From statement 1,

F > A > E

From statement 2,

D > B > F > A > E > C

 C is shorter than A in height.

 Hence, the height of C must be below 172 cm, the only option is 5.

From statement 1,

F > A > E

From statement 2,

D > B > F > A > E > C

Hence, persons who come between F and C are A and E.

From statement 1,

F > A > E

From statement 2,

D > B > F > A > E > C

Hence, the tallest among 6 people is D.

Left side L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3 Right side

So, there is one such number which is followed by vowel and preceded by consonant i.e. Z 6 U.

Hence, one is the correct answer.

Left side L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3 Right side

Numbers between & and # are 9, 5 and 4

So, the sum is 9 + 5 + 4 = 18

Hence, 18 is the correct answer.

Left side L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3 Right side

Fourth element from the right = 7

Symbols which are between the fourth element from the right end and R

L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3

So, there are three such symbols between 7 and R.

Hence, three is the correct answer.

Left side L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3 Right side

So, if we drop all the symbols we get:

L 8 K Z 6 U 3 9 5 R Z 4 G A T E 7 S 3

Then the thirteenth element from right end will be: 3

Hence, 3 is the correct answer.

Left side L ? 8 K Z 6 U 3 & 9 5 $ R + Z 4 @ G A T # E 7 S ! 3 Right side

We have to find the missing combination in this series: L8Z, 639, 5RZ, ?, #7!

L + 2 = 8 and 8 + 2 = Z; Z + 1 = 6

6 + 2 = 3 and 3 + 2 = 9; 9 + 1 = 5

5 + 2 = R and R + 2 = Z; Z + 1 = 4

4 + 2 = G and G + 2 = T; T + 1 = #

+ 2 = 7 and 7 + 2 = !; ! + 1 = 3

Hence, 4GT is the correct answer.

The below table represents symbols used to draw a family tree,

Given:

1) family of seven member having three generations

2. There are more than four females in the family.

3. A is the father of B. L is married to the only son of G.

             

4. L has an unmarried sibling K. B is the nephew of K. 

5) C is the child of A. G is mother of A. 

  

H is the parent of L.

Here  A, B are male members therefore remaining members are definitely are female as it is given that more than 4 females in the family.

We can draw the following Family Tree from the information given above:

Hence, H is the mother of L.

The below table represents symbols used to draw a family tree,

Given:

1) family of seven member having three generations

2. There are more than four females in the family.

3. A is the father of B. L is married to the only son of G.

4. L has an unmarried sibling K. B is the nephew of K. 

5. C is the child of A. G is mother of A. 

H is the parent of L.

Here A, B are male members therefore remaining members are definitely are female as it is given that more than 4 females in the family.

We can draw the following Family Tree from the information given above:

Hence, C is the granddaughter of G.

The below table represents symbols used to draw a family tree,

Given:

1) family of seven member having three generations

2. There are more than four females in the family.

3. A is the father of B. L is married to the only son of G.

             

4. L has an unmarried sibling K. B is the nephew of K. 

5) C is the child of A. G is mother of A. 

  

H is the parent of L.

Here  A, B are male members therefore remaining members are definitely are female as it is given that more than 4 females in the family.

We can draw the following Family Tree from the information given above:

Hence, K is the Sister-in-law of A.

Given word: LEMON

The alphabets are positioned as in the following order,

The given word can be represented as follows,

In forward direction: LO.

In backward direction: NO.

Hence, there are Two pairs of letters.

1. Given word: BOUQUET’

2. The arrangement of letters of a word in English alphabetical order are:

 

Hence, there are two letters which will remain in their original position.

Given Series: - 369 717 922 625 434

When all the numbers are arranged in descending order from left to right, we get

922 717 625 434 369

Second number from right end number is 434.

So, product of the first and last digits is 4 × 4 = 16.

Hence, the correct answer is 16.

Given Series: - 369 717 922 625 434

When first and third digit of each number is interchanged, we get

963 717 229 526 434

Third lowest number is 526

The sum of the first and second digits = 5 + 2 = 7.

Hence, the correct answer is 7.

Given Series: - 369 717 922 625 434

When 1 is subtracted from each odd number and 1 is added to each even number, we get

278 606 833 734 525

Highest number formed is 833.

