ ​(1/7) × 420 + (2/7) × 420 + 120 = ?

⇒ ​60 + 120 + 120 = ?

⇒ ? = 300

∴ The value of ‘?’ Is 300.

 

​14.28% × 420 + 28.56% × 420 + 120 = ?

⇒ ​(1/7) + (2/7 ) × 420 + 120 = ?

⇒ ​(3/7) × 420 + 120  = ?

⇒ ? = 180 + 120

⇒ ? = 300

∴ The value of ‘?’ Is 300.

Hint

14.28% = 1/7

28.56% = 2/7

Given:

(13 + 7)% of 625 = ? - 10% of 102 

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

(13 + 7)% of 625 = ? - 10% of 102 

⇒ 20% of 625 = ? - 10% of 10²

⇒ (1/5) × 625 = ? - (1/10) × 100

⇒ 125 = ? - 10

⇒ ? = 135

∴ The value of '?' is 135.

Hint

Percentage to fraction table:

Given:

144 × (9.09)% of 121 ÷ 132 = ?

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

144 × (9.09)% of 121 ÷ 132 = ?

⇒ 144 × (1/11) × 121 ÷ 132 = ?

⇒ 144 × 11 × (1/132) = ?

⇒ 144 × (1/12) = ?

⇒ ? = 12

∴ The value of '?' is 12.

Hint

Percentage to fraction table:

Given:

96% of 625 + 360 = ? + (23/25) of 575

Concept Used:

​

Calculation:

96% of 625 + 360 = ? + (23/25) of 575

⇒ (24/25) × 625 + 360 = ? + (23/25) of 575

⇒ ? = 24 × 25 - 23 × 23 + 360

⇒ ? = 600 - 529 + 360

⇒ ? = 71 + 360

⇒ ? = 431

∴ The value of (?) is 431.

Given:

(∛1331 × 136) ÷ 17 + 20% of 650 = ?

Concept Used:

​

Calculation:

(∛1331 × 136) ÷ 17 + 20% of 650 = ?

⇒ (11 × 136) ÷ 17 + (1/5) × 650 = ?

⇒ ? = 88 + 130

⇒ ? = 218

∴ The value of (?) is 218.

Given:

65% of 860 + (3/7) of 343 – 78 + ? = 961

Concept Used:

​

Calculation:

65% of 860 + (3/7) of 343 – 78 + ? = 961

⇒ 559 + 147 - 78 + ? = 961

⇒ ? = 961 - 706 + 78

⇒ ? = 333

∴ The value of (?) is 333.

Given:

√? × 49 + 729 ÷ 92 × 6 = 60% of 825

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

√? × 49 + 729 ÷ 92 × 6 = 60% of 825

⇒ √? × 49 + 729 ÷ 81 × 6 = (60/100) × 825

⇒ √? × 49 + 54 = 3/5 × 825

⇒ √? × 49 + 54 = 495

⇒ √? × 49 = 441

⇒ √? = 9

⇒ ? = 81

∴ 81 should come in place of the question mark (?).

Given:

440 + 1825 ÷ 25 + 102 = 215 + ?

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

440 + 1825 ÷ 25 + 102 = 215 + ?

⇒ 440 + (1825/25) + 102 = 215 + ?

⇒ 440 + 73 + 102 - 215 = ?

⇒ ? = 400

∴ The value of ‘?’ Is 400.

Given:

166.67% of 108 + ? = 150% of 700 - 70

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

166.67% of 108 + ? = 150% of 700 - 70

⇒ (5/3) × 108 + ? = (3/2) ×  700 - 70

⇒ 180 + ? = 1050 - 70

⇒ 180 + ? = 980

⇒ ? = 980 - 180

⇒ 800

∴ The value of ‘?’ Is 800.

Hint

166.66% = 5/3

150% = 3/2

 

Number of 'Bowls' sold by company 'Y' in 2002 = 120 × 80% = 96

Number of 'Bowls' sold by company 'Z' in 2002 = 120 × 60% = 72

Total sales generated by company 'Y' and company 'Z' together in 2002 = 96 × 105 + 72 × 75 = 15480 Rs.

Hence, the correct answer is 15480 Rs.

 

Number of knives sold by company 'X' in 2002 = 87.5% × 80 = 70

Number of knives sold by company 'X' in 2004 = 75% × 80 = 60

Total number of knives sold by company 'X' in 2002 and that in 2004 together = 70 + 60 = 130

Hence, the correct answer is 130.

 

Required difference = (1200 - 600)/4 = 150

Hence, the correct answer is 150.

 

The number of 'Spoons' sold by the company in 2005 = 1.75% × 320 = 560

Required% = [(560 - 480)/480] × 100 = 16.66%

Hence, the correct answer is 16.66%.

