
Shortcut Trick
Relative Speed = 96 + 84 = 180 kmph → 180 × (5/18) = 50 m/s.
Total length (Train U + Train V) = 50 × 24 = 1200 m.
Ratio of lengths U : V = 2 : 1 ⇒ 3 units = 1200 m ⇒ Length of Train U = 800 m.
Speed of Train U = 96 × (5/18) = 80/3 m/s.
Total distance in 90 s = (80/3) × 90 = 2400 m ⇒ Platform = 2400 − 800 = 1600 m.
∴ The correct answer is 1600 m.

Alternate Method
Given: Speed of Train U (Su) = 96 kmph, Speed of Train V (Sv) = 84 kmph, Time to cross (T1) = 24 s, Time to cross platform (T2) = 90 s.
Formula Used: Distance = Speed × Time; Relative Speed (Opposite) = S1 + S2; 1 kmph = 5/18 m/s.

⇒ Relative Speed = (96 + 84) × 5/18 = 180 × 5/18 = 50 m/s
⇒ Total Length = Speed × Time = 50 × 24 = 1200 m
⇒ Let length of Train V = L, then Train U = 2L
⇒ 2L + L = 1200 ⇒ 3L = 1200 ⇒ L = 400 m
⇒ Length of Train U = 2 × 400 = 800 m
⇒ Speed of Train U in m/s = 96 × 5/18 = 80/3 m/s
⇒ Distance covered in 90 s = (80/3) × 90 = 2400 m
⇒ Length of Platform = Total Distance − Length of Train U = 2400 − 800 = 1600 m
∴ The correct answer is 1600 m.

Additional Information
Relative Speed Concept
When two objects move in opposite directions, their relative speed is the sum of their individual speeds (S1 + S2).
Crossing Stationary Objects
When a train crosses a platform or bridge, the total distance covered is the sum of the length of the train and the length of the object.
Unit Conversion
To convert speed from km/hr to m/s, multiply by 5/18. To convert m/s to km/hr, multiply by 18/5.