Given:
Number of bananas Rajesh has with him = 12.
Rajesh sells x (out of 12) bananas at profit = 15%
Rajesh sells (12 - x) bananas at loss = 15%.
Final profit% of Rajesh = 10%.
Formulae used:
Let C.P. = Cost price and S.P. = Selling price, then
Profit% = [(S.P. - C.P.) / C.P.] × 100
Loss% = [(C.P. – S.P.) / C.P.] × 100
Calculation:
Let the number of bananas sold by Rajesh at 15% profit be x then the number of bananas sold by Rajesh at 15% loss will be (12 - x).
Also, let the C.P. of 1 banana be Re.
- C.P. of 12 bananas = Rs. 12.
C.P. of x bananas = Rs.
x. S.P. of x bananas which are sold at a profit of 15% will be
Profit% = [(S.P. - C.P.) / C.P.] × 100
\(15 = \left(\dfrac{S.P. - x}{x}\right) × 100 \)
\(\dfrac{15}{100} = \left(\dfrac{S.P. - x}{x}\right) \)
\(\dfrac{3}{20} = \left(\dfrac{S.P. - x}{x}\right) \)
3x = 20 × (S.P. - x)
3x = 20 × S.P. - 20x
23x = 20 × S.P.
S.P. = 23x / 20.
Now,
C.P. of (12 - x) bananas = Rs. (12 - x).
S.P. of (12 - x) bananas which are sold at 15% loss
Loss% = [(C.P. – S.P.) / C.P.] × 100
\(15 = \left(\dfrac{(12 -x)-S.P.}{12-x}\right) × 100\)
\(\dfrac{15}{100} = \left(\dfrac{(12 -x)-S.P.}{(12 - x)}\right) \)
\(\dfrac{3}{20} = \left(\dfrac{(12 -x)-S.P.}{(12 - x)}\right) \)
3 × (12 - x) = 20 × ((12 - x) - S.P.)
36 - 3x = 20 × (12 - x) - 20 × S.P.
36 - 3x = 240 - 20x - 20 × S.P.
17x - 204 = 20 × S.P.
S.P. = (204-17x) / 20
Total S.P. of 12 bananas
\(= \dfrac{23x}{20} + \dfrac{204-17x}{20} \)
= (6x + 204) / 20.
As the final profit is 10%, we have
Profit% = [(S.P. - C.P.) / C.P.] × 100
\(10 = \left(\dfrac{\dfrac{6x + 204}{20} - 12}{12}\right) × 100 \)
\(\dfrac{10}{100} = \left(\dfrac{6x + 204 - (12 × 20)}{20 × 12}\right)\)
\(\dfrac{1}{10} = \left(\dfrac{6x + 204 - 240}{20 × 12}\right) \)
\(\dfrac{1}{10} = \left(\dfrac{6x - 36}{20 × 12}\right) \)
240 / 10 = 6x - 36
24 = 6x - 36
6x = 60
x = 10.
∴ The value of x is 10.
Shortcut TrickLoss of 15% can be denoted as -15% profit.
Using Mixture and Alligation -
The ratio of the number of bananas sold at 15% profit to the number of bananas sold at 15% loss = 25 : 5
⇒ 5 : 1
Now, the number of bananas sold at 15% profit (x) = 12 × 5/(5 + 1)
⇒ 10
∴ The value of x is 10.