The difference between the third digit and the first digit is 8 – 3 = 5.

Hence, the correct answer is 5.

Given Series: - 369 717 922 625 434.

The highest number is 922 and the second lowest number is 434.

First digit of the highest number is 9 and third digit of second lowest number is 4

So, the resultant is = 9 ÷ 4 = 2.25 after divition.

Hence, the correct answer is 2.25.

Given Series: - 369 717 922 625 434

When each digit are arranged in descending order within the number, we get

963 771 922 652 443

Second lowest number is 652.

Hence, the correct answer is 625 .

Word: MARKET

2nd letter = A; 5th letter = E; 6th letter = T

Letters given: AET

Words possible starting with E: EAT.

Hence, only 1 such word is possible.

1. In the above question we have to find the word which is start from the letter 'E'.

Eight persons - A, B, C, D, E, F, G and H

Floor - 1 to 4, Flat - 1 and 2

1. There are two floor between B and C. B lives above C in the different flats. So here two possibilities for this.

 

2) A lives just west of D but on the odd number of floors. So, here remaining odd number floor is number 3. F lives just above C

 

3. No person lives west of G who lives on fourth floor.

In Case - II B lives on flat - 1 so G lives between flat - 2, So here B lives west of G. It contradict the given condition no person lives west of G so here Case - II gets cancelled. 

 

4. H does not live on floor number one. So H will live on floor number 2. There is only one place remaining for the E, on floor number 1.

 

Hence, H lives just east of F.

Eight persons - A, B, C, D, E, F, G and H

Floor - 1 to 4, Flat - 1 and 2

1. There are two floor between B and C. B lives above C. So here two possibilities for this.

 

2) A lives just west of D but on odd number of floor. So, here remaining odd number floor is number 3. F lives just above C

 

3. No person lives west of G who lives on fourth floor.

In Case - II B lives on flat - 1 so G lives between flat - 2, So here B lives west of G. It contradict the given condition no person lives west of G so here Case - II gets cancelled. 

 

4. H does not live on floor number one. So H will live on floor number 2. There is only one place remaining for the E, on floor number 1.

 

Hence, B lives on Fourth Floor.

Eight persons - A, B, C, D, E, F, G and H

Floor - 1 to 4, Flat - 1 and 2

1. There are two floor between B and C. B lives above C. So here two possibilities for this.

 

2) A lives just west of D but on odd number of floor. So, here remaining odd number floor is number 3. F lives just above C

 

3. No person lives west of G who lives on fourth floor.

In Case - II B lives on flat - 1 so G lives between flat - 2, So here B lives west of G. It contradict the given condition no person lives west of G so here Case - II gets cancelled. 

 

4. H does not live on floor number one. So H will live on floor number 2. There is only one place remaining for the E, on floor number 1.

 

Hence, E lives just below H.

Eight persons - A, B, C, D, E, F, G and H

Floor - 1 to 4, Flat - 1 and 2

1. There are two floor between B and C. B lives above C. So here two possibilities for this.

 

2) A lives just west of D but on odd number of floor. So, here remaining odd number floor is number 3. F lives just above C

 

3. No person lives west of G who lives on fourth floor.

In Case - II B lives on flat - 1 so G lives between flat - 2, So here B lives west of G. It contradict the given condition no person lives west of G so here Case - II gets cancelled. 

 

4. H does not live on floor number one. So H will live on floor number 2. There is only one place remaining for the E, on floor number 1.

 

Hence, Floor - 3 Flat - 2 - D is correct pair.

Eight persons - A, B, C, D, E, F, G and H

Floor - 1 to 4, Flat - 1 and 2

1. There are two floor between B and C. B lives above C. So here two possibilities for this.

 

2) A lives just west of D but on odd number of floor. So, here remaining odd number floor is number 3. F lives just above C

 

3. No person lives west of G who lives on fourth floor.

In Case - II B lives on flat - 1 so G lives between flat - 2, So here B lives west of G. It contradict the given condition no person lives west of G so here Case - II gets cancelled. 

 

4. H does not live on floor number one. So H will live on floor number 2. There is only one place remaining for the E, on floor number 1.

