Complete the analogy.
\(\frac{5}{6}:\frac{{64}}{{49}} ::\frac{4}{7}:?\)
- AOption (a)
\(\frac{{16}}{{49}}\)
- BOption (b)
\(\frac{{27}}{{64}}\)
- COption (c)
\(\frac{{64}}{{49}}\)
- DOption (d)
\(\frac{{125}}{{64}}\)
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Correct answer
\(\frac{{27}}{{64}}\)
Why this answer is correct
Logic is as follows:
\({ 5{} \over 6} : { 64{} \over 49}\) → \({ 5{} \over 6} : { (5 -1)^3{} \over (6 + 1)^2}\)
Similarly,
\({ 4{} \over 7} : { (4 -1)^3{} \over (7 + 1)^2}\) → \({4{} \over 7} : { 27{} \over 64}\)
Hence, '\({ 27{} \over 64}\)" is the correct answer.