 

The total number of 'Spoons' sold by the company in 2001 and 2002 together = 280 + 120 = 400

The total number of 'Bowls' sold by the company in 2003 and 2004 together = 240 + 80 = 320

Required ratio = 400 : 320 = 5 : 4

Hence, the correct answer is 5 : 4.

Shortcut Trick

For Area of Circle = 2464 cm², the Radius (r) is always 28 cm and Circumference is 176 cm.

Breadth (b) = (6/7) × 28 = 24 cm.

Perimeter 2(l + 24) = 176 ⇒ l + 24 = 88 ⇒ Length (l) = 64 cm.

Area of Rectangle = 64 × 24 = 1536 cm².

∴ The correct answer is 1536 cm².

Alternate Method

Given: Area of circle = 2464 cm², Ratio (b : r) = 6 : 7, Circumference = Perimeter.

Formula Used: Area = πr²; Circumference = 2πr; Perimeter = 2(l + b); Area = l × b.

⇒ πr² = 2464

⇒ (22/7) × r² = 2464

⇒ r² = 2464 × (7/22) = 112 × 7 = 784

⇒ r = √784 = 28 cm

⇒ Circumference = 2 × (22/7) × 28 = 176 cm

⇒ Breadth (b) = (6/7) × 28 = 24 cm

⇒ Perimeter of Rectangle = 2(l + b) = 176

⇒ l + 24 = 88 ⇒ l = 64 cm

⇒ Area of Rectangle = 64 × 24 = 1536 cm²

∴ The correct answer is 1536 cm².

Additional Information

Standard Circle Values

For r = 7, Area = 154, Circumference = 44. Since Area ∝ r², if r is multiplied by 4 (r=28), Area is multiplied by 16 (154 × 16 = 2464).

Mensuration Formulas

Rectangle Perimeter = 2(Length + Breadth) and Circle Circumference = 2πr. For competitive exams, memorizing squares up to 30 is essential (√784 = 28).

Let, sum invested be Rs. X

Compound interest earned = X × [1 + (10/100)² - 1] = Rs. 0.21X

Simple interest earned = (X × 10 × 2)/100 = Rs. 0.2X

According to question,

0.21X - 0.2X = 202

0.01X = 202

X = 20200

Hence, correct answer is option 1.

Given∶

Humpy invest 4 times the investment of Dumpy.

Humpy investment period is 3 times the investment period of Dumpy.

Dumpy get Rs. 6000 as profit.

Formula used∶

Basic rules of ratio and proportion.

Calculation∶

Let Dumpy invested Rs. x for y months.

And Humpy invested Rs. 4x for 3y months.

So, the ratio for Humpy’s profit to Dumpy’s profit,

Humpy ∶ Dumpy = (4x × 3y) ∶ (x × y) = 12xy ∶ xy = 12 ∶ 1

Sum of the ratio of profit = 12 + 1 = 13

Dumpy’s profit ∶ total profit = 1 ∶ 13

Let the total profit be Rs ‘z’ then,

1/13 = 6000/z

z = 6000 × 13 = 78,000

∴ The total profit is Rs. 78,000.

Given:

Age of teacher = 1.5 × age of ajay

Age of raj = age of ajay + 5

Calculation:

Let ajay's age be x years

⇒ Teacher's age = 1.5x

And raj's age = x + 5

∴ According to question,

x + 1.5x + x + 5/3 = 25

⇒ 3.5x + 5 = 25 × 3

⇒ 3.5x = 75 - 5

⇒ x = 70/3.5

⇒ x = 20 years

∴ Teacher's age = 1.5 × 20 = 30 years

 Ajay's age = 20 years

And raj's age = 20 + 5 = 25 years

∴ Required ratio = 20:25

= 4:5

∴The ratio of ages of ajay and raj = 4:5

GIVEN :

The capital of A, B, C are in the ratio of 10 : 9 : 6.

The ratio of time period of A : B is 2 : 3.

B gets Rs.10, 800 shares out of a total loss of Rs.26, 000.

 

FORMULA USED :

L1 : L2 : L₃ = I1 × T1  : I2 × T2 : I₃ × T3

Here, L = Loss, I = Investment, T = Time

 

CALCULATION :

The capital of A, B, C are in the ratio of 10 : 9 : 6.

The ratio of time period of A : B is 2 : 3.

A invests capital in the business for 8 months 

Then, the time period of B = 8/2 × 3 = 12 months

Let the time period of C be x.

Then, A : B : C = 10 × 8 : 9 × 12 : 6 × x   

⇒ A : B : C = 40 : 54 : 3x

According to the question:

B gets Rs.10, 800 shares out of a total loss of Rs.26, 000.

Then, $\frac{{54}}{{94 + 3x}} \times 26000 = 10800$

⇒ 130 = 94 + 3x

⇒ 3x = 36

⇒ x = 12

∴ The C invests his capital for 12 months.