 

Hence, Floor - 1 Flat - 2 is correct combination.

Seven persons - A, B, C, D, E, F and G.

1. B sits at the extreme right end of the row.
2. E sits exactly between G and B.
3. G sits second to the left of B.

4. Only two persons sit between F and G.
5. D sits third to the left of C and A sits second to the right of D.

Hence, there are two persons sit between B and C.

Seven persons - A, B, C, D, E, F and G.

1. B sits at the extreme right end of the row.
2. E sits exactly between G and B.
3. G sits second to the left of B.

4. Only two persons sit between F and G.
5. D sits third to the left of C and A sits second to the right of D.

Hence, D sits at the extreme left end of the row.

Seven persons - A, B, C, D, E, F and G.

1. B sits at the extreme right end of the row.
2. E sits exactly between G and B.
3. G sits second to the left of B.

4. Only two persons sit between F and G.
5. D sits third to the left of C and A sits second to the right of D.

Hence, C sits exactly in the middle of the line.

Seven persons - A, B, C, D, E, F and G.

1. B sits at the extreme right end of the row.
2. E sits exactly between G and B.
3. G sits second to the left of B.

4. Only two persons sit between F and G.
5. D sits third to the left of C and A sits second to the right of D.

Hence, A is sitting second to the right of D.

The least possible Venn diagram for the given statements is as follows,

Conclusion:

I. No cold is hotter is a possibility → True

II. All cold are hotter → False (It is possible but not definite)

Hence, only conclusion I follows.

The least possible Venn diagram for the given statements is as follows,

Conclusion:

I. All rank are way → False (It is possible but not definite)

II. Some way are not count → True (as the part containing both rank and way, cannot be part of count)

Hence, only conclusion II follows.

The least possible Venn diagram for the given statements is as follows,

Conclusion:

I. Some sea are ocean → False (It is possible but not definite)

II. All ocean are song → False (It is possible but not definite)

Hence, neither conclusion I nor II follows.

According to the given information,

1. C sits second to the left of W.
2. Three people are sitting between C and X. 

3. X and A are sitting immediately right to each other.
4. W is not sitting adjacent to A.

5. B is sitting opposite to Y.
6. B is not sitting adjacent to C.

7. Y and Z are not sitting adjacent to each other.
8. D is not facing outside. Here case 2 gets eliminated.

So, Z is sitting opposite to A.

According to the given information,

1. C sits second to the left of W.
2. Three people are sitting between C and X. 

3. X and A are sitting immediately right to each other.
4. W is not sitting adjacent to A.

5. B is sitting opposite to Y.
6. B is not sitting adjacent to C.

7. Y and Z are not sitting adjacent to each other.
8. D is not facing outside. Here case 2 gets eliminated.

So, D is sitting third to the left of B.

According to the given information,

1. C sits second to the left of W.
2. Three people are sitting between C and X. 

3. X and A are sitting immediately right to each other.
4. W is not sitting adjacent to A.

5. B is sitting opposite to Y.
6. B is not sitting adjacent to C.

7. Y and Z are not sitting adjacent to each other.
8. D is not facing outside. Here case 2 gets eliminated.

So, except A all the other people are facing the center.

According to the given information,

1. C sits second to the left of W.
2. Three people are sitting between C and X. 

3. X and A are sitting immediately right to each other.
4. W is not sitting adjacent to A.

5. B is sitting opposite to Y.
6. B is not sitting adjacent to C.

7. Y and Z are not sitting adjacent to each other.
8. D is not facing outside. Here case 2 gets eliminated.

So, D and C are sitting adjacent to Y.

According to the given information,

1. C sits second to the left of W.
2. Three people are sitting between C and X. 

3. X and A are sitting immediately right to each other.
4. W is not sitting adjacent to A.

5. B is sitting opposite to Y.
6. B is not sitting adjacent to C.

7. Y and Z are not sitting adjacent to each other.
8. D is not facing outside. Here case 2 gets eliminated.

B is sitting immediate left of X, and C is sitting third to the right of B.

So, C is sitting third to the right of the person sitting immediately left of X.

(1) S is sitting third from the extreme end.

(2) Two people are sitting between S and F.

(3) T is sitting second to the right of F.

