This question is based on the given words.
NUT LAP ION NIP
In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding it in the English alphabetical order. In how many letter-clusters thus formed, will no vowel appear?
- AOption (a)
One
- BOption (b)
Four
- COption (c)
Three
- DOption (d)
Two
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Correct answer
Two
Why this answer is correct
Given: NUT LAP ION NIP
According to the question:
| Given words | NUT | LAP | ION | NIP |
|---|---|---|---|---|
| Vowel → (+1) Consonant → (-1) | ||||
| Resultant words | MVS | KBO | JPM | MJO |
| Required answer | No vowel | One vowel | No vowel | One vowel |
Thus, according to the final arrangement, in only two words thus formed will have no vowel.
Hence, "Option 4" is the correct answer.