(4) A is sitting exactly between E and F. A is adjacent to E.

(5) Six people are sitting between T and V, who does not sit at any end.

(6) G is sitting to sixth to the right of T. Case (II) eliminates here.

(7) Number of people sitting to the right of G is same as the people sitting to the left of E.

(8) Two people are sitting between P and R who is sitting to the right of V. Therefore, the final seating arrangement is as follows:

Hence, option 5 is true.

(1) S is sitting third from the extreme end.

(2) Two people are sitting between S and F.

(3) T is sitting second to the right of F.

(4) A is sitting exactly between E and F.  A is adjacent to E.

(5) Six people are sitting between T and V, who does not sit at any end.

(6) G is sitting to sixth to the right of T. Case (II) eliminates here.

(7) Number of people sitting to the right of G is same as the people sitting to the left of E.

(8) Two people are sitting between P and R who is sitting to the right of V. Therefore, the final seating arrangement is as follows:

Hence, number of people sitting to the right of A is same as to the left of P.

(1) S is sitting third from the extreme end.

(2) Two people are sitting between S and F.

(3) T is sitting second to the right of F.

(4) A is sitting exactly between E and F. A is adjacent to E.

(5) Six people are sitting between T and V, who does not sit at any end.

(6) G is sitting to sixth to the right of T. Case (II) eliminated here.

(7) Number of people sitting to the right of G is the same as the people sitting to the left of E.

(8) Two people are sitting between P and R who is sitting to the right of V. Therefore, the final seating arrangement is as follows:

Hence, eight persons are sitting between A and G.

(1) S is sitting third from the extreme end.

(2) Two people are sitting between S and F.

(3) T is sitting second to the right of F.

(4) A is sitting exactly between E and F. A is adjacent to E.

(5) Six people are sitting between T and V, who does not sit at any end.

(6) G is sitting to sixth to the right of T. Case (II) eliminates here.

(7) Number of people sitting to the right of G is same as the people sitting to the left of E.

(8) Two people are sitting between P and R who is sitting to the right of V. Therefore, the final seating arrangement is as follows:

Hence, 17 persons are there in the row.

Given:

(21% of 3600) – (36% of 1050) = ?

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

⇒ (21% of 3600) – (36% of 1050) = ?

⇒ (21/100 × 3600) – (36/100 × 1050) = ?

⇒ 756 – 378 = ?

⇒ 378 = ?

∴ The value of ? is 378

Given:

$\sqrt {\frac{?}{{144}}} = \frac{{36}}{{48}}$

Concept used:

Simplification

Calculation:

⇒ $\sqrt {\frac{?}{{144}}} = \frac{{36}}{{48}}$

⇒ $\frac{{\sqrt ? }}{{12}} = \frac{3}{4}$

⇒ $\sqrt ?= \frac{{12 \times 3}}{4}$

⇒ $\sqrt ? = 9$

Squaring on both sides we get,

∴ ? = 81

Given:

56 × ? – 768 = 576

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

Using the BODMAS rule

⇒ 56 × ? – 768 = 576

⇒ 56 × ? = 576 + 768

⇒ 56 × ? = 1344

⇒ ? = 1344/56

⇒ ? = 24

∴ 24 will come in place of ‘?’

Given:

(72 – 62 – 3) + 12 = ?

Concept used:

Calculation:

(72 – 62 – 3) + 12 = ?

⇒ 49 - 36 - 3 + 12 = ?

⇒ (49 + 12) - 36 - 3 = ?

⇒ 61 - 39 = ?

⇒ ? = 22

∴ The value of ‘?’ is 22.

Concept used:

Follow BODMAS rule to solve this question as per the order given below,

Calculation:

25% of 340 + 17 – 21 = ?

⇒ 85 + 17 – 21 = ?

⇒ 102 – 21 = ?

⇒ ? = 81

∴ The value of ? is 81.

Concept used:

Follow BODMAS rule to solve this question as per the order given below,

Calculation:

(√225 + 6) × 7 = 3 × ?

⇒ (15 + 6) × 7 = 3 × ?

⇒ 21 × 7 = 3 × ?

⇒ 147 = 3 × ?

⇒ ? = 49

∴ The value of ? is 49.

Concept used:

Follow BODMAS rule to solve this question as per the order given below,

Calculation:

(216 ÷ 3) + 9 = ?/5

⇒ 72 + 9 = ?/5

⇒ 81 = ?/5

⇒ ? = 405

∴ The value of ? is 405.

Concept used:

Follow the BODMAS 

rule to solve this question, as per the order given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Now,

$4 \frac {3}{5} + 5\frac{1}{4} - 4 \frac {5}{8} = ?$

 

⇒ (4 + 5 - 4) + 3/5 + 1/4 -5/8 = ?

⇒ 5 + (24 + 10 - 25)/40 = ?

⇒ 5 + 9/40 = ?

⇒ $5\frac{9}{40}$= ?

∴ In the place of question(?) $5\frac{9}{40}$will come

Given:

3542 ÷ 22 + 200 = ?²

Concept used:

Calculation:

Considering the following given question

3542 ÷ 22 + 200 = ?²

⇒ 161 + 200 = ?²

⇒ 361 = ?²

⇒ 19 = ?

∴ The value of ? is 19.

Concept:

This type of question can be solved by the help of BODMAS

Follow BODMAS rule to solve this question, as per the order given below

Step – 1: Parts of an equation enclosed in ‘Brackets’ must be solved first and, in the bracket,

Step – 2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,

Step – 3: Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated,

Step – 4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Calculation:

30% of 30 – 12 + 7 = ?

⇒ 9 – 12 + 7

⇒ 16 – 12

⇒ 4

∴ The required result will be 4.

Calculation:

75% of 480 + (?)² = 5544

⇒ 360 + (?)² = 5544

⇒ (?)² = 5544 – 360

⇒ (?)² = 5184

⇒ ? = √5184

⇒ ? = 72

∴ 72 will come in place of question mark

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

? + 548 = 65% of 1500

⇒ ? + 548 = 975

⇒ ? = 975 – 548

⇒ ? = 427

∴ The value of ? is 427

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

125 × 5⁵ = 5^? × (25)²

⇒ 5³ × 5⁵ = 5^? × 5⁴

⇒ 5³⁺⁵ = 5^{? + 4}

⇒ 5⁸ = 5^{? + 4}

On comparing the powers,

⇒ 8 = ? + 4

⇒ 8 – 4 = ?

⇒ 4 = ?

∴ The value of ? is 4

Concept :

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

Given expression is

{(7776)^1/5 × 1296} = (6)^?

⇒ (6 × 1296) = 6^?

⇒ (6 × 6⁴) = 6^?

⇒ (6^{1 + 4}) = 6^?

⇒ 6⁵ = 6^?

∴ ? = 5

Concept used:

 

Calculation:

Considering the given equation

50% of 2500 – 20% of 1725 = ?

⇒ (1/2)  × 2500 – (1/5) × 1725 = ?

⇒ 1250 – 345 = ?

⇒ ? = 905

∴ The value of ? is 905

Given:

Tap A can empty a tank in 120 minutes (i.e. 2 hours)

Tap B can empty a tank in 60 minutes

Calculation:

⇒ Total capacity of the tank = 120 units

⇒ Tank empty by tap A in 1 minute = 1 unit (i.e. 120 / 120)

⇒ Tank empty by tap B in 1 minute = 2 units (i.e. 120 / 60)

⇒ Tank empty in 1 minute when both the pipes are opened simultaneously = 3 units

∴ Full tank empty by both the pipes = 40 minutes (i.e. 120 / 3)

Given:

Profit % = 35%

Discount % = 10%

Formula:

Profit = SP - CP

Profit % = (SP - CP)/CP × 100

Calculation:

Let cost price of an article be Rs. 100

⇒ 35 = (SP - 100)/100 × 100

Selling price = Rs. 135

Then,

⇒ 135 = marked price × (100 - 10)/100

⇒ Marked price = Rs. 150

Selling price when discount is 20% = 150 × (100 - 20)/100 = Rs. 120

∴ Profit % when discount is 20% = (120 - 100)/100 × 100 = 20%

Given:

For A,

P = Rs. 10,000

Rate = 10% & Time = 2 years

For B,

P = Rs. 18,000

Rate = 20% & Time = 3 years

Formula used:

Simple interest  = (P × R × T)/100

Calculation:

Simple interest earned by A = (10000 × 2 × 10)/100 = Rs 2000

Simple interest earned by B = (18000 × 3 × 20)/100 = Rs 10,800

∴ Required difference = 10,800 - 2000 = Rs 8,800.

Given: 

A’s share : B’s share =  4000 × 12 : 5000 × (12 – 4)

A's share : B's share =  6 : 5

Calculation:

Let the share of A = 6x,

And the share of B = 5x

According to the question, 

⇒ 6x + 5x = 22000   

⇒ 11x = 22000

⇒ x = Rs.2000

⇒ Share of A = 6x 

Put the value of x 

⇒  6 × 2000 

⇒ A's share = Rs.12,000

And  B's share  = 5x

Put the value of x 

⇒ 5 × 2000 =

⇒ B's share = Rs.10,000

∴ Share of A and B are Rs. 12,000 & Rs. 10,000.

 

 

Shares of A and B could be determined by the following method also.

⇒ $A's;share = \frac{6}{{11}} \times 22000 = Rs.12000$

⇒ $B's;share = \frac{5}{{11}} \times 22000 = Rs.10000$

∴ Share of A and B  Rs. 12000 & Rs. 10000.

Given:  

The area of the rectangle = $\frac{1}{3}$ × The area of the square

The area of the square = 576 cm²

The breadth of the rectangle = 12 cm 

Formula Used: 

The area of rectangle = Length × Breadth

The perimeter of rectangle = 2 × (Length + Breadth)

Calculation:

The area of the square = 576 cm2

The area of the rectangle = $\frac{1}{3}$ × The area of the square

⇒ The area of the rectangle = $\frac{1}{3}$ ×  576 cm2 = 192 cm²

The breadth of the rectangle = 12 cm 

The area of rectangle = Length × Breadth

⇒ 192 = Length × 12

⇒ Length = 16 cm

The perimeter of rectangle = 2 × (Length + Breadth)

⇒ The perimeter of rectangle = 2 × (16 + 12)

⇒ The perimeter of rectangle = 2 × 28

⇒ The perimeter of rectangle = 56 cm

∴ The perimeter of rectangle is 56 cm.

Number of bags unsold for companies C and D together = (80 – 50) + (120 – 100) = 50

Number of bags sold by companies A and B together= 80 + 80 = 160

∴ Required percent = 50/160 × 100 = 31.25%

Total number of bags sold by all  the companies = 80 + 80 + 50 + 100 = 310

∴ Required average = 310/4 = 77.5

Number of bags manufactured by company B = 120

Number of bags manufactured by company C = 80

∴ Required percent = (120 – 80)/80 × 100 = 50%

Total number of bags sold by company B and C = 80 + 50 = 130

Number of bags unsold for company D = 120 – 100 = 20

∴ Required ratio = 130 : 20 = 13 : 2

Total number of bags unsold for companies A, B, and C = (100 – 80) + (120 – 80) + (80 – 50) = 90

Number of bags manufactured by company D = 120 

∴ Required difference = 120 – 90 = 30

The series follows the following pattern:

54 + 22 = 58

58 – 32 = 49

49 + 42 = 65

65 – 52 = 40

40 + 62 = 76  

∴ The wrong term in the series is 42.

The series follows the following pattern:

45 + 12 = 46

46 - 22 = 42

42 + 32 = 51

51 - 42 = 35

35 + 52 = 60

∴ The wrong term in the series is 40.

The series follows the following pattern:

50 – 15 = 35

35 + 11 = 46

46 – 15 = 31

31 + 11 = 42

42 – 15 = 27

∴ The wrong term in the series is 44.

The series follows the following pattern:

9 × 2 - 1 = 17

17 × 2 - 1 = 33

33 × 2 - 1 = 65

65 × 2 - 1 = 129

129 × 2 - 1 = 257

∴ The wrong term in the series is 255.

The series follows the following pattern:

32 + 1 = 10

33 + 2 = 29

32 + 3 = 12

33 + 4 = 31

32 + 5 = 14 

33 + 6 = 33

∴ The wrong term in the series is 32.

Given 

A container has capacity of 20 litres .

Formula used 

Milk left in container after n operations/Original quantity of milk in container

Calculation

Here, number of operations is 2, that is n = 2

Now,  Milk left in container after n operations/Original quantity of milk in container

⇒ ((20 – 10)/20)² × 20

⇒ (10/20)² × 20

⇒ 1/4 × 20 = 5 litre

∴ 5 litre of milk is left in the mixture.

Given:

Monthly income of the person = Rs. 6500

Spent on rent = 10%

Spent on Food and other purpose = 25%

Concept:

Saving = Income ─ Expenditure

Calculation:

Total expenditure = 10% + 25% = 35% = 6500 × (35/100) = Rs.2275

∴ Total savings = (6500 ─ 2275) = Rs. 4225

GIVEN:

Ajay : Atul (present) = 4 : 9

Ajay : Atul (9 years ago) = 1 : 3

EXPLANATION:

Let the ages of Ajay and Atul be 4x and 9x respectively.

A.T.Q

4x - 9/9x - 9 = 1/3

12x - 27 = 9x - 9

3x = 18 x = 6

∴ Ajay's age = 4x = 24 yrs

Atul's age = 9x = 54 yrs

Age ratio after 6 years = (24 + 6)/(54 + 6) = 1 : 2

∴ The ratio will be 1 : 2

Solution:

Let the speed of the boat in still water be u km/hr and the speed of the stream is v km/hr.

Formula Used:

Speed while travelling downstream = u + v

Speed while travelling upstream = u – v

Calculations:

Time(upstream) = (Distance/Speed)_upstream = 60/(u - v)

Time(downstream) = (Distance/Speed)_downstream = 120/(u + v)

It is given that he can row 60km upstream in the same time as 120 km downstream.

⇒ 60/(u - v) = 120/(u + v)

⇒ u + v = 2u – 2v

⇒ 3v = u

⇒ u : v = 3 : 1

Let u = 3x and v = x

Speed_(upstream) = u – v = 3x – x = 2x km/hr

It can row 300 km upstream in 10 hours.

⇒ 2x = 300/10

⇒ x = 15

⇒ u = 3x = 15 × 3 = 45 km/hr

Given :

There are four consecutive even numbers, such that the average of the last and the first number is 11.

Calculations :

Let the numbers be 2x, (2x + 2), (2x + 4) and (2x + 6)             (numbers are even)

According to the question 

Average of the first and the last is 11 

So, 

(2x + 2x + 6)/2 = 11 

⇒ 4x + 6 = 22 

⇒ 4x = 16 

⇒ x = 4 

So the number are 8, 10, 12 and 14 

Difference between the second and the third number = 12 - 10 

⇒ 2 

∴ The correct answer will be option number 2 

Alternate Method

Calculations:

Here, all four numbers are consecutive even number and the difference between two consecutive even number is 2.

So, the difference between the second and the third number is 2

∴ The correct answer will be option number 2

Given:

 

Calculations:

Total number of Reporter jobs in three years = 400 + 550 + 720

= 1670

⇒ Required average = 1670/3

∴ Required average = 556.66 ≈ 557

Total number of jobs in year 2001 = 400 + 500 + 640 + 420 = 1960

Total number of jobs in year 2003 = 720 + 600 + 530 + 500 = 2350

Required percentage =

⇒ (2350 – 1960)/2350 × 100%

⇒ 16.59% ≈ 17%

∴ The required percentage is 17%.

Total number of Journalists jobs in three years = 420 + 650 + 500 = 1570

Total number of Anchors jobs in three years = 500 + 400 + 600 = 1500

Required ratio = 1570: 1500

= 157: 150

∴ Required ratio is 157: 150

Total number of Jobs in the year 2002 = 550 + 400 + 750 + 650 =2350

Total number of jobs in the year 2001 = 400 + 500 + 640 + 420 = 1960

Required difference = 2350 – 1960 = 390

∴ Required difference is 390

Total number of Editors jobs in three years = 640 + 750 + 530 = 1920.

Number of Editors jobs in the year 2002 = 750

Required percentage =

⇒ 750/1920 × 100

⇒ 39.06% ≈ 39%

∴ The required percentage is 39%.